Integers and Absolute Value Unit 1 Lesson 5 Integers and Absolute Value Students will be able to: Understand integers and absolute value Key Vocabulary: An integer Positive number Negative number Absolute value Opposite Integers and Absolute Value Integers β’ An integer is a positive or negative whole number. β’ A positive number is a number greater than zero. β’ A negative number is a number less than zero. Integers and Absolute Value This number line shows integers. Negative integers -6 -5 -4 -3 -2 Positive integers -1 0 1 2 3 4 5 Zero is neither positive nor negative 6 Integers and Absolute Value Sample Problem 1: Write an integer to represent each situation. a. ππ ππ below sea level Integers and Absolute Value Sample Problem 1: Write an integer to represent each situation. a. ππ ππ below sea level βππ Integers and Absolute Value Sample Problem 1: Write an integer to represent each situation. b. a bonus of $πππ Integers and Absolute Value Sample Problem 1: Write an integer to represent each situation. b. a bonus of $πππ +πππ Integers and Absolute Value Sample Problem 1: Write an integer to represent each situation. c. π points lost Integers and Absolute Value Sample Problem 1: Write an integer to represent each situation. c. π points lost βπ Integers and Absolute Value Sample Problem 2: Graph each integer or set of integers on a number line. a. βπ Integers and Absolute Value Sample Problem 2: Graph each integer or set of integers on a number line. a. βπ -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Integers and Absolute Value Sample Problem 2: Graph each integer or set of integers on a number line. b. βπ, π, π Integers and Absolute Value Sample Problem 2: Graph each integer or set of integers on a number line. b. βπ, π, π -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Integers and Absolute Value Sample Problem 2: Graph each integer or set of integers on a number line. c. βπ, βπ, π, π Integers and Absolute Value Sample Problem 2: Graph each integer or set of integers on a number line. c. βπ, βπ, π, π -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Integers and Absolute Value β’ Every integer has an opposite integer. β’ A number and its opposite are the same distance from 0. Integers and Absolute Value Sample Problem 3: Find the opposite of each integer. a. βππ Integers and Absolute Value Sample Problem 3: Find the opposite of each integer. a. βππ +ππ Integers and Absolute Value Sample Problem 3: Find the opposite of each integer. b. +πππ Integers and Absolute Value Sample Problem 3: Find the opposite of each integer. b. +πππ βπππ Integers and Absolute Value Sample Problem 3: Find the opposite of each integer. c. π Integers and Absolute Value Sample Problem 3: Find the opposite of each integer. c. π None opposite Integers and Absolute Value Sample Problem 4: Graph each integer and its opposite on a number line. a. βπ Integers and Absolute Value Sample Problem 4: Graph each integer and its opposite on a number line. a. βπ -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Integers and Absolute Value Sample Problem 4: Graph each integer and its opposite on a number line. b. π Integers and Absolute Value Sample Problem 4: Graph each integer and its opposite on a number line. b. π -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Integers and Absolute Value Sample Problem 4: Graph each integer and its opposite on a number line. c. βπ Integers and Absolute Value Sample Problem 4: Graph each integer and its opposite on a number line. c. βπ -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Integers and Absolute Value Sample Problem 5: Compare the following integers. Write <, = ππ >. a. ππ _____ β πππ Integers and Absolute Value Sample Problem 5: Compare the following integers. Write <, = ππ >. a. ππ > βπππ Integers and Absolute Value Sample Problem 5: Compare the following integers. Write <, = ππ >. b. ππ_______ β ππ Integers and Absolute Value Sample Problem 5: Compare the following integers. Write <, = ππ >. b. ππ > βππ Integers and Absolute Value β’ The absolute value of a number is the distance between 0 and the number on a number line. β’ Remember that distance is always a positive quantity (or zero). β’ Two vertical bars are used to represent absolute value. The symbol for absolute value of π is π . Integers and Absolute Value Sample Problem 6: Find the absolute value of the following numbers. a. βππ = Integers and Absolute Value Sample Problem 6: Find the absolute value of the following numbers. a. βππ = βππ = ππ Integers and Absolute Value Sample Problem 6: Find the absolute value of the following numbers. b. +ππ = Integers and Absolute Value Sample Problem 6: Find the absolute value of the following numbers. b. +ππ = +ππ = ππ Integers and Absolute Value Sample Problem 6: Find the absolute value of the following numbers. c. βπ, πππ = Integers and Absolute Value Sample Problem 6: Find the absolute value of the following numbers. c. βπ, πππ = βπ, πππ = π, πππ Integers and Absolute Value Sample Problem 7: Order the values from least to greatest. a. βππ , ππ, βπ, βπ Integers and Absolute Value Sample Problem 7: Order the values from least to greatest. a. βππ , ππ, βπ, βπ βππ = ππ βπ = π ππ, ππ, βπ, π βπ, π, ππ, ππ βπ, βπ , ππ, βππ Integers and Absolute Value Sample Problem 7: Order the values from least to greatest. b. π, +ππ , βπ , βπ, βππ Integers and Absolute Value Sample Problem 7: Order the values from least to greatest. b. π, +ππ , βπ , βπ, βππ +ππ = ππ π, βπ = π βππ = ππ ππ, π, βπ, ππ βπ, π, π, ππ, ππ βπ, π, βπ , βππ , +ππ Integers and Absolute Value Sample Problem 8: Evaluate each of the following expressions. a. βππ + ππ β ππ = Integers and Absolute Value Sample Problem 8: Evaluate each of the following expressions. a. βππ + ππ β ππ = = ππ + ππ β ππ = = ππ β ππ = = ππ Integers and Absolute Value Sample Problem 8: Evaluate each of the following expressions. b. ππ β +ππ β βπ = Integers and Absolute Value Sample Problem 8: Evaluate each of the following expressions. b. ππ β +ππ β βπ = = ππ β ππ β π = = ππ β π = =π Integers and Absolute Value Sample Problem 8: Evaluate each of the following expressions. c. πππ + βπ β ππ β βπ = Integers and Absolute Value Sample Problem 8: Evaluate each of the following expressions. c. πππ + βπ β ππ β βπ = = πππ + π β ππ β π = = πππ + ππ β π = = πππ + πππ = = πππ
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