LINEAR RESPONSE THEORY t = t0 : Interacting system in ground state of potential v0(r) with density 0(r) t > t0 : Switch on perturbation v1(r t) (with v1(r t0)=0). Density: (r t) = 0(r) + (r t) Consider functional [v](r t) defined by solution of the interacting TDSE Functional Taylor expansion of [v] around vo: ρ v rt ρ v0 v1 rt ρ v0 rt δρ v rt δv r't' ρo r v1 r ' t ' d 3r'dt' ρ1 rt v0 δ 2ρ v rt 1 v1 r ', t ' v1 r", t" d 3r'd 3r"dt'dt" 2 δv r't' δv r"t" v 0 ρ2 rt 1(r,t) = linear density response of interacting system rt, r ' t ' : δρ v rt δv r't' = density-density response function of interacting system v0 Analogous function s[vs](r t) for non-interacting system ρS vS rt ρS vS,0 vS,1 rt ρS vS,0 rt S rt, r ' t ' : δρS vS rt δvS r't' δρS vS rt δvS r't' vS,1 r't' d 3r'dt' v S,0 = density-density response function of non-interacting system vS,0 GOAL: Find a way to calculate 1(r t) without explicitly evaluating (r t,r't') of the interacting system starting point: Definition of xc potential vxc ρ rt : vS ρ rt vext ρ rt vH ρ rt Notes: • vxc is well-defined through non-interacting/ interacting 1-1 mapping. • vS[] depends on initial determinant 0. • vext[] depends on initial many-body state 0. In general, vxc vxc ρ,Φ0 ,Ψ0 only if system is initially in ground-state then, via HK, 0 and 0 are determined by 0 and vxc depends on alone. δv xc ρ rt δρ r't' ρ0 δvS ρ rt δρ r't' ρ0 δvext ρ rt δρ r't' ρ0 δ t t' r r' δv xc ρ rt δρ r't' f xc rt, r't' ρ0 δvS ρ rt δρ r't' S1 rt, r't' ρ0 δvext ρ rt δρ r't' 1 rt, r't' ρ0 δ t t' r r' WC rt, r't' δv xc ρ rt δρ r't' f xc rt, r't' ρ0 δvS ρ rt δρ r't' ρ0 S1 rt, r't' δvext ρ rt δρ r't' 1 rt, r't' 1 S f xc WC 1 ρ0 δ t t' r r' WC rt, r't' δv xc ρ rt δρ r't' f xc rt, r't' ρ0 δvS ρ rt δρ r't' ρ0 S1 rt, r't' δvext ρ rt δρ r't' 1 rt, r't' 1 S S • f xc WC 1 • ρ0 δ t t' r r' WC rt, r't' δv xc ρ rt δρ r't' ρ0 f xc rt, r't' δvS ρ rt δρ r't' ρ0 S1 rt, r't' δvext ρ rt δρ r't' 1 rt, r't' 1 S S • f xc WC 1 χ S f xc WC χ χ χ S • ρ0 δ t t' r r' WC rt, r't' χ χ S χ S WC f xc χ Act with this operator equation on arbitrary v1(r t) and use v1 = 1 : 3 ρ1 rt = d r'dt'χ S rt, r't' v1 rt + d r"dt"WC r't', r"t" + f xc r't', r"t" ρ1 r"t" 3 • Exact integral equation for 1(r t), to be solved iteratively • Need approximation for f xc r't', r"t" (either for fxc directly or for vxc) δv xc ρ r't' δρ r"t" ρ0 Adiabatic approximation adiab xc v ρ rt := v static DFT xc ρ t rt In the adiabatic approximation, the xc potential vxc(t) at time t only depends on the density ρ(t) at the very same point in time. e.g. adiabatic LDA: f xcALDA rt, r't' v ALDA xc rt : v δv ALDA rt xc δρ r't' ρ0 LDA xc ρ rt α ρ rt 13 v ALDA δ r r' δ t t' xc ρ r 2ehom xc δ r r'δ t t' n 2 ρ0 r ρ0 r Total photoabsorption cross section of the Xe atom versus photon energy in the vicinity of the 4d threshold. Solid line: self-consistent time-dependent KS calculation [A. Zangwill and P. Soven, PRA 21, 1561 (1980)]; crosses: experimental data [R. Haensel, G. Keitel, P. Schreiber, and C. Kunz, Phys. Rev. 188, 1375 (1969)]. continuum states I1 I2 unoccupied bound states occupied bound states photo-absorption cross section Photo-absorption in weak lasers (ω) Laser frequency No absorption if < lowest excitation energy Standard linear response formalism H(t0) = full static Hamiltonian at t0 H t 0 m Em m exact many-body eigenfunctions and energies of system full response function 0 ˆ r m m ˆ r 0 0 ˆ r ' m m ˆ r ' 0 r, r '; lim E m E 0 i E m E 0 i 0 m The exact linear density response 1 ˆ v1 has poles at the exact excitation energies = Em - E0 Discrete excitation energies from TDDFT exact representation of linear density response: ˆ fˆ 1 ˆ S v1 W C 1 xc 1 “^” denotes integral operators, i.e. f̂ xc1 f xc r, r ' 1 r ' d 3r ' where ˆ S r, r '; j,k M jk r, r ' j k i with M jk r, r ' f k f j j r j r ' k r ' k r 1 if m fm 0 if m * is occupied in KS ground state is unoccupied in KS ground state j k KS excitation energy * 1ˆ ˆ Wˆ fˆ S C xc 1 ˆ S v1 1() for (exact excitation energy) but right-hand side remains finite for hence ˆ fˆ 1ˆ ˆ S W C xc () 0 for This condition rigorously determines the exact excitation energies, i.e., ˆ fˆ 0 1ˆ ˆ S W C xc This leads to the (non-linear) eigenvalue equation (See T. Grabo, M. Petersilka, E. K. U. G., J. Mol. Struc. (Theochem) 501, 353 (2000)) M qq' q qq' q' q q' where M qq' 1 α q' d r d r'Φ q r f xc r, r', Ω Φ q' r' r r' 3 3 q j,a double index q f a f j q r r j r q a j * a Atom Exp erimental Excitation Energies 1S1P (in Ry) KS energy differences KS (Ry) KS + K Be 0.388 0.259 0.391 Mg 0.319 0.234 0.327 Ca 0.216 0.157 0.234 Zn 0.426 0.315 0.423 Sr 0.198 0.141 0.210 Cd 0.398 0.269 0.391 from: M. Petersilka, U. J. Gossmann, E.K.U.G., PRL 76, 1212 (1996) E = KS + K j - k 1 K d r d r ' j r r ' k r ' r f r, r ' r r ' xc 3 3 j k Excitation energies of CO molecule State expt KS-transition 52 A 1 0.3127 a 3 0.2323 I D a' e d 1 1 - 0.3631 KS 0.2523 KS + K 0.3267 0.2238 12 0.3626 0.3626 0.3759 0.3812 0.3127 0.3181 0.3631 0.3626 0.3440 0.3404 3 + 3 3 - T. Grabo, M. Petersilka and E.K.U. Gross, J. Mol. Struct. (Theochem) 501, 353 (2000) LDA approximations made: vxc and fxcALDA Quantum defects in Helium En 1 2 n n 2 a.u. Bare KS exact x-ALDA xc-ALDA (VWN) x-TDOEP M. Petersilka, U.J. Gossmann and E.K.U.G., in: Electronic Density Functional Theory: Recent Progress and New Directions, J.F. Dobson, G. Vignale, M.P. Das, ed(s), (Plenum, New York, 1998), p 177 - 197. (M. Petersilka, E.K.U.G., K. Burke, Int. J. Quantum Chem. 80, 534 (2000)) The above equations are from the Refs. M. Petersilka, U. J. Gossmann, E.K.U.G., PRL 76, 1212 (1996); T. Grabo, M. Petersilka, E. K. U. G., J. Mol. Struc. (Theochem) 501, 353 (2000) They yield the same excitation spectrum as the Casida equations: 2 W v vq qq q q Wqq qq 4 q q M qq 2 q M. E. Casida, in Recent Developments and Applications in Density Functional Theory, edited by J. M. Seminario (Elsevier, Amsterdam, 1996), p. 155-192. Failures of ALDA in the linear response regime • H2 dissociation is incorrect: E 1 u E 1 g (in ALDA) 0 R (see: Gritsenko, van Gisbergen, Görling, Baerends, JCP 113, 8478 (2000)) • response of long chains strongly overestimated (see: Champagne et al., JCP 109, 10489 (1998) and 110, 11664 (1999)) • in periodic solids, f xcALDA q, , c whereas, exact 2 f 1 q for insulators, xc divergent. q 0 • charge-transfer excitations not properly described (see: Dreuw et al., JCP 119, 2943 (2003)) charge-transfer excitation R A B CT excitation energy A r B r ' d r d r' r r' 2 CT IP A EA B 3 3 Infinite R Finite (but large) R In exact DFT IP(A) = – (A) HOMO = – (A) MOL (B) EA(B) = – (B) – ∆ LUMO xc = – (B) MOL derivative discontinuity A r B r ' CT MOL MOL d r d r ' r r' 2 B A 2 3 3 2 A r B r ' CT MOL MOL d r d r ' r r' 2 B A 3 3 ~ 1/R 2 A r B r ' CT MOL MOL d r d r ' r r' 2 B A 3 2 3 ~ 1/R In TDDFT (single-pole approximation) B A CT MOL MOL d3r d3r' *A (r' )B (r' )fxc (r, r' , CT )A (r )*B (r ) A r B r ' CT MOL MOL d r d r ' r r' 2 B A 3 2 3 ~ 1/R In TDDFT (single-pole approximation) B A CT MOL MOL d3r d3r' *A (r' )B (r' )fxc (r, r' , CT )A (r )*B (r ) Exponentially small Exponentially small