Advances in Pure Mathematics, 2013, 3, 563-575 http://dx.doi.org/10.4236/apm.2013.36072 Published Online September 2013 (http://www.scirp.org/journal/apm) Nemytskii Operator in the Space of Set-Valued Functions of Bounded -Variation Wadie Aziz Departamento de Fsica y Matemática, Universidad de Los Andes, Trujillo, RBV Email: [email protected] Received June 13, 2013; revised July 23, 2013, accepted August 19, 2013 Copyright © 2013 Wadie Aziz. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. ABSTRACT In this paper we consider the Nemytskii operator, i.e., the composition operator defined by Nf t H t , f t , where H is a given set-valued function. It is shown that if the operator N maps the space of functions bounded 1 -variation in the sense of Riesz with respect to the weight function into the space of set-valued functions of bounded 2 -variation in the sense of Riesz with respect to the weight, if it is globally Lipschitzian, then it has to be of the form Nf t A t f t B t , where A t is a linear continuous set-valued function and B is a set-valued function of bounded 2 -variation in the sense of Riesz with respect to the weight. Keywords: Bounded Variation; Function of Bounded Variation in the Sense of Riesz; Variation Space; Weight Function; Banach Space; Algebra Space 1. Introduction In [1], it was proved that every globally Lipschitz Nemytskii operator Nu t H t , u t mapping the space Lip a, b ; cc Y into itself admits the following representation: Nu t A t u t B t , u Lip a, b ; cc Y , t a, b , where A t is a linear continuous set-valued function and B is a set-valued function belonging to the space Lip a, b ; cc Y . The first such theorem for singlevalued functions was proved in [2] on the space of Lipschitz functions. A similar characterization of the Nemytskii operator has also been obtained in [3] on the space of set-valued functions of bounded variation in the classical Jordan sense. For single-valued functions it was proved in [4]. In [5,6], an analogous theorem in the space of set-valued functions of bounded p -variation in the sense of Riesz was obtained. Also, they proved a similar result in the case in which that the Nemytskii operator N maps the space of functions of bounded p -variation in the sense of Riesz into the space of set-valued functions Copyright © 2013 SciRes. of bounded q -variation in the sense of Riesz, where 1 q p < , and N is globally Lipschitz. In [7], they showed a similar result in the case where the Nemytskii operator N maps the space RV1 a, b ; K of setvalued functions of bounded 1 -variation in the sense of Riesz into the space RW2 a, b ; cc Y of set-valued functions of bounded 2 -variation in the sense of Riesz and N is globally Lipschitz. While in [8], we generalize article [6] by introducing a weight function. Now, we intend to generalize [7] in a similar form we did in [8], i.e., the propose of this paper is proving an analogous result in which the Nemytskii operator N maps the space RV1 , a, b ; K of setvalued functions of bounded 1 -variation in the sense of Riesz with a weight into the space RW2 , a, b ; cc Y of set-valued functions of bounded 2 -variation in the sense of Riesz with a weight and N is globally Lipschitz. 