Hooke’s Law
Maram AlDukhayyil
ID# 201001719
Group members:
Maram Al-Dukhayyil
Fatima Al-Mubarak
Sara Al-Towaijri
Haifa Al-Humayyed
Rawan Al-Askar
Section: 214
Submission date: 17-10-2012
PHYS 1411: Introductory Physics Lab
Lab Instructor: Nouf Al-Jalaud
Prince Mohammad Bin Fahd University
Fall 2012-2013
1. Abstract (Objective)
Hooke’s Law F= k .x was proved in this experiment by doing many steps. Mainly,
by finding the spring constant (k), which is basically the relation between the force
hanged on the spring and the distance of the stretched spring (x).
2. Theory
The theory behind this experiment is mainly Hooke’s Law (F= k .x) . It is the only
mathematical formulas used where:
1. F = the force being used to stretch the spring
2. K = the spring constant which was 11.5
3. X = the distance by which the spring is stretched from its original position
3. Method
The experiment was based on specific procedure. We used a long rod with an attached
hanger and a sturdy base, a spring scale, a slotted mass, a 50cm ruler, a mass hanger
and a spring. First, we found the force of the spring not including the mass and the
force including the mass. Then we subtracted them from each other which gave us the
value of F. After that, we measured the length using the ruler without the mass L0
and with the mass L1. The we subtracted L0 from L1 to find the value of x. Finally,
we calculated the value of K by dividing F on x (Hooke’s Law). We repeated this
method for four trials.
4. Data
Force on the spring (N)
L0 (m)
L1 (m)
x = L1 – L0
K=F÷Δx
1
1 - .8 - .2
11.5
13
1.5
0.13
2
1.1 - .8 = .3
11.5
13.2
1.7
0.24
3
1.2 - .8 = .4
11.5
13.3
1.8
0.22
4
1.4 - .8 = .6
11.5
14.4
2.9
0.2
Trials
4. Data Analysis (Results Discussion)
2
0.7
y = 0.258x - 0.136
0.6
0.5
0.4
0.3
0.2
0.1
0
0
0.5
1
1.5
2
2.5
3
3.5
After Your corrections :
3.50
3.00
2.90
2.50
2.00
1.50
Series1
1.80
1.70
1.50
Linear (Series1)
1.00
0.50
0.00
0.20
0.30
0.40
0.60
1. Approximate value = 3.514 which is the slop that we found from the graph.
2. Exact value = 0.2 (average value of K = ∑ K/n = 0.79/4 = 0.2)
3. Percentage error = Approximate value – Exact value x 100%
Exact value
PE = 0.258 – 0.2 x 100% = 29
0.2
6. Conclusion
Our main result in this experiment is finding out that the relationship between F and X
is inversely proportional, while it is directly proportional between F and K based on
Hooke’s Law. While doing this report, I learned how to use the Excel and how to
graph my results effectively leading to the best results in finding the percentage error.
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