Hindawi Publishing Corporation Mathematical Problems in Engineering Volume 2013, Article ID 504609, 7 pages http://dx.doi.org/10.1155/2013/504609 Research Article π-Metric Space: A Generalization Farshid Khojasteh,1 Erdal KarapJnar,2 and Stojan RadenoviT3 1 Department of Mathematics, Arak Branch, Islamic Azad University, Arak, Iran Department of Mathematics, Atilim University, IΜncek, 06836 Ankara, Turkey 3 Faculty of Mechanical Engineering, University of Belgrade, Kraljice Marije 16, 11120 Belgrade, Serbia 2 Correspondence should be addressed to Erdal KarapΔ±nar; [email protected] Received 27 May 2013; Accepted 25 July 2013 Academic Editor: Bashir Ahmad Copyright © 2013 Farshid Khojasteh et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We introduce the notion of π-metric as a generalization of a metric by replacing the triangle inequality with a more generalized inequality. We investigate the topology of the spaces induced by a π-metric and present some essential properties of it. Further, we give characterization of well-known fixed point theorems, such as the Banach and Caristi types in the context of such spaces. 1. Introduction Celebrated Banach contraction mapping principle [1] can be considered as a revolution in fixed point theory and hence in nonlinear functional analysis. The statement of this well-known principle is simple, but the consequences are so strong: every contraction mapping in a complete metric space has a unique fixed point. Since fixed point theory has been applied to different sciences and also distinct branches of mathematics, this pioneer result of Banach has been generalized, extended, and improved in various ways in several abstract spaces. After that, many authors stated many types, generalizations, and applications of fixed point theory until now (see also [2, 3]). In 1976, Caristi [4] defined an order relation in a metric space by using a functional under certain conditions and proved a fixed point theorem for such an ordered metric space. Denote R and N as the sets of all real and natural numbers, respectively. The order relation is defined as follows. Lemma 1. Let (π, π) be a metric space and π : π β R a functional. Define the relation ββͺ―β on π by π₯ βͺ― π¦ ββ π (π₯, π¦) β€ π (π₯) β π (π¦) . (1) Then, ββ€β is a partial order relation on π introduced by π, and (π, π) is called an ordered metric space introduced by π. Apparently, if π₯ βͺ― π¦, then π(π₯) βͺ° π(π¦). Caristiβs fixed point theorem states that a mapping π : π β π has a fixed point provided that (π, π) is a complete metric space and there exists a lower semicontinuous map π : π β R such that π (π₯, ππ₯) β€ π (π₯) β π (ππ₯) , for every π₯ β π. (2) This general fixed point theorem has found many applications in nonlinear analysis. Many authors generalized Caristiβs fixed point theorem and stated many types of it in complete metric spaces (see [5β8]). In particular, in 2010, Amini-Harandi [6] extended Caristiβs fixed point and Takahashiβs minimization theorems in complete metric space via the extension of partial ordered relation which