CHAPTER 3
Fourier
Representation of
Signals and LTI
Systems.
EKT 232
1
3.1 Introduction.
Signals are represented as superposition's of complex sinusoids
which leads to a useful expression for the system output and
provide a characterization of signals and systems.
Example in music, the orchestra is a superposition of sounds
generated by different equipment having different frequency
range such as string, base, violin and ect. The same example
applied the choir team.
Study of signals and systems using sinusoidal representation
is termed as Fourier Analysis introduced by Joseph Fourier
(1768-1830).
There are four distinct Fourier representations, each applicable to
different class of signals.
2
Fourier Series
Discrete Time Fourier series (DTFS)
x F n
k NF
X k e j 2 kn / N F
1
X k
NF
n0 N F 1
n n0
x n e j 2 kn / N F
where N F is the representation time and the notation
k NF
means
a summation over any range of consecutive k’s exactly N F in length.
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Fourier Series
Notice that in
x F n
k NF
X k e j 2 kn / N F
the summation is over exactly one period, a finite summation.
This is because of the periodicity of the complex sinusoid,
e j 2 kn / N F
in harmonic number k . That is, if k is increased by any integer
multiple of N F the complex sinusoid does not change.
e j 2 kn / N F e
j 2 k mN F n / N F
, (m an integer)
This occurs because discrete time n is always an integer.
Fourier Series
In the very common case in which the representation time is
taken as the fundamental period N 0 the DTFS is
x n
k N0
X k e
j 2 kn / N 0
1
X k
N0
FS
n N0
x n e j 2 kn / N0
5
CT Fourier Series Definition
The Fourier series representation x F t of a signal x(t )
over a time t0 t t0 TF is
x F t
j 2 kf F t
X
k
e
k
where X[k] is the harmonic function, k is the harmonic
number and f F 1/ TF . The harmonic function
can be found from the signal as
1
X k
TF
t0 TF
x t e j 2 kf F t dt
t0
The signal and its harmonic function form a Fourier series
FS
pair indicated by the notation x t
X k .
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CTFS Properties
Let a signal x(t ) have a fundamental period T0 x and let a
signal y(t ) have a fundamental period T0 y . Let the CTFS
harmonic functions, each using a common period TF as the
representation time, be X[k ] and Y[k ]. Then the following
properties apply.
Linearity
FS
x t y t
X k Y k
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CTFS Properties
FS
x t t0
e j 2 kf0t0 X k
Time Shifting
FS
x t t0
e jk0t0 X k
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CTFS Properties
FS
Frequency Shifting e j 2 k0 f0t x t
X k k0
(Harmonic Number jk t
FS
0 0
e
x
t
X k k0
Shifting)
A shift in frequency (harmonic number) corresponds to
multiplication of the time function
by a complex exponential.
FS
x
t
X k
Time Reversal
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CTFS Properties
Change of Representation Time
FS
With TF T0 x , x t
X k
FS
With TF mT0 x , x t
Xm k
X k / m , k / m an integer
Xm k
, otherwise
0
(m is any positive integer)
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CTFS Properties
Change of Representation Time
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CTFS Properties
Time Differentiation
FS
d
FS
x
t
j 2 kf 0 X k
dt
d
FS
x
t
jk0 X k
dt
FS
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CTFS Properties
Time Integration
Case 1
Case 1. X 0 0
t
Case 2
X k
x d
j 2 kf
FS
0
t
X k
x d
j k
FS
0
Case 2. X 0 0
t
x d is not periodic
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13
CTFS Properties
Multiplication-Convolution Duality
FS
x t y t
X k Y k
(The harmonic functions, X[ k ] and Y[ k ], must be based
on the same representation period TF .)
FS
x t # y t
T0 X k Y k
The symbol # indicates periodic convolution.
Periodic convolution is defined mathematically by
x t # y t x y t d
T0
x t y t x ap t y t where x ap t is any single period of x t
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Fourier Series(DTFS)
x F n
k NF
X k e j 2 kn / N F
1
X k
NF
n0 N F 1
n n0
x n e j 2 kn / N F
where N F is the representation time and the notation
k NF
means
a summation over any range of consecutive k’s exactly N F in length.
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Fourier Series(DTFS)
Notice that in
x F n
k NF
X k e j 2 kn / N F
the summation is over exactly one period, a finite summ
This is because of the periodicity of the complex sinusoid
e j 2 kn / N F
in harmonic number k . That is, if k is increased by any integer
multiple of N F the complex sinusoid does not change.
e j 2 kn / N F e
j 2 k mN F n / N F
, (m an integer)
This occurs because discrete time n is always an integ
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Fourier Series(DTFS)
In the very common case in which the representation time is
taken as the fundamental period N 0 the DTFS is
x n
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k N0
X k e
j 2 kn / N 0
1
X k
N0
FS
n N0
x n e j 2 kn / N0
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DTFS Properties
Let a signal x[n] have a fundamental period N 0 x and let a
signal y[n] have a fundamental period N 0 y . Let the DTFS
harmonic functions, each using a common period N F as
the representation time, be X[ k ] and Y[k ]. Then the following
properties apply.
