Kingdom of Saudi Arabia
Ministry of Education
House of Languages International Schools
Math & Computer
Department
Grade 8
HOLIS
Algebra 1 First Term Final Revision Sheets Gr.8
Page 1
Math Final Revision
Name : ……………………………………..…
Grade : 8
Algebra 1: Ch9 L1-L9
Q1: Choose the correct answer
1) Tell whether the function is quadratic. Explain.
x
y
0
21
1
2
9
4
37
a. No, the function is not quadratic. The second differences are not
constant.
b. Yes, the function is quadratic. The second differences are constant.
2) Tell whether the graph of the quadratic function
opens
upward or downward. Explain.
a.
b.
c.
d.
Because
Because
Because
Because
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, the parabola opens downward.
, the parabola opens downward.
, the parabola opens upward.
, the parabola opens upward.
Algebra 1 First Term Final Revision Sheets Gr.8
Page 2
3) Find the domain and range.
y
10
8
6
4
2
–10 –8
–6
–4
–2
–2
2
–4
4
6
8
10
x
(3, –5)
–6
–8
–10
a. D: all real numbers R:
b. D:
R:
c. D: all real numbers R:
d. D:
R: all real numbers
4) Identify the vertex of the parabola. Then give the minimum or maximum
value of the function.
y
10
8
(3, 6)
6
4
2
–10 –8
–6
–4
–2
–2
2
4
6
8
10
x
–4
–6
–8
–10
a.
b.
c.
d.
The vertex is
The vertex is
The vertex is
The vertex is
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, and the minimum is 6.
, and the maximum is 6.
, and the maximum is 3.
, and the minimum is 3.
Algebra 1 First Term Final Revision Sheets Gr.8
Page 3
5) Find the zeros of the quadratic function
from the graph.
y
10
8
6
4
2
–10 –8
–6
–4
–2
–2
2
4
6
8
10
x
–4
–6
–8
–10
c. –8
d. 2 and –8
a. 1.5
b. 4 and –1
6) Find the axis of symmetry of the parabola.
y
10
8
6
4
2
–10 –8
–6
–4
–2
–2
2
4
6
8
10
x
–4
–6
–8
–10
a.
b.
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c.
d.
Algebra 1 First Term Final Revision Sheets Gr.8
Page 4
7) Find the vertex of the parabola
.
y
10
8
6
4
2
–10 –8
–6
–4
–2
–2
2
4
6
8
10
x
–4
–6
–8
–10
a. (–3, 2)
c. (–2, 0) and (–4, 0)
b. (2, –3)
d. (3, –70)
8) Sketch a graph of the equation.
y
a.
–6
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–4
–2
y
c.
6
6
4
4
2
2
O
2
4
6
x
–6
–4
–2
O
–2
–2
–4
–4
–6
–6
2
4
Algebra 1 First Term Final Revision Sheets Gr.8
6
x
Page 5
y
b.
–6
–4
–2
y
d.
6
6
4
4
2
2
O
2
4
6
x
–6
–4
–2
O
–2
–2
–4
–4
–6
–6
2
4
6
x
9) Order the functions from narrowest graph to widest graph.
,
,
a.
b.
,
, and
,
,
c.
d.
,
,
,
,
10) A rectangular picture measuring 5 in. by 9 in. is surrounded by a frame
with uniform width x. Write a quadratic function in standard form to show
the combined area of the picture and frame.
a.
b.
c.
d.
2
1
x2 – 2 with the graph of
.
a. The graph of
 x – 2 is narrower than the graph of
. The
1 2
 2 x – 2 opens downward, and the graph of
graph of
opens upward. The axis of symmetry is the same. The vertex of
1
 2 x2 – 2 is translated down 2
is (0, 0). The vertex of
units to (0, –2).
1
b. The graph of
 2 x2 – 2 is wider than the graph of
. The
1 2
 2 x – 2 opens downward, and the graph of
graph of
opens upward. The axis of symmetry is the same. The vertex of
1
 2 x2 – 2 is translated up 2 units to
is (0, 0). The vertex of
(0, 2).
11) Compare the graph of
1
2
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2
Algebra 1 First Term Final Revision Sheets Gr.8
Page 6
1
c. The graph of
 2 x2 – 2 is wider than the graph of
. The
1 2
 2 x – 2 opens upward, and the graph of
graph of
opens
upward. The axis of symmetry is the same. The vertex of
is (0,
1 2
 2 x – 2 is translated down 2 units to (0, –2).
0). The vertex of
1 2
d. The graph of
 2 x – 2 is wider than the graph of
. The
1 2
 2 x – 2 opens downward, and the graph of
graph of
opens upward. The axis of symmetry is the same. The vertex of
1
 2 x2 – 2 is translated down 2
is (0, 0). The vertex of
units to (0, –2).
12) Use the Zero Product Property to solve the equation
a. The solutions are –2 and 1.
b. The solutions are 4 and –3.
c. The solutions are –4 and 3.
d. The solutions are 2 and –1.
13) Solve the quadratic equation
a. –4 and 2
b. 4 and 2
by factoring.
c. –4 and –2
d. 4 and –2
14) Solve the quadratic equation
a. 4
b. 1
.
by factoring.
c. 13
d. –1
15) The height of an arrow that is shot upward at an initial velocity of 40
meters per second can be modeled by
, where h is the height in
meters and t is the time in seconds. Find the time it takes for the arrow to
reach the ground.
a. 6 sec
b. 4 sec
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c. 8 sec
d. 2 sec
Algebra 1 First Term Final Revision Sheets Gr.8
Page 7
16) Solve
by using square roots.
a. The solutions are 2 and –2.
b. The solution is 2.
c. There is no solution.
d. The solution is –2.
17) Solve 64x2 – 121 = 0 by using square roots.
a. ± 118
64
b. ± 121
18) Solve
c. No solution
d. ± 118
. If necessary, round to the nearest hundredth.
a. 3.16
b. 100
c. 20
d. There is no solution as you cannot take the square root of a negative
number.
19) Complete the square for
a.
b.
20) Solve
c.
d.
by completing the square.
a. 3 and –2
b. 6 and –2
21) Solve
a. The solution is –5.
b. There is no solution.
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to form a perfect square trinomial.
c. 3 and 0
d. 6 and 3
by completing the square.
c. The solutions are –1 and 5.
d. The solutions are –1 and –5.
Algebra 1 First Term Final Revision Sheets Gr.8
Page 8
22) Solve
by using the Quadratic Formula.
a. x = 9 or x = 1
b. x = 1 or x = 9
c. x = 54 or x = 46
d. x = 18 or x = 2
23) Solve 3x2 – 6x + 1 = 0 by using the Quadratic Formula. If necessary,
round to the nearest hundredth.
a. x 1.82 or x 0.18
b. x 6.82 or x 5.18
c. There are no solutions.
d. x 10.90 or x 1.10
24) Find the number of solutions of the equation
by using the
discriminant.
a. There is one solution.
b. Cannot determine the number of solutions. The discriminant can only
be used for a quadratic equation, and
is not a quadratic
equation.
c. There are no real solutions.
d. There are two solutions.
25) Solve
a.
b.
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or
or
.
c.
d.
or
or
Algebra 1 First Term Final Revision Sheets Gr.8
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Algebra 1 First Term Final Revision Sheets Gr.8
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