Answer on Question #51833-Physics-Other 1) A record turntable rotating at 34 rev/min slows down and stops in 30s after the motor is turned off a) Find its (constant) angular acceleration in revolution per minute-squared b) How many revolutions does it make in this time? Solution a) An angular acceleration is rev βπ π β 0 34 min rev πΌ= = = = 68 . βπ‘ βπ‘ 0.5 πππ min2 b) rev πΌβπ‘ 2 πβπ‘ πβπ‘ 34 min β 0.5 πππ π = πβπ‘ β = πβπ‘ β = = = 8.5 πππ£. 2 2 2 2 Answer: a) ππ π«ππ― π¦π’π§π b) π. π. 2) A uniform solid ball rolls smoothly along a floor, then up a ramp inclined at 30.0^(o).It momentarily stops when it has rolled 1.0m along the ramp. What was its initial speed? Solution According to the conservation of energy law: πΈπ‘ππππ πππ‘πππ + πΈπππ‘ππ‘πππ = πΈπππ‘πππ‘πππ , where πΈπ‘ππππ πππ‘πππ = ππ£ 2 2 is initial translational kinetic energy of the ball, πΈπππ‘ππ‘πππ = πΌπ2 2 is initial rotational kinetic energy of the ball, πΈπππ‘πππ‘πππ = ππβ = πππ sin 30 is final gravitational potential energy of the ball. For a solid ball: 2 πΌ = ππ 2 , 5 where π is a mass of ball, π is a radius of ball. So, πΈπππ‘ππ‘πππ = πΌπ2 1 2 ππ£ 2 = ππ 2 π2 = . 2 25 5 Thus, ππ£ 2 ππ£ 2 + = πππ sin 30. 2 5 7 2 1 π£ = ππ β . 10 2 The initial speed is 5ππ 5 β 9.8 β 1.0 π π£=β =β = 2.6 . 7 7 π π Answer: π. π π . http://www.AssignmentExpert.com/
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