quick test inequality for ibps po

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QUICK TEST INEQUALITY FOR IBPS PO
Directions (Q. 1-10): In each of these questions, relationships between two elements
is shown in the statements. These statements are followed by two conclusions. Read the
statements and give answer
1) if only conclusion I follows.
2) if only conclusion II follows.
3) if either conclusion I or II follows.
4) if neither conclusion I nor II follows.
5) if both conclusions I and II follow.
1. Statements: A > F = E,
Conclusions: I. E > A
D < G < E,
P<D
II. A > P
2. Statements: B > C > T < Q < L,
Conclusions: I. T = R
R > Q,
B<V
II. T < R
3. Statement:
T<M>B=G>P<C
Conclusions: I. M > P
II. P < B
4. Statement:
R>P>Q<S<T>M
Conclusions: I. T > Q
II. R > T
5. Statement:
Q>C<D<P>R>O=B
Conclusions: I. Q > O
II. O > Q
6. Statement:
Q>P<N>M=O>R
Conclusions: I. P < Q
II. N = O
7. Statement:
L<M>O>S=T<U
Conclusions: I. O > U
II. S < O
8. Statement:
F>L<M<N=O>P
Conclusions: I. L > P
II. M > N
9. Statements: E > F < O,
Conclusions: I. F < O
N<H>O
II. N > E
10. Statement:
B > C = E > F < L, D > E < K
Conclusions: I. C < K
II. B < L
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Answers with Explanation
1. 2;
A > F = E ... (i)
D < G < E ... (ii)
P<D
... (iii)
Combining (i) and (ii)
Statements:
Combining (i), (ii) and (iii)
2. 2;
Statements:
B > C > T < Q < L ... (i)
R>Q
... (ii)
B<V
... (iii)
Combining (i), (ii) and (iii)
V>B>C>T<Q<R
Thus, T < R. Hence, I does not follow and II follows.
3. 2;
Statement:
 M > P. Hence I does not follow.
P < B and II follows.
4. 1;
Statement:
Thus, T > Q. Hence, I follows.
But no definite relation can be found between R and T. Thus, R > T does not follow.
5. 3;
Statement:
No relationship can be established but together they form a complementary pair.
6. 1;
Given expression: Q > P < N > M = O > R
... (i)
Q > P means P < Q. Hence, conclusion I follows. But N > O. Thus II does not follow.
7. 2;
Given expression: L < M > O > S = T < U
We can’t compare O and U. Thus, conclusion I does not follow.
Again, O > S means S < O. Hence, conclusion II follows.
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Given statement: F > L < M < N = O > P
We can’t compare L and P. Thus, I does not follow.
Again, M < N is true. Thus, conclusion II does not follow.
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8. 4;
9. 4;
Given statement: E > F < O
... (i)
N<H>O
... (ii)
Combining both statements, we have
E>F<O<H>N
Now, F < O is a restatement and not a conclusion. Hence, I does not follow.
Again, We can’t compare E and N. Thus, conclusion II does not follow.
10. 1; Given statement: B > C = E > F < L ... (i)
D>E<K
... (ii)
Combining both statements, we have
B>C=E<K
Thus, C < K is true. Hence, conclusion I follows.
Again, B > C = E > F < L
We can’t compare B and L. Thus, conclusion II does not follow.
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