CPT Mock Test – 3rd Duration : 2 Hours Test Booklet No. – 110017

CPT Mock Test – 3rd
Test Booklet No. – 110017
(1)
(2)
Ans. c
Explanation:
Cash Book
Add:
Pass Book
+
+
+
Duration : 2 Hours
Total Marks : 100
?
233
233
Ans. b
Explanation:
Cash Book
Less:
(3)
Date: - 25.10.2015
+


Ans. c
Explanation:
Interest = 150000 x 9% x
2
12
= 2250
(4)
Ans. d
Explanation:
Noting charges are borne by drawee in the event of dishonor of bill.
(5)
Ans. a
Explanation:
Pay B, Rs.500 on Presentment
(6)
Ans. a
Explanation:
Generally the value of land keeps on increasing.
(7)
Ans. d
Explanation:
Cost = 90000 + 10000 + 2000 = Rs. 102000
Annual expenses of insurance premium are not added to the cost of Asset.
(8)
Ans. c
Explanation:
Original cost = 150000 + 50000 = Rs.200000
Rate of Dep. = [1 −4 √
81920
200000
] x 100 = 20%
Dep. for 3rd year = (200000 − 20% − 20%) x 20% = Rs. 25600
(9)
Ans. a
Explanation:
Original Cost = 240000 + 20000 = Rs.260000
Depreciation = 260000 x 10% = Rs.26000
(10)
Ans. c
MITTAL COMMERCE CLASSES
1|Page
Explanation:
Original Cost = Rs.80000 + Rs.20000 = Rs.100000
Rate of Dep. = [1 −4 √
40960
100000
] x 100 = 20%
Dep. For 1st year. = 100000 x 20% x
6
12
= Rs.10000
(11)
Ans. d
Explanation:
Purchase return A/c is having credit balance.
(12)
Ans. a
Explanation:
Advance accounts are personal accounts by nature.
(13)
Ans. a
Explanation:
Interest A/c is shown in profit & loss A/c.
(14)
Ans. c
Explanation:
Drawings A/c Dr
To purchases A/c
(15)
Ans. c
Explanation:
Machinery A/c Dr.
To cash A/c
(16)
Ans. b
Explanation:
Loss of stock due to avoidable reasons, is abnormal loss.
(17)
Ans. d
Explanation:
Consignee does not pass such entries.
(18)
Ans. a
Explanation:
Let cost price be 100
Invoice price = 100 + 25 = 125
COGS 
750000
100  Rs .600000
125
Add: Consigner’s Exp. Rs. 10000
Total costs Rs. 610000
Lost goods = 610000 
1
 Rs .61000
10
Recovered value = Rs. 6000
Abnormal loss = 61000-6000 = Rs. 55000
(19)
Ans. c
MITTAL COMMERCE CLASSES
2|Page
Explanation:
Consignment A/c
Dr.
Particulars
To Op. Stock
To Goods sent
on consignment A/c
To Consignor’s Exp.
To Consignee’s Exp.
To Commission
To Del-Credere
Commission
(420000 × 2%)
To Net profit (B/F)
Rs.
20000
400000
10000
4000
5600
8400
Particulars
By sales:
Cash
Credit
By consignment Stock
Ans. b
Explanation:
Cost per unit 
200000
220000
100000
72000
520000
(20)
Cr.
Rs.
520000
(2000  3)  800  NIL  Rs.4
2000  15%
(21)
Ans. d
Explanation:
Name of the act is “The Indian Partnership Act, 1932”.
(22)
Ans. c
Explanation:
Partnership cannot be formed for carrying on charitable activities.
(23)
Ans. b
Explanation:
Int. an capital
‘X’ = 160000 × 9% = 14400
‘Y’ = 100000 × 9% = 9000
Total
23400
Share is to be distributed in capital Ratio i.e. 8:5, as profits are insufficient.
8
 9600
13
5
 6000
Y’s share = 15600 
13
X’s share = 15600 
(24)
Ans. a
Explanation:
Yr
Profits
I
4000
II
52200 – 4400
III
62400+4400-12400
Applying weights:
Yr
Adj. Profit
I
4000
MITTAL COMMERCE CLASSES
Weight
1



4000
47800
54400
Product
4000
3|Page
II
III
47800
54400
2
3
6
Weighted Avg. Adj. Profit =
95600
163200
262800
262800
 Rs .43800
6
Goodwill = 43800×1 = Rs.43800
(25)
Ans. a
Explanation:
A:B:C
5:3:7:5:4
Old Ratio
New Ratio
Sacrificing Ratio:
5 7
10  7
3
 

