Title Slide Models of algebraic concepts 1 Y2 X X2 Y XY PowerPoint Presentation Developed by Harvey Almarode Modified by Carrie Newman The Equation Mat The Equation Mat consists of two Basic Mats with an equal sign in between. + + = _ _ The Pieces X 1 The rectangular yellow pieces will represent the variable, or the number you don’t know yet. The small green cubes will represent one whole. If there are more than one, just count them up! The whole point of algebra is to get that yellow variable block all by itself on one side of the equal sign so you can find out its value! Anything in the top (white) part of your equation math means that it is positive, or that you are ADDING. + What does this say?! If you said “x+2” you were right! _ Anything in the bottom (gray) part of your equation math means that it is negative, or that you are SUBTRACTING. + _ What does this say?! If you said “x – 3” you were right! + _ If you ever have something that matches on the top (positive) and bottom (negative) of the mat, you will call it a “zero pair”. These things will cancel each other out because they are equal to ZERO! Don’t believe me? I’ll prove it! • Hold out your hand • Add (+)2 green cubes to your hand. • Now take away (-) 2 green cubes from your hand • You’re left with ZERO green cubes, aren’t you?! That’s why we call it a zero pair! • Just remember- you can only take away zero pairs on the SAME SIDE OF THE EQUAL SIGN! + X 1 1 1 1 + = 1 1 1 1 1 1 1 1 1 1 1 1 _ What equation is modeled on the Equation Mat? Answer: X + 4 = 12 _ X + + = 1 1 1 1 1 1 1 1 _ What equation is modeled on the Equation Mat? Answer: X-3 = 5 _ + 1 1 + 1 = 1 1 1 1 1 1 1 1 _ What equation is modeled on the Equation Mat? Answer: X+3 = 8 _ + X 1 1 1 1 1 = 1 1 1 1 1 1 1 1 1 1 _ Add Show 3the X to -the each 3 =Zero 7sidePair of the Equation Mat Remove Read results Answer: X = 10 + 1 _ You can check your answers by replacing your yellow “x” block with the number of green “1” cubes that you came up with in your answer. If you come up with the same amount of green cubes on each side of the equal sign, your equation is balanced and your answer is correct! Let’s try some now! + + X 1 1 1 1 = 1 1 1 1 1 _ Add Set 25the toXthe each – 2zero 3 pair of sure the equation mat the variable in Remove Let’s check to=side make by replacing Read X =up results the original equation (X – 2 = 3) with our answer of 5 _ + 1 X1 1 1 1 + 1 1 1 = 1 1 _ _ Set your original equation variable “X” with say? the value 5 Great job! 5 –Replace Now 2 =up 3! what Isthe that does true? yourThen equation your value of xyou wasfound, correct! 1 1 1 + 1 X 1 1 1 1 1 1 1 1 1 1 + 1 1 = 1 1 1 1 1 _ Check Read Let’s your try your results: answer! more Xtogether! Set =side. 5up theSet original up X +equation. 4 = 9 on your mat Subtract from each Get rid of4one your zero pairs _ 1 1 1 1 + 1 1 1 1 1 X 1 1 1 1 1 1 1 1 1 + = _ _ Now you have 9 = 9, is that true?! Your equation is balanced Now replace your variable with your answer. and your answer is correct! Extension: Can you set up and solve these problems on your mat? Sam has some baseball cards and his mom brings him 5 more. Now he has 7. How many did he begin with? + X 1 1 1 1 1 1 = 1 1 1 1 _ 1 1 1 1 1 1 1 1 1 1 1 1 + _ Let’s talk algorithms! When we talk about using the standard algorithm, we mean that we use numbers and operations to solve. It’s exactly what we’ve been doing with our blocks, but we will use inverse operations to solve. For example… Suzie had some apples and picked 3. Now she has 5 apples. What does that look like?! X+3=5 What Addition! do you see?! of addition?! Subtraction! What operation is the inverse operation 2X +X3+=35= 25 - 3 -3 • So let’s subtract 3 from both sides to get the variable by itself! • Now get rid of your zero pairs • +3 and -3 cancel and 5 – 3 = 2 Now to check, go back to your original equation… … and replace the variable with your answer to check! Let’s Practice! X–2=3 Draw a Picture: Show your steps: Solution: X–2=3 +2 +2 X=5 X=5 Check: 5–2=3 Write a word problem: Carrie had some balloons and 2 flew away. Now she has 3.
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