PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 1 1 Optimization Techniques • Methods for maximizing or minimizing an objective function • Examples – Consumers maximize utility by purchasing an optimal combination of goods – Firms maximize profit by producing and selling an optimal quantity of goods – Firms minimize their cost of production by using an optimal combination of inputs PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 2 Expressing Economic Relationships Equations: Tables: TR = 100Q - 10Q2 Q TR 0 0 1 90 2 3 4 5 6 160 210 240 250 240 TR 300 250 Graphs: 200 150 100 50 0 0 1 2 3 4 5 6 7 Q PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 3 Total, Average, and Marginal Revenue TR = PQ AR = TR/Q MR = TR/Q PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Q 0 1 2 3 4 5 6 TR 0 90 160 210 240 250 240 AR 90 80 70 60 50 40 Copyright 2007 by Oxford University Press, Inc. MR 90 70 50 30 10 -10 Slide 4 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 5 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 6 TR 300 250 Total Revenue 200 150 100 50 0 0 1 2 3 4 5 6 7 Q AR, MR 120 100 Average and Marginal Revenue 80 60 40 20 0 -20 0 1 2 3 4 5 6 7 -40 Q PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 7 Total, Average, and Marginal Cost AC = TC/Q MC = TC/Q PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Q 0 1 2 3 4 5 TC AC MC 20 140 140 120 160 80 20 180 60 20 240 60 60 480 96 240 Copyright 2007 by Oxford University Press, Inc. Slide 8 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 9 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 10 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 11 Geometric Relationships • The slope of a tangent to a total curve at a point is equal to the marginal value at that point • The slope of a ray from the origin to a point on a total curve is equal to the average value at that point PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 12 Geometric Relationships • A marginal value is positive, zero, and negative, respectively, when a total curve slopes upward, is horizontal, and slopes downward • A marginal value is above, equal to, and below an average value, respectively, when the slope of the average curve is positive, zero, and negative PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 13 Profit Maximization Q 0 1 2 3 4 5 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. TR 0 90 160 210 240 250 TC Profit 20 -20 140 -50 160 0 180 30 240 0 480 -230 Copyright 2007 by Oxford University Press, Inc. Slide 14 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 15 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 16 Steps in Optimization • Define an objective mathematically as a function of one or more choice variables • Define one or more constraints on the values of the objective function and/or the choice variables • Determine the values of the choice variables that maximize or minimize the objective function while satisfying all of the constraints PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 17 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 18 New Management Tools • • • • Benchmarking Total Quality Management Reengineering The Learning Organization PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 19 Other Management Tools • • • • Broadbanding Direct Business Model Networking Performance Management PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 20 Other Management Tools • • • • • Pricing Power Small-World Model Strategic Development Virtual Integration Virtual Management PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 21 Chapter 2 Appendix PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 22 Concept of the Derivative The derivative of Y with respect to X is equal to the limit of the ratio Y/X as X approaches zero. PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 23 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 24 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 25 Rules of Differentiation Constant Function Rule: The derivative of a constant, Y = f(X) = a, is zero for all values of a (the constant). Y f (X ) a dY 0 dX PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 26 Rules of Differentiation Power Function Rule: The derivative of a power function, where a and b are constants, is defined as follows. Y f (X ) aX b dY b a X b 1 dX PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 27 Rules of Differentiation Sum-and-Differences Rule: The derivative of the sum or difference of two functions, U and V, is defined as follows. U g( X ) V h( X ) Y U V dY dU dV dX dX dX PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 28 Rules of Differentiation Product Rule: The derivative of the product of two functions, U and V, is defined as follows. U g( X ) V h( X ) Y U V dY dV dU U V dX dX dX PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 29 Rules of Differentiation Quotient Rule: The derivative of the ratio of two functions, U and V, is defined as follows. U g( X ) dY dX V h( X ) V dU PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. dX U dV V U Y V dX 2 Copyright 2007 by Oxford University Press, Inc. Slide 30 Rules of Differentiation Chain Rule: The derivative of a function that is a function of X is defined as follows. Y f (U ) U g( X ) dY dY dU dX dU dX PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 31 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 32 Optimization with Calculus Find X such that dY/dX = 0 Second derivative rules: If d2Y/dX2 > 0, then X is a minimum. If d2Y/dX2 < 0, then X is a maximum. PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 33 Univariate Optimization Given objective function Y = f(X) Find X such that dY/dX = 0 Second derivative rules: If d2Y/dX2 > 0, then X is a minimum. If d2Y/dX2 < 0, then X is a maximum. PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 34 Example 1 • Given the following total revenue (TR) function, determine the quantity of output (Q) that will maximize total revenue: • TR = 100Q – 10Q2 • dTR/dQ = 100 – 20Q = 0 • Q* = 5 and d2TR/dQ2 = -20 < 0 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 35 Example 2 • Given the following total revenue (TR) function, determine the quantity of output (Q) that will maximize total revenue: • TR = 45Q – 0.5Q2 • dTR/dQ = 45 – Q = 0 • Q* = 45 and d2TR/dQ2 = -1 < 0 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 36 Example 3 • Given the following marginal cost function (MC), determine the quantity of output that will minimize MC: • MC = 3Q2 – 16Q + 57 • dMC/dQ = 6Q - 16 = 0 • Q* = 2.67 and d2MC/dQ2 = 6 > 0 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 37 Example 4 • Given – TR = 45Q – 0.5Q2 – TC = Q3 – 8Q2 + 57Q + 2 • Determine Q that maximizes profit (π): – π = 45Q – 0.5Q2 – (Q3 – 8Q2 + 57Q + 2) PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 38 Example 4: Solution • Method 1 – dπ/dQ = 45 – Q - 3Q2 + 16Q – 57 = 0 – -12 + 15Q - 3Q2 = 0 • Method 2 – MR = dTR/dQ = 45 – Q – MC = dTC/dQ = 3Q2 - 16Q + 57 – Set MR = MC: 45 – Q = 3Q2 - 16Q + 57 • Use quadratic formula: Q* = 4 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 39 Quadratic Formula • Write the equation in the following form: aX2 + bX + c = 0 • The solutions have the following form: b b 4ac 2a 2 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 40 Multivariate Optimization • Objective function Y = f(X1, X2, ...,Xk) • Find all Xi such that ∂Y/∂Xi = 0 • Partial derivative: – ∂Y/∂Xi = dY/dXi while all Xj (where j ≠ i) are held constant PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 41 Example 5 • Determine the values of X and Y that maximize the following profit function: – π = 80X – 2X2 – XY – 3Y2 + 100Y • Solution – ∂π/∂X = 80 – 4X – Y = 0 – ∂π/∂Y = -X – 6Y + 100 = 0 – Solve simultaneously – X = 16.52 and Y = 13.92 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 42 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 43 Constrained Optimization • Substitution Method – Substitute constraints into the objective function and then maximize the objective function • Lagrangian Method – Form the Lagrangian function by adding the Lagrangian variables and constraints to the objective function and then maximize the Lagrangian function PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 44 Example 6 • Use the substitution method to maximize the following profit function: – π = 80X – 2X2 – XY – 3Y2 + 100Y • Subject to the following constraint: – X + Y = 12 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 45 Example 6: Solution • Substitute X = 12 – Y into profit: – π = 80(12 – Y) – 2(12 – Y)2 – (12 – Y)Y – 3Y2 + 100Y – π = – 4Y2 + 56Y + 672 • Solve as univariate function: – dπ/dY = – 8Y + 56 = 0 – Y = 7 and X = 5 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 46 Example 7 • Use the Lagrangian method to maximize the following profit function: – π = 80X – 2X2 – XY – 3Y2 + 100Y • Subject to the following constraint: – X + Y = 12 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 47 Example 7: Solution • Form the Lagrangian function – L = 80X – 2X2 – XY – 3Y2 + 100Y + (X + Y – 12) • Find the partial derivatives and solve simultaneously – dL/dX = 80 – 4X –Y + = 0 – dL/dY = – X – 6Y + 100 + = 0 – dL/d = X + Y – 12 = 0 • Solution: X = 5, Y = 7, and = -53 PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 48 Interpretation of the Lagrangian Multiplier, • Lambda, , is the derivative of the optimal value of the objective function with respect to the constraint – In Example 7, = -53, so a one-unit increase in the value of the constraint (from -12 to -11) will cause profit to decrease by approximately 53 units – Actual decrease is 66.5 units PowerPoint Slides Prepared by Robert F. Brooker, Ph.D. Copyright 2007 by Oxford University Press, Inc. Slide 49
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