MANYA CAT
SAMPLE PAPER (XAT)
ANSWERS
1. (4)
2. (1)
3. (4)
4. (2)
5. (2)
6. (2)
7. (3)
8. (4)
9. (4)
10. (4)
11. (2)
12. (2)
13. (4)
14. (2)
15. (2)
16. (3)
17. (1)
18. (3)
19. (2)
20. (1)
21. (3)
22. (4)
23. (1)
24. (3)
25. (4)
26. (1)
27. (1)
28. (4)
29. (4)
30. (1)
31. (3)
32. (1)
33. (1)
34. (2)
35. (3)
36. (2)
37. (1)
38. (2)
39. (2)
40. (2)
41. (3)
42. (1)
43. (2)
44. (3)
45. (3)
46. (1)
47. (1)
48. (2)
49. (1)
50. (3)
51. (3)
52. (1)
53. (1)
54. (1)
55. (3)
56. (2)
57. (2)
58. (3)
59. (1)
60. (1)
61. (1)
62. (2)
63. (1)
64. (3)
65. (3)
66. (1)
67. (2)
68. (4)
69. (2)
70. (3)
71. (1)
72. (1)
73. (2)
74. (4)
75. (4)
76. (4)
77. (1)
78. (2)
79. (2)
80. (1)
81. (3)
82. (3)
83. (4)
84. (1)
85. (2)
86. (2)
87. (2)
88. (3)
89. (4)
90. (3)
91. (4)
92. (3)
93. (4)
94. (4)
95. (2)
96. (2)
97. (1)
98. (4)
99. (4)
100. (2)
101. (3)
102. (4)
103. (1)
104. (3)
105. (1)
106. (3)
107. (2)
108. (4)
109. (2)
110. (4)
111. (3)
112. (3)
113. (2)
114. (1)
115. (1)
116. (1)
117. (1)
118. (2)
119. (3)
120. (1)
121. (3)
122. (3)
123 (1)
124. (3)
125. (3)
126. (1)
127. (3)
128. (4)
129. (4)
130. (2)
131. (4)
132. (2)
133. (3)
134. (3)
135. (2)
136. (4)
137. (4)
138. (4)
139. (3)
140. (2)
141. (4)
142. (1)
143. (2)
144. (2)
145. (3)
146. (3)
147. (2)
148. (3)
149. (3)
150. (2)
151. (1)
152. (2)
153. (2)
154. (1)
155. (1)
156. (3)
157. (3)
158. (1)
159. (2)
160. (2)
161. (1)
162. (4)
163. (2)
164. (4)
165. (2)
166. (2)
167. (1)
168. (3)
169. (4)
170. (1)
171. (1)
172. (1)
173. (3)
174. (3)
175. (3)
176. (3)
177. (3)
178. (4)
179. (2)
180. (2)
181. (3)
182. (4)
183. (3)
184. (1)
185. (3)
186. (1)
187. (1)
188. (1)
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Page 1 of 11
MANYA CAT
9. (4)
Explanations:
1. (4)
2. (1)
3. (4)
The Pythagorean triplet 8, 15, 17 satisfies
the given condition. If the ladder is moved
away by 2, it would rest at the foot of the
wall
When P is put as 1 (1 is a positive number),
we see that second terms onwards, all the
terms reduce to zero. Therefore, value
1
1
 .
=
11 2
3x + 6y must be a multiple of 3 but RHS is
not a multiple of 3. Therefore no solution
exists.
4. (2)
3
x
x
a
The best way to do this sum is to use
Pythagoras and work from the choices.
Taking choice (b) we get 12² + 9² = 144 +
81 = 225, hence hypotenuse is 15. To
check the answer, put x = 4.5 and see in
the upper triangle whether the relationship
holds.
5. (2)
6. (2)
Let the width be x/2. Then (20 - x) (10 - x)
= 96. Solving the equation, we get x = 4,
hence width = 2.
y
y
x
y
We have x² = y² + y² = 2y² and 2y + x = 2
(side of square). y = x/2 from (1) which is
2x/2. Then substitute in second equation
to get 2x + x = 2; hence x = 2/(2 + 1).
7. (3)
8 (4)
Sum of natural numbers = n(n + 1)/2 <
1000 We get n² + n < 2000; hence n = 44
since 44² + 44 = 1936 + 44 = 1980.. (n² +
n)/2 = 1980/2 = 990. Hence the number
added twice = 1000 - 990 = 10.
Let the cost be x and y respectively. Then
we get 2 equations: x + y = 17,000….(1)
and 1.13 x + 0.96y = 17,000……(2).
solving the 2 equations, we get x = 4000,
and y = 13000.
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484 = 2124. If the base of conversion is a;
we get 2a3 + a² + 2a + 4 = 484, hence a =
6. Converting 3111 from base 6, we get 3 
63 + 6² + 61 t60 = 648 + 36 + 1 = 691.
10. (4) a : b : c = 9 : 12 : 18; a : b : c : d = 9 : 12 :
18 : 28.5
11. (2) Time taken for the journey = 200/60 = 10/3
hrs. Litres consumed = (10/3)  4 = 40/3 =
13.33
12. (2) At 40 km/hr, she spends 200/4 = 5 hrs and
