Sudoku Puzzle β Precalculus Topics Name:______________________________Per_____ Adapted from a puzzle by David Pleacher Solve the 35 multiple-choice problems below. The choices are integers from 1 to 9 inclusive. Place the answer in the corresponding cell (labeled A, B, C, β¦ Y, Z, a, b,β¦h, i). Then solve the resulting SUDOKU puzzle. The rules of Sudoku are simple. Enter digits from 1 to 9 into the blank spaces. Every row must contain one of each digit. So must every column, and so must every 3x3 square. Each Sudoku has a unique solution that can be reached logically without guessing. 3 4 _______A. If cos π = β 5 and tan π = β 3 then sin π = 3 3 (1)4 4 (2) β 4 4 (3) 5 (4) β 5 _______B. Which of the following is correct? (1) π‘ππ2 π₯ = π ππ 2 π₯ + 1 (2) π ππ2 π₯ = πππ 2 π₯ β 1 (3)π‘ππ2 π₯ = ππ π 2 π₯ + 1 (4) π‘ππ2 π₯ = π ππ 2 π₯ β 1 _______C. The inverse function of π¦ = 3π₯ + 12 (1) π¦ = π₯β12 (2) π¦ = 3 (3)π¦ = 3π₯ β 12 π₯+12 3 (4) π¦ = β3π₯ β 12 _______D. The inverse secant of β2 is (6)β60° (7) 30° (8) 60° (9) 120° _______E. Use the graph to solve the inequality π(π₯) β€ 0. Write the answer in interval notation. (5) π₯ β (ββ, β3) βͺ (1, 5) (6) π₯ β (β3, 1) βͺ (5, β) (7) π₯ β [β3, 1] βͺ [5, β) (8) π₯ β (ββ, β3] βͺ [1, 5] _______F. Choose the correct right-hand side to make the equation an identity. 1 β sin π₯ = 1 + sin π₯ (4) (sec π₯ β cot π₯)2 (5) (sec π₯ β tan π₯)2 (6) (sec π₯ + cot π₯)2 (7) (sec π₯ + tan π₯)2 _______G. Which of the following statements is true? π΄ (1) πππ (π΅) = πππ(π΄) β πππ(π΅) π΄ log π΄ (2) πππ (π΅) = log π΅ (3) log(π΄ β π΅) = log(π΄) β log(π΅) π΄ (4) log(π΄ β π΅) = log (π΅) _______H. Simplify the expression without using a calculator. 4π π ππβ1 [cos ( )] 3 (4) 5π 3 π (5) β 3 (6) 2π 3 π (7) β 6 _______I. The range of π¦ = π ππβ1 π₯ is π π (4) [0, π] (5) [β 4 , 4 ] π π π 5π (6) [β 2 , 2 ] (7) [2, 4 ] _______J. Which of the following is a graph of π¦ = 2π₯+2 (6) (7) (8) (9) _______K. If π(π₯) = 3π₯ + 1 and π(π₯) = βπ₯, determine π(π(5)) (1) 3β5 + 1 (2) 4 (3) 16 (4) β5 _______L. If the graph of π¦ = 2βπ₯ β 1 is reflected in the x-axis, then an equation of the reflection is (1) π¦ = 2π₯ β 1 (4) π¦ = πππ2 (π₯ + 1) (2) π¦ = β2π₯ + 1 (3) π¦ = β2βπ₯ + 1 (5) π¦ = πππ2 (1 β π₯) _______M. What is the domain of the function in interval notation. π(π₯) = (3) [β2, 2] (4) (ββ, 3) βͺ (3, β) (6) (ββ, β2] βͺ [2, 3) βͺ (3, β) βπ₯ 2 β4 π₯β3 (5) (ββ, 2] βͺ [2, β) (7) [2, 3) βͺ (3, β) 1 _______N. Find the value of cos π, given π (β 6 , β with π in standard position. 