is introduced in Lemma 1 and introduced some applications of such results. One of the interesting generalizations of the notion of a metric is the concept of a fuzzy metric, given by Kramosil and MichaΜlek [9], and Grabiec [10], independently. Later, George and Veeramani [11] investigated fuzzy metric structure and observed some important topological properties of such spaces. Furthermore, the authors [9β11] announced existence 2 Mathematical Problems in Engineering and uniqueness of a fixed point of certain mappings in the framework of such spaces. (π5 ) π(π‘, π ) = π‘ + π + π‘π , Definition 2 (see [11]). A binary operation β : [0, 1]×[0, 1] β [0, 1] is a continuous π‘-norm if it is a topological monoid with unit 1 such that π β π β€ π β π whenever π β€ π and π β€ π (π, π, π, π β [0, 1]). (π7 ) π(π‘, π ) = (π‘ + π )(1 + π‘π ). Definition 3 (see [9, 10]). The 3-tuple (π, π, β) is said to be a fuzzy metric space if π is an arbitrary set, β is a continuous π‘-norm, and π : π × π × [0, +β) β [0, 1] is a fuzzy set satisfying the following conditions: (1) π(π₯, π¦, 0) = 0, (2) π(π₯, π¦, π‘) = 1 for all π‘ > 0 if and only if π₯ = π¦, (3) π(π₯, π¦, π‘) = π(π¦, π₯, π‘), (π6 ) π(π‘, π ) = π‘ + π + βπ‘π , Example 5 shows that the category of π΅-actions is uncountable. Next, we derive some lemmas which play a crucial role in our main results. Lemma 6. Let { { { Ξ¨ ={ { {π : [0, +β) σ³¨β [0, +β) : { π ππ ππππ‘πππ’ππ’π , π π‘ππππ‘ππ¦ πππππππ πππ π (0) = 0 π (π‘) < π‘ βπ‘ > 0. } } } . } } } } (4) Then, there exists a correspondence between Ξ₯ and Ξ¨. In other words, Ξ₯ is an infinite set. (4) π(π₯, π¦, π‘) β π(π¦, π§, π‘) β€ π(π₯, π§, π‘ + π ), (5) π(π₯, π¦, β ) : [0, +β) β [0, 1] is left continuous, Proof. For each (π‘, π ) β [0, +β) × [0, +β), define ππ (π‘, π ) = ππ(π‘ + π ), where π β [0, 1) and π β Ξ¨. It is previous that ππ β Ξ₯. Now, define where π₯, π¦, π§ β π and π‘, π > 0. In this paper, inspired from the definition of fuzzy metric spaces, we will introduce π-metric as an extension of metric spaces which is obtained by replacing the triangle inequality with a more generalized inequality. We also investigate the topology of the π-metric space and observe some fundamental properties of it. Furthermore, we give the characterization of the Banach and Caristi type fixed point theorems in the context of π-metric space. First, we give the following definition. Definition 4. Let π : [0, +β) × [0, +β) β [0, +β) be a continuous mapping with respect to each variable. Let Im(π) = {π(π , π‘) : π β₯ 0, π‘ β₯ 0}. A mapping π is called an π΅-action if and only if it satisfies the following conditions: (I) π(0, 0) = 0 and π(π‘, π ) = π(π , π‘) for all π‘, π β₯ 0, π» : Ξ¨ σ³¨β Ξ₯ π» (π) = ππ . (5) π» is well-defined and injective function which completes the proof. Lemma 7. Let π be a π΅-action. For each π β Im(π) and π β π΅ = [0, π], there exist π‘ β [0, π] and a function π : [0, +β) × [0, +β) β [0, +β) such that π(π, π ) = π‘. Then, one derives the following. (π1 ) π(0, 0) = 0. (π2 ) π(π(π, π ), π ) = π and π(π, π(π , π)) = π . (π3 ) π is continuous