151 Bulletin of Society for mathematical services & standards (B SO MA S S) Vol. I No. 2 (2012), pp. 151-171 ISSN: 2277- 8020 © www.ijmsea.com www.jsomass.com ON SIMILARITY AND QUASISIMILARITY EQUIVALENCE RELATIONS Isaiah Nalianya Sitati School of Mathematics, University of Nairobi, Chiromo Campus, P. O. Box 30197-00100, Nairobi. [email protected] Musundi Sammy Wabomba Chuka University College P.O. Box 109-60400, Kenya. [email protected], [email protected] Benard Mutuku Nzimbi School of Mathematics, University of Nairobi, Chiromo Campus, P. O. Box 30197-00100, Nairobi. [email protected] , [email protected], Kirimi Jacob Chuka University College P.O. Box 109-60400, Kenya. [email protected] Abstract Similarity and unitary equivalence can be shown to be of equivalence relations. We discuss a result showing that two similar operators have equal spectra (i.e. point and approximate point spectrum). More so, unitary equivalence results for invariant subspaces and normal operators are proved. For similar normal operators, we state the Fuglede – Putnam –Rosenblum theorem that makes proofs for similar normal operators more simplified. It is also noted that direct sums and summands are preserved under unitary equivalence. Furthermore, we show that the natural concept of equivalence between Hilbert Space operators is unitary equivalence which is stronger than similarity. By introducing the notion of quasisimilarity of operators which is the same as similarity in finite dimensional spaces, but in infinite dimensional spaces, it is a much weaker relation, we further show that quasisimilarity is an equivalence relation. We also link invariant subspaces and hyperinvariant subspaces with quasisimilarity where it is seen that similarity preserves nontrivial invariant subspaces while quasisimilarity preserves nontrivial hyperinvariant subspaces. Mathematics Subject Classification: 47A10; 47A15; 47B15 KEY WORDS: Similarity, equivalence relation, quasisimilarity. 1.1 In this paper, Hilbert spaces or subspaces will be denoted by capital letters and etc , , , etc denote bounded linear operators where an operator means a bounded linear transformation (equivalently, a continuous linear transformation) : bounded linear transformations from to For an operator , and kernel of Similarly, , we denote by . denotes the set of , which is equipped with the (induced uniform) norm. , , Ran , Ker , the spectrum, adjoint, norm, range respectively. and will denote the zero operator and identity operator on An operator an involution if respectively. is said to be: = self adjoint or Hermitian if ℝ ∀ equivalently, if unitary if normal if ∀ (equivalently, if ), an isometry if a partial isometry if or equivalently, if is a projection. From the above definitions we have the following proper class inclusion relations: Unitary ⊆ Isometry ⊆ Partial isometry and Unitary ⊆Normal . An operator is said to be a scalar if it is a scalar multiple of the identity operator , 152 left shift operator if i.e., …..) ∀ …..) = ( given by …..) and where is , this operator is also called a backward weighted shift operator with weights 1, right shift operator if …..) and where , also called the unilateral shift or forward weighted shift operator with weights 1. If and are Hilbert spaces, then their (orthogonal) direct sum will be denoted by ⊕ , which itself is a Hilbert space. A contraction is an operator such that operator with (i.e. , Ker ( ) is the set } is the set subspace of . A strict contraction is an . The Kernel (or null space) of Ker ( ) = ( ) ={ The range of ∀ (i.e. ={ }. i.e, it is a linear manifold that is closed in H for every T manifold that is not necessarily closed in . An operator and is a is a linear is finite-dimensional if is finite- dimensional. A set in is invariant for ⊆ if . is an invariant subspace for which, as a subset of , is invariant for . A subspace of if it is a subspace of is invariant for if and only if is invariant for . A subspace reduces (equivalently, if (or is a reducing subspace for ) if both M and is invariant for both is a hyperinvariant subspace for If is an invariant subspace for =* where Let { { + for operators and are invariant under ). if it is invariant for every operator that commutes with it. then, relative to the decomposition H=M⊕ : is the restriction of and , can be written as , on } be a countable collection Hilbert spaces and consider the Hilbert space } is a bounded set of operators (i.e., ⊕ . Suppose . The (orthogonal) direct sum of 153 { } is the operator such that for each . This is denoted by ⊕ Each reduces and . A direct summand of an operator is a restriction of it to a reducing subspace. (E.g. Let is a direct summand of be a