Standardized Test Practice - Cumulative, Chapter 1-10
1. Which equation below could match the graph shown
on the coordinate grid?
So, the graph of the equation in C will contain the
points (1, 5) and (4, 7).
The graph appears to contain the points (1, 1) and
(4, –1).
Therefore, the correct answer choice is B.
2. Simplify
.
F G A B C
D
SOLUTION: H J SOLUTION: From the graph, the y -intercept appears to be 3.
The y -intercept of the graphs for the equations given
in A and D are both 1. These two choices can be
eliminated. Check the values of the points at x = 1
and 4 for the equations given in B and C and
compare to the graph.
Therefore, the correct answer is H.
3. What is the area of the triangle below?
So, the graph of the equation in B will contain the
points (1, 1) and (4, –1).
A
B
C
D
SOLUTION: So, the graph of the equation in C will contain the
points
(1, 5)
and (4,by7).
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The graph appears to contain the points (1, 1) and
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Standardized Test Practice - Cumulative, Chapter 1-10
Therefore, the correct answer is H.
3. What is the area of the triangle below?
Therefore, the correct answer is D.
4. The formula for the slant height c of a cone is
, where h is the height of the cone
and r is the radius of its base. What is the radius of
the cone below? Round to the nearest tenth.
A
B
C
D
SOLUTION: F 4.9
G 6.3
H 9.8
J 10.2
SOLUTION: Substitute h = 10 and c = 14 into the formula for the
slant height of a cone to find the radius of the cone.
Therefore, the correct answer is D.
4. The formula for the slant height c of a cone is
, where h is the height of the cone
and r is the radius of its base. What is the radius of
the cone below? Round to the nearest tenth.
The radius is about 9.8 units. Therefore, the correct
answer is H.
F 4.9
G 6.3
H 9.8
J 10.2
SOLUTION: Substitute h = 10 and c = 14 into the formula for the
slant height of a cone to find the radius of the cone.
5. Which of the following sets of measures could not be
the sides of a right triangle?
A (12, 16, 24)
B (10, 24, 26)
C (24, 45, 51)
D (18, 24, 30)
SOLUTION: A Since the measure of the longest side is 24, let c =
2
24, a = 12, and b = 16. Then determine whether c =
2
2
a +b .
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SOLUTION: A Since the measure of the longest side is 24, let c =
Standardized Test Practice - Cumulative, Chapter2 1-10
24, a = 12, and b = 16. Then determine whether c =
2
2
a +b .
Because 900 = 900, a triangle with side lengths 18,
24, and 30 is a right triangle.
Therefore, the correct answer is A.
6. Which of the following is an equation of the line
perpendicular to 4x – 2y = 6 and passing through (4,
–4)?
F
Because 576 ≠ 400, a triangle with side lengths 12,
16, and 24 is not a right triangle.
B Since the measure of the longest side is 26, let c =
2
26, a = 10, and b = 24. Then determine whether c =
2
2
a +b .
G
H
J
SOLUTION: First, find the slope of 4x – 2y = 6 by writing the
equation in slope-intercept form.
Because 676 = 676, a triangle with side lengths 10,
24, and 26 is a right triangle.
C Since the measure of the longest side is 51, let c =
2
51, a = 24, and b = 45. Then determine whether c =
2
2
a +b .
So, the slope is 2, and a line perpendicular to y = 2x –
3 will have a slope of
.
Next, find the line passing through (–4, 4).
Because 2601 = 2601, a triangle with side lengths 24,
45, and 51 is a right triangle.
D Since the measure of the longest side is 30, let c =
2
30, a = 18, and b = 24. Then determine whether c =
2
2
a +b .
Because 900 = 900, a triangle with side lengths 18,
24, and 30 is a right triangle.
Therefore, the correct answer is A.
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6. Which of the following is an equation of the line
perpendicular to 4x – 2y = 6 and passing through (4,
Therefore, the correct answer is J.
7. The scale on a map shows that 1.5 centimeters is
equivalent to 40 miles. If the distance on the map
between two cities is 8 centimeters, about how many
miles apart are the cities?
A 178 miles
B 213 miles
C 224 miles
D 275 miles
SOLUTION: Use ratios to find the distance.
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SOLUTION: Standardized
Test Practice - Cumulative, Chapter 1-10
Therefore, the correct answer is J.
7. The scale on a map shows that 1.5 centimeters is
equivalent to 40 miles. If the distance on the map
between two cities is 8 centimeters, about how many
miles apart are the cities?
A 178 miles
B 213 miles
C 224 miles
D 275 miles
SOLUTION: Use ratios to find the distance.