8 16
16
16
3 5
65
1
B  

8 16
16
16
A
Sacrificing Ratio = 3 : 1
(26)
Ans. a
Explanation:
D’s share of goodwill = 243000 
Old Ratio
New Ratio
Sacrificing Ratio
2
 Rs .54000
9
A:B:C:D
4:3:2:_
3:2:2:2
4 3 1
 
9 9 9
3 2 1
B  
9 9 9
2 2
C   0
9 9
A
Sacrificing Ratio = 1 : 1
Share in goodwill :
1
 Rs.27000
2
1
B  54000   Rs.27000
2
A  54000 
Goodwill withdrawn
1
 13500
2
1
B  27000   13500
2
A  27000 
(27)
Ans. c
Explanation:
MITTAL COMMERCE CLASSES
4|Page
Full value of goodwill = 9000 
6
 Rs .54000
1
(28)
Ans. a
Explanation:
Retiring partner can carry on competing business.
(29)
Ans. c
Explanation:
P&L suspense A/c Dr.
To partner’s capital A/c
(30)
Ans. a
Explanation:
Avg. Profit 
53600 + 57400 + 57800 + 48000 + 26800
 Rs .48720
5
Goodwill = 48720 × 3 = Rs. 146160
C’s share in Goodwill
= 146160 
4
 Rs . 36540
16
(31)
Ans. b
Explanation:
Because Indian contact act is not applicable to some matters like stamp value in
contract of sale of land etc.
(32)
Ans. c
Explanation:
Contract because according to section 2 (h) any agreement which is enforceable by
law is known as contract.
(33)
Ans. (a)
Explanation:
An offer to be valid should not contain a term the non-compliance of which would
amount to acceptance.
(34)
Ans. d
Explanation:
Because if there is no free consent then contract will be voidable.
(35)
Ans. c
Explanation:
Because contractual rights & liabilities come into existence by offer & acceptance &
these are made by parties.
(36)
Ans. b
Explanation:
Because every agreement is contract if enforceable by law. It means it is only
agreement which converted into contract if it contains all the essential elements.
(37)
Ans. a
MITTAL COMMERCE CLASSES
5|Page
Explanation:
Because every promise & set of promises forming consideration for each other is
agreement.
(38)
Ans. a
Explanation:
Law always protect the innocent party therefore all innocent promises collateral to
the main illegal promise contained in a contract will be regarded as valid.
(39)
Ans. b
An implied contract is one which is made otherwise than in words. In other words, it
is inferred from the circumstance of the particular case.
Hence in this case when A asks B, a watch repairer to repair his watch. the repairer
accepts the offer and in return A will pay the price for the repair. Thus rights and
obligations are created on the parties therefore it, amounts to implied contract.
(40)
Ans. b
Explanation:
Before An offer can be revoked before offeree put his acceptance into transit.
(41)
Ans. b
Explanation:
Because consideration may be given by any person
(42)
Ans. a
Explanation:
Because past services rendered must be voluntary and not involuntary.
(43)
Ans. b
Explanation:
Specific offer refers to the offer made to a definite person or group of persons. Such
an offer can be accepted by that specified person or group of persons only.
Here, in the given case the Law Book is offered to be sold only to members of ICAI
Council, hence it is a specific offer.
(44)
Ans. a
Explanation:
Because consideration may be insufficient.
(45)
Ans. d
Explanation:
Because Consideration need not to be adequate.
(46)
Ans. a
Explanation:
(47)
Ans. b
Explanation:
MITTAL COMMERCE CLASSES
6|Page
A contract is said to be tacit when it has to be interred from the conduct of the
parties. Obtaining cash through automatic teller machine is an example of the tacit
contract.
(48)
Ans. a
Explanation:
When the offeree offers to qualified acceptance of the offer subject to modifications
and variations in the terms of original offer, he is said to have made a counter offer.
A counter offer amounts to rejection of the original offer i.e. original offer ends or
lapeses.
(49)
Ans. b
Explanation:
Because consideration can be given by any person.
(50)
Ans. c
Explanation:
Because modern style is not certain therefore contract is void because of
uncertainty.
(51)
If the price of apples rises from Rs. 30 per kg. to Rs. 40 per kg and the supply
increases from 240 kg to Rs. 300 kg. Elasticity of supply is:
(a)
.77
(b)
.67
(c)
(-).67
(d)
(-).77
Ans. a
Explanation:
P1  30 / 
Q1  240 / 
P2  40 / 
Q2  300 / 
 Q  Q2 P1  P2 
ea   1