2. Preliminary Results In this section, we introduce some definitions and recall known results concerning the Riesz -variation. Definition 2.1 By a -function we mean any nondecreasing continuous function : 0, 0, APM W. AZIZ 564 such that x 0 if and only if x 0 , and x as x . Let be the set of all convex continuous functions that satisfy Definition 2.1. Definition 2.2 Let X , be a normed space and be a -function. Given I be an arbitrary (i.e., closed, half-closed, open, bounded or unbounded) fixed interval and : I a fixed continuous strictly increasing function called a it is weight. If , we define the (total) generalized -variation V f V f , I , of the function f : I X with respect to the weight function in two steps as follows (cf. [9]). If I a, b is a closed interval and π is a partition π : a t0 < t1 < < tn b of the interval I (i.e., n ), we set n f ti f ti 1 V f , π, : i 1 ti ti 1 ti ti 1 . Denote by the set of all partitions of a, b , we set V f V f , a, b , : sup V f , π, : π . If I is any interval in , we put V f V f , I , : sup V f , a, b , : a, b I . The set of all functions of bounded generalized variation with weight will be denoted by RV I RV I , f : a, b X V f , I , . I f t id t t , t I a, b , a n d q , 0 , q > 1 , the -variation V f , I , , also written as Vq f , is the classical q -variation of f in the sense of Riesz [10], showing that Vq f < if and only if f AC I (i.e., f : I is absolutely continuous) and its almost everywhere derivative f is Lebesgue q -summable on I . Recall that, as it is well known, the space RV I with I, and as above and endowed with the norm f f a Vq f 1q q is a Banach algebra for all q 1 . Riesz’s criterion was extended by Medvedev [11]: if , then f RV I if and only if f AC I and f t dt < . Functions of bounded generalI ized -variation with and id (also called functions of bounded Riesz-Orlicz -variation) were studied by Cybertowicz and Matuszewska [12]. They showed that if f RV I , then and that the space GV I f I such that lim 0V f 0 Copyright © 2013 SciRes. p f inf r 0 V f r 1 . Later, Maligranda and Orlicz [15] proved that the space GV I equipped with the norm f sup tI f t p f is a Banach algebra. 3. Generalization of Medvedev Lemma We need the following definition: Definition 3.1 Let be a -function. We say satisfies condition 1 if lim sup t t t . (1) For φ convex, (1) is just lim t t t . Clearly, for id 1 the space RV f , a, b , id coincides with the classical space BV f , a, b of functions of bounded variation. In the particular case when X and 1 < p < , we have the space RV p , f , a, b ; X of functions of bounded Riesz p -variation. Let a, b , , be a measure space with the Lebesgue-Stieltjes measure defined in -algebra and L p , a, b : f : a, b f is integrable and b a f p d . Moreover, let be a function strictly increasing and continuous in a, b . We say that E a, b has measure 0, if given > 0 there is a countable cover an , bn n by open intervals of E , such that n 1 bn an < . Since is strictly increasing, the concept of “ measure 0 ” coincides with the concept of “measure 0” of Lebesgue. [cf. [16], § 25]. Definition 3.2 (Jef) A function f : a, b is said to be absolutely continuous with respect to , if for every > 0 , there exists > 0 such that j 1 f b j f a j , n for every finite number of nonoverlapping intervals a j , b j , j 1, , n with a j , b j a, b and j 1 b j a j . n V f I f t dt , is a semi-normed linear space with the LuxemburgNakano (cf. [13,14]) seminorm given by The space of all absolutely continuous functions f : a, b , with respect to a function strictly increasing, is denoted by AC . Also the following APM W. AZIZ 565 characterization of [17,18] is well-known: Lemma 3.3 Let f AC a, b . Then f exists and is finite in a, b , except on a set of -measure 0. Lemma 3.4 Let f AC a, b . Then f is integrable in the