Linearity
FS
x t y t
X k Y k
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DTFS Properties
Time Shifting
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FS
x n n0
e j 2 kn0 / NF X k
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DTFS Properties
Frequency Shifting
j 2 k0n / N F
FS
e
x
n
X k k0
(Harmonic Number
Shifting)
Conjugation
FS
x* n
X* k
Time Reversal
FS
x n
X k
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DTFS Properties
Time Scaling
Let z n x an , a 0
If a is not an integer, some values of z[n] are undefined
and no DTFS can be found. If a is an integer (other than
1) then z[n] is a decimated version of x[n] with some
values missing and there cannot be a unique relationship
between their harmonic functions. However, if
x n / m , n / m an integer
z n
, otherwise
0
then
Z k 1/ m X k , N F mN 0
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DTFS Properties
Change of Representation Time
FS
With N F N 0 x , x n
X k
FS
With N F qN 0 x , x n
Xq k
X k / q , k / q an integer
Xq k
, otherwise
0
(q is any positive integer)
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DTFS Properties
FS
x
n
y
n
Y k # X k Y q X k q
Multiplicationq N0
Convolution
FS
x
n
#
y
n
N0 Y k X k
Duality
FS
First Backward x n x n 1
1 e j 2 k / N F X k
Difference
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The Fourier Transform
Extending the CTFS
• The CTFS is a good analysis tool for systems
with periodic excitation but the CTFS cannot
represent an aperiodic signal for all time
• The continuous-time Fourier transform
(CTFT) can represent an aperiodic signal for
all time
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Definition of the CTFT
Forward
X f F x t
Inverse
f form
x t e j 2 ft dt x t F
X j F x t
X f X f e
-1
j 2 ft
x t e
Inverse
form
jt
dt x t F
1
X
j
2
-1
jt
X
j
e
d
Commonly-used notation:
F
x t
X f
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df
Forward
F
or x t X j
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Some Remarkable Implications
of the Fourier Transform
The CTFT expresses a finite-amplitude, real-valued,
aperiodic signal which can also, in general, be time-limite
as a summation (an integral) of an infinite continuum of
weighted, infinitesimal-amplitude, complex sinusoids, eac
of which is unlimited in time. (Time limited means “havin
non-zero values only for a finite time.”)
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The Discrete-Time Fourier
Transform
Extending the DTFS
• Analogous to the CTFS, the DTFS is a good
analysis tool for systems with periodic
excitation but cannot represent an aperiodic
signal for all time
• The discrete-time Fourier transform
(DTFT) can represent an aperiodic signal for
all time
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Definition of the DTFT
F Form
Inverse
x n X F e
1
Inverse
1
x n
2
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2
j 2 Fn
dF X F
F
Forward
j 2 Fn
x
n
e
n
Form
Forward
F
X e j e jn d
X e j
jn
x
n
e
n
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The Four Fourier Methods
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Relations Among Fourier
Methods
Multiplication-Convolution Duality
Continuous Time
Discrete Time
Continuous Time
Discrete Time
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Discrete Frequency
Continuous Frequency
FS
x t y t
X k Y k
F
x t y t
X f Y f
FS
F
x n y n
Y k # X k x n y n
XF # YF
Discrete Frequency
Continuous Frequency
FS
x t # y t
T0 X k Y k
F
x t y t
X f Y f
FS
F
x n # y n
N 0 Y k X k x n y n
XF YF
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Relations Among Fourier
Methods
Time and Frequency Shifting
Discrete Frequency
Continuous Time
FS
x t t0
X k e
Discrete Time
FS
x n n0
X k e
j k0 t0
j k 0 n0
Discrete Frequency
j k00 t
FS
X k k0
j k0 0 n
FS
X k k0
Continuous Time
x t e
Discrete Time
x n e
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Continuous Frequency
F
x t t0
X j e jt0
F
x n n0
X e j e jn0
Continuous Frequency
F
x t e j0t
X j 0
F
x n e j0n
X e
j 0
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,
Tutorials
1. Compute the CTFS:
x
(
t)
4
c
o
s
(
5
0
0
t)TF 1/50
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2. Find the frequency-domain representation of the signal in Figure
3.1 below.
Figure 3.1: Time Domain Signal.
Solution:
Step 1: Determine N and 0.
The signal has period N=5, so 0=2/5.
Also the signal has odd symmetry, so we sum over n = -2 to n = 2
from equation
35
Cont’d…
Step 2: Solve for the frequency-domain, X[k].
From step 1, we found the fundamental frequency, N =5, and we sum
over n = -2 to n = 2 .
1
X k
N
N 1
xne
jk o n
n 0
1 2
X k xne jk 2n / 5
5 n 2
1
x 2e jk 4 / 5 x 1e jk 2 / 5 x0e j 0 x1e jk 2 / 5 x2e jk 4 / 5
5
36
Cont’d…
From the value of x{n} we get,
1 1 jk 2 / 5 1 jk 2 / 5
X k 1 e
e
5 2
2
1
1 j sin k 2 / 5
5
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