there by consumes 5  2.5 = 12.5 litres. At
80 km/hr 2.5  7.9 = 19 litres. Hence she
must reduce the speed.
13. (4) Let the cost price of the product = Rs. 100
Acc. to the Question,
MP = Rs. 187.5,
Manufacturer allows 40% discount,  SP
= 187.5  0.6 = Rs. 112.5(this SP is CP
for distributor)
Distributor allows 30% discount on MP to
retailer = 187.5  0.7 = Rs. 131.25
Therefore, % profit of Distributor = (131.5
100
- 112.5)
= 16.66% Ans.
D)
112.5
14. (2) Let the distance covered by the man each
time = x km
7
He takes 16 min. more when his speed =
11
of usual speed
11
 x  x = 16 min. x = 28 min. Ans. B)
7
15. (2) The number of boxes containing same
number of oranges will be least when there
are maximum boxes containing different
number of oranges.
16. (3) we derive the table as follows:
Chora
Hazri
Mora
Hazri
Male
11264/2 =
5632
14174 - 4020
= 10154
Female
14174 - 2910
= 11264
14174
17. (1) Any three-digit number can be written as:
abc = 100a + 10b + c.
Subtracting (2a + 3b + c) from 100a + 10b
+ c, gives: 98a + 7b = 7 (14a + b)
This number is divisible by 7.
(2a+3b+c) is divisible by 7 and also (98a +
7b) is divisible by 7.
Hence their sum should also be divisible by 7.
Page 2 of 11
MANYA CAT
Thus 100a + 10b + c is also divisible by 7.
Or, ‘abc’ is also divisible by 7.
Which is not a palindrome. So we have to
try the next higher starting number.
We cannot increase the units digit because it
will mean an increase in the hundreds digit
when you reverse the digits. The net result
being that at the end of the 1st repetition, the
number of digits increases to 4.
So lets start with 192
192
+2 9 1
483
+3 8 4
867
+7 6 8
1635
+5 3 6 1
6996
This is a palindrome and satisfies all the
conditions.
Hence the starting number is 192. And the
difference is 99.
18. (3) Let the given odd number be N and let N =
p
q
a b … where a, b are…. prime numbers.
Evidently none of a, b … is 2 (since it is an
odd number). Therefore 12N
2
1
2
p
q
= 2  3  N  2  3  a b ….
The number of divisors of 12N = (2 + 1)
(1 + 1) (p + 1) (q + 1)… But (p + 1) (q + 1)
... = 34.
Therefore required number of divisors = 34
 6 = 204. Ans. (3)
19. (2)
20. (1) use the formula: (1/2) b x h, which is
simpler.
21. (3) Only 4: 1 cannot divide 12 plates into
broken and unbroken plates.
22. (4) 210 - 1 = 1023
23. (1)
The reverse of the first number > the
number itself,
Hence in the starting number the first digit
< the last digit.
Therefore, the starting number must be 102
at the least.
If it is 203 the starting number for 1st
repetition will be 505 and for 2nd repetition
it will be 1010, which is not a 3 digit
number. Hence the starting three-digit
number must be of the type 1a2.
1a2
+2 a 1
3 2a 3
But ‘3’ ‘2a’ ‘3’ is not a palindrome so a > 4
Lets take a = 5.
152
+2 5 1
403
+3 0 4
707
But even at the end of 1st repetition we don’t
get a palindrome, hence the end result of the
1st step has to be minimum 453. But we
cannot have an odd number. So lets take
463 as the end result of the 1st step.
182
+2 8 1
463
+3 6 4
827
+7 2 8
15 5 5
+5 5 5 1
7106
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24. (3) The number can end in multiples of 4, that
is 12, 16, 24, 36, 32, 52, 56, 64 = 8 cases.
The first three positions can be filled by 4
 3  2 = 24 ways. Hence total number of
ways = 24  8 = 192 ways.
25. (4) Ratio of mixture A: B = 5: 7
Let total solution = 12x
Amount of A in solution = 5x
Amount of B in solution = 7x
After the removal of 6lt,
Amount of A in the Sol.
5