 Q1  Q2 P1  P2 
  60 70 
= 


 540  10 
 42 
  0.77
 54 
= 
(52)
If as a result of 10% increase in price, the quantity supplied does not change at all, it
implies that the elasticity of Supply is:
(a)
Zero
(b)
Infinite
(c)
Equal to one
(d)
Greater than Zero but less than are
Ans. a
Explanation:
If there is no change in Quantity supplied it means quantity supplied remains
unchanged then elasticity will be zero.
MITTAL COMMERCE CLASSES
7|Page
y
s
P1
e1
Price P1
e0
P2
e2
0
Q0
x
Q.S.
(53)
When supply is perfectly elastic, elasticity of supply is equal to________________
(a)
+1
(b)
0
(c)
—1
(d)
infinity.
Ans. d
Explanation:
When there is no change in price even quantity supplied changes then the elasticity
is perfectly elastic.
(54)
The law of consumer surplus is based on
(a)
Indifference curve analysis
(b)
Revealed preference theory.
(c)
Law of substitution
(d)
The law of diminishing marginal utility.
Ans. d
Explanation:
Because consumer surplus is measured with what a consumer is ready to pay and it
can only measured by marginal utility only.
(55)
Who is the main exponent of Marginal utility analysis ?
(a)
Paul Samuelson
(b)
Hicks
(c)
Keynes
(d)
Marshall
Ans. d
Explanation:
According to Marshall, “Utility is measurable in terms of money”.
(56)
What does ‘ceteris paribus’ mean?
(a) Other things remaining constant
(b) Price of other goods remaining constant
(c) Other things are simultaneously changing
MITTAL COMMERCE CLASSES
8|Page
(d) None of the above
Ans. a
Explanation: ‘ceteris paribus’ mean Other things remaining constant
(57)
Expansion of demand is shown by:
(a) Upward movement on the demand curve
(b) Downward movement on the demand curve
(c) Rightward shift of the demand curve
(d) Leftward shift of the demand curve
Ans. b
(58)
When cross elasticity of demand is positive, then two goods are:
(a) Substitutes
(b) Complements
(c) Not related
(d) Perfect complements
Ans. a
Explanation: Tea and Coffee.
(59)
Saturation point means:
(a) TU is rising, and MU is falling
(b) TU is falling and MU is negative
(c) TU is maximum and MU is zero
(d) Falling MU curve
Ans. c
Explanation: Saturation point means TU is maximum and MU is zero
(60)
A downward sloping curve can have the following shape:
(a) Convex
(b) Concave
(c) Straight line
(d) All of the above
Ans. a
(61)
When supply curve is horizontal, Es = _________?
(a) Es = 0
(b) Es = 1
(c) Es = ∞
(d) Es > 1
Ans. c
Explanation:
MITTAL COMMERCE CLASSES
9|Page
ew
Y;
Y
X
ek=k
(62)
When TP is at its point of inflexion, the MP is:
(a) Falling
(b) Negative
(c) Zero
(d) Maximum
Ans. d
Explanation: When TP is at its point of inflexion, the MP is maximum.
(63)
In stage II of law of Variable Proportions, both AP and MP are:
(a) Falling but positive
(b) Rising
(c) Falling and become negative
(d) None of the above
Ans. a
Explanation: In stage II of law of Variable Proportions, both AP and MP are falling but
positive.
(64)
AVC is defined as:
(a) Variable cost per unit of output produced
(b) Cost of one unit of output produced
(c) Additional cost of one unit of output produced
(d) None of the above
Ans. a
Explanation: AVC is defined as variable cost per unit of output produced.
(65)
When AC = MC, AC is _________ .
(a) Minimum
(b) Falling
(c) Rising
(d) Maximum
Ans. a
Explanation: When AC = MC, AC is minimum.
(66)
MC curve is ________ shaped.
(a) L-shaped
(b) Straight line
MITTAL COMMERCE CLASSES
10 | P a g e
(c) U-shaped
(d) Inverse S-shaped
Ans. c
Explanation: MC curve is U-shaped.
(67)
Reason for the shape of MC curve is:
(a) Law of Variable Proportions
(b) Returns to scale
(c) Law of diminishing cost
(d) Law of increasing cost
Ans. a
Explanation: Reason for the shape of MC curve is due to law of variable proportions.
(68)
Long-run AC curve is also called:
(a) Planning curve
(b) Envelope curve
(c) Cost frontier
(d) All of the above
Ans. d
Explanation:
From the Table given below, answer question 69 to question 75
Units
0
1
2
3
TC
80
100
118
140
(69)
What is the value of TFC when 1 unit of output is produced?
(a) 100
(b) 80
(c) 10
(d) 50
Ans. b
Explanation: Since even if there is whatever production TFC will be 80 only.
(70)
What is TVC when 1 unit of output is produced?
(a) 20
(b) 30
(c) 38
(d) 60
Ans. a
Explanation: TVC = TC – TFC
=100 – 80 = 20
(71)
What is the value of AFC when 2 units of output are produced?
(a) 80
(b) 100
(c) 40
(d) 0
Ans. c
MITTAL COMMERCE CLASSES
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Explanation: AFC =
(72)
What is the value of AVC when 3 units of output are produced?
(a) 20
(b) 19
(c) 30
(d) 3
Ans. a
Explanation: TVC = TC – TFC
=140 – 80 = 60
AVC =
(73)
TFC 80