sense Lebesgue-Stieltjes and f x f a L S f t d t , x a, b . x a Lemma 3.5 Let such that satisfies the 1 condition. If f RV f , a, b , , then f is -ab- solutely continuous in a, b , i.e., Also the following is a generalization of Medvedev Lemma [11]: Theorem 3.6 (Generalization a Medvedev Lemma) Let such that satisfies the 1 condition, f : a, b X . Then 1) If f is -absolutely continuous on a, b and a f x d x < , b then f t d t t1 d t t2 t2 t1 t 2 f t d t . t 1 Let π : a t0 < < tn b be any partition of interval a , b ; then f t2 f t1 n t t t2 t1 i 1 2 1 t j f t d t a f t d t , i 1 t i 1 b and we have V f , a, b , a f x d x . b Thus f RV f , a, b , . 2 ) Let f RV a, b . Then f is -absolutely continuous on a, b by Lemma 3.5 and f exist a.e. on a, b . For every n , we consider a partition of the interval a, b define by and π n :a t0, n t1, n tn, n b f RV f , a, b , RV f , a, b , a f x d x . b t2 n RV f , a, b , AC a, b . t1 ti , n a i ba , i 0,1, , n . n 2) If f RV f , a, b , (i.e., RV f < ), then f is -absolutely continuous on a, b and Let f n n be a sequence of step functions, defined by f n : a,b a f x d x RV f , a, b , . f ti 1, n f ti , n , ti , n t ti 1, n t f n t ti 1, n ti , n t b 0, b Proof. 1 ) Since f is absolutely continuous, there exists f a.e. in a, b by Lemma 3.3. Let t1 , t2 a, b , t1 < t2 f t2 f t1 t2 t1 t2 t1 t 2 f t d t t 1 t2 t1 t2 t1 by Lemma 3.4 and is strictly increasing t2 f t d t t 1 t2 t1 t t 2 1 t2 f t d t t1 t2 t2 t1 t d t 1 using the generalized Jenssen’s inequality Copyright © 2013 SciRes. f n n converge to f a.e. on a, b . It is sufficient to prove f n f in those points where f is differentiable and different from ti , n , i 0,, n for n , i.e., in t a, b f t exists ti ,n n , i 0,1, , n For t , and each n , there exists k 0, , n such that tk , n t < tk 1, n , so f tk 1,n f tk ,n fn t tk 1,n tk ,n tk 1,n t f tk 1,n f t tk 1,n tk ,n tk 1,n t t tk , n f t f tk , n tk 1,n tk ,n t tk ,n . APM W. AZIZ 566 Therefore, f n t is a convex combination of points f tk 1, n f t tk 1, n t and f t f tk , n t tk , n . tk 1, n t and f t f tk , n t tk , n b 4. Set-Valued Function Now if n , then tk , n t and tk 1, n t and since f is -differentiable for t , the expressions f tk 1, n f t a f x d x RV f , a, b , . Let cc X be the family of all non-empty convex compact subsets of X and D be the Hausdorff metric in cc X , i.e., D A, B : inf t 0 : A B tS , B A tS , . tend f t to which is -differentiable from f in t . So results lim f n t f t t a.e. in a, b . where S y X : y 1 , or equivalently, D A, B max e A, B , e A, B : A, B cc X , where n Since is continuous, we have lim f n t lim f n t f t n n t . Using the Fatou’s Lemma and definition of sequence, results that f n f n t d t a f t d t a nlim b b n n 1 t lim inf t i 1,n f n t d t . n i 0 i ,n By definition from f n Definition 4.1 Let , a fixed continuous strictly increasing function and F : a, b cc X . We say that F has bounded -variation in the sense of Riesz if f ti 1, n f ti , n ti 1, n ti , n n i 0 i ,n ti 1, n ti , n t n 1 f t i 1, n f ti , n i1,nd t lim inf n i 0 t ti ,n i 1, n ti , n n 1 f t i 1, n f ti , n ti 1, n ti , n lim inf n i 0 t ti , n i 1, n V f , a, b . n (3) D F ti , F ti 1 : sup ti ti 1 , π i 1 ti ti 1 where the supremum is taken over all partitions π of a, b . Definition 4.2 Denote by RW* F , a, b , n 1 t i 1,n lim inf t which is what we wished to demonstrate. Corollary 3.7 Let such that satisfies the 1 condition, then f RV I if and only if f is -absolutely continuous on a, b and a f x d x < . b