Electric Drive Systems Electric Drive Systems © 2014 2/00 Topics • • • • • • • Structure Commutator & Brush Torque Equation EMF Equation Steady State Model Back EMF & Torque Constants DC Machine Losses DC Drive Systems- DC Machines • • • • • • • Efficiency Speed-Torque Curve Speed Control Methods DC Machine Capability Curves Field Weakening Region Series DC Motor Comparison of Small & Large Motors Electric Drive Systems © 2014 3/00 DC Machine- Structure Commutator Field or Stator Yoke Armature Winding N turns • Bli machine Brush • Stator - Field I S I + V - • Rotor - Armature N • Commutator & Brush Field Poles Armature Core DC Drive Systems- DC Machines Field Winding Electric Drive Systems © 2014 4/00 DC Machine- Commutator & Brush • Closed-loop circuit in armature winding • Each segment of the commutator is connected to the armature conductor. • Commutator segments limit the motor voltage rating. • Brush is placed at 90 apart from poles. • The voltage between brushes maintains a constant (except for a small commutator ripple). • Brush is laminated along the rotating direction. IR Brush drop 1~2V I DC Drive Systems- DC Machines Electric Drive Systems © 2014 5/00 Derivation of Torque Equation q • From F=Bli, f (q ) B(q )l (i / a) f avg Bavg l (i / a ) r N S 2 / P 1 where Bavg B(q )dq 0 2 / P Apole Bavg (2 rl / P) Bavg T r ( Nf avg ) lrN Bavg (i / a) - Conductor length: l - Number of conductor: N - Armature current: i - Number of parallel path: a - radius of armature: r - Number of poles: P DC Drive Systems- DC Machines NP T i K i K t i 2 a • Torque is proportional to the field flux, armature current, and pole number. Electric Drive Systems © 2014 6/00 Derivation of EMF Equation • From e=Blv, eavg = Bavglr E N N P eavg a a 2 E K Kv • The EMF (Electromotive force) is proportional to the field flux, rotor speed, and pole number. • A rectangular wave form of B(q) is best for torque production. For ac machine, positive or negative torque DC Drive Systems- DC Machines • Torque Volume i T rNBavg l a N i a Bavg 2 r A/ m Wb/m 2 Current Magnetic loading loading 2 rl m3 Volume • Current loading thermal cond. • Magnetic loading: saturation • Motor Cost Torque not power ex) 10hp, 1800rpm & 10hp 900rpm Electric Drive Systems © 2014 7/00 DC Machine- Steady State Model R • Steady state voltage equation La Lf + I V E + Vf T, - V IR E Rf - • Back EMF equation E K Kv • Torque equation • R: resistance of armature winding T K I Kt I • La: armature inductance (0) • Lf: field inductance • Energy balance VI I 2 R EI Pmech E I Kv I Pout T Kt I If DC Drive Systems- DC Machines Kv Kt in MKS unit Electric Drive Systems © 2014 8/00 Measuring Kv and Kt • Measuring Kv – e = Kv – Rotate armature – Measure open-circuit voltage, no current flow – Open-circuit test DC Drive Systems- DC Machines • Measuring Kt – T = KtI – Stall armature – Measure stall torque using the spring – Measure current – Short-circuit test Electric Drive Systems © 2014 9/00 Why Kt < Kv in data sheet? • Rotational loss – EI = KvI : Electrically converted mechanical power – T = KtI : Mechanical shaft power – Difference = (Kv - Kt ) I : Mechanical loss (windage, friction) & armature iron loss (eddy current & hysteresis) 5% Note) No iron loss in field flux because of stationary flux. • Flux loss caused by armature reaction such that Kt = f(I): closed circuit, Kv f(I): open circuit. Kt is measured smaller due to the saturation. DC Drive Systems- DC Machines Electric Drive Systems © 2014 10/00 DC Machine Losses Armature resistive loss Iron core loss - Pa,cu = i2R - Pcore in armature core only - DC field in stator core Brush loss R - Pbrush La + IR V I Rc E T, Brush drop 1~2V I Friction & windage loss - Pfw , Tfw = B Field winding resistive loss Total loss Ploss = Pa,cu + Pbrush + Pf,cu + - Pf,cu = if2Rf Pcore + Pfw - = = Lfif DC Drive Systems- DC Machines Electric Drive Systems © 2014 11/00 DC Machine- Efficiency • DC Motor Pin Pout Ploss Pout Efficiency m 100 Pout Ploss EI E E E IR V EI I 2 R Pf ,cu Pout 100 or Pin DC Drive Systems- DC Machines Electric Drive Systems © 2014 12/00 DC Machine- Speed-Torque Curve • For a separately-excited DC machine E E K v Kv V IR Kv V TR T K t I K v K v Kt 2 E V IR Let Kv = Kt = K, V R 2T K K DC Drive Systems- DC Machines _ noload Speed Source R Slope= TL R K2 Tstall TR no _ load T V V , Tstall K K R • For ideal speed source, R, K . Super-conducting machine Electric Drive Systems © 2014 13/00 Speed Control Methods for DC Motors Stable & Unstable Operating Points V R 2T K K Stable point Adjustable series armature resistance R Adjustable armature voltage V Field weakening , K Tload Tmotor T Unstable point Tload Tmotor T DC Drive Systems- DC Machines Electric Drive Systems © 2014 14/00 Speed Control by Series Armature Resistance Rext R La - TL V K + V Speed Source noload _ Rtot E T, Slope= R K2 TR • Economical • Poor efficiency DC Drive Systems- DC Machines T T V ( R) 2 R K K Electric Drive Systems © 2014 15/00 Speed Control by Armature Voltage V1 K V2 K • Expensive • Powerful Speed Source TL R Slope= 2 K V3 K VVV >> 123 TR 1 RT (V ) V 2 K K DC Drive Systems- DC Machines Variable DC T M R Constant speed AC motor Variable M MS Ward-Leonard Drives Electric Drive Systems © 2014 16/00 Speed Control by Flux Weakening V K1 V K2 • For extending speed range • Reduce Torque/Amp Speed Source KK< 12 R T = Ki K: Torq/Amp cap. K12 R K 22 3 R 2 Less speed source As K decreases R T V RT (K ) 2 K K • K = Kv or KtI DC Drive Systems- DC Machines 2 TR 3 TR T Lower field flux higher speed destructive mechanically Electric Drive Systems © 2014 17/00 DC Machine Capability Curves(1) Voltage source limit - Vo constrains speed Current limit - Io constrains torque Operating Regions • Constant Torque region – Control armature voltage – Constant rated field flux Field flux limit - o constrains speed Torque limit: To = KtoIo = KoIo Capability Representation in Torque-Speed Curves DC Drive Systems- DC Machines • Constant Power region – Field flux weakening – Constant armature voltage Max. torque is limited by current limit Electric Drive Systems © 2014 18/00 Torque- per unit DC Machine Capability Curves(2) Constant Torque Region Constant Power Region Constant field flux Field Weakening Armature voltage control Constant armature voltage Corner T , point o c Io, ec 1.0 (To) KK< 1 Ko2 R VVV 12<< 0 V1 V2 Ko Ko DC Drive Systems- DC Machines o Ko2 R Vo o 1 Ko Speed- per unit o K12 R Vo K1 2.0 Electric Drive Systems © 2014 19/00 DC Machine Capability Curves(3) Vo I=Io o c o Pc Definition of Corner point c at To, Io , Vo , Ko , ec c Vo R 2 To , To K o I o Ko Ko V RI o ec c o Ko Ko DC Drive Systems- DC Machines o Vo Ko Pc Toc K o I o ec K o ec I o If small R (large motor), c o Electric Drive Systems © 2014 20/00 Field Weakening Region • Speed > c • Flux < c, = f()? e Kv , ec Kvoc In the field weakening region, e=ec c o Max. torque: T K t I o Kt • Torque/Ampere capability is reduced. • Speed regulation is worse due to the slope of torquespeed curve. • Maximum speed is limited ( 3 times rated speed) by mechanical condition. ec P Io c K v DC Drive Systems- DC Machines Electric Drive Systems © 2014 21/00 Series DC Motor R L Torque limit + Variable DC Lf M - Assume linear iron (no saturation), V I ( R R f ) KI T K I KI 2 Neglecting IR drop, 1 V2 T KI 2 K 2 DC Drive Systems- DC Machines TL Increase V T or I I Speed • High torque at low speed and low torque at high speed • At no load, run away ! Electric Drive Systems © 2014 22/00 DC Motor driven by AC voltage? • For shunt motor, T K I K m cos t I m sin t Tavg 0 • For series motor, T K I • Universal Motor – AC or DC series motor – Vacuum cleaner: high speed 25,000 ~ 30,000 rpm – Drills – Blenders – Power tools K m sin t I m sin t Tavg 0 The series DC motor operates at AC voltage. Universal motor DC Drive Systems- DC Machines Electric Drive Systems © 2014 23/00 Comparison of Small & Large Machines(1) • • • • • P=10 hp, R =1750 rpm Rcold = 0.57 Rhot 1.2Rcold = 0.684 Kv = 1.17 V/(rad/s) Kt = 0.81 ft•lbs/A ER = Kv•R = 1.17•1750(2/60) = 214.4 V TR = P/R = 10•746/(1750 •2/60) = 40.7 Nm or 30 ft•lbs IR = TR/ Kt = 30/0.81 = 37 A VR = IRRhot + ER = 37•0.684 + 214.4 = 239.7 V Note) 1 Nm = 0.738 ft•lbs DC Drive Systems- DC Machines • • • • • 100 hp, 1750 rpm Rcold = 0.0144 Rhot 1.2Rcold = 0.0173 Kv = 1.27 V/(rad/s) Kt = 0.885 ft•lbs/A ER = Kv•R = 1.27•1750(2/60) = 233 V TR = P/R = 100•746/(1750 •2/60) = 407 Nm or 300 ft•lbs IR = TR/ Kt = 300/0.885 = 339 A VR = IRRhot + ER = 339•0.0173 + 233 = 239 V Note) 1 Nm = 0.738 ft•lbs Electric Drive Systems © 2014 24/00 Comparison of Small & Large Machines(2) = ER/VR = 214.4/239.7 = 0.89 = ER/VR = 233/239 = 0.97 no_load = VR/ Kv = 239.7/1.17 •(60/ no_load = VR/ Kv = 239/1.27 •(60/ 2) = 1956 rpm Ishort_circuit = VR/Rcold =239.7/0.57 = 421 A 10 times rated • • • • 2) = 1797 rpm Ishort_circuit = VR/Rcold =239/0.0144 = 16,600 A 40 times rated Large machine is more efficient. Large machine is more speed source. Large machine has more starting or inrush current. In the large machine machine, current and torque are more sensitive to the input voltage variation due to low IR drop. • For small machine, m >> e mechanical system dominates. • For large machine, e >> m electrical system dominates. DC Drive Systems- DC Machines Electric Drive Systems © 2014 25/00 DC Machine Dynamics Assuming constant flux, <Small machine> • 2 energy storage mechanisms L 0, d – Mechanical energy J m V K