Math 180 - David Beydler`s Math

Math 180
2.5 - Continuity
1
Informally, a function is continuous if you can
draw it without lifting up your pencil. Here are
some examples of continuous and discontinuous
functions:
2
continuous
3
continuous
4
discontinuous at π‘₯ = 2
5
discontinuous at π‘₯ = 3
6
Here’s the formal definition that we’ll be using:
𝑓(π‘₯) is continuous at 𝒙 = 𝒄 if lim 𝑓(π‘₯) = 𝑓(𝑐) .
π‘₯→𝑐
(Note that 𝑓(𝑐) must be defined and lim 𝑓(π‘₯) must exist.)
π‘₯→𝑐
πœ‹
2
ex: 𝑓 π‘₯ = sin(π‘₯) is continuous at π‘₯ = since
lim sin π‘₯ = ____ and 𝑓 πœ‹/2 = ____.
π‘₯β†’πœ‹/2
7
Here’s the formal definition that we’ll be using:
𝑓(π‘₯) is continuous at 𝒙 = 𝒄 if lim 𝑓(π‘₯) = 𝑓(𝑐) .
π‘₯→𝑐
(Note that 𝑓(𝑐) must be defined and lim 𝑓(π‘₯) must exist.)
π‘₯→𝑐
πœ‹
2
ex: 𝑓 π‘₯ = sin(π‘₯) is continuous at π‘₯ = since
lim sin π‘₯ = ____ and 𝑓 πœ‹/2 = ____.
π‘₯β†’πœ‹/2
8
Here’s the formal definition that we’ll be using:
𝑓(π‘₯) is continuous at 𝒙 = 𝒄 if lim 𝑓(π‘₯) = 𝑓(𝑐) .
π‘₯→𝑐
(Note that 𝑓(𝑐) must be defined and lim 𝑓(π‘₯) must exist.)
π‘₯→𝑐
πœ‹
2
ex: 𝑓 π‘₯ = sin(π‘₯) is continuous at π‘₯ = since
lim sin π‘₯ = ____ and 𝑓 πœ‹/2 = ____.
π‘₯β†’πœ‹/2
9
Here’s the formal definition that we’ll be using:
𝑓(π‘₯) is continuous at 𝒙 = 𝒄 if lim 𝑓(π‘₯) = 𝑓(𝑐) .
π‘₯→𝑐
(Note that 𝑓(𝑐) must be defined and lim 𝑓(π‘₯) must exist.)
π‘₯→𝑐
πœ‹
2
ex: 𝑓 π‘₯ = sin(π‘₯) is continuous at π‘₯ = since
lim sin π‘₯ = ____
𝟏 and 𝑓 πœ‹/2 = ____.
π‘₯β†’πœ‹/2
10
Here’s the formal definition that we’ll be using:
𝑓(π‘₯) is continuous at 𝒙 = 𝒄 if lim 𝑓(π‘₯) = 𝑓(𝑐) .
π‘₯→𝑐
(Note that 𝑓(𝑐) must be defined and lim 𝑓(π‘₯) must exist.)
π‘₯→𝑐
πœ‹
2
ex: 𝑓 π‘₯ = sin(π‘₯) is continuous at π‘₯ = since
lim sin π‘₯ = ____
𝟏 and 𝑓 πœ‹/2 = ____.
𝟏
π‘₯β†’πœ‹/2
11
Here’s the formal definition that we’ll be using:
𝑓(π‘₯) is continuous at 𝒙 = 𝒄 if lim 𝑓(π‘₯) = 𝑓(𝑐) .
π‘₯→𝑐
(Note that 𝑓(𝑐) must be defined and lim 𝑓(π‘₯) must exist.)
π‘₯→𝑐
πœ‹
2
ex: 𝑓 π‘₯ = sin(π‘₯) is continuous at π‘₯ = since
lim sin π‘₯ = ____
𝟏 and 𝑓 πœ‹/2 = ____.
