ANALELE ŞTIINŢIFICE ALE UNIVERSITĂŢII “AL.I. CUZA” DIN IAŞI (S.N.) MATEMATICĂ, Tomul LXI, 2015, f.1 DOI: 10.2478/aicu-2013-0049 A NEW APPLICATION OF ALMOST INCREASING SEQUENCES BY H.S. ÖZARSLAN and A. KETEN Abstract. Bor has proved a main theorem dealing with |N̄ , pn |k summability factors of infinite series. In this paper, we have generalized this theorem to the ϕ − |A, pn |k summability factors, under weaker conditions by using an almost increasing sequence instead of a positive monotonic non-decreasing sequence. Mathematics Subject Classification 2010: 40D25, 40F05, 40G99. Key words: absolute matrix summability, almost increasing sequences, infinite series. 1. Introduction A positive sequence (bn ) is said to be almost increasing if there exists a positive increasing sequence (cn ) and Ptwo positive constants A and B such that Acn ≤ bn ≤ Bcn (see [1]). Let an be a given infinite series with the partial sums (sn ). Let (pn ) be a sequence of positive numbers such that (1) Pn = n X pv → ∞ as n → ∞, (P−i = p−i = 0, i ≥ 1) . v=0 The sequence-to-sequence transformation (2) n 1 X σn = pv s v Pn v=0 defines the sequence (σn ) of the N̄ , pn mean of the sequenceP(sn ), generated by the sequence of coefficients (pn ) (see [5]). The series an is said Unauthenticated Download Date | 7/28/17 7:18 PM 154 2 H.S. ÖZARSLAN and A. KETEN to be summable N̄ , pn k , k ≥ 1, if (see [2]) ∞ X Pn k−1 (3) n=1 pn |σn − σn−1 |k < ∞. Let A = (anv ) be a normal matrix, i.e., a lower triangular matrix of nonzero diagonal entries. Then A defines the sequence-to-sequence transformation, mapping the sequence s = (sn ) to As = (An (s)), where (4) An (s) = n X anv sv , n = 0, 1, ... v=0 The series P an is said to be summable |A, pn |k , k ≥ 1, if (see [7]) (5) ∞ X Pn k−1 n=1 pn ¯ n (s)|k < ∞, |∆A ¯ n (s) = An (s) − An−1 (s). Let (ϕn ) be any sequence of positive real where ∆A P numbers. We say that the series an is summable ϕ − |A, pn |k , k ≥ 1, if ∞ X (6) n=1 ¯ n (s)k < ∞. ϕnk−1 ∆A If we take ϕn = Ppnn , then ϕ − |A, pn |k summability reduces to |A, pn |k summability. Also, if we take ϕn = Ppnn and anv = Ppvn , then we get N̄ , pn k summability. Furthermore, if we take ϕn = n and anv = Ppvn and pn = 1 for all values of n, then ϕ − |A, pn |k summability reduces to |C, 1|k summability (see [4]). Before stating the main theorem we must first introduce some further notations. Given a normal matrix A = (anv ), we associate two lower semi matrices Ā = (ānv ) and  = (ânv ) as follows: (7) ānv = n X ani , n, v = 0, 1, ... i=v (8) â00 = ā00 = a00 , ânv = ānv − ān−1,v , n = 1, 2, ... Unauthenticated Download Date | 7/28/17 7:18 PM 3 A NEW APPLICATION OF ALMOST INCREASING SEQUENCES 155 It may be noted that Ā and  are the well-known matrices of series-tosequence and series-to-series transformations, respectively. Then, we have (9) An (s) = ¯ n (s) = ∆A (10) n X v=0 n X anv sv = n X ānv av , v=0 ânv av . v=0 2. Known result Bor [3] has proved the following theorem for N̄ , pn k summability method. Theorem A. Let (pn ) be a sequence of positive numbers such that (11) Pn = O(npn ) n → ∞. as If (Xn ) is a positive monotonic non-decreasing sequence such that (12) λm Xm = O(1) as m → ∞, m X nXn |∆2 λn | = O(1), (13) n=1 m X (14) n=1 1 where tn = n+1 Pn v=1 pn |tn |k = O(Xm ) Pn vav then the series P as m → ∞, an λn is summable |N̄ , pn |k , k≥1. 