page.1 Game Theory Extensive Form Games: Applications Levent Koçkesen Koç University Levent Koçkesen (Koç University) Extensive Form Games: Applications 1 / 23 page.2 A Simple Game You have 10 TL to share A makes an offer ◮ x for me and 10 − x for you If B accepts ◮ A’s offer is implemented If B rejects ◮ Both get zero Half the class will play A (proposer) and half B (responder) ◮ ◮ Proposers should write how much they offer to give responders I will distribute them randomly to responders ⋆ They should write Yes or No Click here for the EXCEL file Levent Koçkesen (Koç University) Extensive Form Games: Applications 2 / 23 page.3 Ultimatum Bargaining A Two players, A and B, bargain over a cake of size 1 x Player A makes an offer x ∈ [0, 1] to player B If player B accepts the offer (Y ), agreement is reached ◮ ◮ B Y A receives x B receives 1 − x If player B rejects the offer (N ) both receive zero Levent Koçkesen (Koç University) x, 1 − x Extensive Form Games: Applications N 0, 0 3 / 23 page.4 Subgame Perfect Equilibrium of Ultimatum Bargaining We can use backward induction B’s optimal action ◮ ◮ x < 1 → accept x = 1 → accept or reject 1. Suppose in equilibrium B accepts any offer x ∈ [0, 1] ◮ ◮ What is the optimal offer by A? x = 1 The following is a SPE x∗ = 1 s∗B (x) = Y for all x ∈ [0, 1] 2. Now suppose that B accepts if and only if x < 1 ◮ What is A’s optimal offer? ⋆ ⋆ x = 1? x < 1? Unique SPE x∗ = 1, s∗B (x) = Y for all x ∈ [0, 1] Levent Koçkesen (Koç University) Extensive Form Games: Applications 4 / 23 page.5 Bargaining Bargaining outcomes depend on many factors ◮ Social, historical, political, psychological, etc. Early economists thought the outcome to be indeterminate John Nash introduced a brilliant alternative approach ◮ Axiomatic approach: A solution to a bargaining problem must satisfy certain “reasonable” conditions ⋆ ◮ ◮ These are the axioms How would such a solution look like? This approach is also known as cooperative game theory Later non-cooperative game theory helped us identify critical strategic considerations Levent Koçkesen (Koç University) Extensive Form Games: Applications 5 / 23 page.6 Bargaining Two individuals, A and B, are trying to share a cake of size 1 If A gets x and B gets y,utilities are uA (x) and uB (y) If they do not agree, A gets utility dA and B gets dB What is the most likely outcome? uB 1 dB dA Levent Koçkesen (Koç University) Extensive Form Games: Applications 1 uA 6 / 23 page.7 Bargaining Let’s simplify the problem uA (x) = x, and uB (x) = x dA = dB = 0 A and B are the same in every other respect What is the most likely outcome? uB 1 45◦ 0.5 (dA , dB ) Levent Koçkesen (Koç University) 0.5 Extensive Form Games: Applications 1 uA 7 / 23 page.8 Bargaining How about now? dA = 0.3, dB = 0.4 uB 1 45◦ 0.55 0.4 0.3 0.45 1 uA Let x be A’s share. Then Slope = 1 = 1 − x − 0.4 x − 0.3 or x = 0.45 So A gets 0.45 and B gets 0.55 Levent Koçkesen (Koç University) Extensive Form Games: Applications 8 / 23 page.9 Bargaining In general A gets 1 dA + (1 − dA − dB ) 2 B gets 1 dB + (1 − dA − dB ) 2 But why is this reasonable? Two answers: 1. Axiomatic: Nash Bargaining Solution 2. Non-cooperative: Alternating offers bargaining game Levent Koçkesen (Koç University) Extensive Form Games: Applications 9 / 23 page.10 Bargaining: Axiomatic Approach John Nash (1950): The Bargaining Problem, Econometrica 1. Efficiency ⋆ No waste 2. Symmetry ⋆ If bargaining problem is symmetric, shares must be equal 3. Scale Invariance ⋆ Outcome is invariant to linear changes in the payoff scale 4. Independence of Irrelevant Alternatives ⋆ If you remove alternatives that would not have been chosen, the solution does not change Levent Koçkesen (Koç University) Extensive Form Games: Applications 10 / 23 page.11 Nash Bargaining Solution What if parties have different bargaining powers? Remove symmetry axiom Then A gets xA = dA + α(1 − dA − dB ) B gets xB = dB + β(1 − dA − dB ) α, β > 0 and α + β = 1 represent bargaining powers If dA = dB = 0 xA = α Levent Koçkesen (Koç University) and xB = β Extensive Form Games: Applications 11 / 23 page.12 Alternating Offers Bargaining Two players, A and B, bargain over a cake of size 1 At time 0, A makes an offer xA ∈ [0, 1] to B ◮ ◮ If B accepts, A receives xA and B receives 1 − xA If B rejects, then at time 1, B makes a counteroffer xB ∈ [0, 1] ◮ ◮ If A accepts, B receives xB and A receives 1 − xB If A rejects, he makes another offer at time 2 This process continues