February Break Extra Credit 2015-16 Assessment ID: ib.577576 Directions: Answer the following question(s). 1 Select the statement that is true for the graphs of all functions g(x). 3 A. The graph of g(x + 1) is the graph of g(x) shifted up 1 unit. B. The graph of g(x + 1) is the graph of g(x) shifted right 1 unit. C. The graph of g(–x) is the graph of g(x) reflected over the x–axis. D. The graph of g(–x) is the graph of g(x) reflected over the y–axis. A student claims that a negative x–coordinate will always result in a negative tanθ when θ is the angle formed by the x–axis and the line that connects the origin to the point. What information would disprove the student's claim? Select two choices. A. If point A is located at (–4, –4), then tanθ equals –1. B. If point A is located at (–3, 5), then tanθ equals –5/3. C. If point A is located at (4, 5), then tanθ equals 4/5. 2 A student claims that sin2θ + cos2θ = 1 can only be written one other way. First, decide if the student is correct. Next, justify your decision by either providing examples that support or disprove the student's claim. Select two choices. D. If point A is located at (–4, –7), then tanθ equals 7/4. E. If point A is located at (4, 8), then tanθ equals 2. F. If point A is located at (–3, –3), then tanθ equals 1. A. The student is correct. The identity can only be rewritten as sin2θ = 1 – cos2θ. 4 B. The student is correct. The identity can only be rewritten as cos2θ = 1 – sin2θ. C. The student is correct. The identity can only be rewritten as cos2θ = 1 – cos2θ. D. The student is incorrect. The identity can also be rewritten as sin2θ = 1 – cos2θ and cos2θ = 1 – sin2θ. E. The student is incorrect. The identity can also be rewritten as sin2θ = 1 – cos2θ and sin2θ = 1 – sin2θ. F. The student is incorrect. The identity can also be rewritten as cos2θ = 1 – sin2θ and cos2θ = –1 + sin2θ. A student claims that they can use rules about the coordinates of point A to tell whether the cosine of the angle formed by the x–axis and the line that connects the origin to point A will equal a positive or a negative value. What information would support the student's claim? Select two choices. A. If the x– and y–coordinates are negative, the cosine will equal a positive value. B. If the x– and y–coordinates are negative, the cosine will equal a negative value. C. If the x–coordinate is negative, the cosine will equal a negative value. D. If the y–coordinate is positive, the cosine will equal a positive value. E. If the x–coordinate is in Quadrant I, the cosine will equal a negative number. F. Illuminate Itembank™ Generated On February 11, 2016, 1:32 PM PST If the x–coordinate is in Quadrant II, the cosine will equal a positive number. Continue: Turn to the next page. Page 1 February Break Extra Credit 2015-16 Assessment ID: ib.577576 Directions: Answer the following question(s). 5 On a circle, a line is drawn from the origin to A(5, 12). The angle θ is between the line and the x–axis. A student argues that the Pythagorean Theorem can be used to find cosθ. Identify the strategy that supports the student's argument. A. Use a ruler to determine the length of the hypotenuse. B. Use the squares of 5 and 12 to find the length of the hypotenuse. 6 The length of an arc on a circle is π inches. 3 Alyssa contends that this means that the measure of the central angle on the circle will also be 2 π radians for every circle. Test 3 Alyssa's conjecture by selecting two choices that are true. A. A circle with a radius of 1 inch and a central C. Use a trigonometric formula to determine the length of the hypotenuse. 2 angle of 2 3 D. Use the arc to calculate the hypotenuse. of 2 3 π radians forms an arc with a length π inches. B. A circle with a radius of 1 inch and a central angle of 2 3 of 4 3 π radians forms an arc with a length π inches. C. A circle with a radius of 2 inches and a central angle of 2 3 of 2 3 π radians forms an arc with a length π inches. D. A circle with a radius of 2 inches and a central angle of 2 3 of 4 3 Illuminate Itembank™ Generated On February 11, 2016, 1:32 PM PST π radians forms an arc with a length π inches. Continue: Turn to the next page. Page 2 Assessment ID: February Break Extra Credit 2015-16 ib.577576 Directions: Answer the following question(s). 