J Ki TL K TL dt R – Electrical energy L a 2 d K KV TL • 2nd-order coupled system dt RJ RJ J • For small machine, m >> a RJ J For large machine, a >> m m 2 2 K K /R <Large machine> di J L Ri V K const. dt Slope of T- curve a L / R DC Machine Dynamics Electric Drive Systems © 2014 26/00 Block Diagram of Sep. Exc. DC Motor di V L Ri K dt d J Ki TL B dt V + + - - i Ie pt , e pt Laplace Transform 1 Lp I K V LpI RI K Jp KI TL TL T+ - 1 Jp R E DC Machine Dynamics K Electric Drive Systems © 2014 27/00 Transfer Function of DC Machine 1 R K2 1 K L JR V JLp 2 JRp K 2 R R K2 2 p p L L JR 1 1 K m a V p2 1 p 1 a m a L JR where a , m 2 R K • If L is negligible (small machine ), a 0 1 1 K m V p 1 m DC Machine Dynamics Electric Drive Systems © 2014 28/00 Characteristic Poles- Small & Large Machines • Characteristic poles: p1,2 Small Machine • a / m << 1 p1,2 Large Machine • a / m >> 1 1 4 a 1 2 m 1 1 1 1 , 1 1 2 a 2 a m a m p1,2 m 4 1 1 a 2 a 2 a m 1 1 j 2 a a m 1 e t / m 1 e t / 2 a t DC Machine Dynamics 4 a 1 1 1 2 a 2 a m t Electric Drive Systems © 2014 29/00 Root Locus • Movement of eigenvalues as adjusting a / m • a < m /4 Im a m 1 a 1 2 a DC Machine Dynamics 2 real poles Larger machine a 1 m 4 • a > m /4 2 complex poles Re Electric Drive Systems © 2014 30/00 Standard Form for 2nd Order System p 2 2 n p n 2 0 p 2 1 a p 1 a m 0 • Natural frequency n 1 a m • Damping factor 1 m 2 a Response • Settling time(within 2%) 4 n 8 a • % overshoot max fin 100[%] fin 1 2 e 100[%] • For 2 real poles, % overshoot=0 Settling time = 4 a DC Machine Dynamics Electric Drive Systems © 2014 31/00 Speed Control + - V GC 1 ( K a m ) 1 1 p2 p a m a Im G GC GM KP Controller Zero Controller Zero DC Machine Dynamics Im Re Re Motor Poles 1 ( K a m ) pa 2 p p (1 a ) p (1 m a ) Motor Poles Electric Drive Systems © 2014 32/00 Current Control(1) I* + GI V+ - 1 Lp R • Current Negative Feedback I K I GI I * Lp R GI GI I* V' + GI - 1 Lp R K DC Machine Dynamics I 1 V ' Lp R GI I • GI는 R을 변화시키는 효과 • For fast a, larger GI • For unit dc gain, very large GI Electric Drive Systems © 2014 33/00 Current Control(2) V" I* + - GI Lp R GI K/GI I • Feedback disturbance gain K/GI • For PI controller, GI G1 G2 p Effect: Dynamic armature resistance change DC Machine Dynamics Electric Drive Systems © 2014 34/00 DC Machine Drives DC Machine Drives Electric Drive Systems © 2014 35/00 Four Quadrants of Motor Drive Operation Reverse Regenerating Voltage <0 Current >0 Torque R Forward Motoring L + I V Voltage >0 Current >0 - M Speed Voltage <0 Current <0 Reverse Motoring DC Machine Drives Voltage >0 Current <0 Forward Regenerating Electric Drive Systems © 2014 36/00 DC Machine Drives 1. Thyristor DC Drives • Use semi-controlled switches; SCR(Thyristor) • Power converters (AC to DC) Single-phase full-wave controlled rectifier Three-phase full-wave controlled rectifier 2. DC Chopper Drives • Use fully-controlled switches; BJT, MOSFET, IGBT • Power converters(DC to DC) DC chopper Full bridge (H bridge) DC converter DC Machine Drives Electric Drive Systems © 2014 37/00 Single-phase half-wave controlled rectifier L R • Unipolar current • DC current in AC source + Vs