Hilbert space and . The set is invertible is called the resolvent set of of all complex number for which . Equivalently, { } { The complement of the resolvent set } denoted by is called the spectrum of { } { such that ⊕ i.e, } which is the set of all fails to be invertible (i.e. fails to have a bounded inverse on On the basis of this failure, the spectrum can be split into many disjoint parts. A classical disjoint partition comprises of three parts: the set of those is called the point spectrum of, that has no inverse, denoted by i.e, { } , which is exactly the set of all eigenvalues of { A scalar such that is an eigenvalue of an operator if there exists a nonzero vector { } . The set of all those ; equivalently, if . has a densely defined but unbounded inverse on its range, denoted by such for which is called the continuous spectrum of , i.e, { } { If } has an inverse that is not densely defined then denoted The parts . That is { } { , belongs to the residual spectrum of , } are pairwise disjoint and Other subsets of the spectrum exist such as: approximate point spectrum, denoted belongs to the approximate point spectrum of vectors { Let and } such that if and only if there exists a sequence of unit . be Hilbert spaces. An operator is invertible if it is injective (one -to- one) and surjective (onto or has dense range); equivalently if the class of invertible linear operators by ; a number . 154 { } and We denote The commutator of two operators and is [ The self- commutator of an operator Two operators and ] is defined by if there exists an operator i.e, where which is an invertible operator from Linear operators and unitary operator . ] are similar (denoted such that subalgebra of , denoted by [ is a Banach to are unitarily equivalent (denoted ), if there exists a such that . Two operators are considered the “same” if they are unitarily equivalent since they have the same, properties of invertibility, normality, spectral picture (norm, spectrum and spectral radius). An operator is quasi-invertible or a quasi-affinity if it is an injective operator with dense { } and range (i.e. { ̅ } and, ; equivalently, is quasi-invertible if and only if is quasi-invertible). is a quasi –affine transform of An operator such that if there exists a quasi-invertible . exists a quasi-invertible operator intertwining Two operators and is a quasiaffine transform of are quasi-similar (denoted T S) if they are quasi-affine such that and ). is said to be densely intertwined to (T) of if there to . transforms of each other (i.e., if there exists quasi-invertible operators The multiplicity { ̅ } thus if there exists an operator with dense range intertwining is the minimum cardinality of a set such that ⋁ For the unilateral shift operator and for the backward shift, = 155 to . 1.2 A natural method for constructing an invariant subspace for an operator on a Hilbert space is to find a second, known operator which is similar in some weak sense to the given operator and then use this second operator and the weak similarity to construct the desired subspace. One such weak similarity is the notion of quasisimilarity introduced by Sz.-Nagy and Foias [13]. T.B. Hoover [6] studied hyperinvariant subspaces and proved the result that if operators acting on the Hilbert spaces so does . If in addition, and respectively, and if and are quasi similar has a hyperinvariant subspace, then is normal, then the lattice of hyperinvariant subspaces for lattice which is lattice isomorphic to the lattice of spectral projections for contains a sub Similar results for hyperinvance have been studied by C.S. Kubrusly [9] and has show that similarity preserves nontrivial subspaces while quasisimilarity preserves hyperinvariant subspaces. Hoover [1] has also shown some properties of operators that are preserved by quasisimilarity and those that are not. He gave a result to show that quasisimilar normal operators are unitarily equivalent. Quasisimilarity and weak similarity are also discussed. In addition, quasisimilar isometries are shown to be unitarily equivalent. He also gave an example to show that quasisimilarity preserves neither spectra nor compactness. Equality of spectra of quasisimilar normal operators was proved in [2, Lemma 4.1 p. 683] but the result did not generalize to pairs of quasisimilar hyponormal operators as seen in [4, solution156, p. 309] and [7, Theorem 2.5. p.681]. In spite of these examples, Clary [1, Theorem 2, p.89] went ahead to show that quasisimilar hyponormal operators had equal spectra. In 1981, J.G. stampfli [12] extended Clary’s results on quasisimilar hyponormals where an inclusion relation for the spectra of quasisimilar operators satisfying Dunford’s