Math 111 Week 6 Homework Due 2/16/2016 9.5 Problems #75 to 80 75. Write the matrix here: 76. Answer the question. _4______ Describe how the matrix shows that this page can be reached by one click from any other web page: The four 1s in column 4 show that page 4 can reach each of the other pages in a single click. 77. Write π΄2 here: 78. Answer the question. ____________________ Pages 1 and 2 cannot be reached using two click path from any other page in the network. 79. __There are two different 2-click paths from page 2 to page 3._ 80. __You can get from pge 4 back to page 4 in 2 clicks._ 9.6 #72 on page 779 (a) Nothing to write here, just read the traffic map and see why the equations work. (b) Show the matrix equation: Show what you enter in your calculator to solve this system: You can show either of these: π₯1 1 0 0 0 1 0 0 0 5 5 π₯2 β1 1 0 0 β1 1 0 0 β3 β3 [ ]β[π₯ ] = [ ] [ ] β [π΄] [ ] β [π΅] , [π΄]β1 β [π΅] = 0 β1 1 0 0 β1 1 0 3 3 3 π₯ 0 0 1 1 4 0 0 1 1 11 11 or 1 0 0 1 1 0 [ 1 1 1 β1 β1 β1 π₯1 0 5 π₯ 0 β3 2 ]β[ ]=[π₯ ] 0 3 3 π₯4 1 11 Show the matrix result: 5 2 [ ] 5 6 (c) What does your result mean about traffic? Between intersection A and B there are 5 cars per minute, 2 cars per minute between B and C, 5 cars per minute between C and D and 6 cars per minute between A and D. 9.7 #36 on page 787 Create three triangles, and yours may be different than mine. The left-hand triangle gives first matrix, the middle triangle gives the middle matrix, and the last triangle goes with the third matrix. After saving each matrix, I completed the calculation below on my calculator: Left Triangle: Middle Triangle: Right Triangle: The area of the shaded pentagon is 26. No units were given. 9.7 Extended and Discovery #10 Show the matrix before you take the determinant. And I am going to show my work: ππ + ππ π π π π π π] = π πππ [ π π βπ π π ππ π π π ππ + ππ πππ [ π π ππ π π βπ π π π π π π π] π π π π π π π π π π π π π π = (ππ + ππ ) [βπ π π] β π [ π π π] + π [ π βπ π] β π [ π βπ π] π π π ππ π π ππ π π ππ π π =π = (ππ + ππ )(βπ) β π(βππ) + π(ππ) β π(π) = π Evaluating the determinants βπππ + πππ β πππ + πππ β π = π Reorganizing in order to complete the squares ππ β ππ + ππ β ππ + π = π Divide both sides by β π. (ππ β ππ + π) + (ππ β ππ + π) = π Complete both squares. Set equal to constant What is the equation of the circle? (π β π)π +(π β π)π = π The circle has center (-1, -2) and the radius is 2.
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