=  5x   6  lt. & after addition of 6 lt.
12


of B,
7
Amount of B in the sol. = 7x   6  9
12
According to question
5
5x   6
7
12
=
 x = 7.5

7
11
7x   6  6
12
Initially value of A = 5x = 37.5 lt.
26. (1)
27. (1)
Present cost of maruti and Ambassador is
respectively: 15 x/4 and 6x (using the ratios
given). Then 15x/4 + 6x = 3.9; x = 0. Cost of
Ambassador one year beck 4  0.4 = 1.6
28. (4) Work from the choices. A + D = t/4 + 1/32
= 9/32 B + C = 1/8 + 1/16 = 3/16 and a/32
 2/3 = 3/16.
Page 3 of 11
MANYA CAT
29. (4) Let the cost price of the product = Rs. 100
Acc. to the Question, MP = Rs. 187.5,
Manufacturer allows 40% discount,  SP
= 187.5  0.6 = Rs. 112.5(this SP is CP for
distributor)
Distributor allows 30% discount on MP to
retailer = 187.5  0.7 = Rs. 131.25
Therefore, % profit of Distributor = (131.5
100
- 112.5)
= 16.66%
112.5
equation & putting their value in 2nd
equation.
2x + 3y = 15 ---- (1)
3x + y = 9 ------- (2)
 multiplying (1) by 2 and (2) by 2 we
have
6x + 9y = 45
6x + 2y = 18
 7y = 27
 y = 27
7
Putting value of y in (1) we have
15  3  27
7
x=
2
105  81 24 12



7
14
14
1
1



 ......  

4  1 2 2  3 3  4

 1 1   1 1 

      

1  1 2   2 3 


4 1 1
1 
1
      ......  
 
 n n 1
 3 4
30. (1) N =
1 1
Putting the value of x & y in
Kx – y = 4
 K 12  27  4
7
7
28  27 7
55


K=
12 12
7
When number of terms is assumed to be n
1 1
1  1 n 
N  
 

4 1 n 1 4  n 1

1
1


.
4  1  (1/n) 
When n approaches
approaches 0.
Therefore, we get ¼
infinity,
1/n
31. (3) We know a - b= 0 and hence we cannot
divide both the sides by 0. Hence the
transition to step 5 is
wrong.
32. (1) Red light = 60/3 = 20 sec and green light =
120/5 = 24 sec. They will flash together in
120 sec (LCM of 20 and 24); i.e. 2 min. No.
of times they flash in an hour = 60/2 = 30.
33. (1) All else cancle out by rationalisation
except for √100-1
34. (2) The coin should be put as follows: 1, 2, 4,
8, 16, 32, 64, 1, 2, 4, 8, 16, and hence he
can meet all denominations. Hence 12 bags
35. (3) The ratio between ages of Ramesh &
Rahul is 5: 7
Let their ages be 5x & 7x according to Q
(5x + 9) = 2 (7x – 9)
 5x + 9 = 14x - 18
 - 9x = - 27
 x=3
 their ages are 15 and 21 respectively.
37. (1) Make the following equation
 1 1  14
x 
 = 1
 21 28  28
x (No. of days for which they work together
i.e. after A leaves) = 6 days
38. (2) The length of perpendicular from a point
(x1 y1)
On ax + by + c = 0 is given as
ax1  by1  c
= P where P is length of
2
2
a b
perpendicular.
So length of perpendicular from P (1, 2) on
x + 2y + 3 = 0 is
11  2  2  3 1  4  3
8