condition was obtained. It is in this paper that quasimilarity and the unilateral shift was discussed. These results were extensively analyzed by Lambert [10] in his thesis where he showed that any two unilateral weighted shifts which are quasisimilar are actually similar, but if unilateral shift is replaced by bilateral as pointed out by Fialkow [3] the results fail. A question on whether quasisimilar hyponormal operators had equal spectra as asked by S.Clary in [1] was studied and answered by L.R.Williams in [17]. i.e. they indeed had equal spectra. He went further to give some results that relate quasisimilarity and hyponormal operators; for instance if one of the quasiaffinities of the two hyponormals is compact, then they have equal essential spectra [15, Theorem A, P.126]. 156 By considering the natural concept of equivalence between Hilbert Space operators to be unitary equivalence, we show that similarity is an equivalence relation on Similarly by introducing the notion of quasisimilarity of operators which is the same as similarity in finite dimensional spaces, but in infinite dimensional spaces, it is a much weaker relation, we show that quasisimilarity is an equivalence relation. Furthermore, we establish the link between invariant subspaces and hyperinvariant subspaces with similarity and quasisimilarity operator properties. We recall that two operators and an invertible operator Similarly, are similar (denoted by ) if there exists such that and operator . are unitarily equivalent (denoted ) if there exisits a unitary such that . Theorem 2.1. Unitary equivalence is an equivalence relation. Proof: We show that unitary equivalence is (i) Reflective, (ii) Symmetric and (iii) Transitive. (i) Reflexivity: i.e. Let . Then where is a unitary operator. Hence In this case, we may choose (without loss of generality (ii) Symmetry: i.e. . Now suppose that . We show that operator ). . Let and . There exists a unity such that ……………………………………………….. Pre multiplying by and post multiplying the same by Hence (iii) Transitivity i.e. If exist unitary operators . gives . and , then and . Suppose and . Then there where is a Hilbert space such that and Using and we have that unitary operator since where are unitary. Hence 157 . is a Remark 2.2. Similarly, it can be proved (as Theorem 2.1.1 above) that similarity is an equivalence relation on The natural concept of equivalence between Hilbert space operators is unitary equivalence which is stronger than similarity. A nice approach of determining whether two operators are similar or not is by use of matrices. We need to compute a particular canonical form, and in our case, we may use the triangular or Jordan form which we describe briefly as follows: Definition 2.3 [23]. A matrix is said to be triangular if all its entries above the main diagonal are 0, or equivalently, if is a linear operator on over a scalar field , the matrix of is in the basis is triangular if i.e, if is a linear combination only of and its predecessors in the basis. Theorem 2.4 (Schur’s Theorem ). If an operator (matrix) there exists an operator such that has all its eigenvalues in is a triangular matrix. Remark 2.5. Theorem 2.4 above is usually described by saying that triangular form over can be brought to a In other words every matrix A on a finite dimensional space is unitarily equivalent to a triangular matrix. The elements of the main diagonal of its matrix are precisely the eigenvalues of . 1 0 0 Definition 2.6 [23]. (Jordan form). An m m matrix with then on the main diagonal, 0 1 1 0 1 0 1 0 above the main diagonal and 0’s elsewhere such that [ ] 1 0 { 0 0 1 1 158 0 1 0 1 0 is a basic Jordan block belonging to Corollary 2.7 [5]. Two linear operators in which have all their eigenvalues in are similar if and only if they can be brought to the same Jordan form. Remark 2.8. The Jordan form acts as a “determiner” for similarity classes to this type of linear operators. Theorem 2.9. [5]. Let be a linear operator on the complex { } Then there is a basis dimensional vector space such that [ ] where where ,there exists a nonsingular matrix such that Remark 2.10. The Jordan form of an operator or matrix plays a very important role in understanding the structure of matrices and linear operators (very applicable in the study of differential equations). Example 2.11. Let on * + and by √ ( √ √ (√ √ √ i.e. + be two dimensional operators on ) whose inverse is ) (√ ( Then * ) (√ √ )( √ √ ) ) ( √ ). ( ) and √ (√ √ √ √ √ I.e √ . Define an invertible operator and hence ) and ( √ ) are similar i.e. . Example 2.12. Let invertible [ ] and [ ] be two matrix. Define (square) matrices such that ∑ and 159 ∑ where is an be the sum of