with respect to the first variable. (II) (π4 ) If π(π, π ) β₯ 0, then 0 β€ π β€ π. π (π , π‘) < π (π’, V) either π < π’, π‘ β€ V, if { or π β€ π’, π‘ < V, (3) (III) for each π β Im(π) and for each π β [0, π], there exists π‘ β [0, π] such that π(π‘, π ) = π, (IV) π(π , 0) β€ π , for all π > 0. We denote by Ξ₯ the set of all π΅-actions. Example 5. The following functions are examples of π΅action: (π1 ) π(π‘, π ) = π(π‘ + π ), where π β (0, 1], (π2 ) π(π‘, π ) = π(π‘ + π + π‘π ), where π β (0, 1], (π3 ) π(π‘, π ) = π‘π /(1 + π‘π ), (π4 ) π(π , π‘) = βπ 2 + π‘2 , Proof. By (III) of Definition 4, for each π β Im(π) and for each π β [0, π], there exists π‘ β₯ 0 such that π(π‘, π ) = π. Now, define π(π, π ) = π‘. Let π‘ and π‘σΈ be two values such that π(π, π ) = π‘ and π(π, π ) = π‘σΈ . If π‘ =ΜΈ π‘σΈ , then π‘ < π‘σΈ or π‘ > π‘σΈ . If π‘ < π‘σΈ , then π = π(π‘, π ) < π(π‘σΈ , π ) = π and this is a contradiction. For π‘ > π‘σΈ , we have the same argument. Thus, π is well defined. On the other hand, (π1 ), (π2 ), and (π4 ) are straightforward from (III) of Definition 4. Also, (π3 ) holds since if π β Im(π) and {ππ } is a sequence in Im(π) such that ππ β π, then π(π(ππ , β ), β ) = ππ . Thus, π ( lim π (ππ , β ) , β ) = lim π (π (ππ , β ) , β ) πββ πββ (6) = π = π (π (π, β ) , β ) . If limπ β β π(ππ , β ) > π(π, β ) or limπ β β π(ππ , β ) < π(π, β ), then by (II) of Definition 4 and (6), we conclude a contradiction. So, π is continuous with respect to the first variable. Mathematical Problems in Engineering 3 The following definition arises from Lemma 7. Definition 8. The function π, mentioned in Lemma 7, is called π΅-inverse action of π. One says that π is regular if π satisfies π(π, π) = 0, for each π > 0. Ξ₯π . The set of all regular π΅-inverse actions will be denoted by Example 9. Let π1 (π‘, π ) = π‘ + π and π2 (π‘, π ) = βπ π‘π + π π . It is evident that π1 (π‘, π ) = π‘ β π and π(π‘, π ) = βπ π‘π β π π . Furthermore, π1 , π2 satisfy all the conditions of Lemma 7. Note that π1 , π2 are regular. Lemma 10. If π β π, π β Im(π) and π β [0, π], then π(π, π) β€ π implies that π β€ π(π, π). Example 13. Let π = {π₯, π¦, π§} and ππ : π × π β [0, +β) defined by ππ (π₯, π¦) = 2, ππ (π₯, π₯) = 0, ππ (π₯, π§) = 6, ππ (π¦, π¦) = 0, ππ (π₯, π¦) = ππ (π¦, π₯) , ππ (π§, π¦) = 10, ππ (π§, π§) = 0, ππ (π₯, π§) = ππ (π§, π₯) , (9) ππ (π§, π¦) = ππ (π§, π₯) . For π(π , π‘) = π + π‘ + π π‘, the function ππ forms a metric, and hence, the pair (π, ππ ) is a π-metric space. Remark 14. Notice that ππ , in Example 13, is not a metric on π, since we have ππ (π§, π¦) > ππ (π₯, π¦) + ππ (π₯, π§). Proof. Suppose, on the contrary, that π(π, π) < π. Then, we have Definition 15. Let (π, ππ ) be a π-metric space. An open ball π΅ππ (π₯, π) at a center π₯ β π with a radius π β Im(π) is defined as follows: π = π (π (π, π) , π) < π (π, π) , π΅ππ (π₯, π) = {π¦ β π : ππ (π₯, π¦) < π} . (7) (10) Lemma 16. Every open ball is an open set. a contradiction. Proof. We show that, for each π₯ β π and π > 0 and for each π¦ β π΅ππ (π₯, π), there exists πΏ > 0 such that 2. Main Results