2
2
5
5
1 2
39. (2) Let the sides of square ABCD be ‘a’. Since
EFGH are midpoints of AD; AB, BC, and
DC ________ we have
36. (2) The value of K can be found by first
finding value of X & Y using 1st & 3rd
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Page 4 of 11
A
F
I
B
J
E
G
L
D
K
C
H
MANYA CAT
 m = 2520 and the number is (2520)n –
1. This number is least when n = 1. Hence
the required number is 2519.
AF = AE = a/2
Also  A = 90o (angles of the square are
slight angled).
We can apply the Pythagorean theorem
 2   a 2  = FE2
2
 a
43. (2) Use the probability when one is lying other
is speaking truth
2
2
2
a
a
2
 FE 
 FE
4
2
Now FE =
a
also FG = GH = EH =
a
.
2
2
Since I is mid point of EF and j is mid
point of FG
a
a
 FI 
FJ 
2 2
2 2
2
 a   a 
 JJ  
 

2 2 2 2
2
2
2
 JJ  2
a
44. (3) u = 45 km/hr & v = 25 km/hr.
In the same direction, R.V. = u - v = 45 –
25 = 20 km/hr.
Time taken by the faster train to cross a
man in the slower train, t = 36 sec.
l
l


= 36
5
5
(u  v) 
20 
18
18
 l = 200m
45. (3)
A
2

8
 JJ 
a
2
Area of ABCD = a2
2
a
a a
Area of JJKL =    2 
4
2 a
 Ratio of area is a2:
2
a
2
B
The required length is
3 (50) + 3 (50 – 10) + 3 (50 – 20) + 3 (50 –
30) + 3 (50 – 40)
= 150 + 120 + 90 + 60 + 30
= 450 cm.
2
 4: 1
4
40. (2) Since Ram & Shiv brings apple in the ratio
3: 5 and the consumption is equal
 the money i.e. Rs.8 has also to be
divided in the ratio 3 : 5
 Ram will get Rs.3
Shiv will get Rs.5
41. (3) 20 +10 + 10 + 5+5 +
5

5

5
5
.  . .......
4
4
2 2
5 5 5
= 20 + 2 (10 + 5 +    ......... )
2 4 8
1
= 20 + 2  5(2 + 1 +  …….)
2
46. (1) Since there were 40 cannibals, on the 20th
day after the first man is eaten, there will
1
not be any person liked by more than
2
the others and so there will be no dinner on
the 20th day!
47. (1) Given equation can be written as –3 < (11
– x) / 2 < 3 => -6 < 11 –x < 6 i.e. –17 < -x
< -5 i.e. 5 < x <17.
48. (2)