3. The main result The aim of this paper is to generalize Theorem A to ϕ − |A, pn |k summability. Now we shall prove the following theorem. Theorem. Let A = (anv ) be a positive normal matrix such that (15) ān0 = 1, (16) an−1,v ≥ anv , f or n ≥ v + 1, pn ann = O , Pn |ân,v+1 | = O (v |∆v ânv |) . (17) (18) n = 0, 1, ..., Unauthenticated Download Date | 7/28/17 7:18 PM 156 4 H.S. ÖZARSLAN and A. KETEN Let (Xn ) be an almost increasing sequence and ( ϕPnnpn ) be a non-increasing sequence. If conditions (11)-(13) of Theorem A and k m X pn k−1 ϕn (19) |tn |k = O(Xm ) as m → ∞, P n n=1 P are satisfied, then the series an λn is summable ϕ − |A, pn |k , k ≥ 1. It should be noted that if we take (Xn ) as a positive monotonic nondecreasing sequence, anv = Ppvn and ϕn = Ppnn in this theorem, then we get Theorem A. In this case, condition (19) reduces to condition (14) and the condition ”( ϕPnnpn ) is a non-increasing sequence” is automatically satisfied. We require the following lemma for the proof of the theorem. Lemma ([6]). Under the conditions on (Xn ) and (λn ) which are taken in the statement of our theorem, then we have the following: (20) nXn |∆λn | = O(1) as n → ∞, ∞ X Xn |∆λn | < ∞. (21) n=1 4. Proof of the theorem P Let (Tn ) denotes A-transform of the series an λn . Then, by (9) and (10), we have ¯ n= ∆T n X ânv av λv = n X ânv λv v=1 v=1 v vav . Applying Abel’s transformation to this sum, we get ¯ n ∆T = n−1 X ∆v v=1 = ânv λv v X v rar + r=1 n−1 X n ânn λn X rar n r=1 v+1 n+1 ann λn tn + ∆v (ânv ) λv tv n v v=1 + n−1 X v=1 = n−1 X1 v+1 ân,v+1 ∆λv tv + ân,v+1 λv+1 tv v v v=1 Tn,1 + Tn,2 + Tn,3 + Tn,4 , say. Unauthenticated Download Date | 7/28/17 7:18 PM 5 A NEW APPLICATION OF ALMOST INCREASING SEQUENCES 157 To prove theorem, by Minkowski’s inequality, it is sufficient to show P thek−1 that ∞ ϕ |Tn,r |k < ∞, for r = 1, 2, 3, 4. Firstly, we have that n=1 n k m m X X k−1 n + 1 k−1 k ann λn tn ϕn ϕn |Tn,1 | = n n=1 n=1 k k m m X X pn pn k−1 k k−1 k−1 k ϕn |λn ||tn | = O(1) ϕn |λn | |λn ||tn | = O(1) Pn Pn n=1 n=1 k k n m−1 m X X X pr pv k−1 k−1 k ϕr ∆|λn | = O(1) ϕv |tr | + O(1)|λm | |tv |k Pr Pv = O(1) = O(1) n=1 m−1 X n=1 m−1 X r=1 v=1 ∆|λn |Xn + O(1)|λm |Xm |∆λn |Xn + O(1)|λm |Xm = O(1) as m → ∞, n=1 by virtue of the hypotheses of the theorem and lemma. Applying Hölder’s inequality with indices k and k′ , where k > 1 and 1 1 k + k ′ = 1, as in Tn,1 , we have that k n−1 m+1 m+1 X v + 1 X X k−1 k−1 k ϕn ∆v (ânv )λv tv ϕn |Tn,2 | = v v=1 n=2 n=2 !k−1 ! n−1 n−1 m+1 X X X |∆v (ânv )| |∆v (ânv )||λv |k |tv |k × ϕnk−1 = O(1) = O(1) = O(1) n=2 m+1 X n=2 m X ϕn pn Pn k−1 |λv | = O(1) k |λv ||tv | = O(1) k |λv | |tv | as k |∆v (ânv )||λv | |tv | v=1 m+1 X ϕv pv Pv |λv | |tv |k ϕvk−1 v=1 = O(1) k n=v+1 v=1 m X n−1 X k−1 v=1 m X v=1 v=1 ϕn pn Pn k−1 m+1 X k−1 ! |∆v (ânv )| |∆v (ânv )| n=v+1 pv Pv k m → ∞, Unauthenticated Download Date | 7/28/17 7:18 PM 158 6 H.S. ÖZARSLAN and A. KETEN by virtue of the hypothesesof the theorem and lemma. 