diagonal entries of matrices of and respectively. Then, since and are similar, they have the same characteristic polynomial. In addition, they have the same trace i.e. trace of matrix is similarity invariant. Solution Assume .Then we have [ I.e. and By ] have got the same characteristic polynomial. Let we have that . So multiplicities), say and and be two similar matrices. have got the same eigenvalues (together with their . Now since the trace of an matrix coincides with the sum of its ∑ eigenvalues, where are the eigenvalues of (counted with their multiplicities). ∑ implies that as required. Example 2.13. Let be an operator on an represent dimensional vector space. If two with respect to different bases of then and ] and [ matrices and are similar. Solution Assume that the two } and { bases { [ matrices for ∑ ( ) and for Next, for each j choose scalars ( ) ∑ ( ) ∑ and such that ∑ and note that [ , we get ∑ ∑ with respect to } respectively. That is ∑ invertible. Using ] represent the operator ∑ ∑ =∑ ∑ 160 ∑ ∑ and from . we obtain ] is Therefore , ∑ ∑ . In matrix notation, this equivalent to which establishes that matrices and or are similar. Remark 2.14. The Lemma below is vital in proving the result that if two operators and are similar, then they have equal spectrum. Lemma 2.15. [4]. Suppose that Lemma 2.16. [4]. Suppose that and and is invertible, then . are similar operators on a Hilbert space , then and have the same a) Spectrum b) Point spectrum c) Approximate point spectrum. Example 2.17. Consider two similar operators and given in example 2.11 above. We now show that they have the same spectrum. The spectrum of and Thus is the set of their respective eigenvalues since i.e. * Using the same approach, we find that + { i.e. and It follows that are finite. { }. } as required. Remark 2.18. [8, Theorem 7.1-3]: In view of example 2.1.11 above, all operators (matrices) representing a given linear operator on a finite dimensional normed space bases have the same spectra. 161 relative to different The following results help us investigate the relationship between similarity and unitary equivalence for normal operators: [ ] is a unitary operator for any self adjoint operator [ Theorem 3.2. Assume that where Proof: By proposition 3.1 above, and ] are normal and , then is a unitary operator , where S is any self-adjoint operator. The hypothesis number for any natural , so that for any ̅ ̅ Define a function ̅ ̅ ̅ Since . . This function can be expressed as ̅ ̅ ̅ and ̅ since By the normality of are both unitary operators by ∀ yields and by . are both self-adjoint operators, so that ensures that . Consequently, ̅ ̅ and is analytic and bounded is a constant by Lioville’s Theorem i.e. and ̅ for any , so that holds. By differentiating both sides with respect to we obtain the desired result Remark 3.3. The hypothesis of theorem 3.2 does not imply that self-adjoint and ( ( ) are ( ) , then by simple calculation, it is true that . Theorem 3.4. ([11]). If with and is normal for consider: ) but , even when is invertible, then an isometry (which is in fact unitary) and decomposition in which and has a unique polar decomposition . If commute with each other. 162 is normal, then has a polar We are now ready to show that similar normal operators are unitarily equivalent in the theorem that follows: Theorem 3.5. Suppose that , . If Proof: are normal is the polar decomposition of From . Hence so that is invertible and , then by . Theorem B 2.2.2. Hence , since This yields The Unilateral Shift On Hilbert space { } family { an operator is said to be a unilateral shift if there exists an infinite sequence of non-zero pairwise orthogonal subspaces of } spans ) and maps each By the above definition, isometry and hence and symmetrically onto and unitary. Therefore, for every and its adjoint such that (i.e. the orthogonal . is an isometry, thus a surjective and are unitarily equivalent . This constant dimension is the multiplicity of are identified with infinite matrices 0 U1 * 0 0 0 U * 2 0 U3 * 0 ⊕ 0 0 U 1 0 0 U2 0 U3 0 of transformations, where every entry below (above) the main block diagonal in the matrix (Equivalently , for every ). 