 2 
 20  10 
 20  10  4
1
1  
 2
The problem can best be solved by looking at
choices.
49. (1) ac = b2
y – x = z – y or x – y = y – z
 (x – y) (loga + logc) + (2y – x – x) logb
= (x – y) log b2 – 2 (x – y) log b = 0
 20  40  60 feet.
42. (1) The number must be of the form (mn – 1)
where m is the LCM of 2, 3, 4, 5, 6, 7, 8
and 9; and n is an integer.
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C
50. (3) PT2 = PC  PB; let PB= x
i.e., 64 = 4 x
 x = 16
i.e. PB = BC + PC
 16 = BC + 4
Page 5 of 11
MANYA CAT
 BC = 2 OC =12
Hence radius is 6 cm.
the last digit of the house number thus 121
gives 1211 which is not a square.
1444 is a square of 38. So that means that
144 is the house number and 441 is
telephone number and the difference is 297.
51. (3) Given that the ball selected is red, since
there are 6 red balls, the probability that
the ball selected is a particular ball is 1/6.
52. (1) AC = AB/2 = 3m. if the radii of the circles
are r1 and r2, r12 + 32 = 422.  r2 = 5m.
53. (1)
54. (1)
55.
2b + 3b + 4a = 15. 30 + 2b + a = 10.
Adding, 50 + 5b + 5a = 25.
 30 + 3b + 3a = 15.
A
D
C
Starting from A, the possible roots are,
ABDA, ABDCA, ABCA, ABCDA,
ACDA, ACBDA, ADBA, ACDBA,
ACBA, ADCBA, ADCA, ADBCA.
(Last 6 roots are the first 6 reversed)
57.
f0g(x) = f0g(x) = g0f(x) = x. So these
functions acting repeatedly still give the
value x. Both the brackets evaluate to x, so
their product is x².
58.
The function to f(x), which is equal to 2x +3.
59.
Last two digits are as follows
1 – 02
2 – 04
3 – 08
4 – 16
5 – 32
6 – 64
7 – 28
8 – 56
9 – 12
10 – 24
11 – 48
12 – 96
13 – 92
14 – 84
15 – 68
16 – 36
17 – 72
18 – 44
19 – 88
20 – 76
21 – 52
22 – 04
23 – 08
65. (3) Substitute ‘fancy’ with each of these words
in the sentence. The only word that best
retains the meaning is imagine. To fancy is
to visualize or to like something.
66. (1) Such a rebuke is not quite a disciplinary
measure, hence admonish is the most
appropriate word here.
67. (2) The other three are forms of government,
but voting is one of the methods by which
a government is chosen in a democracy.
Hence this is the odd one out.
69. (2) The other three are titles that an athlete
might earn in the course of his career, and
so ‘athlete’ is the odd one out.
121, 144, 441 are the possible choices
Manas's car registration number is a four
digit number which is also a square
number as well, and is formed by repeating
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64. (3) Within the confines of the information the
passage gives us, there is no indication that
Alice found her life dull and stupid. She
just liked novelty. Hence the most probable
answer is (3).
68. (4) The other three are qualities, but ‘warrior’
is a person.
From 22nd power of 2 the last 2 digits start
repeating.
Hence 32 is the last 2 digit in case of 25 or
even 22005
60.
62. (2) Alice’s readiness to try anything new,
without hesitation, has been presented in a
positive light. Therefore, it is that spirit
that would best qualify as the sum of the
passage.
63. (1) ‘Curious’ here means strange, or odd. The
answer cannot be ‘new’ because its novelty
is not what she finds remarkable.
56.
B
61. (1) Alice did not hesitate at the prospect of
something new, and readily ate the cake.
Her excitement at the prospect of exploring
a garden in a strange world is also
indicative of her adventurousness.
70. (3) The other three words refer to a an inflow
of cash, while ‘expenditure’ is an outflow
of money.
71. (1) ‘Cruel’, ‘kind’ and ‘loyal’ are qualities, or
adjectives, and ‘authority’ is a noun.
72. (1) “She thought” and “in her opinion” are
repetitive. “Rose up” is incorrect in this
context, and so is “passed on”. Hence (1) is
the correct answer.
Page 6 of 11
MANYA CAT
73. (2) “Since” is usually followed by whatever
has followed, in present perfect tense.
Hence (2) is the correct answer.
74. (4) A doctor cures disease, and a teacher can
be said to cure ignorance.
75. (4) A dart is the smaller version of the weapon
called the spear, and the gun is a miniature
of the cannon.
76. (4) Just as acrylic is made from wool, terylene
is made from cotton.
77. (1) Just as food can assuage hunger, sleep can
assuage weariness.
78. (2) Just as a building is made of bricks, a
highway is made of asphalt.
79. (2) Just as the basic part of a tree is its trunk,
the basic component of a car is its chassis.
80. (1) Just as an arc is part of a circle, a segment
is part of a line.
81. (3) To ponder is to think – about something.
Something that is imponderable, then,
would be something that cannot be thought
about – or that cannot be evaluated.
82. (3) To retaliate is to respond to an attack –
physical, verbal or strategic. Thus to repay
in kind is closer to this.
83. (4) To concede is to agree, and agreement is
only possible in the presence of other
people, hence the prefix ‘con-’. Thus, to
cede would be to yield.