Also a f x d x RV f , a, b , . b Corollary 3.8 Let such that satisfies the 1 condition. If f RV I , then f is -absolutely continuous on a, b and Copyright © 2013 SciRes. (2) W F , a, b , lim inf a f n t d t b e A, B sup d x, B : x A , d x, B inf d x, y : y B . (4) : F : a, b cc X : W F , a, b , and RW F , a, b , : F : a, b (5) cc X : RW* F for some 0 , both equipped with the metric D F1 , F2 : D F1 a , F2 a (6) inf 0 : W F1 , F2 1 , where W F1 , F2 n D F1 ti F2 ti 1 , F1 ti 1 F2 ti sup ti ti 1 π i 1 ti ti 1 . Now, let X , , Y , be two normed spaces and K be a convex cone in X . Given a set-valued function H : a, b K cc Y we consider the Nemytskii a ,b a ,b operator N : K Y generated by H , that is APM W. AZIZ the composition operator defined by: Nf t : H t , f t , lity, we get f : a, b K ;t a, b . D A C , B C D A, B . D F t , F t0 t t0 lim (7) t t0 (8) such that satisfies the 1 F RW a, b ; cc Y , , i 1 for all partitions of t , t0 a, b , we have a, b Copyright © 2013 SciRes. 1 2 x, y X . (13) (14) Proof. 1) Since N is globally Lipschitz, there exists a constant M 0, such that D2 Nf1 , Nf 2 M f1 f 2 (10) 1 f,f 1 2 RV1 a, b , ; K . (15) Using the definitions of the operator N and metric D2 we have f,f (12) 0. H t , x A t x B t t a, b , x K (9) D ht ,t N f , f , ht ,t N f , f n i i 1 1 2 i 1 i 1 2 D Nf1 a , Nf 2 a inf 0 : sup 2 t t π i 1 i i 1 1 M 2) There are functions A : a, b L K , cc Y and B RW2 f , a, b , ; cc Y such that M >0 Since is convex -function, from the last inequa- M f1 f 2 D H t, x , H t, y M t x y , in particular given D F t , F t0 t t0 M . t t0 lim RW2 f , a, b , ; cc Y and if it is globally Lipschitz, then the set-valued function H satisfies the following conditions: 1) For every t a, b there exists M t 0, , such that 5. Main Results D F ti , F ti 1 ti ti 1 M , ti ti 1 This proves the continuity of F at t0 . Thus F is continuous on a, b . Now, we are ready to formulate the main result of this work. Main Theorem 5.2 Let X , , Y , be normed spaces, K be a convex cone in X and 1 , 2 be two convex -functions in X , strictly increasing, that satisfy 1 condition and such that there exists constants c and T0 with 2 t 1 ct for all t T0 . If the Nemitskii operator N generated by a set-valued function H : a, b K cc Y maps the space RV1 f , a, b , ; K into the space We will extend the results of Aziz, Guerrero, Merentes and Sánchez given in [8] and [21] to set-valued functions of -bounded variation with respect to the weight function . n M t t0 1 t t0 1 F x A t B , x K . (11) limD F t , F t0 if and only if there exists an additive set-valued function A : K cc Y and a set B cc Y such that then F : a, b cc X is continuous. Proof. Since F RW a, b , , exists such that . By (1), Lemma 4.4 ([20]) Let X , , Y , be normed spaces and K be a convex cone in X . A set-valued function F : K cc Y satisfies the Jensen equation x y 1 F F x F y , x, y K , 2 2 M t t0 1 t t0 1 We denote by L K ; cc Y the space of all setvalued function A : K cc Y , i.e., additive and positively homogeneous, we say that A is linear if A L K ; cc Y . In the proof of the main results of this paper, we will use some facts which we list here as lemmas. Lemma 4.3 ([19]) Let X , be a normed space and let A, B, C be subsets of X . If A, B are convex compact and C is non-empty and bounded, then Lemma 5.1 If condition and 567 RV1 a, b , ; K , t t i i 1 1 APM W. AZIZ 568 where hs ,t N f1 , f2 : Nf1 s NF2 t . In particular, D d f , f H , t, t , d f , f H , t , t 1 2 1 2 inf 0 : 2 t t for all f1 , f 2 RV1 a, b , ; K t t , where and t , t a, b , 1 M f1 f 2 t t 1 t t i i d f1 , f2 H , s, t H s, f1 s H t , f 2 t . Since 1 and 2 satisfy 1 , t t 1, i 1, 2, (16) we obtain D d f , f H , t, t , d f , f H , t , t 1 2 1 2 inf 0 : 2 t t t t 1 D d f1 , f 2 H , t, t , d f , f H , t , t . 