EXAMPLE 5 Write a joint variation equation The variable z varies jointly with x and y. Also, z = –75 when x = 3 and y = –5. Write an equation that relates x, y, and z. Then find z when x = 2 and y = 6. SOLUTION STEP 1 Write a general joint variation equation. z = axy STEP 2 Use the given values of z, x, and y to find the constant of variation a. Substitute 75 for z, 3 for x, and 25 for y. –75 = a(3)(–5) Simplify. –75 = –15a 5=a Solve for a. EXAMPLE 5 Write a joint variation equation STEP 3 Rewrite the joint variation equation with the value of a from Step 2. z = 5xy STEP 4 Calculate z when x = 2 and y = 6 using substitution. z = 5xy = 5(2)(6) = 60 EXAMPLE 6 Compare different types of variation Write an equation for the given relationship. Relationship a. y varies inversely with x. b. z varies jointly with x, y, and r. c. y varies inversely with the square of x. Equation y= a x z = axyr a y= 2 x d. z varies directly with y and z = ay x inversely with x. e. x varies jointly with t and r and inversely with s. atr x= s GUIDED PRACTICE for Examples 5 and 6 The variable z varies jointly with x and y. Use the given values to write an equation relating x, y, and z. Then find z when x = –2 and y = 5. 9. x = 1, y = 2, z = 7 SOLUTION STEP 1 Write a general joint variation equation. z = axy GUIDED PRACTICE for Examples 5 and 6 STEP 2 Use the given values of z, x, and y to find the constant of variation a. 7 = a(1)(2) Substitute 7 for z, 1 for x, and 2 for y. 7 = 2a Simplify. 7 Solve for a. 2 =a STEP 3 Rewrite the joint variation equation with the value of a from Step 2. z = 7 xy 2 GUIDED PRACTICE for Examples 5 and 6 STEP 4 Calculate z when x = – 2 and y = 5 using substitution. 7 7 z = 2 xy = 2 (– 2)(5) = – 35 ANSWER z = 7 xy ; – 35 2 GUIDED PRACTICE 10. for Examples 5 and 6 x = 4, y = –3, z =24 SOLUTION STEP 1 Write a general joint variation equation. z = axy STEP 2 Use the given values of z, x, and y to find the constant of variation a. Substitute 24 for z, 4 for x, and –3 for y. 24 = a(4)(– 3) 24 = –12a –2 =a Simplify. Solve for a. GUIDED PRACTICE for Examples 5 and 6 STEP 3 Rewrite the joint variation equation with the value of a from Step 2. z = – 2 xy STEP 4 Calculate z when x = – 2 and y = 5 using substitution. z = – 2 xy = – 2 (– 2)(5) = 20 ANSWER z = – 2 xy ; 20 GUIDED PRACTICE for Examples 5 and 6 The variable z varies jointly with x and y. Use the given values to write an equation relating x, y, and z. Then find z when x = –2 and y = 5. 11. x = –2, y = 6, z = 18 SOLUTION STEP 1 Write a general joint variation equation. z = axy GUIDED PRACTICE for Examples 5 and 6 STEP 2 Use the given values of z, x, and y to find the constant of variation a. 18 = a(– 2)(6) Substitute 18 for z, – 2 for x, and 6 for y. 18 = –12a Simplify. – 3 =a Solve for a. 2 STEP 3 Rewrite the joint variation equation with the value of a from Step 2. z = – 3 xy 2 GUIDED PRACTICE for Examples 5 and 6 STEP 4 Calculate z when x = – 2 and y = 5 using substitution. z = – 3 xy = – 3 (– 2)(5) = 15 2 2 ANSWER z = – 3 xy ; 15 2 GUIDED PRACTICE for Examples 5 and 6 The variable z varies jointly with x and y. Use the given values to write an equation relating x, y, and z. Then find z when x = –2 and y = 5. 12. x = –6, y = – 4, z = 56 SOLUTION STEP 1 Write a general joint variation equation. z = axy GUIDED PRACTICE for Examples 5 and 6 STEP 2 Use the given values of z, x, and y to find the constant of variation a. 56 = a(– 6)(–4) Substitute 56 for z, – 6 for x, and – 4 for y. 56 = 24a 7 3 =a Simplify. Solve for a. STEP 3 Rewrite the joint variation equation with the value of a from Step 2. z = 7 xy 3 GUIDED PRACTICE for Examples 5 and 6 STEP 4 Calculate z when x = – 2 and y = 5 using substitution. z = 7 xy = 7 (– 2)(5) = – 70 3 3 3 ANSWER z = 7 xy ; – 70 3 3 GUIDED PRACTICE for Examples 5 and 6 Write an equation for the given relationship. 13. x varies inversely with y and directly with w. SOLUTION x= a w y 14. p varies jointly with q and r and inversely with s. SOLUTION p = aqr s
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