Lesson 2 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS Lesson 2: Wishful ThinkingβDoes Linearity Hold? Student Outcomes ο§ Students learn when ideal linearity properties do and do not hold for classes of functions studied in previous years. ο§ Students develop familiarity with linearity conditions. Lesson Notes This is the second day of a two-day lesson that looks at common mistakes that students make, all based on assuming linearity holds for all functions. In Lesson 1, students were introduced to a new definition of linearity. π(π₯) is a linear transformation if π(π₯ + π¦) = π(π₯) + π(π¦) and π(ππ₯) = ππ(π₯). Students continue to explore linearity by looking at common student mistakes. In Lesson 1, students explored polynomials and radical equations. Lesson 2 extends this exploration to trigonometric, rational, and logarithmic functions. The last exercise in this lesson, Exercise 4, has no real solutions, leading to the discovery of complex solutions, and this launches the study of complex numbers. This study includes operations on complex numbers as well as using the conjugates to find moduli and quotients. Classwork In this Exploratory Challenge, students work individually while discussing the steps as a class. The exercises are completed in pairs with the class coming together at the end to present their findings and to watch a video. Opening Exercise (8 minutes) In the last problem of the Problem Set from Lesson 1, students were asked to use what they had learned in Lesson 1 and then to think back to some mistakes that they had made in the past simplifying or expanding functions and to show that the mistakes were based on false assumptions. In this Opening Exercise, students give examples of some of their misconceptions. Have students put the examples on the board. Some of these are studied directly in Lesson 2, and others can be assigned as part of classwork, homework, or as extensions. ο§ In the last problem of the Problem Set from Lesson 1, you were asked to think back to some mistakes that you had made in the past simplifying or expanding functions. Show me some examples that you wrote down, and I will ask some of you to put your work on the board. οΊ Answers will vary but could include mistakes such as sin(π₯ + π¦) = sin(π₯) + sin(π¦), log(2π) = 2βlog(π), 10π+π = 10π + 10π , 1 π+π = 1 π 1 + , and many others. π Note: Emphasize that these examples are errors, not true mathematical statements. Pick a couple of the simpler examples of mistakes that are not covered in class, and talk about those, going through the steps of Lesson 1. For each example of a mistake, have students verify with numbers that the equation is not true for all real numbers and then find a solution that is true for all real numbers. Indicate to students the statements that are to be reviewed in class. List other statements that may be reviewed later. Lesson 2: Wishful ThinkingβDoes Linearity Hold? This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.26 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 2 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS Exploratory Challenge (14 minutes) ο§ In Lesson 1, we discovered that not all functions are linear transformations. Today, we will study some different functions. ο§ Letβs start by looking at a trigonometric function. Is π(π₯) = sin(π₯) a linear transformation? Explain why or why not. MP.3 οΊ ο§ Students may need a reminder of how to convert between radians and degrees and critical trigonometric function values. Create a chart for students to complete that lists degrees, radian measure, sin(π₯), and cos(π₯). A copy of a table follows this lesson in the student materials. No, sin(π₯ + π¦) β sin(π₯) + sin(π¦) and sin(ππ₯) β π sin(π₯). Does sin(π₯ + π¦) = sin(π₯) + sin(π¦) for all real values of π₯ and π¦? οΊ ο§ Scaffolding: Answers may vary. Substitute some values of π₯ and π¦ into this equation. Some students may use degrees and others radians. Allow students to choose. Alternatively, assign half of students to use degrees and the other half to use radians. Compare answers. ο§ Did anyone find values of π₯ and π¦ that produced a true statement? οΊ Answers will vary but could include π₯ = 0°, π¦ = 0° or π₯ = 180°, π¦ = 180° or π₯ = 0°, π¦ = 90° or the π equivalent in radians π₯ = 0, π¦ = 0 or π₯ = π, π¦ = π or π₯ = 0, π¦ = . 2 ο§ If you used degrees, compare your answers to the answers of a neighbor who used radians. What do you notice? οΊ ο§ The answers will be the same but a different measure. For example, π₯ = 180°, π¦ = 180° is the same as π₯ = π, π¦ = π because 180° = π rad. For example, sin(π + π) = sin(2π) = 0, and sin(π) + sin(π) = 0 + 0 = 0, so the statement is true. Did anyone find values of π₯ and π¦ that produced a false statement? Explain. οΊ Answers will vary but could include π₯ = 45°, π¦ = 45° or π₯ = 30°, π¦ = 30°or π₯ = 30°, π¦ = 60° or the π π π π π π equivalent in radians π₯ = , π¦ = or π₯ = , π¦ = or π₯ = , π¦ = . For example, 4 4 6 6 6 3 β2 β2 π π π π π sin ( + ) = sin ( ) = 1, but sin ( ) + sin ( ) = + = β2, so the statement is false. 