1 2 Therefore D d f1 , f2 H , t , t , d f1 , f 2 H , t , t M f1 f 2 1 Define the auxiliary function : a, b 0,1 by: a , a t : t a 1, t b. 1 t t t t 2 Let us fix f i : a, b K (18) f1 f 2 1 i 1, 2 (17) and define the functions by: f1 : x, f 2 : y x x, Then RV1 a, b , and 1 V1 , a, b , 1 t a x, y K . (19) a, b . t a . Then the functions fi RV1 a, b , ; K i 1, 2 and f1 a f 2 a n inf 0 : sup1 π i 1 f1 f 2 ti f1 f 2 ti 1 ti ti 1 ti ti 1 1 (20) From the definition of f1 and f 2 , we have f1 f 2 1 x y inf > 0 : 1 t a t a 1 . (21) From (16), we get x y inf > 0 : 1 t a x y t a 1 t a 1 1 t a (22) Hence, Copyright © 2013 SciRes. APM W. AZIZ D d f1 , f2 H , t , t , d f1 , f 2 H , t , t 569 1 M t t 21 t t 1 t a 11 t a Hence, substituting in inequality (5) the particular functions fi i 1, 2 x y (23) defined by (19) and taking t a in (23), we obtain 1 t a D H t , x H a, x , H a, x H t , y M 1 11 t a 21 for all t a, b , x, y K . 1 : By Lemma 4.3 and the inequality (24), we have 1 t a D H t, x , H t, y M 1 11 t a 21 x y , for all t a, b , x, y K . Now, we have to consider the case t b . 1 a , a, b . b a 1 V1 1 1 b a f1 : x, f 2 : 1 x y y; a, b . b a 1 1 b a 1 x y 1 1 1 b a 1 b a Substituting t a and t b , and consider b a , we obtain MK a, b, x, y, , for all x, y K , where Copyright © 2013 SciRes. (26) x y b a 11 1 2 b a . Then the functions fi RV1 a, b , ; K (i = 1,2) and x y 1 1 (25) Let us fix x, y K and define the functions fi : a, b K i 1, 2 by x y x y inf 0 : 1 b a D H b, x H a, y , H a, x H b, x (24) Then the function 1 RV1 a, b , and Define the function 1 : a, b 0,1 by f1 f 2 x y , (27) . K a, b, x, y, 11 , 21 1 21 1 x y 1 11 1 APM W. AZIZ 570 By Lemma 4.3 and the above inequality, we get 1 1 a, b ; f1 : 2 2 x 1 2 2 y, (29) f : 1 1 x 1 1 y, a, b . 2 2 2 2 2 D H a, y , H a, x 1 1 1 M 2 x y 1 11 1 The functions fi RV1 a, b , ; K f1 f 2 for all x, y K . Define the function M : a, b by 1 21 t a M 1 1 1 t a M t M 1 1 x y 2 ,a t b 1 1 , t a. 1 1 1 Hence M t x y x, y X , t a, b , and, consequently, for every t a, b the function H : a, b K cc Y is continuous. This completes the proof of part 1). Now we shall prove that H satisfies equality 2). Let us fix t , t0 a, b such that t0 < t . Since the Nemytskii operator N is globally Lipschitzian, there exists a constant M , such that D d u , v H , t , t 0 , d u , v H , t0 , t where , (28) du ,v H , s, t H s, u s H t , v t . Define the function 2 : a, b 0,1 by a , a t0 , t0 a t 2 , t0 t , t t0 0, t b. The function 2 RV1 a, b , . Let us fix x, y K and define the functions fi : a, b K by Copyright © 2013 SciRes. x y 2 and . Hence, substituting in the inequality (28) the particular functions fi i 1, 2 defined by (29), we obtain x y x y D H t 0 , x H t , y , H t0 , H t, 2 2 1 1 M t t0 21 t t0 2 (30) x y . Since N maps RV1 a, b , ; K into RW2 a, b , ; cc Y , then H , z is continuous for all z K . Hence letting t0 t in the inequality (30), we get x y x y D H t, x H t, y , H t, H t, 2 2 (31) 0, D H t, x , H t, y 1 M u v t0 t 2 1 t0 t 1 i 1, 2 for all t a, b and x, y K . Thus for all t a, b , x, y K , we have x y x y H t, H t, x H t, y . H t, 2 2 (32) Since H is convex, we have x y 1 H t, H t , x H t , y , 2 2 (33) for all t a, b , x, y K . Thus for all t a, b , the set-valued function H t , : K cc Y satisfies the Jensen Equation (33). Now by Lemma 4.4, there exists an additive set-valued function A t : K cc Y and a set B t cc Y , such that H t , x A t x B t , x K , t a, b . (34) Substituting H t , x A t x B t into inequality (13), we deduce that for all t a, b there exists M t 0, , such that D A t x, A t y M t x y x, y K , consequently, for every t a, b the set-valued function A t : K cc Y is continuous, and A t L K , cc Y . Since A t is additive and 0 K , then A t 0 for all t a, b , thus H , 0 B . APM W. AZIZ The Nemytskii operator N maps the space RV1 a, b , ; K into the space RW2 a, b ; cc Y , then H , 0 B RW2 a, b , ; K . Consequently the set-valued function H has to be of the form H t , x A t x B t , t a, b , x K , where A t L K , cc Y and a, b , ; cc Y . X , , Y , be normed spaces, B RW2 Theorem 5.3 Let K a convex cone in X and 1 , 2 be two convex -functions in X , strictly increassing, satisfying 1 condition and lim t 21 1 t t . If the Nemytskii 571 D1 Nf1 , Nf 2 M f1 f H t , x H t , 0 t a, b , x K ; i.e., the Nemytskii operator is constant. Proof. Since the Nemytskii operator N is globally Lipschizian between RV1 a, b , ; K and the space RW1 a, b , ; cc Y , then there exists a constant M , such that f1 f 2 2 f,f 1 2 (35) RV2 a, b , ; K . Let us fix t , t0 a,b such that t0 < t . Using the definitions of the operator N and of the metric D1 , we have D H t , f1 t H t0 , f 2 t0 , H t0 , f1 t0 H t , f 2 t M t t0 f1 f 2 2 f,f 1 2 RV2 a, b , ; K 1 t t0 11 (36) Define the auxiliary function 3 : a, b 0,1 . by a t0 , 1, t 3 : , t0 t , t t0 0, t b. operator N generated by a set-valued function H : a, b K cc Y maps the space RV2 a, b ; K into the space RW1 a, b , ; cc Y and if it is globally Lipschizian, then the set-valued function H satisfies the following condition 2 2 The function 3 RV2 a, b , and 1 V2 3 ; a, b t t0 21 t t0 Let us fix x K and fi : a, b K i 1, 2 by f1 : x, define the n f1 f 2 ti f1 f 2 ti 1 f1 a f 2 a inf 0 : sup2 ti ti 1 π i 1 x t t0 1 inf 0 : 2 t t0 x . 1 t t0 21 t t0 Hence, substituting in the inequality (36) the auxiliary functions fi D H t , x H t0 , x , H t0 , x H t , 0 M t t0 i 1, 2 functions f 2 : 3 x, a, b . The functions fi RV2 a, b , ; K . i 1, 2 (37) and ti ti 1 1 defined by (37), we obtain 1 t t0 1 t t0 21 t t0 11 x. By Lemma 4.3 and the above inequality, we get Copyright © 2013 SciRes. APM W. AZIZ 572 D H t , x , H t , 0 M t t0 Since lim t 21 1 t t , letting t0 t in the above inequality, we have D H t , x , H t , 0 0. Thus for all t a, b and for all x K , we get H t, x H t, 0 . Theorem 5.4 Let X , , Y , be normed spaces, K a convex cone in X and be a convex function in X satisfying the 1 condition. If the Nemytskii operator N generated by a set-valued function H : a, b K cc Y maps the space RV a, b , ; K into the space BW a, b ; cc Y and if it is globally Lipschizian, then the left regularization H : a, b K cc Y of the function H defined by H t , x , H * t , x : limH s, x , s a t a, b , x K ; t a, x K , satisfies the following conditions: for all t a, b there exists M t , such that f1 f 2 n f1 a f 2 a inf 0 : sup π i 1 1 t t0 1 t t0 21 t t0 11 x. D H * t, x , H * t, y M t x y x, y K . H * t , x A t x B t t a, b x K , where A t is a linear continuous set-valued function, and B BW a, b ; cc Y . Proof. We take t a, b , and define the auxiliary function 4 : a, b 0,1 by: a t, 1, 4 : b , t b. t b The function 4 RV a, b , ; K and 1 V 4 , a, b b t b t . Let us fix x, y K and define the functions fi : a, b K i 1, 2 by f1 : x, f 2 : 