163 that . More so is unitary and the remaining entries are all null. From the above matrices, we see that so The canonical unilateral shift on Let . be a Hilbert space and Consider the operator be unitary so that for every ⊕ =⊕ Since the composition and direct sum of unitary transformations are again unitary, it follows that is unitary and 0 0 I 0 0 I 0 I Thus 0 such that is unitary equivalent to If (i.e, if multiplicity 1 acting on basis for which is a unilateral shift of multiplicity acting on in the case of a complex space) then we get a canonical unilateral shift of and is the operator on that shifts the canonical orthonormal . Consequently, we prove the following results of unitary equivalence for unilateral shifts: Proposition 3.6. Two unilateral shifts are unitarily equivalent if and only if they have the same multiplicity. Proof Let and be unilateral shifts which are unitarily equivalent. Then they are unitarily equivalent to the canonical unilateral shifts of multiplicity Conversely, let and and have the same multiplicity, canonical unilateral shifts of multiplicity, Proposition 3.7 . Hence . Hence and have the same multiplicity. . Then they are unitarily equivalent to the are unitarily equivalent . If an operator is unitarily equivalent to a unilateral shift, then it is a unilateral shift itself of the same multiplicity. Proof Let be a unilateral shift of multiplicity acting on a Hilbert space countably infinite orthogonal family of unitarily equivalent subspaces of 164 and let { ⊕ } be the underlying so that for all .Take an operator transformation Since acting on a Hilbert space such that is unitary, it follows that ⊕ set so that is an orthogonal family ( { . } is orthogonal and because the range of an isometry is closed. Moreover, { inner product) of subspaces of i.e. . For each and suppose that there exists a unitary preserves } spans . Furthermore, since for each . Finally, note that Thus is an isometry and so any restriction of it (in particular Thus is a unilateral shift with the same multiplicity of ( Let and ∀ ) from to A quasi-affinity from If affinity to once to is a linear one-to-one and bicontinuous We recall that two operators similar if there exists an affinity such that and are said to be and as a result, is a bounded linear operator which is one-to-one and has a dense range. and , we say tha such that is a quasi-affine transform of The operators and and 165 if there exists a quasi- are called quasi-similar if they are quasi-affine transforms of each other, i.e. if there exists quasi-affinities such that ). . be Hilbert spaces. An affinity from transformation is an isometry for every and Theorem 4.1.1. (i) If and is a quasi-affinity from to and is a quasi-affinity from to where are finite dimensional then (a) is a quasi-affinity from (b) to . is a quasi-affinity from Proof (a) since to . is a quasi-affinity, then the operator is intertwined to the operator by . That is . In like manner, if , then From is intertwined to .Putting in .That is to . That is that is on the right hand side of which implies that is a quasi-affinity from . (b) implies that for all and linear one-to-one continuous transformation from exists and as a result, and so . Since a quasi-affinity is a onto a dense linear manifold in . But the map , the inverse is essentially the map as required. Theorem 4.1.2. If (a) , that is we get . Applying gives by is a quasi-affine transform of and is a quasi-affine transform of , then is a quasi-affine transform of (b) is a quasi-affine transform of Proof: . a quasi-affine transform of such that Similarly, that there exists a quasi-affinity , that is implies that there exists a quasi-affinity a quasi-affine transform of such that is a quasi-affine transform of implies By Theorem 4.1.1, with quasi-affinity where . Part (b) follows from Theorem 4.1.1 (b). Proposition 4.1.3. If from to ) . Moreover is a quasi-affinity from to then √ is a quasi-affinity on extends by continuity to a unitary transformation 166 from to . (i.e. Lemma 4.1.4 [8, Lemma 2.6-11]. Let and and be quasi-affinities where are finite dimensional Hilbert spaces. Then the inverse exists and of the composite . Proposition 4.1.5. If a unitary operator unitary operator Proof: on a Hilbert space Let on a Hilbert space is the quasi-affine transform of a then and are unitarily equivalent. be a quasi-affinity. implies that From Then . and we obtain and by iteration for every polynomial uniformly on the interval 0 and } be a sequence of polynomials tending to Let { . Then that we obtain a limit relation From hence converges (in the operator norm) to . ) it follows that results that so because | . By Proposition 4.1.3 above is unitary and hence is dense in and , it are unitarily equivalent. Theorem 4.1.6. Quasi-similarity is an equivalence relation on the class of all operators. Proof: Let be a finite dimensional Hilbert space and let Then . First we show and where invertible operators. Choosing Now suppose that are quasi- (without loss of generality) we have that . We show that Thus and . Since exists quasi-affinities i.e. and such that and i.e. . Hence Suppose and . Then we show that . There exist quasi-invertible operators and respectively such that and and and . 