π΅ππ (π¦, πΏ) β π΅ππ (π₯, π) . (11) In this section, we introduce the notion π-metric and discuss the induced topology generated by ππ on a nonempty subset π. In particular, we will show that πππ is Hausdorff and first countable. Further, we derive that (π, ππ ) is a metrizable topological space. By (III) of Definition 4, we can choose πΏ > 0 such that π(πΏ, ππ (π₯, π¦)) = π. Now, if π§ β π΅ππ (π¦, πΏ), then we have Definition 11. Let π be a nonempty set. A mapping ππ : π × π β [0, +β) is called a π-metric on π with respect to π΅action π β Ξ₯ if ππ satisfies the following: It means that π§ β π΅ππ (π₯, π) and (11) is proved. (A1) ππ (π₯, π¦) = 0 if and only if π₯ = π¦, (A2) ππ (π₯, π¦) = ππ (π¦, π₯), for all π₯, π¦ β π, A pair (π, ππ ) is called a π-metric space. Remark 12. If (π, ππ ) is a π-metric space, π(π , π‘) = π(π + π‘), and π β (0, 1], then (π, ππ ) is a metric space. Conversely, for π(π , π‘) = π(π + π‘), π β (0, 1), we have that there exists metric space (π, π) which is not π-metric space. For example, if π = {1, 2, 3} and π : π × π β [0, +β) defined by π (1, 1) = 0, π (1, 3) = 1, π (2, 2) = 0, π (2, 3) = 2, π (3, 3) = 0, Lemma 17. If (π, ππ ) is a π-metric space, then the collection of open sets forms a topology, denoted by πππ . A pair (π, ππ ) is called topological space induced by a π-metric. Lemma 18. The set {π΅ππ (π₯, 1/π) : π β N} is a local base at π₯, and the above topology is first countable. (A3) ππ (π₯, π¦) β€ π(ππ (π₯, π§), ππ (π§, π¦)), for all π₯, π¦, π§ β π. π (1, 2) = 1, ππ (π§, π₯) β€ π (ππ (π§, π¦) , ππ (π¦, π₯)) < π (πΏ, ππ (π¦, π₯)) = π. (12) 1 π= , 2 Proof. For each π₯ β π and π > 0, we can find π0 β N such that 1/π0 < π. Thus, π΅ππ (π₯, 1/π) β π΅ππ (π₯, π). This means that {π΅ππ (π₯, 1/π) : π β N} is a local base at π₯ and the above topology is first countable. Theorem 19. A topological space (π, πππ ) is Hausdorff. Proof. Let π₯, π¦ be two distinct points of π. Suppose that 0 < πΌ < ππ (π₯, π¦) is arbitrary. By Definition 4, we conclude that πΌ β Im(π). Therefore, there exist π, π > 0 such that π(π, π ) = πΌ. It is clear that π΅ππ (π₯, π) β© π΅ππ (π₯, π ) = 0. For if there exists π§ β π΅ππ (π₯, π) β© π΅ππ (π₯, π ), then ππ (π₯, π¦) β€ π (ππ (π₯, π§) , ππ (π§, π¦)) (8) π is a metric, but π is not a π metric. < π (π, π ) = πΌ < ππ (π₯, π¦) , a contradiction. (13) 4 Mathematical Problems in Engineering Theorem 20. Let (π, ππ ) be a π-metric space and πππ the topology induced by the π-metric. Then, for a sequence {π₯π } in π, π₯π β π₯ if and only if ππ (π₯π , π₯) β 0 as π β β. Definition 24. Let (π, ππ ) be a π-metric space. One says that (π, ππ ) is complete π-metric space if every Cauchy sequence {π₯π } is convergent in π. Proof. Suppose that π₯π β π₯. Then, for each π > 0, there exists π0 β N such that π₯π β π΅ππ (π₯, π), for all π β₯ π0 . Thus, ππ (π₯π , π₯) < π; that is, ππ (π₯π , π₯) β 0 as π β β. The converse is verified easily. Lemma 25 (see [12]). A Hausdorff topological space (π, πππ ) is metrizable if and only if it admits a compatible uniformity with a countable base. Theorem 21. Let (π, ππ ) be a π-metric space and π₯π β π₯, π¦π β π¦.Then, ππ (π₯π , π¦π ) σ³¨β ππ (π₯, π¦) . (14) Proof. For each π β N, there exists πΎ > 0 such that, for all π β₯ πΎ, 1 ππ (π₯π , π₯) < , π 1 ππ (π¦π , π¦) < . π (15) Thus, by the continuity of π with respect to each variable, we have ππ (π₯, π¦) β€ π (ππ (π₯, π₯π ) , π (ππ (π₯π , π¦π ) , ππ (π¦π , π¦))) 1 1 < π ( , π (ππ (π₯π , π¦π ) , )) . π π (16) Theorem 26. Let (π, ππ ) be a π-metric space. Then, (π, πππ ) is a metrizable topological space. Proof. For each π β N, define 1 (19) }. π We will prove that {Uπ : π β N} is a base for a uniformity U on π whose induced topology coincides with πππ . We first note that for each π β N, Uπ = {(π₯, π¦) β π × π : ππ (π₯, π¦) < {(π₯, π₯) : π₯ β π} β Uπ , Uπ+1 β Uπ , Uπ = Uβ1 π . (20) On the other hand, for each π β N, there is, by the continuity of π, an π β N such that 1 1 1 (21) π > 2π, π( , ) < . π π π Then, Uπ β Uπ β Uπ : indeed, let (π₯, π¦) β Uπ and (π¦, π§) β Uπ . Thus, Therefore, 1 1 ππ (π₯, π¦) β€ lim π ( , π (ππ (π₯π , π¦π ) , )) πββ π π = π (0, π ( lim ππ (π₯π , π¦π ) , 0)) πββ ππ (π₯, π§) β€ π (ππ (π₯, π¦) , ππ (π¦, π§)) β€ lim ππ (π₯π , π¦π ) πββ β€ lim π (ππ (π₯, π₯π ) , π (ππ (π₯, π¦) , ππ (π¦π , π¦))) πββ 1 1 β€ lim π ( , π (ππ (π₯, π¦) , )) πββ π π β€ ππ (π₯, π¦) . (17) Thus, ππ (π₯π , π¦π ) β ππ (π₯, π¦). Lemma 22. Let (π, ππ ) be a π-metric space. Let {π₯π } be a sequence in π and π₯π β π₯. Then, π₯ is unique. Proof. Suppose that π₯π β π₯ and π₯π β π¦. We show that π₯ = π¦. For each π β N, there exists π > 0 such that ππ (π₯π , π₯) < 1/π and ππ (π₯π , π¦) < 1/π. By the continuity of π, we have 0 β€ ππ (π₯, π¦) β€ π (ππ (π₯π , π₯) , ππ (π₯π , π¦)) 1 1 < π ( , ) σ³¨β 0, π π In the following theorems we apply the previous lemma and the concept of uniformity (see [12] for more information) to prove the metrizability of a topological space (π, πππ ). (π σ³¨β β) . (18) Hence, we have π₯ = π¦. Definition 23. Let (π, ππ ) be a π-metric space. Then, for a sequence {π₯π } in π, one says that {π₯π } is a Cauchy sequence if for each π > 0, there exists π > 0 such that, for all π β₯ π β₯ π, ππ (π₯π , π₯π ) < π. (22) 1 1 1 , )< . π π π Therefore, (π₯, π§) β Uπ . Hence, {Uπ : π β N} is a base for a uniformity U on π. Since for each π₯ β π and each π β N, Uπ (π₯) = {π¦ β π : ππ (π₯, π¦) < 1/π}. We deduce from Lemma 25 that (π, πππ ) is a metrizable topological space. < π( Let us recall that a metrizable topological space (π, π) is said to be completely metrizable if it admits a complete metric [13]. Theorem 27. Let (π, ππ ) be a complete π-metric space. Then, (π, πππ ) is completely metrizable. Proof. It follows from the proof of Theorem 26 that {Uπ : π β N} is a base for a uniformity U on π compatible with πππ , where Uπ = {(π₯, π¦) β π×π : ππ (π₯, π¦) < 1/π}, for every π β N. Then, there exists a metric π on π whose induced uniformity coincides with U. We want to show that the metric π is complete. Indeed, given a Cauchy sequence {π₯π } in (π, π), we will prove that {π₯π } is a Cauchy sequence in (π, π). To this end, fix π > 0. Choose π β N such