A r B r ' CT MOL MOL d r d r ' r r' 2 B A 3 2 3 ~ 1/R In TDDFT (single-pole approximation) B A CT MOL MOL d3r d3r' *A (r' )B (r' )fxc (r, r' , CT )A (r )*B (r ) Exponentially small Exponentially small CONCLUSIONS: To describe CT excitations correctly • vxc must have proper derivative discontinuities • fxc(r,r’) must increase exponentially as function of r and of r’ for ω→ΩCT How good is ALDA for solids? optical absorption (q=0) ALDA Solid Argon L. Reining, V. Olevano, A. Rubio, G. Onida, PRL 88, 066404 (2002) OBSERVATION: In the long-wavelength-limit (q = 0), relevent for optical absorption, ALDA is not reliable. In particular, excitonic lines are completely missed. Results are very close to RPA. EXPLANATION: In the TDDFT response equation, the bare Coulomb interaction and the xc kernel only appear as sum (WC + fxc). For q 0, WC diverges like 1/q2, while fxc in ALDA goes to a constant. Hence results are close to fxc = 0 (RPA) in the q 0 limit. CONCLUSION: Approximations for fxc are needed which, for q 0, correctly diverge like 1/q2. Such approximations can be derived from many-body perturbation theory (see, e.g., L. Reining, V. Olevano, A. Rubio, G. Onida, PRL 88, 066404 (2002)). WHAT ABOUT FINITE Q?? see: H.C. Weissker, J. Serrano, S. Huotari, F. Bruneval, F. Sottile, G. Monaco, M. Krisch, V. Olevano, L. Reining, Phys. Rev. Lett. 97, 237602 (2006) Silicon: Loss function Im χ(q,ω) X-ray absorption spectroscopy of 3d metals d band EF 2 1 2p3/2 (4-fold degenerate M3 , 1 , 1 , 3 ) 2 2 2 2 2p1/2 (2-fold degenerate M1 , 1 ) 2 2 Core levels localized: TDDFT works well Pioneers: John Rehr Hubert Ebert Detailed analysis using two-pole approximation M12 ω1 M11 β Ωβ ω2 M22 M 21 From knowledge of the KS orbitals and the KS excitation energies ω1 , ω2 and the experimental excitation energies Ω1 , Ω2 and their branching ratio, one can deduce experimental values for the matrix elements Mij, i.e. one can “measure” fxc. A. Scherz, E.K.U.G., H. Appel, C. Sorg, K. Baberschke, H. Wende, K. Burke, PRL 95, 253006 (2005) PRIZE QUESTION No 2 H(t0) = full static Hamiltonian (without laser field) H t 0 m Em m exact many-body eigenfunctions and energies of system Whenever ρ1(ω) has a pole, the frequency of that pole corresponds to an excitation energy (Em–Eo) of the many-body Hamiltonian H(to) Question: Does each excitation energy (Em–Eo) of the manybody Hamiltonian H(to) yield a pole of ρ1(ω)? In other words, can we expect to get the complete spectrum of the many-body Hamiltonian H(to) from linear-response TDDFT? ANSWER to PRIZE QUESTION No 2 The answer to the question depends on the system under study, but generally the answer is “NO”. The reason is that for some excitation energies (Em-Eo) appearing in the denominator of the response function the numerator may vanish (usually due to symmetry considerations/selection rules, etc.), i.e. there is no pole. It is an experimental fact, that certain states, so-called dark states, are not accessible by a simple direct transition in a weak laser. We do not observe these states in weak-laser experiments and, correspondingly, we also do not observe them in linear-response theory. One may observe these states experimentally, e.g., by cascades from higher states. For the theoretical description, one then needs to calculate non-linear processes. Another possibility to “see” these states within the linear response regime -both experimentally and theoretically- is to apply other probes, such as magnetic fields (instead of lasers).
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