LESSON 20 (3.1) EXPONENTIAL FUNCTIONS AND THEIR GRAPHS You should learn to: 1. Recognize, evaluate, and graph exponential functions with base any base. 2. Use exponential functions to model and solve real-life problems. Terms to know: exponential function with base a, natural base e, compound interest: non-continuous vs. continuous compounding, exponential growth (or decay), half-life. The exponential function with base a is written as f x a x , where a > 0, a 1, and x is any real number. Exponential Function: y a x Graph: For exponential functions, the base is constant (some number) and the exponent is variable. x 1 You need to be careful not to confuse y 2 , y 3 , y , etc. 2 x x 1 2 with y x , y x , y x , etc. (power functions) 2 3 Example 1: Graph the following exponential functions. Find the domain and asymptotes of each. y 2x y 5x y 3x X -2 Y ¼ X -1 Y 1/3 X -1 Y 1/5 -1 ½ 0 1 0 1 0 1 1 3 1 5 1 2 2 9 2 4 Domain: Domain: Domain: Range: y 0 Range: y 0 Range: y 0 Asymptote : y 0 Asymptote : y 0 Asymptote : y 0 List the common features for the graphs. These are the characteristics for all exponential graphs of the form y a x , a 1. R: y 0 D: Asy: y 0 Key Point: (1, a), 1, 1a y-int: (0,1) continuous and always increasing. Example 2: Graph the following based on the graphs from #1. ( x 3) a. y 3 x b. y 2 y 3x y 2x reflected through shifted right the y axis. 3 units c. y 2 ( x 1) 2 y 2x shifted left 1 unit and down 2 units In Calculus, by far the most commonly used base for exponential functions is base e. It is known as the natural base. e 2.718 Example 3: Graph y e x . Use it to graph the other functions listed. List 2 points and the asymptote for each. y ex 3 y ex Key points: (0,1), (1, e) Asy: y 0 y e x 2 Key points: (0, 2), (1, e 3) Asy: y 3 Asy: y 2 Key points: (0,1), (1, e 2) A common business application of the number e occurs in computing interest for investments. 1. Non-continuous compounding: Interest is calculated a specific number of times each year. (Daily (365) , weekly (52) , monthly (12) , quarterly (4) , semi-annual (2) , and annual (1) compoundings are the most common types) 2. Continuous compounding: Interest is always being calculated - an infinite number of times. r A P 1 n Compound Interest: nt A = Amount P = Principal r = rate t = time (yrs) n = number of compounds per year Continuous Interest: A Per t Example 4: Suppose you have $10,000 to invest in a college fund, and you can leave the money in the fund for 8 years before you start college. Which of the following would provide you with the most money for college? a. A fund providing an interest rate of 5.35% compounded semi-annually. r A P 1 n A? b. A fund providing an interest rate of 5.3% compounded continuously. A Pe r t nt A? P 10, 000 r .053 P 10, 000 t 8 r .0535 A 10, 000e.0538 t 8 A $15, 280.62 n2 .0535 A 10, 000 1 2 28 A $15, 255.81 The continuous compoundings would provide the most money for college. *The two most common student errors in solving interest problems are: 1. Not changing the interest percent to a pure decimal rate of r. 2. Using parentheses incorrectly for non-continuous compoundings. Make sure you enclose the exponent n t in parentheses. Many common applications of exponential growth (or decay) occur in the sciences. Example 5: Radioactive Decay Let Q represent the mass, in grams, of radioactive radium 226 Ra , whose half-life is 1620 years. The mass of t 1 1620 radium present after t years is given by the formula: Q (t) 16 . 2 a. What is the initial mass? t 0 b. What amount of radioactive radium 226 Ra remains after 1000 years? t 1000 t 1 1620 Q (t) 16 2 0 t 1 1620 Q (t) 16 2 1000 1 1620 Q (0) 16 2 1 1620 Q (1000) 16 2 Q (0) 16 grams Q (1000) 10.430 grams ASSIGNMENT 20 Pages 193-195 (Vocabulary Check 4-5, 1-5, 7, 9, 13-17, 21, 23-24, 29, 37, 45 (find asymptotes by letting x 100 and x 100. The graph of this function is called a logistics curve.), 50, 52, 54, 60, 68, 72, 75, 78, 85, 87)
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