that 1/π < π. Then, there exists π0 β N such that (π₯π , π₯π ) β Uπ for every π, π β₯ π0 . Consequently, for each π, π β₯ π0 , ππ (π₯π , π₯π ) β€ 1/π < π. We have shown that {π₯π } is a Cauchy sequence in the complete π-metric space (π, π) and so is convergent with respect to (π, π). Thus, (π, π) is a complete metric space. Mathematical Problems in Engineering 5 3. Two Fixed Point Theorems which implies that In this section, we introduce two fixed point theorems in πmetric spaces. First, we introduce the Banach fixed point and Caristiβs fixed point theorems in such spaces. 3.1. Banach Fixed Point Theorem Theorem 28. Let (π, ππ ) be a complete π-metric space and π : π β π a mapping that satisfies the following: ππ (ππ₯, ππ¦) β€ πΌππ (π₯, π¦) , ππ (π₯π(π+1)β1 , π₯π(π)β1 ) σ³¨β 1+ Step 3. We will show that {π₯π } is a Cauchy sequence. Let π, π β N with π > π ππ (π₯π , π₯π ) = ππ (ππ₯πβ1 , ππ₯πβ1 ) β€ πΌππ (ππ₯πβ2 , ππ₯πβ2 ) for each π₯, π¦ β π, where πΌ β [0, 1). Then, π has a unique fixed point. Step 1. We claim that ππ (π₯π , π₯π+1 ) β 0. Indeed, we have ππ (π₯π+1 , π₯π ) β€ πΌππ (π₯π , π₯πβ1 ) (31) .. . β€ πΌπ ππ (ππ₯πβπ , π₯0 ) . Since {π₯π } is a bounded sequence, therefore, limπ,π β β ππ (π₯π , π₯π ) = 0; that is, {π₯π } is a Cauchy sequence. Thus, there exists π₯ β π such that π₯π β π₯. Further, we derive that ππ (π₯π+1 , ππ₯) = ππ (ππ₯π , ππ₯) β€ πΌ2 ππ (π₯πβ1 , π₯πβ2 ) (24) .. . (30) Since ππ (π₯π(π+1) , π₯π(π) ) β€ πΌππ (π₯π(π+1)β1 , π₯π(π)β1 ), we have 1 β€ πΌ1, a contradiction. Thus, the sequence {π₯π } is bounded. (23) Proof. Let π₯0 β π and π₯π+1 = ππ₯π . We divide our proof into four steps. as (π σ³¨β +β) . β€ πΌππ (π₯π , π₯)) σ³¨β 0, (π σ³¨β β) . (32) It means that π₯π+1 β ππ₯; that is, ππ₯ = π₯. β€ πΌπ ππ (π₯1 , π₯0 ) σ³¨β 0 , as (π σ³¨β β) . Step 4. In the last step, we prove that the π₯ is the unique fixed point of π. Suppose, on the contrary, that π₯, π¦ are two distinct fixed points of π. So, we get that Thus, we have ππ (π₯π , π₯π+1 ) β 0. Step 2. We assert that the sequence {π₯π } is bounded. Suppose, on the contrary, that {π₯π } is an unbounded sequence. Thus, there exists subsequence {π(π)} such that π(1) = 1 and for each π β N, π(π + 1) is minimal in the sense that the relation ππ (π₯π(π+1) , π₯π(π) ) > 1 (25) ππ (π₯π , π₯π(π) ) β€ 1 (26) does not hold and holds for all π β {π(π) + 1, π(π) + 2, . . . , π(π + 1) β 1}. Hence, by using the triangle inequality, we derive that 1 < ππ (π₯π(π+1) , π₯π(π) ) β€ π (ππ (π₯π(π+1) , π₯π(π+1)β1 ) , ππ (π₯π(π+1)β1 , π₯π(π) )) (27) By taking the limit from two sides of (27) and using (II) of Definition 4, we derive that as (π σ³¨β +β) . (28) Also, we have is a contradiction. This completes the proof. 