1 Now, since v|∆λv | = O Xv = O(1), by (20), we have that n−1 k X v + 1 ϕnk−1 ϕnk−1 |Tn,3 | = ân,v+1 ∆λv tv v v=1 n=2 n=2 !k−1 ! n−1 n−1 m+1 X X X |ân,v+1 ||∆λv | |ân,v+1 ||∆λv ||tv |k × ϕnk−1 = O(1) m+1 X = O(1) = O(1) m+1 X k n=2 v=1 m+1 X n−1 X ϕnk−1 n=2 m+1 X n=2 v=1 v|∆v ânv ||∆λv ||tv |k v=1 ϕn pn Pn k−1 m X n−1 X ! n−1 X × v|∆v ânv ||∆λv | v=1 k v|∆v ânv ||∆λv ||tv | v=1 m+1 X !k−1 ! ϕn pn k−1 v|∆λv ||tv | = O(1) |∆v ânv | Pn n=v+1 v=1 m+1 m X ϕv pv k−1 X |∆v ânv | v|∆λv ||tv |k = O(1) P v n=v+1 v=1 k m X pv v|∆λv ||tv |k ϕvk−1 = O(1) Pv v=1 k v m−1 X X pr k−1 ϕr |∆ (v|∆λv |)| = O(1) |tr |k Pr r=1 v=1 k m X pv k−1 |tv |k ϕv + O(1)m|∆λm | Pv k v=1 = O(1) m−1 X 2 vXv |∆ λv | + O(1) as Xv |∆λv+1 | + O(1)m|∆λm |Xm v=1 v=1 = O(1) m−1 X m → ∞, by virtue of the hypotheses of the theorem and lemma. Finally, using the fact Pn = O(npn ), by (11), as in Tn,1 , we have that k m+1 m+1 n−1 X X X 1 ϕnk−1 ϕnk−1 |Tn,4 |k = ân,v+1 λv+1 tv v n=2 n=2 v=1 Unauthenticated Download Date | 7/28/17 7:18 PM 7 A NEW APPLICATION OF ALMOST INCREASING SEQUENCES = O(1) m+1 X ϕnk−1 v=1 n=2 = O(1) m+1 X n−1 X ϕnk−1 n=2 m+1 X n−1 X v=1 1 |ân,v+1 ||λv+1 |k |tv |k v ! × 1 |ân,v+1 ||λv+1 |k |tv |k v ! × 159 !k−1 1 |ân,v+1 | v v=1 !k−1 n−1 X |∆v ânv | n−1 X v=1 ! n−1 ϕn pn k−1 X 1 = O(1) |ân,v+1 ||λv+1 |k |tv |k Pn v n=2 v=1 m m+1 X1 X ϕn pn k−1 k−1 k = O(1) |ân,v+1 | |λv+1 | |λv+1 ||tv | v Pn v=1 n=v+1 k−1 m+1 m X X 1 k ϕv pv |ân,v+1 | |λv+1 ||tv | = O(1) v Pv n=v+1 v=1 m X 1 ϕv pv k−1 = O(1) |λv+1 ||tv |k v Pv v=1 k m X pv Pv k k−1 |λv+1 ||tv | ϕv = O(1) vp P v v v=1 m k X pv |λv+1 ||tv |k ϕvk−1 = O(1) P v v=1 = O(1) as m → ∞, by virtue of the hypotheses of the theorem and lemma. This completes the proof of the theorem. Corollary 1. If we take ϕn = |A, pn |k summability. Corollary 2. If we take anv = with |N̄ , pn , ϕn |k summability. Pn pn , pv Pn , then we get a result concerning the then we have another a result dealing Corollary 3. If we take anv = Ppvn and pn = 1 for all values of n, then we get a result dealing with |C, 1, ϕn |k summability. Corollary 4. If we take ϕn = n, anv = Ppvn and pn = 1 for all values of n, then we get a result for |C, 1|k summability. Unauthenticated Download Date | 7/28/17 7:18 PM 160 8 H.S. ÖZARSLAN and A. KETEN Corollary 5. If we take k = 1 and anv = Ppvn , then we get a result for |N̄ , pn | summability and in this case the condition ”( ϕPnnpn ) is a nonincreasing sequence” is not needed. REFERENCES 1. Bari, N.K.; Stečkin, S.B. – Best approximations and differential properties of two conjugate functions, (Russian) Trudy Moskov. Mat. Obšč., 5 (1956), 483–522. 2. Bor, H. – On two summability methods, Math. Proc. Cambridge Philos. Soc., 97 (1985), 147–149. 3. Bor, H. – On absolute summability factors, Proc. Amer. Math. Soc., 118 (1993), 71–75. 4. Flett, T.M. – On an extension of absolute summability and some theorems of Littlewood and Paley, Proc. London Math. Soc., 7 (1957), 113–141. 5. Hardy, G.H. – Divergent Series, Oxford, at the Clarendon Press, 1949. 6. Mazhar, S.M. – Absolute summability factors of infinite series, Kyungpook Math. J., 39 (1999), 67–73. 7. Sulaiman, W.T. – Inclusion theorems for absolute matrix summability methods of an infinite series. IV, Indian J. Pure Appl. Math., 34 (2003), 1547–1557. Received: 27.III.2012 Revised: 6.VII.2012 Accepted: 13.VII.2012 Department of Mathematics, Erciyes University, 38039, Kayseri, TURKEY [email protected] [email protected] Unauthenticated Download Date | 7/28/17 7:18 PM
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