7 Kyle is working in the lab using sound waves and finding the models to describe the sound waves. He neglected to find the model of the sound wave shown below. ƒ(x) = 3cos 8 ( ) 2π x ƒ(x) = 4sin(πx) 3 Which of the following options correctly graphs the function of the radio station's radio signal? Which graph of the sound wave correctly matches the equation above? A. A student studying radio signals decided to focus in on a certain radio station to determine the graph of the radio signals used. The student determined that the radio station uses the following function for its radio signals. A. B. B. C. C. Illuminate Itembank™ D. Generated On February 11, 2016, 1:32 PM PST Continue: Turn to the next page. Page 3 February Break Extra Credit 2015-16 Assessment ID: ib.577576 Directions: Answer the following question(s). 9 A. B. C. D. Which of the following values for x are solutions to the equation x2 – 2x = –10? Select two that apply. 12 A. B. C. D. E. 0 1 + 3i 1 – 3i 1 + √ 10i E. 1 – √ 10i 10 13 The table below shows points that are on the graph of the function h(x). x 3 5 Lorelai claims that (x + 3) is a factor of p(x) = x4 + 5x3 + x2 – 11x + 12. Which of the following methods could she use to prove her claim? Select three that apply. is a polynomial C. show that p(x) = (x + 3) · q(x) for some polynomial q(x) (1, –1) D. show that the remainder when p(x) is divided by (2, 0) (x + 3) is 0 (3, 11) (4, 10) 14 (5, 1) Maggie claims that the function g(x) = x –4 is the inverse of the function of ƒ(x) = 3x + 4. Which statement provides a correct analysis of Maggie's claim? Maggie's claim is correct because if you add 4 to g(x) and then multiply it by 3 you get ƒ(x). B. Maggie's claim is correct because when g(x) is substituted into every occurrence of x in ƒ(x), ƒ(g(x)) = x, and when ƒ(x) is substituted into every occurrence of x in g(x), g(ƒ(x)) = x. C. 0 x+3 3 A. –3 show that the quotient of Select all of the points that are on the graph of the inverse function h–1(x). 11 –5 A. show that the value of p(3) is 0 B. p(x) 0 1 2 3 4 5 h(x) 2 5 8 11 14 17 A. B. C. D. E. Which of the following values are zeros of x(x + 5)(x – 3)? Select three that apply. Maggie's claim is incorrect because when g(x) is substituted into every occurrence of x in ƒ(x), ƒ(g(x)) = x – 8; therefore, g(x) is not the inverse of ƒ(x). D. Maggie's claim is incorrect because when g(x) is substituted into every occurrence of x in ƒ(x), ƒ(g(x)) = x; therefore, g(x) is not the inverse of ƒ(x). Illuminate Itembank™ Generated On February 11, 2016, 1:32 PM PST A. B. C. D. E. F. 15 A. B. C. D. Tarik claims that the function ƒ(x) = 5x5 – 15x4 – 45x3+ 85x2 + 90x – 120 has no zeros for 0 ≤ x ≤ 5. Based on the factorization of ƒ(x), which values of x could be used to refute Tarik's claim? Select two that apply. 0 1 2 3 4 5 Which expression is equal to (6i – 5) – (2 – 3i)? –3 + 3i –7 + 3i –3 + 9i –7 + 9i Continue: Turn to the next page. Page 4 February Break Extra Credit 2015-16 Assessment ID: ib.577576 Directions: Answer the following question(s). 16 A student claims that the function ƒ(x) = 6x4 + 4x2 – 3 is an even function. Is the student correct? 20 A. – A. The student is correct because when ƒ(x) is changed into ƒ(–x), it results in the same function, ƒ(x) = 6x4 + 4x2 – 3. ƒ(x) = + 4x2 – 3 is an odd function. B. 17 A. B. C. D. C. 18 4i2 4 – 4i 4i – 4i What is the simplified form of –3 √ –8 ? A. 6i B. 12i C. –6i √ 2 D. What is the product of (2 – 3i) (6 + 4i)? A. B. 10i C. –10i D. 24 – 10i 24 21 A. B. C. D. 22 A. B. C. D. 23 A. B. C. D. E. Illuminate Itembank™ Generated On February 11, 2016, 1:32 PM PST –6 ± √ 46 4 D. –12i √ 2 19 –6 ± i √ 34 4 Select each quantity that represents an imaginary number. 4i –3 ± √ 19 2 D. The student is not correct because ƒ(x) = 6x4 + 4x2 – 3 is neither an odd nor even function. 