84. (1) ‘Vicious’ is nasty, cruel or mean.
Therefore, to vitiate is to be cruel – to
cause harm, or to impair.
85. (2) If you have heard the term ‘business
acumen’, then it cannot be business
accuracy – it has to be shrewdness,
because shrewdness implies a certain
competence and understanding.
88. (3) If all you know about juncture is that it is a
traffic crossing, you can deduce that it can
be interpreted as that point at which you
have to make a decision about which way
to turn. Therefore, a critical moment.
89. (4) Calumny mean slander or malicious gossip
– hence (4) is the correct answer.
90. (3) Verbiage contains the word ‘verb’, which
in Latin means word, and sounds like that
too. So verbiage would have to be
something to do with words, hence (3).
91. (4) Since the passage talks about how ants
do/do not communicate, thus this is the
right answer.
92. (3) Since the ants reject others of the same
species who do not belong to their nest,
and hostile means unfriendly, therefore the
correct answer is hostile.
93. (4) The author’s anecdote proves that ants
communicate with each other even when
they might be in no condition to give
passwords, hence that is the only statement
that is disproved.
94. (4) Since fatality here means a fatal outcome,
and the ants died after inhaling chloroform,
thus (4) is the correct answer.
95. (2) The element of humor in the passage is
whimsical, which means unusual or
fanciful, thus the correct answer is
whimsy.
96. (2) To exhaust is to deplete and finish.
Therefore its opposite will be that which
provides, adds, therefore the right answer
is to fortify, to reinforce.
97. (1) Calculation
is
mathematical
and
systematic, guesses are not. Hence the
right answer is (1).
98. (4) Grim means gloomy and serious, therefore
cheerful is the closest in meaning to its
opposite.
86. (2) Temerity means audacity – what people
otherwise call ‘guts’. Hence recklessness is
the closest in meaning.
99. (4)
87. (2) Fabric is something that is made – cloth
has to be woven, sewn and/or dyed, etc.
So, to fabricate something is to make
something – to make it up, hence, to
concoct.
100. (2) To enunciate is to say clearly, so to
stammer will be its closest opposite.
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Decomposition
means
disintegration,
reconstitution is the opposite because it means
to build up again. Hence (4)
101. (3) To be candid is to be very open and honest,
therefore the closest opposite is withdrawn.
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MANYA CAT
102. (4) To prescribe is to recommend, therefore
the right answer is to disallow.
103. (1) To be conspicuous is to be very visible, to
be undistinguished is to be not very
striking or remarkable, therefore the right
answer is (1).
104. (3) To fester is to irritate, to worsen, as in “a
festering wound”. Therefore, the closest
opposite is to mend.
105. (1) To conciliate is to pacify and bring
together, so the closest opposite is to
provoke, which means to incite, usually to
a fight.
106. (3) Myopic means shortsighted, literally – it is
the term optometrists use for actual
shortsightedness. Therefore, farsighted is
the correct opposite.
107. (2) When a field lies fallow, that means it is
not in use. Therefore, its opposite will be
to be creative, productive.
108. (4) Ambivalence is an inability to decide
which side to take, therefore its opposite
will be o be decisive.
109. (2) To mitigate is to lessen, therefore the
closest opposite is to amplify.
110. (4) Proclivity is a liking, an inclination, so its
closest opposite here is dislike.
111. (3) What is routine is what is usual, something
that happens everyday, so the closest
opposite here is rare – something that is
unusual.
112. (3) When amounts are mentioned, the most
appropriate sense of substantial here would
be considerable.
113. (2) It is not character in the sense of a role, in
a play or a film, which is meant here. Here,
character means the nature of this
development.
114. (1) Objectives here mean aims, targets or
goals.
115. (1) Personnel here means neither personal –
private – nor only employers or managers.
Hence the correct answer is workers.
116. (1) Supplement here means to add or increase,
not nutritional supplements, angles or
supplication – request.
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117. (1) Authoritarian here is a political and social
system that demands absolute obedience,
hence dictatorial.
118. (2) To accumulate is to build up, not
accommodate – to adjust. Neither does it
mean to hoard or to credit.
119.
The subsistence level is that stage where
one can produce just about enough to feed
oneself and one’s dependants, with no
surplus produce. Hence the correct answer
here is survival.
120. (1) Since college students are intelligent and
Ram goes to college, therefore Ram is
intelligent.
121. (3) There is no connection between women