 40
Q
2
TVC 60

 20
Q
3
What is the value of MC when 2 units of output are produced?
(a) 18
(b) 20
(c) 22
(d) 24
Ans. a
Explanation: MC = DTC / DQ =
118  100
 18
2 1
(74)
What is the value of TVC when 3 units of output are produced?
(a) 60
(b) 20
(c) 38
(d) 30
Ans. a
Explanation: TVC = TC – TFC
= 140 – 80 = 60
(75)
When both AC and MC are rising, _________ rises at a faster rate:
(a) AC
(b) MC
(c) AVC
(d) AFC
Ans. b
Explanation:
Y
AC
MC
O
MITTAL COMMERCE CLASSES
X
12 | P a g e
(76)
In a football championship 153 matches were played. Every team played one match
with each other team. How many teams participated in the championship ?
(a)
21
(b)
18
(c)
17
(d)
15
Ans. b
Explanation:
nc 2  153
nn  1
 153
2
n  18
(77)
What is the number of ways of arranging the letters of the word "BANANA" so that
no two N's appear together ?
(a)
40
(b)
60
(c)
80
(d)
100
Ans. a
Explanation:
No. of ways that can be formed by using the word 'BANANA' =
No. of ways in which two N comes together =
6!
 60
3!2!
5!
 20
3!
 Required No. of ways = 60–20 = 40
(78)
What is the number of signals that can be sent by 6 flags of different colours taking
one or more at a time ?
(a)
21
(b)
63
(c)
720
(d)
1956
Ans. b
Explanation:
Required no. of ways = 26–1 = 63
(79)
In what time will Rs.800 amount to Rs.926.10 at 10% per annum interest
compounded half yearly?
(a)
3 year
1
(b)
1 year
2
1
(c)
2 year
(d)
2 year
3
1
2
Ans: (b)
Explanation:
MITTAL COMMERCE CLASSES
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A = 𝑃 (1 +
𝑟
100
)
𝑛
926.10 = 800 (1 +
9261
8000
= (1 +
1
20
21 3
21 2n
20
20
)
5
100
)
2n
2n
( ) =( )
∴ 2n = 3
1
n = 1 Year
2
(80)
There are deer and peacocks in a Zoo. By counting heads they are 80. The number
of their Legs is 200. How many peacocks are there?
(a)
30
(b)
50
(c)
60
(d)
20
Ans: (c)
Explanation:
Let the no. of deer and peacocks are 𝑥 and 𝑦
𝑥 + 𝑦 = 80.......................(i)
4𝑥 + 2𝑦 = 200.......................(i)
By solving the eqn (i) and eqn (ii)
y = 60
(81)
What are the linear constraints for which the shaded area in the above figure is the
solution set?
(a)
𝑥 − 𝑦 ≥ 1; 𝑥 + 2𝑦 ≥ 8; 𝑥 + 𝑦 ≥ 1; 𝑥, 𝑦 ≥ 0
(b)
𝑥 − 𝑦 ≤ 1; 𝑥 + 2𝑦 ≥ 8; 𝑥 + 𝑦 ≤ 1; 𝑥, 𝑦 ≥ 0
(c)
𝑥 − 𝑦 ≤ 1; 𝑥 + 2𝑦 ≤ 8; 𝑥 + 𝑦 ≥ 1; 𝑥, 𝑦 ≥ 0
(d)
𝑥 − 𝑦 ≤ 1; 𝑥 + 2𝑦 ≤ 8; 𝑥 + 𝑦 ≤ 1; 𝑥, 𝑦 ≥ 0
Ans. (c)
Explanation: The linear constraints for which the shaded region in the given figure
is the solution set, are
𝑥 − 𝑦 ≤ 1; 𝑥 + 2𝑦 ≤ 8; 𝑥 + 𝑦 ≥ 1; 𝑥, 𝑦 ≥ 0
MITTAL COMMERCE CLASSES
14 | P a g e
(82)
A manufacturer produces 80 T.V. sets at a cost Rs. 2,20,000 and 125 T.V. sets at a
copy of Rs.2,87,500. Assuming the cost curve to be linear find the cost of 95 sets.
(a)
Rs. 3,52,500
(b)
Rs. 1,45,550
(c)
Rs. 2,42,500
(d)
None of these
Ans. c
Explanation :
Since the cost curve is linear we consider cost curve as y=Ax+B where y is total
cost. Now for x=80, y=2,20,000. ∴ 2,20,000 = 80A+B…….(i)
and for x = 125; y=2,87,500 ∴ 2,87,500 = 125A+B………(ii)
Subtracting (i) from (ii) 45A=67,500 or A=1500
