Approximate North
Main Gate
TBM
9.09 m A.A.D.
Burnaby Building
Top of door level at entrance to structures laboratory
Ground level at entrance to structures laboratory
TBM
10.00 m A.A.D.
Point 1
Start at a TBM outside the main entrance of Burnaby Building and obtain the
RL values of three points before closing onto another TBM near the main gate.
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
HPC
RL
Corr
Corr RL
M.A.R.
Remarks
TBM 10.00m AAD
It is important to complete details at the top of booking forms or
on every page of field books.
Key
TBM
Level Posn.
BS
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
1.546
HPC = RL + BS
HPC
RL
11.546 10.000
Corr
Corr RL
M.A.R.
Remarks
TBM 10.00m AAD
HPC = 10.000 + 1.546 = 11.546
We now signal to the staff person to move to the next point.
As the next required point is too far away (it is also round a corner)
we will eventually need to move the instrument.
So, we must move the staff to a change point (CP), to allow us to move the
instrument to a better position later on.
Key
TBM
CP
Level Posn.
BS
FS
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
1.546
HPC
RL
11.546 10.000
1.562
9.984
RL = HPC - FS
Corr
Corr RL
M.A.R.
Remarks
TBM 10.00m AAD
C.P.
New staff
position
therefore
a new row.
Each row
represents
a staff
position.
RL = 11.546 - 1.562 = 9.984
After we make a FS and we have calculated the new RL we are finished
with that instrument position.
Move the Instrument (about the CP) to a new position where we can see the CP
and also the next point we want the RL value of.
Key
TBM
CP
Level Posn.
BS
FS
IS
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
HPC
RL
Corr
1.546
11.546 10.000
1.418
1.562 11.402 9.984
HPC = RL + BS
Corr RL
M.A.R.
Remarks
TBM 10.00m AAD
C.P.
HPC = 9.984 + 1.418 = 11.402
Same staff
position as
last reading
therefore
the same row
Key
TBM
CP
Level Posn.
BS
FS
IS
It isThis
not So
reading
the itlast
is known
from
is notthis
the
as position
an
firstINTERMEDIATE
so it(we
is not
canasee
BSSIGHT
the next(IS)
points) so it is not a FS
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
HPC
RL
1.546
11.546 10.000
1.418
1.562 11.402 9.984
1.390
10.012
RL = HPC - IS
Corr
Corr RL
M.A.R.
Remarks
TBM 10.00m AAD
C.P.
Point 1
RL = 11.402 - 1.390 = 10.012
New staff
position
therefore
a new row
Key
TBM
CP
Level Posn.
BS
FS
IS
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
HPC
RL
1.546
11.546 10.000
1.418
1.562 11.402 9.984
1.390
10.012
1.281
RL = HPC - IS
10.121
Corr
Corr RL
M.A.R.
Remarks
TBM 10.00m AAD
C.P.
Point 1
GL Struct. Lab Door
RL = 11.402 - 1.281 = 10.121
New staff
position
therefore
a new row
Key
TBM
CP
Level Posn.
BS
FS
IS
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
HPC
RL
Corr
1.546
11.546 10.000
1.418
1.562 11.402 9.984
1.390
10.012
1.281
10.121
-2.420
13.822
Requires an inverted staff
M.A.R.
Corr RL
Remarks
TBM 10.00m AAD
C.P.
Point 1
GL Struct. Lab Door
New staff
position
Top Struct. Lab Door
therefore
a new row
i.e turn the staff upside down
Read and then book the staff with a negative sign
The negative sign will keep all the calculations correct
RL = HPC - IS
RL = 11.402 - (-2.420) = 11.402 + 2.420 = 13.822
Key
TBM
CP
Level Posn.
BS
FS
IS
The last point
So we
required
need aisCP.
theThis
TBM.
willHowever
be theTherefore
last
it issighting
too long
a FS
from
a sight.
this position
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
HPC
1.546
11.546
1.418
1.562 11.402
RL
10.000
M.A.R.
Cor r
Corr RL
Remarks
TBM 10.00m AAD
9.984
C.P.
1.390
10.012
Point 1
1.281
-2.420
10.121
13.822
1.321
RL = HPC - FS
GL Struct. Lab Door
Top Struct. Lab Door
10.081
CP
RL = 11.402 - 1.321 = 10.081
Last Reading -- FS -- Move the instrument
New staff
position
therefore
a new row
Key
TBM
CP
Level Posn.
BS
FS
IS
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
HPC
1.546
11.546
1.418
1.562 11.402
1.011
RL
10.000
M.A.R.
Cor r
Corr RL
Remarks
TBM 10.00m AAD
9.984
C.P.
1.390
10.012
Point 1
1.281
-2.420
10.121
13.822
1.321
HPC = RL + BS
GL Struct. Lab Door
Top Struct. Lab Door
11.092 10.081
HPC = 10.081 + 1.011 = 11.092
CP
Same staff
position as
last reading
therefore
the same row
Key
TBM
CP
Level Posn.
BS
FS
IS
Burnaby Building
L 52
Site:
………………………………….
Instrument:
………………………………….
Date:
07/10/98
………………………………….
Observer:
M.A.R.
………………………………….
Weather:
Good
………………………………….
Booker:
………………………………….
BS
IS
FS
HPC
RL
1.546
11.546
1.418
1.562 11.402
1.011
10.000
M.A.R.
Cor r
Corr RL
Remarks
TBM 10.00m AAD
9.984
C.P.
1.390
10.012
Point 1
1.281
-2.420
10.121
13.822
1.321
2.007
RL = HPC - FS
GL Struct. Lab Door
Top Struct. Lab Door
11.092 10.081
9.085
CP
TBM 9.09m AAD
RL = 11.092 - 2.007 = 9.085
New staff
position
therefore
a new row
Before we look more fully at the results we will complete the
second half of the levelling exercise
Key
TBM
CP
Level Posn.
BS
FS
IS
Top of door level at entrance to structures laboratory
Ground level at entrance to structures laboratory
Point 2
Key
TBM
CP
Level Posn.
BS
FS
IS
Key
TBM
CP
Level Posn.
BS
FS
IS
Key
TBM
CP
Level Posn.
BS
FS
IS
Key
TBM
CP
Level Posn.
BS
FS
IS
Key
TBM
CP
Level Posn.
BS
FS
IS
Key
TBM
CP
Level Posn.
BS
FS
IS
Key
TBM
CP
Level Posn.
BS
FS
IS
Key
TBM
CP
Level Posn.
BS
FS
IS
Key
TBM
CP
Level Posn.
BS
FS
IS
Key
TBM
CP
Level Posn.
BS
FS
IS