indefinitely until a player accepts an offer If agreement is reached at time t on a partition that gives player i a share xi ◮ ◮ player i’s payoff is δit xi δi ∈ (0, 1) is player i’s discount factor If players never reach an agreement, then each player’s payoff is zero Levent Koçkesen (Koç University) Extensive Form Games: Applications 12 / 23 page.13 A xA B Y N B xA , 1 − xA xB A Y N A δA (1 − xB ), δB xB xA B Y N A 2 x , δ 2 (1 − x ) δA A B A Levent Koçkesen (Koç University) Extensive Form Games: Applications 13 / 23 page.14 Alternating Offers Bargaining Stationary No-delay Equilibrium A 1. No Delay: All equilibrium offers are accepted xA B 2. Stationarity: Equilibrium offers do not depend on time Y Let equilibrium offers be (x∗A , x∗B ) What does B expect to get if she rejects x∗A ? ◮ N B xA , 1 − xA xB δB x∗B A Therefore, we must have Y N A 1 − x∗A = δB x∗B δA (1 − xB ), δB xB xA B Similarly 1 − x∗B = δA x∗A Y N A 2 x , δ 2 (1 − x ) δA A B A Levent Koçkesen (Koç University) Extensive Form Games: Applications 14 / 23 page.15 Alternating Offers Bargaining There is a unique solution 1 − δB 1 − δA δB 1 − δA x∗B = 1 − δA δB x∗A = There is at most one stationary no-delay SPE Still have to verify there exists such an equilibrium The following strategy profile is a SPE Player A: Always offer x∗A , accept any xB with 1 − xB ≥ δA x∗A Player B: Always offer x∗B , accept any xA with 1 − xA ≥ δB x∗B Levent Koçkesen (Koç University) Extensive Form Games: Applications 15 / 23 page.16 Properties of the Equilibrium Bargaining Power Player A’s share πA = x∗A = 1 − δB 1 − δA δB Player B’s share πB = 1 − x∗A = δB (1 − δA ) 1 − δA δB Share of player i is increasing in δi and decreasing in δj Bargaining power comes from patience Example δA = 0.9, δB = 0.95 ⇒ πA = 0.35, πB = 0.65 Levent Koçkesen (Koç University) Extensive Form Games: Applications 16 / 23 page.17 Properties of the Equilibrium First mover advantage If players are equally patient: δA = δB = δ πA = δ 1 > = πB 1+δ 1+δ First mover advantage disappears as δ → 1 lim πi = lim πB = δ→1 Levent Koçkesen (Koç University) δ→1 1 2 Extensive Form Games: Applications 17 / 23 page.18 Capacity Commitment: Stackelberg Duopoly Remember Cournot Duopoly model? ◮ ◮ Two firms simultaneously choose output (or capacity) levels What happens if one of them moves first? ⋆ or can commit to a capacity level? The resulting model is known as Stackelberg oligopoly ◮ After the German economist Heinrich von Stackelberg in Marktform und Gleichgewicht (1934) The model is the same except that, now, Firm 1 moves first Profit function of each firm is given by ui (Q1 , Q2 ) = (a − b(Q1 + Q2 ))Qi − cQi Levent Koçkesen (Koç University) Extensive Form Games: Applications 18 / 23 page.19 Nash Equilibrium of Cournot Duopoly Best response correspondences: Q1 = a − c − bQ2 2b Q2 = a − c − bQ1 2b Nash equilibrium: (Qc1 , Qc2 ) = a−c a−c , 3b 3b In equilibrium each firm’s profit is π1c = π2c = Levent Koçkesen (Koç University) (a − c)2 9b Extensive Form Games: Applications 19 / 23 page.20 Cournot Best Response Functions Q2 a b a−c b a−c 2b a−c 3b B1 b B2 a−c a−c 3b 2b Levent Koçkesen (Koç University) a−c b Extensive Form Games: Applications a b Q1 20 / 23 page.21 Stackelberg Model The game has two stages: 1. Firm 1 chooses a capacity level Q1 ≥ 0 2. Firm 2 observes Firm 1’s choice and chooses a capacity Q2 ≥ 0 1 Q1 2 Q2 u1 , u2 ui (Q1 , Q2 ) = (a − b(Q1 + Q2 ))Qi − cQi Levent Koçkesen (Koç University) Extensive Form Games: Applications 21 / 23 page.22 Backward Induction Equilibrium of Stackelberg Game Sequential rationality of Firm 2 implies that for any Q1 it must play a best response: a − c − bQ1 Q2 (Q1 ) = 2b Firms 1’s problem is to choose Q1 to maximize: [a − b(Q1 + Q2 (Q1 ))]Q1 − cQ1 given that Firm 2 will best respond. Therefore, Firm 1 will choose Q1 to maximize [a − b(Q1 + a − c − bQ1 )]Q1 − cQ1 2b This is solved as Q1 = Levent Koçkesen (Koç University) a−c 2b Extensive Form Games: Applications 22 / 23 page.23 Backward Induction Equilibrium of Stackelberg Game Backward Induction Equilibrium a−c 2b a − c − bQ1 Qs2 (Q1 ) = 2b Qs1 = Backward Induction Outcome a−c a−c > = Qc1 2b 3b a−c a−c Qs2 = < = Qc2 4b 3b Equilibrium Profits Qs1 = (a − c)2 (a − c)2 > = π1c 8b 9b (a − c)2 (a − c)2 < = π2c π2s = 16b 9b π1s = Levent Koçkesen (Koç University) Firm 1 commits to an aggressive strategy There is first mover advantage Extensive Form Games: Applications 23 / 23
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