1 (5) β 3 (6) β3 (7) β β2 ) is 3 on the terminal side of angle π, 2β2 3 3 (8) β 2β2 _______O. Determine the solution of log 5 π₯ + log 5 (π₯ + 4) = 1 (1) π₯ = 1 and π₯ = β5 (2) π₯ = β2 ± β3 (3) π₯ = 1 and π₯ = β5 is extraneous (4) π₯ = β5 _______P. Determine the constant π if π₯ β 3 is a linear factor of 3π₯ 3 β 9π₯ 2 + ππ₯ β 12 (1) π = 3 (2) π = 4 (3) π = 5 (4) π = 6 _______Q. Find the equation of all lines parallel to 5π₯ β 3π¦ + 4 = 0 (6) 5π₯ + 3π¦ + π = 0 (7) 3π₯ β 5π¦ + π = 0 (8) 5π₯ β 3π¦ + π = 0 (9) 3π₯ + 5π¦ + π = 0 _______R. Determine the domain of π(π₯) = log β16 β π₯ 2 (1) π₯ β [β4, 4] (2) π₯ β (ββ, β4) βͺ ( 4, β) (3) π₯ β (ββ, +β) (4) π₯ β (β4, 4) ______S. Determine the solution of log(βπ₯ β 1) = log(5π₯) + log(π₯) (6) π₯ = 1±2β5 (7) π₯ = 10 _______T. If π(π₯) = π₯ π₯β1 π₯ βπ₯ (6) 1βπ₯ (7) 1βπ₯ 1±β21 10 1 (8) π₯ = 5 and π₯ = β1 (9) No solution and π(π₯) = 1 β π₯ then π(π(π₯)) = 1 (8) π₯ (9) π₯β1 π₯ _______U. Determine the solution of log 3 ( π₯ β 4) + log 3 ( 7) = 2 (1) π₯ = 37 7 (2) π₯ = β19 7 (3) π₯ = 67 (4) π₯ = 13 7 β2 _______V. Simplify the expression without using a calculator: csc[sinβ1 ( 2 )] (1) β β2 2 (2) β 1 β3 2 (3) 2 (4) β2 2 (5) β2 _______W. The inverse function for π¦ = 2π₯ β 5 is 1 (3) π¦ = β2π₯ + 5 (5) π¦ = (4)π¦ = 2π₯β5 π₯+5 (6)π¦ = 2 π₯β5 2 _______X. Complete the square of the following to write in standard form. What is the length of the major axis? 4π₯ 2 + 9π¦ 2 β 16π₯ + 18π¦ β 11 = 0 (1) 10 (2) 2 (3) 4 (4) 6 _______Y. Solve the triangle. Find sides to the nearest tenth. π = 16π, π΄ = 37° , π΅ = 44° (1) πΆ = 99° , π β 17.8π, π β 25.7π (2) πΆ = 99° , π β 18.3π, π β 26.7π (3) πΆ = 99° , π β 18.5π, π β 26.3π (4)πΆ = 99° , π β 19.0π, π β 26.1π _______Z. Which of the following equations has a graph that is symmetric with respect to the origin? (5) π¦ = π₯β1 (6) π¦ = 2π₯ 4 + 1 π₯ π₯ (8) π¦ = π₯ 3 +1 (7) π¦ = π₯ 3 + 2 (9) π¦ = π₯ 3 + 2 _______a. A pilot wishes to fly from Pleasant Hills to Sheldon. She calculates the distances shown using a map, with York for reference since it is due east from Pleasant Hills. What is the measure of angle P? S Sheldon 852 miles 105 miles Y Pleasant Hills York P 784 miles (1) 4.7° (2) 5.6° (3) 6.8° (4) 7.5° _______b. Which of the following equations has a graph that is symmetric with respect to the y-axis? (5) π¦ = π₯β1 (6) π¦ = π₯ 3 + 2π₯ π₯ (7) π¦ = 2π₯ 4 + 1 π₯ (8) π¦ = π₯ 3 + 2 (9) π¦ = π₯ 3 +1 ________c. Solve using an appropriate method. ln(π₯ + 3) + ln 10 = 2 (4) π₯ = π 2 β 13 (5) π₯ = ln 2 β 13 (6) π₯ = π 2 β30 10 (7) π₯ = ln 2β30 10 _______d. Solve the exponential equation. 27π₯+2 = 3 5 2 (5)3 2 (6) 3 5 (7)β 3 (8) β 3 _______e. The range of π¦ = πππ β1 π₯ is π π π (1) [0, 2 ] (2) [β 2, , 2 ] π 3π (3) [ 2 , 2 ] (4) [0, π] 5π₯+1 _______f. The domain of π¦ = π₯ 2 β2π₯ is 1 1 (6) π₯ β (ββ, β 5) βͺ (β 5 , β) (7) π₯ β (2, β) 1 (8) π₯ β (β 5 , β) (9) π₯ β (ββ, 0) βͺ (0, 2) βͺ (2, β) _______g. Convert 75° to radians π (1) 12 _______h. Convert (1) 29° (2) 2π 9 2π 5 (3) 3π 5 5π (4) 12 to degrees. (2) 33° (3) 40° (4) 50° _______i. (β (5) β 4β5 5 β5 β11 , 4 ) is 4 a point on the unit circle corresponding to angle π‘. Find sin π‘. (6) 4β11 11 (7)β β5 4 (8) β11 4 Here is a blank Sudoku for you to use.
© Copyright 2026 Paperzz