Answer on Question #51833-Physics

Answer on Question #51833-Physics-Other
1) A record turntable rotating at 34 rev/min slows down and stops in 30s after the motor is turned off
a) Find its (constant) angular acceleration in revolution per minute-squared
b) How many revolutions does it make in this time?
Solution
a) An angular acceleration is
rev
βˆ†πœ” πœ” βˆ’ 0 34 min
rev
𝛼=
=
=
= 68
.
βˆ†π‘‘
βˆ†π‘‘
0.5 π‘šπ‘–π‘›
min2
b)
rev
π›Όβˆ†π‘‘ 2
πœ”βˆ†π‘‘ πœ”βˆ†π‘‘ 34 min βˆ™ 0.5 π‘šπ‘–π‘›
𝑁 = πœ”βˆ†π‘‘ βˆ’
= πœ”βˆ†π‘‘ βˆ’
=
=
= 8.5 π‘Ÿπ‘’π‘£.
2
2
2
2
Answer: a) πŸ”πŸ–
𝐫𝐞𝐯
𝐦𝐒𝐧𝟐
b) πŸ–. πŸ“.
2) A uniform solid ball rolls smoothly along a floor, then up a ramp inclined at 30.0^(o).It momentarily stops
when it has rolled 1.0m along the ramp. What was its initial speed?
Solution
According to the conservation of energy law:
πΈπ‘‘π‘Ÿπ‘Žπ‘›π‘ π‘™π‘Žπ‘‘π‘–π‘œπ‘› + πΈπ‘Ÿπ‘œπ‘‘π‘Žπ‘‘π‘–π‘œπ‘› = πΈπ‘π‘œπ‘‘π‘’π‘›π‘‘π‘–π‘Žπ‘™ ,
where πΈπ‘‘π‘Ÿπ‘Žπ‘›π‘ π‘™π‘Žπ‘‘π‘–π‘œπ‘› =
π‘šπ‘£ 2
2
is initial translational kinetic energy of the ball, πΈπ‘Ÿπ‘œπ‘‘π‘Žπ‘‘π‘–π‘œπ‘› =
πΌπœ”2
2
is initial rotational
kinetic energy of the ball, πΈπ‘π‘œπ‘‘π‘’π‘›π‘‘π‘–π‘Žπ‘™ = π‘šπ‘”β„Ž = π‘šπ‘”π‘™ sin 30 is final gravitational potential energy of the ball.
For a solid ball:
2
𝐼 = π‘šπ‘Ÿ 2 ,
5
where π‘š is a mass of ball, π‘Ÿ is a radius of ball. So,
πΈπ‘Ÿπ‘œπ‘‘π‘Žπ‘‘π‘–π‘œπ‘› =
πΌπœ”2 1 2
π‘šπ‘£ 2
=
π‘šπ‘Ÿ 2 πœ”2 =
.
2
25
5
Thus,
π‘šπ‘£ 2 π‘šπ‘£ 2
+
= π‘šπ‘”π‘™ sin 30.
2
5
7 2
1
𝑣 = 𝑔𝑙 βˆ™ .
10
2
The initial speed is
5𝑔𝑙
5 βˆ™ 9.8 βˆ™ 1.0
π‘š
𝑣=√
=√
= 2.6 .
7
7
𝑠
π’Ž
Answer: 𝟐. πŸ” 𝒔 .
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