Linear Programming By: Sara Greelman and Cindy Vo Problem The high school senior class are going to rent busses and vans for a class trip. Each bus transports 40 students and 3 chaperones and costs $1200 each. Each van can transport 8 students and 1 chaperone for $100. They must plan for at least 400 students and at most 36 chaperones. Variables X= Busses Y= Vans Constraints X≥0 Y≥0 40x+8y≥ 400 3x+y≤ 36 Objective $=1200x+100y We are trying to find the minimal transportation costs Graph Solution (10,0) $=1200(10)+100(0) or $12000 (12,0) $=1200(12)+100(0) or $14400 (7,15) $=1200(7)+100(15) or $9900 Summary We plugged in the points from our graph into the objective function. The points created a triangle or our feasible region. They should rent 7 busses and 15 vans for $9900.
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