being islands and Meera being Laxman’s
wife. There is one between Laxman being
a man, the fact that no men are islands and
Laxman not being an island.
122. (3) A and B describe the qualities of roses. F
speaks of plants in general. Hence CDE are
in logical order – since all roses are plants,
and all plants need air, therefore roses (all
being plants) need air.
123. (1) B, C and E do not follow logically from
one another in nay order. ADF do, in that
order. Hence (1) is the right answer.
124. (3) A Venn diagram would explain this – since
some nurses are qualified, and all nurses
are attendants, hence some attendants
(being nurses) are qualified.
125. (3) Since different hues can be obtained from
primary colors and red is a primary color,
therefore red can produce different hues.
126. (1) Again, though the other three statements
are related, they do not have at least one
premise in common in any logical order.
Hence (1) is the correct answer.
127. (3) The other three words are adjectives that
refer to mental processes. Material means
physical or tangible.
128. (4) Apt, relevant and appropriate all mean
suitable or proper. Adept means competent
or proficient.
129. (4) Invoice is a bill, and octroi means a duty
paid on goods brought into an area.
Quotation is the only one issued before
payment is made. Quotation means the
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MANYA CAT
statement of the current market price of a
product or of services. It requires no
payment.
130. (2) Ring, finger and write are all related to the
hand/hands. Shoulder is the odd one out.
131. (4) The first three words refer to horses. Bark
is what dogs do.
132. (2) Quell, allay and pacify all mean to mitigate
or to soothe. Ruffle means the opposite –
to disturb.
133. (3) Eulogy, panegyric and glorification are all
means of praise. Ignominy means shame.
Therefore, 1.08x = 1.08,000; Hence x =
Rs. 1,00,000
142. (1) % Profit between Jan 1 and Apr 30 =
(1.08x - x/x) X 100
143. (1) Investment in the month of April = Rs.
1,20,000
Amount received at end of April = Rs.
1,08,000
Therefore, Loss = Rs. 12,000
144. (2) Maximum amount invested by Ghosh
Babu is in the month of February = Rs.
1,25,000
145-158
134. (3) A symphony is composed, and similarly, a
novel is authored.
135. (2) A cow belongs to a herd. In the same way,
a child belongs to a family.
145. (3) Profit per rupee of sales = Total sales Total expenditure/Total sales
136. (4) The study of birds is ornithology.
Similarly, the study of plants is botany.
146. (3) Profit per rupee of total expenditure =
Total sales - Total expenditure? Total sales
Company ‘C’ has the lowest profit per
rupee of sales = (12.3 - 11.3)/12.3 = 0.081
137. (4) Blandishment means something meant to
coax or cajole. Hence flattery is the closest
meaning out of the four.
147. (2) Sales per rupee of share capital = Total
sales Share capital Company ‘B’ has
highest sales per rupee of share capital = 8
138. (4) Noble means honorable. With the prefix
‘ig-’, it becomes the opposite –
dishonorable.
148. (3) Profit per rupee of share capital = Total
sales - Total expenditure/Share Capital
Company ‘C’ has the lowest profit per
rupee of share capital = (12.3 - 11.3)/8 =
0.125
139. (3) To eulogize is to praise, and to belittle is to
disparage. Therefore (3) is the right
answer.
140. (2) Tenacious means dogged and firm. The
closest opposite is frail, which means
weak.
141. (4) Let the amount received by Ghosh Babu in
Dec. 1991 be Rs. x, as retirement benefits:
Therefore, investment in the month of Jan
1992 = s. x
Profit of 25% at the end of Jan 1992.
Hence, investment in the month of Feb
1992 = Rs. 1.25x
Loss of 20% at the end of Feb 1992
Hence, investment in the month of March
1992 = Rs. (0.8  1.25x) = Rs. x
Profit of 20% at the end of March 1992
Hence, investment in the month of April
1992 = Rs. 1.2x
Loss of 10% at the end of April 1992
Therefore the amount left at the end of
April 1992 = Rs. (0.8  1.2x) = Rs. 1.08x
Amount at the end of April 1002 = Rs.
1,08,000
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149-152:
149. (3) Total No. of line employees with 3-5 years
of employment = 140
No of line employee with 3-5 years of
employment who attended Financial
Management programme = 80
No. of line employee with 3 – 5 years of
employment who have not attended
Financial management programme = 140 80 = 60
150. (2) No. of employee with less than 3 years of
employment who attended Decision
Making programme = 70
No. of employee with less than 3 years of
employment who attended Financial
Management programme = 50.
No. of employee who attended both the
programme = 25.
No. of employee who attended only one of
the programme = (70 - 25) + (50 - 25) = 70
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MANYA CAT
151. (1) Total No. of employee with more than 5
years of employment = 360
no of employee with more than 5 years of