𝟏
π‘₯β†’πœ‹/2
12
Here’s the formal definition that we’ll be using:
𝑓(π‘₯) is continuous at 𝒙 = 𝒄 if lim 𝑓(π‘₯) = 𝑓(𝑐) .
π‘₯→𝑐
(Note that 𝑓(𝑐) must be defined and lim 𝑓(π‘₯) must exist.)
π‘₯→𝑐
πœ‹
2
ex: 𝑓 π‘₯ = sin(π‘₯) is continuous at π‘₯ = since
lim sin π‘₯ = ____
𝟏 and 𝑓 πœ‹/2 = ____.
𝟏
π‘₯β†’πœ‹/2
13
Here’s the formal definition that we’ll be using:
𝑓(π‘₯) is continuous at 𝒙 = 𝒄 if lim 𝑓(π‘₯) = 𝑓(𝑐) .
π‘₯→𝑐
(Note that 𝑓(𝑐) must be defined and lim 𝑓(π‘₯) must exist.)
π‘₯→𝑐
πœ‹
2
ex: 𝑓 π‘₯ = sin(π‘₯) is continuous at π‘₯ = since
lim sin π‘₯ = ____
𝟏 and 𝑓 πœ‹/2 = ____.
𝟏
π‘₯β†’πœ‹/2
14
𝑓 π‘₯ is continuous from the left at 𝒙 = 𝒄 if
limβˆ’ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
𝑓 π‘₯ is continuous from the right at 𝒙 = 𝒄 if
lim+ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
ex: 𝑓 π‘₯ = π‘₯ βˆ’ 1 is continuous from the right at π‘₯ =
1 since lim+ π‘₯ βˆ’ 1 = ____ and 𝑓 1 = ____.
π‘₯β†’1
15
𝑓 π‘₯ is continuous from the left at 𝒙 = 𝒄 if
limβˆ’ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
𝑓 π‘₯ is continuous from the right at 𝒙 = 𝒄 if
lim+ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
ex: 𝑓 π‘₯ = π‘₯ βˆ’ 1 is continuous from the right at π‘₯ =
1 since lim+ π‘₯ βˆ’ 1 = ____ and 𝑓 1 = ____.
π‘₯β†’1
16
𝑓 π‘₯ is continuous from the left at 𝒙 = 𝒄 if
limβˆ’ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
𝑓 π‘₯ is continuous from the right at 𝒙 = 𝒄 if
lim+ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
ex: 𝑓 π‘₯ = π‘₯ βˆ’ 1 is continuous from the right at
π‘₯ = 1 since lim+ π‘₯ βˆ’ 1 = ____ and 𝑓 1 = ____.
π‘₯β†’1
17
𝑓 π‘₯ is continuous from the left at 𝒙 = 𝒄 if
limβˆ’ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
𝑓 π‘₯ is continuous from the right at 𝒙 = 𝒄 if
lim+ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
ex: 𝑓 π‘₯ = π‘₯ βˆ’ 1 is continuous from the right at
𝟎 and 𝑓 1 = ____.
π‘₯ = 1 since lim+ π‘₯ βˆ’ 1 = ____
π‘₯β†’1
18
𝑓 π‘₯ is continuous from the left at 𝒙 = 𝒄 if
limβˆ’ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
𝑓 π‘₯ is continuous from the right at 𝒙 = 𝒄 if
lim+ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
ex: 𝑓 π‘₯ = π‘₯ βˆ’ 1 is continuous from the right at
𝟎 and 𝑓 1 = ____.
𝟎
π‘₯ = 1 since lim+ π‘₯ βˆ’ 1 = ____
π‘₯β†’1
19
𝑓 π‘₯ is continuous from the left at 𝒙 = 𝒄 if
limβˆ’ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
𝑓 π‘₯ is continuous from the right at 𝒙 = 𝒄 if
lim+ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
ex: 𝑓 π‘₯ = π‘₯ βˆ’ 1 is continuous from the right at
𝟎 and 𝑓 1 = ____.
