Chapter Four Problems 4.23, 4.27, 4.33, and 4.35. 4.23 a) Compute MAD and MAPE for management’s technique. Ans: 2009-2010 Period Unit Sales July 100 August 93 September 96 October 110 November 124 December 119 January 92 February 83 March 101 April 96 May 89 June 108 Management's Forecast Forecast 120 114 110 108 Total Average Abs Pct Error Absolute Squared Err -19 19 361 18.81% -18 18 324 18.75% -21 21 441 23.60% 0 0 0 0 -58 58 1126 61.16% -14.5 14.5 281.5 15.29% Bias MAD MSE MAPE b) Do management’s results outperform (i.e., have smaller MAD and MAPE than) a naive forecast? Ans: Data 2009-2010 Unit Period Sales July August September October November December January February March April May June 100 93 96 110 124 119 92 83 8 10 15 9 Naive Forecast Abs Pct Forecast Error Absolute Squared Err 5 3 3 9 37.50% 6 4 4 16 40.00% 11 4 4 16 26.67% 12 -3 3 9 33.33% Total 8 14 50 137.50% Average 2 3.5 12.5 34.38% Bias MAD MSE MAPE Management’s Forecast, MAD = 14.5 and MAPE = 15.29% As per the Naive Forecast, MAD = 12.25 and MAPE = 12.12% Using the Naive Forecast, the MAD and MAPE value is lower compared to Management’s Forecast. c) Which forecast do you recommend, based on lower forecast error? Ans: I would recommend that the firm should use the Naive Forecast method to forecast for the 4 months. 4.27 Ans: Year 2006 2008 2009 Season Demand 2007 Demand Demand Demand Winter 1400 1200 1000 900 Spring 1500 1400 1600 1500 Summer 1000 2100 2000 1900 Fall 600 750 650 500 Total average annual demand Average Average 2006-2009 Seasonal Seasonal Demand Demand Index 1125 1250 0.9 1500 1250 1.2 1750 1250 1.4 625 1250 0.5 1250 As per Mark’s forecast, annual demand for his sailboats in 2011 will equal 5,600 sailboats. Demand level for Mark’s sailboats in the spring of 2011 = (5600/4) * 1.2 = 1680 sailboats 4.33 a) Forecast the number of transistors to be made next year, using linear regression. Ans: Period Year 1 Year 2 Year 3 Year 4 Year 5 Intercept Slope Abs Pct Demand Period Forecast Error Squared Err 140 1 144 -4 16 02.86% 160 2 162 -2 4 01.25% 190 3 180 10 100 05.26% 200 4 198 2 4 01.00% 210 5 216 -6 36 02.86% 126 18 Total Average 0 160 13.23% 0 32 02.65% Bias MSE MAPE Number of transistors to be made next year, using linear regression = 126 + 18*6 = 126 + 108 = 234 b) Compute the mean squared error (MSE) when using linear regression. Ans: Mean squared error (MSE) when using linear regression = 32 c) Compute the mean absolute percent error (MAPE). Ans: Mean absolute percent error (MAPE) = 2.65 % 4.35 a) Use the model to predict the selling price of a house that is 1,860 square feet. Ans: The model is: Y = 13,473 + 37.65X The price (Y) of the house = 13473 + 37.65 * 1860 = $ 83502 b) A 1,860-square-foot house recently sold for $95,000. Explain why this is not what the model predicted. Ans: Coefficient of correlation measure expresses the degree or strength of the linear relationship. The coefficient of correlation for the model is 0.63. The strength of relationship as per the model is not that significant and so there is a difference in the model prediction and the actual sale value of the house. c) If you were going to use multiple regression to develop such a model, what other quantitative variables might you include? Ans: Multiple regressions is an associative forecasting method with more than one independent variable. Other quantitative variables that can be considered for this multiple regression would be: - Nos. of floors in the house Distance of the house from major hospital Average distance between two adjacent houses in that area Rent prevailing in the surrounding areas Distance from the Walmart or major shopping complex in the town d) What is the value of the coefficient of determination in this problem? Ans: Coefficient of determination = 0.63 * 0.63= 0.3969
© Copyright 2026 Paperzz