employment who attended Decision
making programme = 90
No. of employee with more than 5 years of
employment who attended Financial
Management programme = 90 No. of
employee who attended both the
programme = 50
Therefore, No. of employee who does not
attended either programme = 36 - (90 + 90
- 5) = 230
% of the employee with more than 5 years
of employment who does not attended
either programme
= 230  100/360 = 63.88%
152. (2) Total No. of employee with more than 5
years of employment = 360
No. of employee with more than 5 years
employment who attended Decision
making programme = 90
No. of employee with more than 5 years
employment who attended Financial
Management programme = 90
No. of employee who attended at least one
programme = (90 + 90 - 50) = 130.
153-166
153.(2) For Machine 1,
% of production rejected = 20
% of production accepted = 80
Let the total production be = x
Production accepted = 0.8x
Number of accepted = 400;
therefore 0.8x = 400
Hence x = 500
154. (1) For Machine 5,
Let the total production be x
% of production rejected = 12
% of production accepted = 88
Number of Fuse accepted = 430;
therefore 0.88x = 430
Hence x = 430/0.88
Number of fuses rejected =
0.12 X (430/0.88) = 59
155. (1) Let the total production be X
Let % of production accepted = Y
Number accepted = N; Then (Y  X)/100 =
N
From the above formulae you can calculate
the total production for any Machine The
total production is highest of the Machine
1 = 500.
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156. (3) Using the same formulae as in above
question, the total production is lowest for
Machine = 452.
157-161:
The time given in the table is for per uniform to be
stitched.
157. (3) No. of working hours for each person = 10
hour
Total time available for cutters in a day =
20 hour = 1200 min Max. No. of uniform
that 2 cutters can cut for Little Flower in
a day = 1200/30 = 40 Time required for
stitching 40 uniform = 40  60 = 2400 min
and Amit has 5 tailors for stitching that
means the Total available time is (5  10 
60) = 300 min Hence maximum number of
Little Flower uniforms can be completed in
a day = 40
158. (1) To complete 20 Little Flower uniforms, the
time consumed by different persons are
Tim consumed by Cutters = 20  20 = 600
min
Time consumed by Tailors = 20  60 =
1200 min
Time consumed by Assistants = 20  30 =
600 min
Time available for Cutters = (1200 - 500) =
600 min
Time available for Tailors = (3000 - 1200)
= 1800 min
Time available for Assistant = (1200 - 600)
= 600 min
Max. No of uniform that 2 cutters can for
May Flower in a day = 600/20 = 30
Time required to stitch 30 uniform = (30 
60) = 1800 min and is exactly equal to the
time available for tailors.
Hence No. of Mayflower uniform that can
be completed on that day is 30.
159. (2) To complete 30 Little Flower uniforms ,
the time consumed by different persons are
Time consumed by Cutters = ( 30  30) =
900 min
Time consumed by tailors = (30  60) =
1800 min
Time consumed by assistant = (30  30) =
900 min
Time available for cutters = (1200 - 900) =
300 min
Time available for tailors = (3000 - 1800)
= 120 min
Time available for Assistant = (1200 - 900)
= 300 min
As they are not working in this available
time it is the idle time. Hence total man
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MANYA CAT
hour that is idle = (300 + 1200 + 300) =
1800 min = 30 hours
160. (2) Hiring one more assistant increases the
time available for stitching buttons and
button holes. Max. No. of uniform those
cutter can cut for Mayflower in a day =
1200/20 = 60 Time required by Tailors to
stitch 60 uniforms = (60  60) 3600 min;
Whereas time available is 3000 min only.
161. (1) Max. Number of uniforms that can be cut
by those 2 cutters in a day for May Flower
is 60. And the buttons
and buttonholes
can be easily stitched by the 2 assistant for
these 60 uniform in a day in the time
available for them. While 5 tailors can
stitch only 50 uniforms in the available
time.
Hence, A lord will hire 1 tailor to get
maximum increase in production capacity
in a day.
162-165:
162. (4) When converting from percentage to
absolute value, we find that the statement
a, b and c are false and hence
the
correct answer is option.
163.(2) No. Of Households in 1970 = 120 millions
No. Of Households in 1990 = 160 millions
% increase in Household = (40/120)  100
= 33.333%
This increase of 33.33% is over the period
of 20 years (1970-1990)
Hence simple annual growth rate
(33.33/20) = 1.66%
164. (4) The average number of children per
household in 1990 cannot be determined,
as the total number of children
can’t
be determined in the category of three or
more children.
165. (2) No. of Household in 1970 = 120 millions
Household without any children in 1970 =
35% (from the pie chart)
Therefore, household without any children
= (35/100)  120 = 42 million
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MANYA CAT