3.2. Caristi-Type Fixed Point Theorem Definition 29. Suppose that (π, ππ ) be a complete π-metric space and P the class of all maps π : π×π β [0, +β) which satisfies the following conditions: Μ β ) is bounded below (πΈ1 ) there exists π₯Μ β π such that π(π₯, and lower semicontinuous, and π(β , π¦) is upper semicontinuous for each π¦ β π, (πΈ2 ) π(π₯, π₯) = 0, for each π₯ β π, (πΈ3 ) π(π(π₯, π¦), π(π¦, π§)) β€ π(π₯, π§), for each π₯, π¦, π§ β π. β€ ππ (π₯π(π+1)β1 , π₯π(π)β1 ) β€ π (ππ (π₯π(π+1)β1 , π₯π(π) ) , ππ (π₯π(π) , π₯π(π)β1 )) π (π₯, π¦) β€ π (π (π₯, π§) , π (π¦, π§)) , (34) for each π₯, π¦, π§ β π. Proof. By Lemma 10, we obtain the desired result. Example 31. Let π(π‘, π ) = π‘π /(1+π‘π ); thus, Im(π) = [0, 1). Now, let π : π β R be a lower bounded, lower semicontinuous function and 1 < ππ (π₯π(π+1) , π₯π(π) ) β€ π (1, ππ (π₯π(π) , π₯π(π)β1 )) , (33) Lemma 30. By Definition 29, one has β€ π (ππ (π₯π(π+1) , π₯π(π+1)β1 , 1)) . ππ (π₯π(π+1) , π₯π(π) ) σ³¨β 1+ ππ (π¦, π₯) = ππ (ππ¦, ππ₯) β€ πΌππ (π¦, π₯) (29) ππ(π¦)βπ(π₯) π (π₯, π¦) = { 0 π₯ =ΜΈ π¦ π₯ = π¦. Then, π satisfies all conditions of Definition 29. (35) 6 Mathematical Problems in Engineering Example 32. Let π(π‘, π ) = βπ‘2π+1 + π 2π+1 ; thus, Im(π) = [0, +β). Now, let π : π β R be a lower bounded, lower semicontinuous function and 2π+1 π (π₯, π¦) = βπ (π¦) β π (π₯). 2π+1 (36) Then, π satisfies all conditions of Definition 29. Also, π(π‘, π ) = 2π+1 2π+1 βπ‘ β π 2π+1 , and π is regular. From now to end, we assume that π is regular (see Definition 8). Lemma 33. Let (π, ππ ) be a complete π-metric space and π β P. Let πΎ : [0, +β) β [0, +β) be π-subadditive; that is, πΎ(π(π₯, π¦)) β€ π(πΎ(π₯), πΎ(π¦)), for each π₯, π¦ β [0, +β), nondecreasing continuous map such that πΎβ1 {0} = {0}. Define the order βΊ on π by π₯ βΊ π¦ ββ πΎ (ππ (π₯, π¦)) β€ π (π₯, π¦) , (37) for any π₯, π¦ β π. Then, (π, βΊ) is a partial order set which has minimal elements. Proof. At first, we show that (π, βΊ) is a partial ordered set. For each π₯ β π, we have 0 = πΎ(0) = πΎ(ππ (π₯, π₯)) β€ π(π₯, π₯) = 0. Thus, π₯ βΊ π₯. If π₯ βΊ π¦ and π¦ βΊ π₯, then πΎ(ππ (π₯, π¦)) β€ π(π₯, π¦) and πΎ(ππ (π₯, π¦)) β€ π(π¦, π₯). Thus, we give πΎ (π (ππ (π₯, π¦) , ππ (π₯, π¦)) β€ π (πΎ (ππ (π₯, π¦)) , πΎ (ππ (π₯, π¦))) below. Let {πΌπ } be an increasing sequence of elements from Ξ such that Μ π₯πΌπ ) = inf {π (π₯, Μ π₯πΌ ) : πΌ β Ξ} = π. lim π (π₯, πββ Then, for each π β₯ π, we infer that πΎ (ππ (π₯πΌπ , π₯πΌπ )) β€ π (π₯πΌπ , π₯πΌπ ) Μ π₯πΌπ )) . Μ π₯πΌπ ) , π (π₯, β€ π (π (π₯, lim sup πΎ (ππ (π₯πΌπ , π₯πΌπ )) π,π β β β€ π (π₯πΌπ , π₯πΌπ ) π,π β β β€ π (π, π) = 0. Then, our assumption on πΎ implies that {π₯πΌπ } is a Cauchy sequence and therefore converges to some π₯ β π. Since πΎ is continuous and π(β , π₯πΌπ ) is upper semicontinuous, then we have πΎ (ππ (π₯, π₯πΌπ )) = lim sup πΎ (ππ (π₯πΌπ , π₯πΌπ )) πββ πββ β€ π (π₯, π₯) = 0. β€ π (π (π₯, π¦) , π (π¦, π§)) This shows that π₯ βΊ π₯πΌπ for all π β₯ 1, which means that π₯ is lower bound for {π₯πΌπ }. In order to see that π₯ is also a lower bound for {π₯πΌ }πΌβΞ , let π½ β Ξ be such that π₯π½ βΊ π₯πΌπ for all π β₯ 1. Then, for each π β N, we have 0 β€ πΎ (ππ (π₯π½ , π₯πΌπ )) (39) β€ π (π₯π½ , π₯πΌπ ) (45) Μ π₯π½ )) . Μ π₯πΌπ ) , π (π₯, β€ π (π (π₯, β€ π (π₯, π§) . It means that π₯ βΊ π§. Thus, (π, βΊ) is a partial ordered set. To show that (π, βΊ) has minimal elements, we show that any decreasing chain has a lower bound. Indeed, let {π₯πΌ }πΌβΞ be a decreasing chain; then we have Hence, for all π β₯ 1, Μ π₯π½ ) β€ π (π₯, Μ π₯πΌπ ) π (π₯, (46) which implies that Μ π₯πΌ ) : πΌ β Ξ} Μ π₯π½ ) = inf {π (π₯, π (π₯, 0 β€ πΎ (ππ (π₯πΌ , π₯π½ )) β€ π (π₯πΌ , π₯π½ ) (44) β€ π (π₯, π₯πΌπ ) . (38) β€ π (πΎ (ππ (π₯, π¦)) , πΎ (ππ (π¦, π§))) (43) Μ π₯πΌπ ) , π (π₯, Μ π₯πΌπ )) β€ lim sup π (π (π₯, β€ lim sup π (π₯πΌπ , π₯πΌπ ) πΎ (ππ (π₯, π§)) β€ πΎ (π (ππ (π₯, π¦) , ππ (π¦, π§)) (42) By taking limit from two sides of (42), the regularity of π, and continuity of π, we give β€ π (π (π₯, π¦) , π (π¦, π₯)) It means that π₯ = π¦. Finally, if π₯ βΊ π¦ and π¦ βΊ π§, then πΎ(ππ (π₯, π¦)) β€ π(π₯, π¦) and πΎ(ππ (π¦, π§)) β€ π(π¦, π§). Thus, we give (41) (40) Μ π₯πΌ )) ; Μ π₯π½ ) , π (π₯, β€ π (π (π₯, Μ π₯πΌ ) β€ π(π₯, Μ π₯π½ ). Thus, by definition of π, we have π(π₯, Μ π₯πΌ )}πΌβΞ is decreasing net of reals which is bounded {π(π₯, Μ π₯πΌπ ) . = lim π (π₯, (47) πββ Thus, from (46), we get limπ β β π₯πΌπ = π₯π½ , which implies that π₯π½ = π₯. Therefore, for any πΌ β Ξ, there exists π β N such that π₯πΌπ βΊ π₯πΌ ; that is, π₯ is a lower bound of {π₯πΌ }. Zornβs lemma will therefore imply that (π, βΊ) has minimal elements. Mathematical Problems in Engineering 7 Theorem 34. Let (π, ππ ) be a complete π-metric space and π β P. Let πΎ : [0, +β) β [0, +β) be as in Lemma 33. Let π : π β π be a map satisfying the following: πΎ (ππ (π₯, ππ₯)) β€ π (ππ₯, π₯) , (48) for any π₯ β π. Then, π has a fixed point. Proof. By Lemma 33, (π, βΊ) has a minimal element say π₯. Thus, π π₯ βΊ π₯. It means that π π₯ = π₯. Corollary 35. Let (π, ππ ) be a complete π-metric space and π β P. Let πΎ : [0, +β) β [0, +β) be as in Lemma 33. Let π : π β 2π be a multivalued mapping satisfying the following: πΎ (ππ (π₯, π¦)) β€ π (π¦, π₯) , βπ¦ β ππ₯. (49) Then, π has an endpoint; that is, there exists π₯ β π such that π π₯ = {π₯}. In Corollary 35, we can introduce many types of Caristiβs fixed point theorem as follows. If we set π as in Example 32, then (48) has the following form: πΎ (ππ (π₯, ππ₯)) β€ βπ (ππ₯) β π (π₯). 2π+1 (50) References [1] S. 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Amini-Harandi, βSome generalizations of Caristiβs fixed point theorem with applications to the fixed point theory of weakly contractive set-valued maps and the minimization problem,β Nonlinear Analysis: Theory, Methods & Applications, vol. 72, no. 12, pp. 4661β4665, 2010. [7] E. Karapinar, βGeneralizations of Caristi Kirkβs theorem on partial metric spaces,β Fixed Point Theory and Applications, vol. 2011, article 4, 2011. [8] R. P. Agarwal and M. A. Khamsi, βExtension of Caristiβs fixed point theorem to vector valued metric spaces,β Nonlinear Analysis: Theory, Methods & Applications, vol. 74, no. 1, pp. 141β 145, 2011. [9] I. Kramosil and J. MichaΜlek, βFuzzy metrics and statistical metric spaces,β Kybernetika, vol. 11, no. 5, pp. 336β344, 1975. [10] M. Grabiec, βFixed points in fuzzy metric spaces,β Fuzzy Sets and Systems, vol. 27, no. 3, pp. 385β389, 1988. [11] A. George and P. 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