From (i) 2,20,000 – 1500 (80) = B or B =2,20,000-1,20,000=1,00,000
Thus equation of cost line is y = 1,500x+1,00,000.
For x=95, y=1,42,500+1,00,000=Rs. 2,42,500.
∴ Cost of 95 T.V. set will be Rs. 2,42,500.
(83)
If 𝑥 = 7 + 4√3, 𝑦 = 7 − 4√3, what is the value of
1
𝑥2
+
1
𝑦2
.
(a)
194
(b)
198
(c)
212
(d)
196
Ans. (a)
Explanation:
1
𝑥2
1
2
+ 𝑦 2 = (7 − 4√3) + (7 + 4√3)
2
= 49 + 48 + 49 + 48
= 194
(84)
Which Statement is correct in the following?
Linear system of equation
2𝑥 + 3𝑦 = 4 and 4𝑥 + 6𝑦 = 7 has
(a)
no solution
(b)
Unique solution
(c)
exactly 2 solution
(d)
Infinite solution.
Ans. (a)
Explanation:
MITTAL COMMERCE CLASSES
15 | P a g e
For the lines 2𝑥 + 3𝑦 = 4 and 4𝑥 + 6𝑦 = 7
2
4
3
4
=6≠7
So, the given system of equation have no solution because, both lines are parallel to
each other.
(85)
How much amount is required to be invested every year so as to accumulate
Rs.4,00,000 at the end of 10 years, if interest is compounded annually at 10%
(a)
Rs. 24506.18
(b)
Rs. 25098.16
(c)
Rs. 22506.18
(d)
Rs. 21098.16
Ans. (b)
Explanation:
R
A = [(1 + r)n − 1]
r
400000 =
R
0.10
[(1 + 0.10)10 − 1]
R = Rs. 25098.16
(86)
The present value of Rs. 10000 due in 2 years at 5% p.a. compound interest when
the interest is paid on half-yearly basis is:
(a)
Rs. 9070.50
(b)
Rs. 9069.50
(c)
Rs. 9061.50
(d)
Rs. 9059.50
Ans. d
Explanation:
Present value  A(1  i )  n  10000 / (1  0.025) 4
 10000 / (1.025) 4
 10000 / (1.1038)
 Rs.9059.50
(87)
The value of k for which the points (k, 3), (5, 5) and (10, 7) may be collinear is
(a)
k= 0
(b)
k= 7
(c)
k= 9
(d)
k= l
Ans. a
Explanation:
For collinearity of three points,
Area of triangle = 0
MITTAL COMMERCE CLASSES
16 | P a g e
1
 x1( y2  y3 )  x2 ( y3  y1 )  x3 ( y1  y2 ) = 0
2
Given : x1  k , x2  5, x3  10
y1  3, y2  5, y3  7
K (5  7)  5(7  3)  10(3  5)  0
2k  20  20  0
k 0
(88)
In how many ways can a team of 11 cricketers be chosen from 9 batsmen and 6
bowlers to give a majority of batsman if at least 3 bowlers are to be included.
(a)
1224
(b)
3224
(c)
1324
(d)
1125
Ans. a
Explanation:
Since the team is to contain at least 3 bowlers out of 6 bowlers and 9 batsmen ;
This can be done in the following ways.
(i)
3 bowlers and 8 batsmen.
It can be selected in
(ii)
6
C3  9C8  180 ways.
… (1)
4 bowlers and 7 batsmen.
This can be done in
(iii)
6
C4  9C7  540 ways.
… (2)
5 bowlers and 6 batsmen.
This can be done in
6
C5  9C6  504 ways.
… (3)
Total number of ways = 180+540+504 = 1224 ways.
(89)
Which of the following statements is true for tabulation ?
(a)
Statistical analysis of data requires tabulation
(b)
It facilitates comparison between rows and columns
(c)
Diagrammatic representation of data requires tabulation
(d)
All of these
Ans. d
Explanation:
(90)
Let L be the lower class boundary of a class in a frequency distribution and may be
the mid-point of the class. Which one of the following is the higher class boundary of
the class ?
(a)
(b)
mL
2
mL
L
2
m
(c)
2m–L
(d)
m–2L
Ans. c
Explanation:
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X=
LCL  UCL L  UCL

