Math 180 2.5 - Continuity 1 Informally, a function is continuous if you can draw it without lifting up your pencil. Here are some examples of continuous and discontinuous functions: 2 continuous 3 continuous 4 discontinuous at π₯ = 2 5 discontinuous at π₯ = 3 6 Hereβs the formal definition that weβll be using: π(π₯) is continuous at π = π if lim π(π₯) = π(π) . π₯βπ (Note that π(π) must be defined and lim π(π₯) must exist.) π₯βπ π 2 ex: π π₯ = sin(π₯) is continuous at π₯ = since lim sin π₯ = ____ and π π/2 = ____. π₯βπ/2 7 Hereβs the formal definition that weβll be using: π(π₯) is continuous at π = π if lim π(π₯) = π(π) . π₯βπ (Note that π(π) must be defined and lim π(π₯) must exist.) π₯βπ π 2 ex: π π₯ = sin(π₯) is continuous at π₯ = since lim sin π₯ = ____ and π π/2 = ____. π₯βπ/2 8 Hereβs the formal definition that weβll be using: π(π₯) is continuous at π = π if lim π(π₯) = π(π) . π₯βπ (Note that π(π) must be defined and lim π(π₯) must exist.) π₯βπ π 2 ex: π π₯ = sin(π₯) is continuous at π₯ = since lim sin π₯ = ____ and π π/2 = ____. π₯βπ/2 9 Hereβs the formal definition that weβll be using: π(π₯) is continuous at π = π if lim π(π₯) = π(π) . π₯βπ (Note that π(π) must be defined and lim π(π₯) must exist.) π₯βπ π 2 ex: π π₯ = sin(π₯) is continuous at π₯ = since lim sin π₯ = ____ π and π π/2 = ____. π₯βπ/2 10 Hereβs the formal definition that weβll be using: π(π₯) is continuous at π = π if lim π(π₯) = π(π) . π₯βπ (Note that π(π) must be defined and lim π(π₯) must exist.) π₯βπ π 2 ex: π π₯ = sin(π₯) is continuous at π₯ = since lim sin π₯ = ____ π and π π/2 = ____. π π₯βπ/2 11 Hereβs the formal definition that weβll be using: π(π₯) is continuous at π = π if lim π(π₯) = π(π) . π₯βπ (Note that π(π) must be defined and lim π(π₯) must exist.) π₯βπ π 2 ex: π π₯ = sin(π₯) is continuous at π₯ = since lim sin π₯ = ____ π and π π/2 = ____. π π₯βπ/2 12 Hereβs the formal definition that weβll be using: π(π₯) is continuous at π = π if lim π(π₯) = π(π) . π₯βπ (Note that π(π) must be defined and lim π(π₯) must exist.) π₯βπ π 2 ex: π π₯ = sin(π₯) is continuous at π₯ = since lim sin π₯ = ____ π and π π/2 = ____. π π₯βπ/2 13 Hereβs the formal definition that weβll be using: π(π₯) is continuous at π = π if lim π(π₯) = π(π) . π₯βπ (Note that π(π) must be defined and lim π(π₯) must exist.) π₯βπ π 2 ex: π π₯ = sin(π₯) is continuous at π₯ = since lim sin π₯ = ____ π and π π/2 = ____. π π₯βπ/2 14 π π₯ is continuous from the left at π = π if limβ π π₯ = π π . π₯βπ π π₯ is continuous from the right at π = π if lim+ π π₯ = π π . π₯βπ ex: π π₯ = π₯ β 1 is continuous from the right at π₯ = 1 since lim+ π₯ β 1 = ____ and π 1 = ____. π₯β1 15 π π₯ is continuous from the left at π = π if limβ π π₯ = π π . π₯βπ π π₯ is continuous from the right at π = π if lim+ π π₯ = π π . π₯βπ ex: π π₯ = π₯ β 1 is continuous from the right at π₯ = 1 since lim+ π₯ β 1 = ____ and π 1 = ____. π₯β1 16 π π₯ is continuous from the left at π = π if limβ π π₯ = π π . π₯βπ π π₯ is continuous from the right at π = π if lim+ π π₯ = π π . π₯βπ ex: π π₯ = π₯ β 1 is continuous from the right at π₯ = 1 since lim+ π₯ β 1 = ____ and π 1 = ____. π₯β1 17 π π₯ is continuous from the left at π = π if limβ π π₯ = π π . π₯βπ π π₯ is continuous from the right at π = π if lim+ π π₯ = π π . π₯βπ ex: π π₯ = π₯ β 1 is continuous from the right at π and π 1 = ____. π₯ = 1 since lim+ π₯ β 1 = ____ π₯β1 18 π π₯ is continuous from the left at π = π if limβ π π₯ = π π . π₯βπ π π₯ is continuous from the right at π = π if lim+ π π₯ = π π . π₯βπ ex: π π₯ = π₯ β 1 is continuous from the right at π and π 1 = ____. π π₯ = 1 since lim+ π₯ β 1 = ____ π₯β1 19 π π₯ is continuous from the left at π = π if limβ π π₯ = π π . π₯βπ π π₯ is continuous from the right at π = π if lim+ π π₯ = π π . π₯βπ ex: π π₯ = π₯ β 1 is continuous from the right at π and π 1 = ____. π π₯ = 1 since lim+ π₯ β 1 = ____ π₯β1 20 π π₯ is continuous from the left at π = π if limβ π π₯ = π π . π₯βπ π π₯ is continuous from the right at π = π if lim+ π π₯ = π π . π₯βπ ex: π π₯ = π₯ β 1 is continuous from the right at π and π 1 = ____. π π₯ = 1 since lim+ π₯ β 1 = ____ π₯β1 21 π(π₯) is continuous on an interval if it is continuous at every point of the interval. 