167 Putting equation in we have and that is and It then follows from where that and i.e. and as required. The following Theorem enables us obtain an example of quasi-similar operators: Theorem 4.1.7 [7, Theorem 2.5]. Suppose that for each and and operators in some index set and there are Hilbert spaces respectively which are quasi-similar. Let be the operator ∑ ⊕ ∑ ⊕ acting on the Hilbert space which is the direct sum of the spaces Example 4.1.8. Let and dimensional Hilbert space similar. If ∑ where ∑ and ⊕ Then is quasi-similar to be unilateral shift operators with weights . Then . and is the Jordan canonical form for ∑ then by the above Theorem and respectively on an and so and are is quasi-similar to . Recall that an operator intertwines to if intertwined to , then there exists an operator with dense range intertwining . If to is densely . The Lemma below gives a sufficient condition for transferring nontrivial invariant subspaces from to whenever is densely intertwined to . Lemma 4.1.9 [9, Lemma 4.1]. Let Suppose , and is a nontrivial invariant subspace for inverse image of under If be such that and . { } the is a nontrivial invariant subspace for Remark 4.1.10. If the intertwining operator is a nontrivial invariant subspace for is surjective, (i.e. ) then . Thus we have the following corollary: Corollary 4.1.11 [9, Corollary 4.2]. If two operators are similar and if one of them has a non trivial invariant subspace, then so has the other. 168 , { } is the set of all operators in Definition 4.1.12. The commutator of commutes with that , i.e. { } { }. In other words, the commutant of an operator is the set of all operators intertwining it to itself. { } and Claim: Proof: { } { } whenever { { } . }. Now , that is and that is as required. Actually { } is an operator algebra which contains the identity. A linear manifold (subspace) of a normed space is hyperinvariant for every operator in on a normed space { { }} Hence and for each vector ⊆ { } subspace, then for every (i.e. Proposition 4.1.13. For each Proof: Let { }} such that and ,there exists every (since linear manifold of that { }. Since in . Therefore, if is a subspace of ⊆ { } has no nontrivial hyperinvariant i.e. if and only if which is hyperinvariant for Take an operator .If and consider the { } then there exist operators { } If { } because and hence { } such that { } , it follows that is never empty unless be an arbitrary vector in a normed space { set set . Then { } for every nonzero { } . For any and so for every scalar and { } ). It follows that, as an algebra, { } is a linear space and hence . Now take an arbitrary (for { } . If ⊆ ) .Thus , then and hence for some ⊆ is a { } so because is continuous. Recalling that the closure of a linear manifold is a subspace and since we conclude that ̅̅̅̅ is invariant for every is an arbitrary operator in { } { } equivalently, ̅̅̅̅ is a hyperinvariant subspace for 169 Lemma 4.1.14. Let , . Suppose and be such that is a nontrivial hyperinvariant subspace for { } then If and , ̅̅̅̅ is a nontrivial hyperinvariant { } and for each nonzero subspace for . Proof: By Proposition 4.1.13, { } for every { } . If { } . We note that for every commutes with so that Now let ̅̅̅̅ commutes with then { } for every i.e. be a nontrivial hyperinvariant subspace for . Since hyperinvariant for is and take an arbitrary so that invariant, it follows that must be in then ̅̅̅̅̅̅̅̅̅̅ Therefore if ̅̅̅̅ for every ̅̅̅̅̅̅̅ ensure that there exists an and as because ̅̅̅̅̅̅̅̅̅ ̅̅̅̅̅ ⊆ and is closed and is continuous. and hence ̅̅̅̅̅̅̅̅̅̅ { } ( i.e. if such that if implies and since ⊆ ), then { }. Hence ̅̅̅̅̅̅̅̅̅̅ { } is nonzero. Thus { } then ̅̅̅̅ is a nontrivial hyperinvariant for and only if for some Thus in order to show that ̅̅̅̅ is a nontrivial hyperinvariant for , we must in { }, Since ⊆ . There for , it is { } . Since . But ̅̅̅̅ is is a hyper invariant subspace for for every whenever so that for some ̅̅̅̅̅ ⊆ ̅ properly included in { }. is hyperinvariant for { } . Take an arbitrary whenever { } for every nonzero (for ̅̅̅̅ and if ) with ̅̅̅̅̅̅̅̅̅̅ and such that ̅̅̅̅ is a nontrivial hyperinvariant subspace for . Thus Remark 4.1.15. In view of the above Lemma, if then there exists and we have the following corollary: Corollary 4.1.16. If two operators are quasi-similar and if one of them has a nontrivial hyperinvariant subspace then so has the other . 170 [1] Clary S. Equality of spectra of quasisimilar hyponormal operators, Pro. Amer. Math. Soc. 53 (1975), No.1, 88-90. [2] Douglas R.G. On the operator equation (1969), 19-32. and related topics, Acta Sci. Math (Szeged) 30 [3] Fialkol L.A. 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