Lesson 14: Graphing Factored Polynomials Classwork Opening Exercise An engineer is designing a roller coaster for younger children and has tried some functions to model the height of the roller coaster during the first 300 yards. She came up with the following function to describe what she believes would make a fun start to the ride: π»(π₯) = β3π₯ 4 + 21π₯ 3 β 48π₯ 2 + 36π₯, where π»(π₯) is the height of the roller coaster (in yards) when the roller coaster is 100π₯ yards from the beginning of the ride. Answer the following questions to help determine at which distances from the beginning of the ride the roller coaster is at its lowest height. a. Does this function describe a roller coaster that would be fun to ride? Explain. b. Can you see any obvious π₯-values from the equation where the roller coaster is at height 0? c. Using a graphing utility, graph the function π» on the interval 0 β€ π₯ β€ 3, and identify when the roller coaster is 0 yards off the ground. d. What do the π₯-values you found in part (c) mean in terms of distance from the beginning of the ride? e. Why do roller coasters always start with the largest hill first? f. Verify your answers to part (c) by factoring the polynomial function π». g. How do you think the engineer came up with the function for this model? h. What is wrong with this roller coaster model at distance 0 yards and 300 yards? Why might this not initially bother the engineer when she is first designing the track? Discussion: Based on what we have discussed in this course so far related to polynomial functions, what can you say about the roller coaster function, π»(π₯), and its graph? Example 1 Graph each of the following polynomial functions. What are the functionβs zeros (counting multiplicities)? What are the solutions to π(π₯) = 0? What are the π₯-intercepts to the graph of the function? How does the degree of the polynomial function compare to the π₯-intercepts of the graph of the function? a. π(π₯) = π₯(π₯ β 1)(π₯ + 1) b. π(π₯) = (π₯ + 3)(π₯ + 3)(π₯ + 3)(π₯ + 3) c. π(π₯) = (π₯ β 1)(π₯ β 2)(π₯ + 3)(π₯ + 4)(π₯ + 4) d. π(π₯) = (π₯ 2 + 1)(π₯ β 2)(π₯ β 3) Example 2 Consider the function π(π₯) = π₯ 3 β 13π₯ 2 + 44π₯ β 32. a. Use the fact that π₯ β 4 is a factor of π to factor this polynomial. b. Find the π₯-intercepts for the graph of π. c. At which π₯-values can the function change from being positive to negative or from negative to positive? d. To sketch a graph of π, we need to consider whether the function is positive or negative on the four intervals π₯ < 1, 1 < π₯ < 4, 4 < π₯ < 8, and π₯ > 8. Why is that? e. How can we tell if the function is positive or negative on an interval between π₯-intercepts? f. For π₯ < 1, is the graph above or below the π₯-axis? How can you tell? g. For 1 < π₯ < 4, is the graph above or below the π₯-axis? How can you tell? h. For 4 < π₯ < 8, is the graph above or below the π₯-axis? How can you tell? i. For π₯ > 8, is the graph above or below the π₯-axis? How can you tell? j. Use the information generated in parts (f)β(i) to sketch a graph of π. k. Graph π¦ = π(π₯) on the interval from [0,9] using a graphing calculator, and compare your sketch with the graph generated by the graphing calculator. Discussion: Discussion For any particular polynomial, can we determine how many relative maxima or minima there are? Consider the following polynomial functions in factored form and their graphs. π(π₯) = (π₯ + 1)(π₯ β 3) π(π₯) = (π₯ + 3)(π₯ β 1)(π₯ β 4) β(π₯) = (π₯)(π₯ + 4)(π₯ β 2)(π₯ β 5) Degree of each polynomial: Number of π₯-intercepts in each graph: Number of relative maximum and minimum points shown in each graph: What observations can we make from this information? Is this true for every polynomial? Consider the examples below. π(π) = ππ + π π(π) = (ππ + π)(π β π) Degree of each polynomial: Number of π₯-intercepts in each graph: Number of relative maximum and minimum points shown in each graph: What observations can we make from this information? π(π) = (π + π)(π β π)(π β π)(π β π) Lesson Summary A polynomial of degree π may have up to π π₯-intercepts and up to π β 1 relative maximum/minimum points. The function π has a relative maximum at π if there is an open interval around π so that for all π₯ in that interval, π(π₯) β€ π(π). That is, looking near the point (π, π(π)) on the graph of π, there is no point higher than (π, π(π)) in that region. The value π(π) is a relative maximum value. The function π has a relative minimum at π if there is an open interval around π so that for all π₯ in that interval, π(π₯) β₯ π(π). That is, looking near the point (π, π(π)) on the graph of π, there is no point lower than (π, π(π)) in that region. The value π(π) is a relative minimum value. The plural of maximum is maxima, and the plural of minimum is minima. Problem Set 1. For each function below, identify the largest possible number of π₯-intercepts and the largest possible number of relative maxima and minima based on the degree of the polynomial. Then use a calculator or graphing utility to graph the function and find the actual number of π₯-intercepts and relative maxima and minima. a. π(π₯) = 4π₯ 3 β 2π₯ + 1 b. π(π₯) = π₯ 7 β 4π₯ 5 β π₯ 3 + 4π₯ c. β(π₯) = π₯ 4 + 4π₯ 3 + 2π₯ 2 β 4π₯ + 2 Function 2. a. π b. π c. β Largest number of π-intercepts 1 2 Largest number of relative max/min Actual number of π-intercepts Actual number of relative max/min Sketch a graph of the function π(π₯) = (π₯ + 5)(π₯ + 1)(π₯ β 2) by finding the zeros and determining the sign of the values of the function between zeros. 3. Sketch a graph of the function π(π₯) = β(π₯ + 2)(π₯ β 4)(π₯ β 6) by finding the zeros and determining the sign of the values of the function between zeros. 4. Sketch a graph of the function π(π₯) = π₯ 3 β 2π₯ 2 β π₯ + 2 by finding the zeros and determining the sign of the values of the function between zeros. 5. A function π has zeros at β1, 3, and 5. We know that π(β2) and π(2) are negative, while π(4) and π(6) are positive. Sketch a graph of π. 6. The function β(π‘) = β16t 2 + 33t + 45 represents the height of a ball tossed upward from the roof of a building 45 feet in the air after π‘ seconds. Without graphing, determine when the ball will hit the ground.
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