3±i 2 B. The student is correct only when x > 0. C. The student is not correct because 6x4 What is the value of x in the equation 2x2 + 6x = –5? What is the simplified form of (–7 + 8i) – (–5i + 4i2)? –11 + 3i –11 + 13i –3 + 3i –3 + 13i Serena claims that (x + 3) is a factor of p(x) = x4 + 6x3 + 12x2 + 10x + 3. Which equation must Serena show to be true in order to prove her claim? p(0) = 3 p(3) = 0 p(0) = –3 p(–3) = 0 Evan claims that three of the polynomials below have a remainder of 0 when divided by x + 4. Select each polynomial that supports Evan's claim. p(x) = x3 – 12x + 16 p(x) = x3 – 5x2 + 8x – 4 p(x) = x3 – 7x2 + 14x – 8 p(x) = x3 + 3x2 – 10x – 24 p(x) = x3 + 12x2 + 48x + 64 Continue: Turn to the next page. Page 5 February Break Extra Credit 2015-16 Assessment ID: ib.577576 Directions: Answer the following question(s). 24 A. B. C. D. E. F. The graph of a function, ƒ(x), is plotted on the coordinate plane. Select two of the following functions that would move the graph of the function to the right on the coordinate plane. ƒ(x + 6) ƒ(x) + 4 ƒ(x – 3) + 1 ƒ(x) – 3 ƒ(x – 5) 27 A. B. C. D. (a + b)(a2 – ab + b2) (a – b)(a2 + ab + b2) (a – b)(a2 – ab + b2) (a – b)(a2 – ab – b2) ƒ(x + 2) – 7 28 25 Wyatt is asked to prove the polynomial identity a3 – b3. Which of the following expressions is the equivalent form of this identity? Which statement is true for all functions f(x)? A. The graph of –f(x) is the graph of f(x) reflected over the x–axis. B. The graph of –f(x) is the graph of f(x) reflected over the y–axis. C. The graph of f(kx) is the graph of f(x) shifted left A. B. C. D. The polynomial identity (a – b)2 can be expanded into which of the following expressions? a2 – b2 a2 – ab + b2 a2 – 2ab – b2 a2 – 2ab + b2 or right by k units. D. The graph of f(x) + k is the graph of f(x) shifted left or right by k units. 26 James is working with the equation ax2 + bx + c = 0. Which of the following will James be able to prove is the solution for x? A. 29 A. B. C. D. It can be proven that the expression (a + b)(a2 – ab + b2) is equivalent to which of the following polynomial identities? (a + b)3 (a – b)3 a3 + b3 a3 – b3 B. 30 C. D. Illuminate Itembank™ Generated On February 11, 2016, 1:32 PM PST A. B. C. D. Factor the polynomial f(x) = x2 – x – 6 to determine the zeros of the function. (–1, 0) and (6, 0) (1, 0) and (–6, 0) (–3, 0) and (2, 0) (3, 0) and (–2, 0) Continue: Turn to the next page. Page 6 February Break Extra Credit 2015-16 Assessment ID: ib.577576 Directions: Answer the following question(s). 31 Adam graphed a polynomial with zeros at x = –1, x = 2 and x = 5. Which of the following graphs did he draw? A. C. B. D. 32 A. B. C. D. Find the remainder of (3x4 – 2x3 + x2 – 5x + 8) ÷ (x + 2) by using the Remainder Theorem. –18 4 34 86 Illuminate Itembank™ Generated On February 11, 2016, 1:32 PM PST Continue: Turn to the next page. Page 7 February Break Extra Credit 2015-16 Assessment ID: ib.577576 Directions: Answer the following question(s). 33 A. B. C. D. Identify the zeros of the graphed polynomial. (0, –5) (0, 5) 35 A. B. C. D. Which of these polynomial functions is graphed below? y = x3 – 8 y = x3 – 2 y = x3 + 2 y = x3 + 8 (–5, 0) and (1, 0) (5, 0) and (–1, 0) 36 Perform the operation. (5x4 + 3x2 + 8) ÷ (x2 + 2x – 1) 34 Which of these polynomial functions is graphed below? A. B. C. D. A. B. C. D. 5x2 – 10x + 28 + 5x2 – 7 + –66x + 36 x2 + 2x – 1 27x – 7 x2 + 2x – 1 5x2 + 10x + 18 + 5x3 + 5x2 + 8x + 26 – 10 x2 + 2x – 1 16 x2 + 2x – 1 y = –x2 + 2x – 1 y = –x2 + 1 y = x2 – 2x + 1 y = x2 – 1 Illuminate Itembank™ Generated On February 11, 2016, 1:32 PM PST Continue: Turn to the next page. Page 8 February Break Extra Credit 2015-16 Assessment ID: ib.577576 Directions: Answer the following question(s). 37 A. Which statement below can only be true if the functions, ƒ(x) and g(x), are inverses of each other? f–1(x) = 1 f(x) 1 and g–1(x) = g(x) B. ƒ(g(x)) = x and g(ƒ(x)) = x C. ƒ(ƒ(x)) = x and g(g(x)) = x D. ƒ(g(x)) = g(ƒ(x)) 38 Each of the four graphs below represents a function. Which function has an inverse that is also a function? A. C. B. D. Illuminate Itembank™ Generated On February 11, 2016, 1:32 PM PST Continue: Turn to the next page. Page 9 February Break Extra Credit 2015-16 Assessment ID: ib.577576 Directions: Answer the following question(s). 39 If i = √ –1 , which graph below shows –4 + 2i correctly on the plane at Point Z? A. C. B. D. 40 A. B. C. D. Use the table below to evaluate i49: –1 1 -i i Illuminate Itembank™ Generated On February 11, 2016, 1:32 PM PST Stop: You have finished the assessment. Page 10
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