A"
Student
Class
\C..£''f
Date
-----
_
Acceleration 3H
Use the acceleration equations on the Reference Table to answer the following
questions. Show all work on your notebook, formulas with substifution, Significant
figures and units.
1.
A ball rolling down an incline travels 0.060 m in the first 0.25
seconds, and 0.240 m in the first 0.50 seconds.
a. What is the average speed for the first 0.25 seconds?
:-; ~,-
-
cAl
-
At,
-
O.OGOM
z:
0.2S5
E]
o.
'2.4 ~
.5
b. What is the average speed for the second 0.25 seconds?
O.'L~Q-O.ObO
o.s o -
...
.
z:
(0.
72
.>
s
0.1.5
n. .
c. What is the ball's acceleration?
0.12-
AV
t:
O.2lt
- ~n-SJ
IM/.>
-
D.S-O -0.2..5.s
•
5'1
(z
2.
V·1-::0.0
cl-=-
M
A baseball starts from rest and rolls
seconds.
-
5
a. What is the baseball's acceleration?
5"0.0 ......
t-::(o.o~
_
d
V - - -t; -
$""0.0.......
-
\0.0.$
-
k
7.
,f,
COM
c- 00 -
()._-=.7
;:}
• 0-
_ ~_
I
OL_
-r.' -
What is the baseball's velocity aft~
~=
L(50.0~)
(\0.0..»'2..
::[00; 1
$"1-
-
$ -
"f-Vi. _
t::
-
(0.0-0,0
10.0 seconds?
IO.OV
lO.o~
~
$~
+l~~)
3.
'J,=4.o ~
An object has an in initial velocity of 4.0 m/s and a constant
acceleration of 2.0 m/s2. How far does it travel in 10.0 seconds?
5
'2..0 ~
Gt:=
i::
d=
d--
S't.
+ 1.
z..
It,-t'Z.
.
d::..
s
-I.t;~
+
too ~
~
Q49)1-vI
An object has an initial forward velocity of 25 m/s and a
constant acceleration of -1.5 m/s2. How far does it travel in
5.0 seconds?
d= V~t.+ _, atL
'l.
5
lto M
(IO.O~)'-
>'Z.-
2
s
?
z:
i: = S.O.s
d=
+ 1. (l.o.!::!)
d::{(f.o~)(IO.os)
Vi:::t5~
cA-::: (2-, ~ )(5.05) -+ .L (-l.~ ~ )( ~.o»
5
,?
a~-I.r;~
W\ea~J
.5'l.
t\te object
d:::
l~~
5.
2.-.s1--
-
1&.,5"'-'
=:
56.
25M
Vt
a
A soccer ball rolls to a stop from
speed of 21 m/s with an
2
acceleration of -2.0m/s • How far does it roll until it stops?
t:;' 21 """ 5>
o..-::;.-'LOWt/f,
"f -:=:- O. 0
d=
"2.
l'~
~l()\vl6 Jaw
--.J
I..
to.O}
4.
11 V\..-
V't_
l.
'W\l>
?
110.25
M
6.
A skateboarder rolls down Beach Avenue with an initial velocity
of 3.5 m/s. If her acceleration is 1.5 m/s2, how long will it
"i:::.':).5 ~ take her to reach the bottom 120 m away?
a.:::I. S"
_I -::: \
Ol
i: =-
1..
Vf
~l.
_J
z,
:::V L +
2. CA, til
"'" )"t.. + '2... (
",f;: (3 7c -;\if '\.=- '372.2 S ~:
LO "'"
'l.
I.~ !:! ) (11.0
I
?
,$"-
t;:
M )
Vf-\l~
a.
1'1·3 - 3.5"' ""'I.>
t;::
1.S W\ Is 1..
(t~tls)
('1 c.I is+ 7.
·A cyclist moving with constant velocity of 6.0 m/s forward passes
a car that is just starting. If the car has a constant
V'::: b.O~ _'I acceleration of 2.0 m/s2, where and when will the car overtake
I
5-~thecyclist?
If we +~te
+==0.05
w'-'e",
t(.·y-.rt~-et+)
Co.r
. ~
v; -:;0.0 ~
\AI
5
loA-
~
-e{
"v\~'t.t
w \.H be th e
,. -::: 2. 0 ~
/7',
e",
;:}
.....
'"
C'1Cll>'
t
-
0
'4
oh'J."rlC\(ekocf&-ft~
I
.1...
'L- -:::
== vi:
I r ,«
L~
(j_
0
L."
""
l
S .,- Q,'-\ T
2
(.i\t"l.
::;:(o.o~)t + ~('l..,o::.}t
5
(b)
=?
+;:.0 J
Jlf~e\(I1_~;::
An object moves for 3.0 seconds with constant acceleration,
during which time it travels 81 m. The acceleration ceases, and
during the next 3.0 seconds it travels 72 m.
::=. [}
'=
~,
t (t-b) =- 0
=0
d ~ v; t:::: ,
8.
j
<
)
~ 0 TLO V.
"2..
'l. .
V~t + J_
t'1.- 61::
O\V\J
_
5 ({ "",e .
J
a.=
+
-\{Me
O\_~~u'~
+~I
(:, ~ ~
t
.
?(L
b S]
,t\~{'
a. How would you describe its motion in the last 3.0 seconds?
$lV\ce
o: =- 0
C o..cc.ele
~"*l'O'"
Cecue 5 )
+tt e_
\V\..!)+(_'O~
.' b.
-::::>
v
=
2.? ;
V
d
= t
=
V (+-
..
L ~ ; ;;)
'I
"
A car travelling at 60.0 m/s forward slows down to 40.0 m/s
forward in 2.5 seconds. Assuming that this acceleration
continues, how many second~ would it take the car to slow to
9.
Vi:; b
0
.....J>
Vf~lto
""'/5
t'l
t:;.. 'l-. '7_.S
0\)
a. 12 m/s forward?
"0 -~o ......
'5
z:
?
V-f"::--o.o~ b. rest?
5
/::-:;..
Vf-
t::::
?
+
"..f-V~
ct
t::::
S
Z.~
Vf -::;:1?.,~/.s
i:>
b)
== Vf- V~
i7
Vi=:
~~fV\
VL
+~{'
",,0"'"
401-1/j
0.0 - ~c .....
IS
__ g
Ct
fv-o\.vo.
1N1J5L-
ft'\..., e
w'heV\
~e
V,' ~ c.,·o ~
>
---- 10.
\I'-OOW\
~\-
e,
at
___
_,)
.
\S) ~r'!""--
~.,?
~
>
A toy friction car is propelled forward from rest by a girl's
hand. The car reaches a forward velocity of 3.5 m/s in 0.40
seconds. The car is then released and later stops in 5.6 seconds.
o.,-=-
?
t.751
a. What is the acceleration with which the car speeds up?
t ,:;...0 .• 405
_'3_'
S_-_o_~_o_""'_I?_ ~
o. ~o .>
)1
b. What is the acceleration with which the car slows down?
0.0 - 3.~
-7
- O.bIS
5.b>
~
-
S"'L.
.~
c. How far did the toy car travel?
d =- cl, + d'2.
d,:= V~tl+ tali,
. d, ~
2·
:::(O.o~
~
)(0.40$)+
~(8.75~)(O,'tos)
O.,OW\
-'-z.= V·vt1...+l
G\
rJ'L ~ Cf.&
h'I
2.
a'"L-t~ ::::(:;.6~)(5.6»
s ,
+.1
(-O.bLS".>~){S.b»'"L
Z