Genetics - Othe Patterns of Inheritance File

Genetics - Other Patterns of Inheritance - WEB practice
Multiple Choice
Identify the choice that best completes the statement or answers the question.
____
____
1. Linked genes
a. are never separated.
b. assort independently.
c. are on the same chromosome.
d. are always recessive.
2. If two genes are on the same chromosome and rarely assort independently,
a. crossing-over never occurs between the genes.
b. crossing-over always occurs between the genes.
c. the genes are probably located far apart from each other.
d. the genes are probably located close to each other.
Figure 11-1
____
3. Refer to Figure 11-1. If individual III-2 marries a person with the same genotype as individual I-1, what is
the chance that one of their children will be afflicted with hemophilia?
a. 0%
c. 50%
b. 25%
d. 75%
____
____
4. What type of inheritance pattern does the trait represented by the shaded symbols in Figure 11-1 illustrate?
a. incomplete dominance
c. codominance
b. multiple alleles
d. sex-linked
5. For the trait being followed in the pedigree, individuals II-1 and II-4 in Figure 11-1 can be classified as
____.
a. homozygous dominant
b. mutants
____
____
c. homozygous recessive
d. carriers
6. What is the relationship between individual I-1 and individual III-2 in Figure 11-1?
a. grandfather-granddaughter
c. great aunt-nephew
b. grandmother-grandson
d. mother-son
7. If a female fruit fly heterozygous for red eyes (XRXr) crossed with a white-eyed male (XrY), what percent of
their offspring would have white eyes?
a. 0%
c. 50%
b. 25%
____
d. 75%
8. When roan cattle are mated, 25% of the offspring are red, 50% are roan, and 25% are white. Upon
examination, it can be seen that the coat of a roan cow consists of both red and white hairs. This trait is one
controlled by ____.
a. multiple alleles
c. sex-linked genes
b. codominant alleles
d. polygenic inheritance
____
9. A cross between a white rooster and a black hen results in 100% blue Andalusian offspring. When two of
these blue offspring are mated, the probable phenotypic ratio seen in their offspring would be ____.
a. 100% blue
c. 75% blue, 25% white
75%
black,
25%
white
b.
d. 25% black, 50% blue, 25% white
Completion
Complete each statement.
10. A normal human karyotype displays ____________________ pairs of autosomes.
Short Answer
11. What is a linkage group?
Table 11-1
12. Two couples, the Pages and the Bakers, had baby boys in the same hospital at the same time. There was a
mixup in the hospital nursery. Use the information given in Table 11-1. Which baby belongs to which
family?
13. Based on the Bakers' blood types, could Baby #1 be their child? Could Baby #2 be their child? Use Table
11-1 to explain your answer.
Essay
14. Explain the difference between incomplete dominance and codominance.
True/False
Indicate whether the statement is true or false.
____
15. The staff in the neonatal unit at a hospital are not sure which of two babies belong to which set of parents.
The blood types of the babies are AB and O. One set of parents has blood types A and B. With this
knowledge it would still be necessary to test the second couple.
Genetics - Other Patterns of Inheritance - WEB practice
Answer Section
MULTIPLE CHOICE
1. ANS: C
2. ANS: D
3. ANS: A
PTS:
PTS:
1
1
REF: p. 279
REF: p. 279
Feedback
A
B
C
D
You are right.
You are on the right track.
Please consider the pattern in the pedigree again.
Please refer to notes.
PTS: 1
NAT: LS_2b
4. ANS: D
DIF: Bloom's Level E
STA: III.3.1
TOP: 11-1
REF: 299
Feedback
A
B
C
D
You are on the right track.
Please consider again all the factors.
Please refer to your notes.
You are correct.
PTS: 1
NAT: LS_2b
5. ANS: D
DIF: Bloom's Level D
STA: III.3.1
TOP: 11-5
REF: 299–300 | 307–308
Feedback
A
B
C
D
Please consider again the reference to the individual, not the allele.
Please consider the factors again.
Please refer to.your notes.
You are correct.
PTS: 1
NAT: LS_2b
6. ANS: B
DIF: Bloom's Level B
STA: III.3.1
TOP: 11-3
Feedback
A
B
C
D
You are on the right track.
You are right.
Please consider again the symbols in creating a pedigree.
Please refer to your notes.
REF: 299–300
PTS: 1
TOP: 11-3
7. ANS: C
DIF:
Bloom's Level B
REF: 299
Feedback
A
B
C
D
Please consider all the factors.
You are on the right track.
You are correct.
Please refer to your notes.
PTS: 1
NAT: LS_2b
8. ANS: B
DIF: Bloom's Level C
STA: III.3.1
TOP: 11-1
REF: 296–300
Feedback
A
B
C
D
You are on the right track.
You are right!
Please consider again the inheritance pattern.
You are heading in the right direction.
PTS: 1
NAT: LS_2b
9. ANS: D
DIF: Bloom's Level C
STA: III.3.1
TOP: 11-4
REF: 299–300
Feedback
A
B
C
D
Please consider again the results of mating two from the second generation.
You are on the right track.
Please refer to your notes.
You are correct.
PTS: 1
NAT: LS_2b
DIF: Bloom's Level D
STA: III.3.1
TOP: 11-4
REF: 302–303
DIF: Bloom's Level B
TOP: 11-7
REF: 311
COMPLETION
10. ANS: 22
PTS: 1
NAT: LS_2b
SHORT ANSWER
11. ANS:
A linkage group is all the genes on the same chromosome.
PTS:
1
REF: p. 279
12. ANS:
Baby #2 must belong to the Bakers because only Baby #1 can belong to the Pages.
PTS: 1
NAT: LS_2b
13. ANS:
DIF: Bloom's Level E
STA: III.3.1
TOP: 11-3
REF: 299–300
Either Baby #1 or Baby #2 could be theirs. If Mrs. Baker is /Bi and Mr. Baker is /Ai or /A/A, then their
baby could be /Ai, making it Baby #1. If Mrs. Baker is /Bi and Mr. Baker is /Ai, then their baby could be ii,
making it Baby #2.
PTS: 1
NAT: LS_2b
DIF: Bloom's Level F
STA: III.3.1
TOP: 11-4
REF: 304
ESSAY
14. ANS:
In incomplete dominance, one allele is not completely dominant over another. As a result, the heterozygous
phenotype is somewhere in between the two homozygous phenotypes. In codominance, both alleles
contribute to the phenotype of the organism. As a result, the heterozygous phenotype shows both
homozygous phenotypes.
PTS:
1
REF: p. 272
TRUE/FALSE
15. ANS: T
The parents with blood types A and B could have genotypes IaIi, and IbIi and so could have a child with
either one of the blood types. If the second set of parents had the genotypes IiIi and IiIa, the answer would
then be clear.
PTS: 1
NAT: LS_2b
DIF: Bloom's Level D
STA: III.3.1
TOP: 11-4
REF: 304