4-3 The Second Derivative Test What does the 2nd derivative f tell us about f ? Definition: Concavity Suppose that f is differentiable on an interval I. f is said to be concave up on I if f is increasing on I. f is said to be concave down on I if f is decreasing on I. Theorem: Suppose that f exists on an interval I If f ( x) 0 on I, then f is concave up on I If f ( x) 0 on I, then f is concave down on I Definition: Inflection Point Suppose f is continous on an open interval I The point (c, f (c)) is called an inflection point if f changes from concave up to concave down (or from concave down to concave up) at point c Determine the inflection points and the intervals on which 4 3 f ( x) x 4x 1 3 is concave up and concave down. Second Derivative Test for Local Extrema Suppose f is continuous on the interval (a, b) and c(a,b) is a critical number for which f (c) 0 . If f (c) 0 , then f (c) is a local maximum. If f (c) 0 , then f (c) is a local minimum. If f (c) 0 or f (c) is undefined, then we can conclude nothing. Determine the local extrema of 4 3 f ( x) x 4x 1 3 If c is a critical number, but f (c) 0 or undefined, you can tell nothing about local extrema. Ex. f (x) x4 f (x) 4x3 f (x) 12x2 f ( x) x4 f ( x) 4x3 f ( x) 12x2 f ( x) x3 f (x) 3x2 f (x) 6x Note: all three graphs have a critical number at c=0 f (0) 0 If we look at the graphs: The graph may have a local minimum, local maximum or neither Some Notes on the Second Derivative Test The second derivative test is nice to use because, in most cases, it is easier to use than the first derivative test o Find the critical numbers c for which fʹ(x)=0 o Determine the sign of fʹʹ by substituting each c into fʹʹ However, there are some restrictions: It cannot be used for critical numbers for which fʹ is undefined It cannot be use if fʹ(c)=0 and fʹʹ(c)=0 In either of these cases, we say “The Second Derivative Test Fails” If the 2nd Derivative Test fails, you need to use the 1st Derivative test to determine whether is a local extremum or not.
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