10. GRIDDED RESPONSE In football, a field goal is
worth 3 points, and the extra point after a touchdown
is worth 1 point. During the 2006 season, John Kasay
of the Carolina Panthers scored a total of 100 points
for his team by making a total of 52 field goals and
extra points. How many field goals did he make?
SOLUTION: Setup and solve a system in equations where x
represents the number of field goals and y represents
the number of extra points.
First, solve for x.
The cities are about 213 miles apart. Therefore, the
correct answer is B.
8. GRIDDED RESPONSE How many times does the
2
graph of y = x - 4x + 10 cross the x-axis?
SOLUTION: 2
Since the equation y = x – 4x + 10 is a quadratic, it
will cross the x-axis 0, 1, or 2 times. Graph the equation.
Therefore, the number of field goals is 24.
11. Shannon bought a satellite radio and a subscription to
satellite radio. What is the total cost for his first year
of service?
SOLUTION: Let C represent the total cost for the first year of
service.
[–10, 10] scl: 1 by [–10, 10] scl: 1
2
The graph of y = x – 4x + 10 does not cross the xaxis. Therefore, the answer is 0.
9. Factor
completely.
SOLUTION: Therefore, the total cost is $183.87.
12. GRIDDED RESPONSE The distance required for
a car to stop is directly proportional to the square of
its velocity. If a car can stop in 242 meters at 22
kilometers per hour, how many meters are needed to
stop at 30 kilometers per hour?
SOLUTION: Substitute 242 for d and 22 for v. 10. GRIDDED RESPONSE In football, a field goal is
worth 3 points, and the extra point after a touchdown
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is worth
1 point.
During
the 2006 season, John Kasay
of the Carolina Panthers scored a total of 100 points
for his team by making a total of 52 field goals and
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Standardized
Test Practice - Cumulative, Chapter 1-10
Therefore, the total cost is $183.87.
12. GRIDDED RESPONSE The distance required for
a car to stop is directly proportional to the square of
its velocity. If a car can stop in 242 meters at 22
kilometers per hour, how many meters are needed to
stop at 30 kilometers per hour?
SOLUTION: Substitute 242 for d and 22 for v. 15. GRIDDED RESPONSE For the first home
basketball game, 652 tickets were sold for a total
revenue of $5216. If each ticket costs the same, how
much is the cost per ticket? State your answer in
dollars.
SOLUTION: Let x be the cost of a ticket.
Thus, each ticket costs $8.00.
A car will need 450 meters to stop at 30 kilometers
per hour.
13. The highest point in Kentucky is at an elevation of
4145 feet above sea level. The lowest point in the
state is at an elevation of 257 feet above sea level.
Write an inequality for this situation.
16. Karen is making a map of her hometown using a
coordinate grid. The scale of her map is 1 unit = 2.5
miles.
SOLUTION: 257 ≤ x ≤ 4,145
14. Simplify the expression below. Show your work.
SOLUTION: a. Use the Pythagorean Theorem to find the actual
distance between Karen’s school and the park.
Round to the nearest tenth of a mile
if necessary. b. Suppose Karen’s house is located at (0.5, 0.5).
What is farthest from her house, the zoo, the park,
the school, or the mall?
15. GRIDDED RESPONSE For the first home
basketball game, 652 tickets were sold for a total
revenue of $5216. If each ticket costs the same, how
much is the cost per ticket? State your answer in
dollars.
SOLUTION: Let x be the cost of a ticket.
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SOLUTION: a. The coordinates of the school are (4, 5), and the
coordinates of the park are (5, –5). Use the
Pythagorean theorem to find the distance between
the school and the park.
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SOLUTION: a. The coordinates of the school are (4, 5), and the
coordinates of the park are (5, –5). Use the
Pythagorean
theorem
to find
the distanceChapter
between 1-10
Standardized
Test
Practice
- Cumulative,
the school and the park.
The school is located at (4, 5), so the distance
between Karen's house and the school is:
So, the distance is 10.04 units. Since 1 unit = 2.5
miles, the distance in miles is 10.04 · 2.5 or about
25.1 miles.
The park is 7.11 units away from Karen's house, the
school is 5.7, and the zoo is 4.75. The park is farthest
from Karen's house, which will be true even if the
scale is changed. b. Let (x 1, y 1) = (0.5, 0.5). The zoo is located at (–
4, 2), so the distance between Karen's house and
the zoo is:
The park is located at (5, –5), so the distance
between Karen's house and the park is:
The school is located at (4, 5), so the distance
between Karen's house and the school is:
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