Applied Mathematic
(Preliminary General 1)
Range and IQR
With Stem-and-Leaf
Stage 6 - Year 11$
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1
Interquartile Range = Q3 – Q1
Stem
0
1
2
3
4
5
Leaf
1
2
3
First find median.
1 2 7
4
5
6
7
0 1 1 5
There are 27 scores.
28 29 310 511 712
Median = 14th score.
(The middle score.)
013 214 515 716 817 918
319 320 421 522 623
Median
=
32.
24 25 26 27
0 0 1 2
End of
Slide
2
Interquartile Range = Q3 – Q1
Stem
0
1
2
3
4
5
Leaf
1
1
4
0
28
13
0
3
0
2
3
2 7
7
5
6
1 1 5
29 310 511 712
214 5 7 8 9
3 4 5 6
0 1 2
Now find Q1.
There are 13 scores
in the lower half.
Q1 = 7th score.
(The middle score.)
Q1 = 15.
End of
Slide
3
Interquartile Range = Q3 – Q1
Stem
0
1
2
3
4
5
Leaf
Next find Q3.
1 2 7
7
0 1 1 5
There are 13 scores
in the upper half.
2 2 3 5 7
1
2 17
4
14 15
0 2 5 716
83 918
Q3 = (14+7)st score.
5
7
(The middle score.)
6 421
319 320
58 69
10 11 12
13
0 0 1 2
Q3
=
44.
st
21 score
End of
Slide
4
Interquartile Range = Q3 – Q1
Stem
0
1
2
3
4
5
Leaf
1
0
2
0
3
0
2 7
7
1 1 5
2 3 5 7
214 5 7 8 9
3 421 5 6
0 1 2
IQR = 44 - 15
= 29
Range = 52 - 1
= 51
End of
Slide
5
Interquartile Range = Q3 – Q1
Stem
0
1
2
3
4
5
Leaf
3
1
0
0
3
2
4
3
1
2
4
Median = (21+23)÷2
6 7 9 9
= 22
5
Q1 = 9
3 6
Q3 = 34
3 4 9
IQR = 34 - 9 = 25
5
Range = 52 - 3 = 49
End of
Show
6