M
2
2
UCL = 2m - L
(91)
The weighted arithmetic mean of first n natural numbers whose weights are equal to
the corresponding numbers is equal to :
2n  1
3
2n  1
6
2n  1
3
(a)
(b)
(c)
(d)
None of the above
Ans. c
Explanation:
x
1
2
f
1
2
3
3
...
...
n
n
fx:
32
...
n2
12
22
nn  12n  1
2n  1
6
Mean =
.

nn  1
3
2
(92)
Total
nn  1
2
nn  1 2n  1
6
Geometric mean of 2, 4, 8 ... 2n.
(a)
2n+1/2
(b)
2n–1/2
(c)
2n/2
(d)
22/n
Ans. a
Explanation:

Gm = 2  2  2  ....2
2
3

1
n n
 2 n1 / 2
(93)
Age of applicants for life insurance and the premium of insurance-correlation are :
(a)
positive
(b)
negative
(c)
zero
(d)
None
Ans. a
Explanation:
(94)
If it rains, a dealer of umbrella can earn Rs.300 per day, if it does not rain he can
lose Rs. 80 per day. What is his expectation if the probability of a rainy day is 0.57
(in rupees) ?
(a)
136.6
(b)
138.6
(c)
146.6
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(d)
146
Ans. a
Explanation:
x
300
–80
p
0.57
0.43
Expected value = 300×0.57–80×0.43 = 136.6
(95)
In a binomial distribution with 6 independent trails, the probability of 3 and 4
successes are found to be 0.2457 and 0.0819, respectively. Find the parameter 'P' of
the binomial.
(a)
3/13
(b)
4/13
(c)
5/13
(d)
6/13
Ans. b
Explanation:
px  3  6 C3 p 3 q 3  0.2457
px  4  6 C4 p 4 q 2  0.0819
20 q = 45 p
p=
4
13
(96)
If the 1st quartile and the mean deviation about median of a normal distribution are
13.25 and 8, respectively, then the mode of the distribution is :
(a)
20
(b)
10
(c)
15
(d)
12
Ans. a
Explanation:
Q1 =m–0.675 s = 13.25
MD = 0.8 s = 8
s = 10
m = 20
mode = 20
(97)
During a certain period the cost of living Index number goes up from 110 to 200 and
the salary of the worker is also raised form Rs. 325 to Rs. 500. Does the worker :
(a)
gain
(b)
looses
(c)
fully compensated
(d)
gain lay 10%
Ans. b
Explanation:
Revised salary =
200
 325  590.90
110
It means worker is in loss.
(98)
P1Q1  248, P0Q0  150, Paasche's index number = 150 and Dorbish-Bowley's index
number = 145. Then the Fisher's ideal index number is:
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(a)
75
(b)
144.91
(c)
145.97
(d)
None of these
Ans. b
Explanation:
Dorbish-Bowley's index number =
LP
 145
2
L = 290 – P = 140
f=
(99)
L  P  140 150  144.91
If u = 2x+5, v=–3y +1, and the regression coefficient of y on x is – 1.2, the
regression coefficient of v on u is :
(a)
1.8
(b)
–1.8
(c)
3.26
(d)
0.8
Ans. a
Explanation:
bvu 
=
p
 byx
q
3
 1.2  1.8
2
(100) If P A  1/ 2, PB  1/ 3, P A  B  1/ 4, then what is P(A'/B') ?
(a)
1/3
(b)
4/5
(c)
5/8
(d)
None
Ans. c
Explanation:
P(A'/B') =
P A'B' 1  P A  B 

 5/8
P  B '
1  P B 
***
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