Lecture18.notebook
March 01, 2017
Lecture18.notebook
1. Represent the dividend (129).
2. Represent the divisor (4) with 4 sets.
3. Start with the flats. There are less than 4 flats, so trade.
4. Place the rods evenly among the 4 sets.
5. Place the cubes evenly among the 4 sets. There is 1 cube left.
6. Count the number of base ten blocks in each set to find the quotient.
(3 rods and 2 cubes).
Therefore, 129 ÷ 4 = 32 R1
March 01, 2017
Lecture18.notebook
March 01, 2017
1. Represent the dividend (135).
2. Remove sets of 23 (2 rods and 3 cubes) repeatedly until less than 23 remain (making trades when necessary).
3. Count how many sets of 23 we removed. (5­­The quotient)
4. Count the number of base ten blocks remaining (2 rods or 20­­­the remainder)
Therefore, 135 ÷ 23 = 5 R20
Lecture18.notebook
March 01, 2017
Use partitioning for smaller divisors (single digit) and repeated subtraction for larger divisors.
Lecture18.notebook
March 01, 2017
3754 ÷ 23 = 163 R5
Lecture18.notebook
March 01, 2017
B F R C 1 0 3
4867 ÷ 47 = 103 R26
1
1
1
1
4 7 4 8 6 7 4 7
1 6 7
4 7
1 2 0
4 7
7 3
4 7
2 6
Lecture18.notebook
March 01, 2017
1. Represent the dividend (135).
2. Represent the divisor (3) with 3 sets.
3. Start with the flats. There are less than 3 flats, so trade.
4. Place the rods evenly among the 3 sets.
5. Place the cubes evenly among the 3 sets. There are 2 cubes left.
6. Count the number of base ten blocks in each set to find the quotient.
(3 rods and 1 cubes).
Therefore, 135 ÷ 3 = 31 R2
Lecture18.notebook
March 01, 2017
1. Represent the dividend (135).
2. Remove sets of 23 (2 rods and 3 cubes) repeatedly until less than 23 remain (making trades when necessary).
3. Count how many sets of 23 we removed. (3­­The quotient)
4. Count the number of base ten blocks remaining (2 rods and 2 cubes or 22­­­the remainder)
Therefore, 135 ÷ 23 = 3 R22
Lecture18.notebook
March 01, 2017
Lecture18.notebook
March 01, 2017