𝟎
π‘₯ = 1 since lim+ π‘₯ βˆ’ 1 = ____
π‘₯β†’1
20
𝑓 π‘₯ is continuous from the left at 𝒙 = 𝒄 if
limβˆ’ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
𝑓 π‘₯ is continuous from the right at 𝒙 = 𝒄 if
lim+ 𝑓 π‘₯ = 𝑓 𝑐 .
π‘₯→𝑐
ex: 𝑓 π‘₯ = π‘₯ βˆ’ 1 is continuous from the right at
𝟎 and 𝑓 1 = ____.
𝟎
π‘₯ = 1 since lim+ π‘₯ βˆ’ 1 = ____
π‘₯β†’1
21
𝑓(π‘₯) is continuous on an interval if it is
continuous at every point of the interval.
1
π‘₯
ex: 𝑓 π‘₯ = is continuous on (0, ∞).
22
𝑓(π‘₯) is continuous on an interval if it is
continuous at every point of the interval.
1
π‘₯
ex: 𝑓 π‘₯ = is continuous on (0, ∞).
23
Ex 1.
Is 𝑓 continuous or discontinuous at each π‘₯-value? Is 𝑓
continuous from the left? Is 𝑓 continuous from the
right?
π‘₯=2
π‘₯=3
π‘₯=4
24
Ex 2.
π‘₯βˆ’1
2
Explain why 𝑓 π‘₯ =
3βˆ’π‘₯
discontinuous at π‘₯ = 0.
if π‘₯ < 0 is
if π‘₯ β‰₯ 0
25
Ex 2.
π‘₯βˆ’1
2
Explain why 𝑓 π‘₯ =
3βˆ’π‘₯
discontinuous at π‘₯ = 0.
if π‘₯ < 0 is
if π‘₯ β‰₯ 0
26
Ex 3.
How would you define 𝑓 2 in a way that makes
𝑓 π‘₯ =
π‘₯ 2 βˆ’5π‘₯+6
π‘₯βˆ’2
continuous at π‘₯ = 2?
(This is called β€œremoving the discontinuity”.)
27
Ex 3.
How would you define 𝑓 2 in a way that makes
𝑓 π‘₯ =
π‘₯ 2 βˆ’5π‘₯+6
π‘₯βˆ’2
continuous at π‘₯ = 2?
(This is called β€œremoving the discontinuity”.)
28
Ex 3.
How would you define 𝑓 2 in a way that makes
𝑓 π‘₯ =
π‘₯ 2 βˆ’5π‘₯+6
π‘₯βˆ’2
continuous at π‘₯ = 2?
(This is called β€œremoving the discontinuity”.)
29
Properties of Continuous Functions
If 𝑓 and 𝑔 are continuous at π‘₯ = 𝑐, then all of
the following functions are also continuous at
π‘₯ = 𝑐:
𝑓+𝑔
𝑓⋅𝑔
π‘“βˆ’π‘”
𝑓 𝑔
π‘˜β‹…π‘“
𝑓
𝑛
𝑛
𝑓
30
Why? Here’s the proof of 𝑓 + 𝑔:
lim 𝑓 + 𝑔 π‘₯ = lim 𝑓 π‘₯ + 𝑔 π‘₯
π‘₯→𝑐
π‘₯→𝑐
= lim 𝑓(π‘₯) + lim 𝑔(π‘₯)
π‘₯→𝑐
π‘₯→𝑐
=𝑓 𝑐 +𝑔 𝑐
= (𝑓 + 𝑔)(𝑐)
31
Notes:
β€’ Any polynomial 𝑃 π‘₯ is continuous since,
lim 𝑃 π‘₯ = 𝑃(𝑐).
π‘₯→𝑐
ex: 𝑓 π‘₯ = π‘₯ 2 + 3π‘₯ βˆ’ 4 is continuous
everywhere (that is, (βˆ’βˆž, ∞)).
β€’ Any rational function 𝑃(π‘₯)/𝑄(π‘₯) is continuous
wherever 𝑄 π‘₯ β‰  0.
ex: 𝑓 π‘₯ =
π‘₯+1
is
π‘₯βˆ’2
continuous for all π‘₯ except 2.
32
Notes:
β€’ Any polynomial 𝑃 π‘₯ is continuous since,
lim 𝑃 π‘₯ = 𝑃(𝑐).
π‘₯→𝑐
ex: 𝑓 π‘₯ = π‘₯ 2 + 3π‘₯ βˆ’ 4 is continuous
everywhere (that is, (βˆ’βˆž, ∞)).
β€’ Any rational function 𝑃(π‘₯)/𝑄(π‘₯) is continuous
wherever 𝑄 π‘₯ β‰  0.
ex: 𝑓 π‘₯ =
π‘₯+1
is
π‘₯βˆ’2
continuous for all π‘₯ except 2.
33
β€’
π‘₯ , sin π‘₯, and cos π‘₯ are continuous
________.
β€’
π‘₯ is continuous ____________.
34
β€’
π‘₯ , sin π‘₯, and cos π‘₯ are continuous
for all 𝒙
________.
β€’
π‘₯ is continuous ____________.
35
β€’
π‘₯ , sin π‘₯, and cos π‘₯ are continuous
for all 𝒙
________.
β€’
π‘₯ is continuous ____________.
36
β€’
π‘₯ , sin π‘₯, and cos π‘₯ are continuous
for all 𝒙
________.
β€’
for all 𝒙 β‰₯ 𝟎
π‘₯ is continuous ____________.
37
β€’ If 𝑓 is continuous at 𝑐 and 𝑔 is continuous at
𝑓(𝑐), then 𝑔 ∘ 𝑓 is continuous at 𝑐.
ex: π‘₯ + 1 is continuous everywhere on its
domain since 𝑓 π‘₯ = π‘₯ + 1 is continuous and
𝑔 π‘₯ = π‘₯ is continuous, so 𝑔 ∘ 𝑓 π‘₯ =
𝑔 𝑓 π‘₯ = π‘₯ + 1 is continuous.
38
β€’ If 𝑓 is continuous at 𝑐 and 𝑔 is continuous at
𝑓(𝑐), then 𝑔 ∘ 𝑓 is continuous at 𝑐.
ex: π‘₯ + 1 is continuous everywhere on its
domain since 𝑓 π‘₯ = π‘₯ + 1 is continuous and
𝑔 π‘₯ = π‘₯ is continuous, so 𝑔 ∘ 𝑓 π‘₯ =
𝑔 𝑓 π‘₯ = π‘₯ + 1 is continuous.
39
Ex 4.
π‘₯+3
At what points is the function 𝑦 = 2
π‘₯ βˆ’3π‘₯βˆ’10
continuous?
Ex 5.
At what points is the function 𝑦 = sec 2π‘₯
continuous?
40
One useful fact about continuous functions is
that they satisfy the
_________________________.
A function has this property if it takes on all
values between any two function values.
41
One useful fact about continuous functions is
that they satisfy the
Intermediate Value Property
_________________________.
A function has this property if it takes on all
values between any two function values.
42
Intermediate Value Theorem
If 𝑓 is a continuous function on a closed interval
π‘Ž, 𝑏 , and if 𝑦0 is any value between 𝑓(π‘Ž) and
𝑓(𝑏), then 𝑦0 = 𝑓(𝑐) for some 𝑐 in π‘Ž, 𝑏 .
43
Ex 6.
Use the Intermediate Value Theorem to show that
there is a root of 3 π‘₯ = 1 βˆ’ π‘₯ in the interval 0,1 .
44
Ex 6.
Use the Intermediate Value Theorem to show that
there is a root of 3 π‘₯ = 1 βˆ’ π‘₯ in the interval 0,1 .
45
Ex 6.
Use the Intermediate Value Theorem to show that
there is a root of 3 π‘₯ = 1 βˆ’ π‘₯ in the interval 0,1 .
46
Ex 6.
Use the Intermediate Value Theorem to show that
there is a root of 3 π‘₯ = 1 βˆ’ π‘₯ in the interval 0,1 .
47