1 π₯ ex: π π₯ = is continuous on (0, β). 22 π(π₯) is continuous on an interval if it is continuous at every point of the interval. 1 π₯ ex: π π₯ = is continuous on (0, β). 23 Ex 1. Is π continuous or discontinuous at each π₯-value? Is π continuous from the left? Is π continuous from the right? π₯=2 π₯=3 π₯=4 24 Ex 2. π₯β1 2 Explain why π π₯ = 3βπ₯ discontinuous at π₯ = 0. if π₯ < 0 is if π₯ β₯ 0 25 Ex 2. π₯β1 2 Explain why π π₯ = 3βπ₯ discontinuous at π₯ = 0. if π₯ < 0 is if π₯ β₯ 0 26 Ex 3. How would you define π 2 in a way that makes π π₯ = π₯ 2 β5π₯+6 π₯β2 continuous at π₯ = 2? (This is called βremoving the discontinuityβ.) 27 Ex 3. How would you define π 2 in a way that makes π π₯ = π₯ 2 β5π₯+6 π₯β2 continuous at π₯ = 2? (This is called βremoving the discontinuityβ.) 28 Ex 3. How would you define π 2 in a way that makes π π₯ = π₯ 2 β5π₯+6 π₯β2 continuous at π₯ = 2? (This is called βremoving the discontinuityβ.) 29 Properties of Continuous Functions If π and π are continuous at π₯ = π, then all of the following functions are also continuous at π₯ = π: π+π πβ π πβπ π π πβ π π π π π 30 Why? Hereβs the proof of π + π: lim π + π π₯ = lim π π₯ + π π₯ π₯βπ π₯βπ = lim π(π₯) + lim π(π₯) π₯βπ π₯βπ =π π +π π = (π + π)(π) 31 Notes: β’ Any polynomial π π₯ is continuous since, lim π π₯ = π(π). π₯βπ ex: π π₯ = π₯ 2 + 3π₯ β 4 is continuous everywhere (that is, (ββ, β)). β’ Any rational function π(π₯)/π(π₯) is continuous wherever π π₯ β 0. ex: π π₯ = π₯+1 is π₯β2 continuous for all π₯ except 2. 32 Notes: β’ Any polynomial π π₯ is continuous since, lim π π₯ = π(π). π₯βπ ex: π π₯ = π₯ 2 + 3π₯ β 4 is continuous everywhere (that is, (ββ, β)). β’ Any rational function π(π₯)/π(π₯) is continuous wherever π π₯ β 0. ex: π π₯ = π₯+1 is π₯β2 continuous for all π₯ except 2. 33 β’ π₯ , sin π₯, and cos π₯ are continuous ________. β’ π₯ is continuous ____________. 34 β’ π₯ , sin π₯, and cos π₯ are continuous for all π ________. β’ π₯ is continuous ____________. 35 β’ π₯ , sin π₯, and cos π₯ are continuous for all π ________. β’ π₯ is continuous ____________. 36 β’ π₯ , sin π₯, and cos π₯ are continuous for all π ________. β’ for all π β₯ π π₯ is continuous ____________. 37 β’ If π is continuous at π and π is continuous at π(π), then π β π is continuous at π. ex: π₯ + 1 is continuous everywhere on its domain since π π₯ = π₯ + 1 is continuous and π π₯ = π₯ is continuous, so π β π π₯ = π π π₯ = π₯ + 1 is continuous. 38 β’ If π is continuous at π and π is continuous at π(π), then π β π is continuous at π. ex: π₯ + 1 is continuous everywhere on its domain since π π₯ = π₯ + 1 is continuous and π π₯ = π₯ is continuous, so π β π π₯ = π π π₯ = π₯ + 1 is continuous. 39 Ex 4. π₯+3 At what points is the function π¦ = 2 π₯ β3π₯β10 continuous? Ex 5. At what points is the function π¦ = sec 2π₯ continuous? 40 One useful fact about continuous functions is that they satisfy the _________________________. A function has this property if it takes on all values between any two function values. 41 One useful fact about continuous functions is that they satisfy the Intermediate Value Property _________________________. A function has this property if it takes on all values between any two function values. 42 Intermediate Value Theorem If π is a continuous function on a closed interval π, π , and if π¦0 is any value between π(π) and π(π), then π¦0 = π(π) for some π in π, π . 43 Ex 6. Use the Intermediate Value Theorem to show that there is a root of 3 π₯ = 1 β π₯ in the interval 0,1 . 44 Ex 6. Use the Intermediate Value Theorem to show that there is a root of 3 π₯ = 1 β π₯ in the interval 0,1 . 45 Ex 6. Use the Intermediate Value Theorem to show that there is a root of 3 π₯ = 1 β π₯ in the interval 0,1 . 46 Ex 6. Use the Intermediate Value Theorem to show that there is a root of 3 π₯ = 1 β π₯ in the interval 0,1 . 47
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