Answers to Packet in Class from Thursday

These are the hardest questions from the updated items.
C.
Has to be bigger than x  x
Only way this can happen is if pi is bigger than x.
0 makes a tie. And -2 makes
3.
negative but x2 positive
You need the # to be under 3 and above 0. C and D are the only 2 that do this.
Closed dot because of the equal to sign
4.
5.
L  S  10
# of cans
7L  3S  54
$ equation
A doesn’t work in the first equation.
B. is the only one that works when you plug in.
See if you could graph it here:
This line means you spend under $54. Stay under it.
I got it by plugging in 3 for large and 11 for small.
The 2nd point was 6 large, 4 small is also $54.
Small Cans
This line means you have 10 cans. Stay above it.
Large Cans
6.
35/2 becomes 17.5 miles per hour.
He needs 8 hours until he goes that far.
Could plug in and see which equation will work in both.
Or, do y2 – y1 over x2 – x1 and get 1/3.
From here you could use a graph to see if you connected the
points – where they would cross the y-axis.
Or, use y- y1 = m ( x – x1) and plug the slope in for m and a point
into x1 and y1.
The y-intercept is definitely not 50.
This leaves A or B. Can’t use Rise over Run because
of the intervals on the sides.
Draw the line and do y2 – y1 over x2 – x1
Or decide are you going to go 11 miles every 50
minutes or 50 miles every 10 minutes.
A is your answer.