4 y x x, a, b . The functions fi RV a, b , ; K i 1, 2 f1 f 2 ti f1 f 2 ti 1 ti ti 1 1 ti ti 1 (38) and (39) From the definition of f1 and f 2 , we obtain f1 f 2 1 x y 1 1 b t 1 b t Since the Nemytskii operator N is globally Lipschitzian between . (40) RV a, b , ; K and BW a, b ; cc Y , then there exists a constant M , such that D H b, f1 b H t , f 2 t , H t , f1 t H b, f 2 b M f1 f 2 . for f1 , f 2 RV a, b , ; K . By Lemma 4.3, substituting the particular functions fi above inequality, we obtain i 1, 2 defined by (38) in the D H b, f1 b H t , f 2 t , H t , f1 t H b, f 2 b M t x y , (41) Copyright © 2013 SciRes. APM W. AZIZ for all x, y K , t a, b . By Lemma 4.3, we get D H t, x , H t, y M t x y (42) for all t a, b and x, y K . In the case where t b , by a similar reasoning as 573 above, we obtain that there exists a constant M b , such that D H b, x , H b, y M b x y x, y K . (43) Define the function M : a, b by 1 M 1 M (t ) 1 b t 1 b t M b , , a t < b, t b. (44) fine the partition π n of the interval t0 , t by Hence, D H t, x , H t, y M t x y , π n : a t0 t1 t2 n 1 t2 n t , t a , b , x, y K . where ti ti 1 By passing to the limit in the inequality (41) by the inequality (43) and the definition of H * we have for all t a,b that there exists M t , such that D H * t, x , H * t, y M t x y The Nemytskii operator N is globally Lipschitzian between RV a, b , ; K and BW a, b ; cc Y , then there exists a constant M > 0 , such that n D d f , f H , t2i , t2i 1 , d f , f H , t2i 1 , t2i t a , b x, y K i 1 Now we shall prove that H * satisfies the following equality H t, x A t x B t * t a, b , x K , where A t is a linear continuous set-valued functions, and B BW a, b ; cc Y . Let us fix t , t0 a, b , n such that t0 < t . De0, ti 1 , ti ti 1 5 : ti , t t i i 1 0, t t0 , i 1, 2, , 2n. 2n 1 2 1 M f1 f 2 2 (45) , where f1 , f 2 RV a, b , ; K and d f1 , f2 H , s, t H s, f1 s H t , f 2 t . We define the function 5 : a, b 0,1 in the following way: a t0 ; ti 1 ti , i 1,3, , 2n 1; ti 1 ti , i 2, 4, , 2n; t b. The function 5 RV a, b , ; K and 2n V 5 , ; a, b t t0 t ( t0 . Let us fix x, y K and define the functions fi : a, b K by: Copyright © 2013 SciRes. APM W. AZIZ 574 1 1 a, b ; f1 : 2 5 x 1 2 5 y, f : 1 1 x 1 1 y, a, b . 5 5 2 2 2 (46) The functions fi RV a, b , ; K i 1, 2 and f1 f 2 x y 2 Substituting in the inequality (45) the particular functions fi n i1 D H t2i 1 , x H t2i , y , H t2i 1 , x y x y * D H * t, x H * t, y , H * t, H t, 2 2 M x y . 2n for all x, y K and n . By passing to the limit when n , we get x y x y * * * H * t, H t, H t, x H t, y , 2 2 t a , b , x, y K . Since H * t , x is a convex function, then x y 1 * * H * t, H t , x H t , y 2 2 t a , b , x, y K . Thus for every t a, b , the set-valued function H * t , : K cc Y satisfies the Jensen equation. By Lemma 4.4 and by the property (a) previously established, we get that for all t a, b there exist an additive set-valued function A : K cc Y and a set B t cc Y , such that defined in (46), we obtain t a, b , x K . A t L K , cc Y and B BW a, b ; cc Y . 6. Acknowledgements This research was partly supported by CDCHTA of Universidad de Los Andes under the project NURR-C- x, y K . (47) 547-12-05-B. REFERENCES [1] A. Smajdor and W. Smajdor, “Jensen Equation and Nemytskii Operator for Set-Valued Functions,” Radovi Matematicki, Vol. 5, 1989, pp. 311-319. [2] J. Matkwoski, “Functional Equation and Nemytskii Operators,” Funkcialaj Ekvacioj, Vol. 25, No. 2, 1982, pp. 127-132. [3] G. 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