I V - DC Machine Drives – Transformer M Electric Drive Systems © 2014 38/00 Single-phase full-wave controlled rectifier(1) L R + T2 Vs T1 I V T3 2 Inversion 2 T4 2 Vs ,m • Average output voltage Braking Vdc 2Vs sin t d ( t ) 2 2 Vs cos 0.9Vs cos Motoring M - 1 Vs ,m DC Machine Drives 2 Vs ,m K Motoring Increase 2 Motoring Braking Vs ,m K Electric Drive Systems © 2014 39/00 Single-phase full-wave controlled rectifier(2) vac v IRa Ea v vac t t Ea IRa I dc is is t • RMS input current Is 1 0 I dc 2 dq I dc • Fundamental RMS input I s1 t • Input power factor PF Vs I s1 cos 2 2 cos Vs I s 1 2 2 2 I sin q d q I dc dc 0 2 DC Machine Drives Electric Drive Systems © 2014 40/00 Single-phase full-wave controlled rectifier(3) • Output DC voltage Vdc 2 2 • Power factor varies as a function of firing angle Vs cos • Output RMS voltage Vo 1 • Maximum PF 0.9 2 2Vs sin q dq Vs • Poor PF • Output DC & RMS current: Idc • Output power factor PF Vdc I dc 2 2 cos Vs I dc DC Machine Drives Electric Drive Systems © 2014 41/00 Single-phase rectifier with freewheel diode(1) L R + T1 • Input fund. & rms voltage: Vs • Input rms current I T2 M Vs V T3 T4 vac v 1 • Input fund. current Is 1 2 I s1 I dc sinq dq 2 IRa Ea t 2 is PF t I dc (1 cos ) • Input power factor I dc DC Machine Drives I dc 2 dq I dc 2(1 cos ) ( ) Electric Drive Systems © 2014 42/00 Single-phase rectifier with freewheel diode(2) • Output dc & rms current: Idc • Output power factor • Output rms voltage Vo 1 ( 2Vs sin q ) 2 dq • Output dc voltage Vdc 0.926 (1/ 2)sin 2 PF1_input ( ) Vs 1 2 DC Machine Drives 1 0.8 0.6 PF2_input ( ) PF2_output ( ) 0.4 2Vs sinq dq Vs 1 cos 2(1 cos ) ( (1/ 2)sin 2 ) PF 0.2 0 0 0 0 20 40 60 80 100 180 Electric Drive Systems © 2014 90 43/00 Three-phase full-wave controlled rectifier L R Vsa + c Vs T1 T2 I T3 Vs b Va T4 T5 M T6 - • Advantage of 3-phase vs 1-phase – Smoother output: – Higher ripple frequency: 360Hz 120Hz – Lower harmonic distortion DC Machine Drives Electric Drive Systems © 2014 44/00 Waveform of three-phase controlled rectifier vsa v vsb vsc va t Va t I dc isa 120 t DC Machine Drives Electric Drive Systems © 2014 45/00 Three-phase controlled rectifier • Output DC voltage Vdc • Output RMS voltage 1 3 3 3 3 3 2 2VLL sin q dq VLL cos 1.35VLL cos 1 Vrms 3 3 3 VLL 1 3 2VLL sin q 2 1/ 2 dq 3 3 cos 2 2 • Output DC & RMS current: Idc • Output power factor DC Machine Drives Electric Drive Systems © 2014 46/00 Three-phase controlled rectifier • Input fund. & rms voltage: Vs • Input fundamental RMS current 1 2 5 6 I sa1 I sin q d q dc 2 6 • Input RMS current • Input power factor – Independent on firing angle DC Machine Drives I sa I dc 6 I dc 0.78I dc 120 2 I dc 0.816 I dc 180 3 6 I PF _ input 2 3I dc dc 3 0.955 Electric Drive Systems © 2014 47/00 Four Quadrant DC Drive L L T2 Ia Vs M T3 T1' T2' T3' T4' Va T4 Vs T1 + - DC Machine Drives Electric Drive Systems © 2014 48/00 DC Chopper Drive- 1 Quad + L Va - DC Machine Drives I v M IRa Ea DT T t Electric Drive Systems © 2014 49/00 DC Chopper Drive- H-Bridge Converter Va L - M + I DC Machine Drives Electric Drive Systems © 2014
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