4 4 2 4 4 2 2 ο§ Is this function a linear transformation? Explain this to your neighbor. οΊ This function is not a linear transformation because sin(π₯ + π¦) β sin(π₯) + sin(π¦) for all real numbers. Exercises (15 minutes) In the exercises below, allow students to work through the problems in pairs. Circulate and give students help as needed. Call the class back together, and have groups present their results. All groups can be assigned Exercises 1β4. For advanced groups, ask students to find the imaginary solutions to Exercise 4, and/or assign some of the more complicated examples that students brought to class from the Lesson 1 Problem Set and presented in the Opening Exercise. Lesson 2: Wishful ThinkingβDoes Linearity Hold? This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.27 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 2 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS Exercises 1. Let π(π) = π¬π’π§(π). Does π(ππ) = ππ(π) for all values of π? Is it true for any values of π? Show work to justify your answer. π π π π Scaffolding: π π No. If π = , π¬π’π§ (π ( )) = π¬π’π§(π ) = π, but ππ¬π’π§ ( ) = π(π) = π, so the statement does not hold for every value of π. It is true anytime π¬π’π§(π) = π, so for π = π, π = ±π , π = ±ππ . 2. Let π(π) = π₯π¨π (π). Find a value for π such that π(ππ) = ππ(π). Is there one? Show work to justify your answer. π₯π¨π (ππ) = πβπ₯π¨π (π) π₯π¨π (ππ) = π₯π¨π (ππ ) ππ = ππ ππ β ππ = π π(π β π) = π Thus, π = π or π = π. Because π is not in the domain of the logarithmic function, the only solution is π = π. MP.3 3. Let π(π) = πππ . Show that π(π + π) = π(π) + π(π) is true for π = π = π₯π¨π (π) and that it is not true for π = π = π. For π = π = π₯π¨π (π) ο§ For advanced learners, have students determine the general solution that works for all real numbers. ο§ Monitor group work, and target some groups with more specific questions to help them with the algebra needed. Students may need a reminder of the properties of logarithms such as πβlog(π₯) = log(π₯ π ). ο§ Some groups may need to complete the trigonometry value table before starting the exercises. π π(π + π) = ππ(π₯π¨π (π)+π₯π¨π (π)) = πππβπ₯π¨π (π) = πππ₯π¨π (π ) = ππ = π π(π) + π(π) = πππ₯π¨π π + πππ₯π¨π π = π + π = π Therefore, π(π + π) = π(π) + π(π). For π = π = π π(π + π) = πππ+π = πππ = πππππ π(π) + π(π) = πππ + πππ = πππ + πππ = πππ Therefore, π(π + π) β π(π) + π(π). 4. π π Let π(π) = . Are there any real numbers π and π so that π(π + π) = π(π) + π(π)? Explain. Neither π nor π can equal zero since they are in the denominator of the rational expressions. π π π = + π+π π π π π π ππ(π + π) = ππ(π + π) + ππ(π + π) π+π π π ππ = π(π + π) + π(π + π) ππ = ππ + ππ + ππ + ππ ππ = ππ + πππ + ππ ππ = (π + π)π This means that ππ must be a positive number. Simplifying further, we get π = ππ + ππ + ππ . The sum of three positive numbers will never equal zero, so there are no real solutions for π and π. 5. What do your findings from these exercises illustrate about the linearity of these functions? Explain. Answers will vary but should address that in each case, the function is not a linear transformation because it does not hold to the conditions π(π + π) = π(π) + π(π) and π(ππ) = π(π(π)) for all real-numbered inputs. Lesson 2: Wishful ThinkingβDoes Linearity Hold? This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.28 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 2 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS Closing (3 minutes) As a class, have a discussion using the following questions. ο§ What did you notice about the solutions of trigonometric functions? Why? οΊ ο§ Which functions were hardest to find solutions that worked? Why? οΊ ο§ ο§ There are more solutions that work for trigonometric functions because they are cyclical. Answers will vary, but many students may say logarithmic or exponential functions. Are π = 0 and/or π = 0 always solutions? Explain. οΊ No. It depends on the function. οΊ For example, cos(0 + 0) β cos(0) + cos(0) and 10(0+0) β 100 + 100 . Are trigonometric, exponential, and logarithmic functions linear transformations? Explain. οΊ No. They do not meet the conditions required for linearity: π(π + π) = π(π) + π(π) and π(ππ₯) = π(π(π₯)) for all real-numbered inputs Exit Ticket (5 minutes) Lesson 2: Wishful ThinkingβDoes Linearity Hold? This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.29 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 2 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS Name Date Lesson 2: Wishful ThinkingβDoes Linearity Hold? Exit Ticket 1. Koshi says that he knows that sin(π₯ + π¦) = sin(π₯) + sin(π¦) because he has substituted in multiple values for π₯ and π¦, and they all work. He has tried π₯ = 0° and π¦ = 0°, but he says that usually works, so he also tried π₯ = 45° and π¦ = 180°, π₯ = 90° and π¦ = 270°, and several others. Is Koshi correct? Explain your answer. 2. Is π(π₯) = sin(π₯) a linear transformation? Why or why not? Lesson 2: Wishful ThinkingβDoes Linearity Hold? This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.30 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 2 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS Exit Ticket Sample Solutions 1. Koshi says that he knows that π¬π’π§(π + π) = π¬π’π§(π) + π¬π’π§(π) because he has substituted in multiple values for π and π, and they all work. He has tried π = π° and π = π°, but he says that usually works, so he also tried π = ππ° and π = πππ°, π = ππ° and π = πππ°, and several others. Is Koshi correct? Explain your answer. Koshi is not correct. He happened to pick values that worked, most giving at least one value of π¬π’π§(π) = π. If he had chosen other values such as π = ππ° and π = ππ°, π¬π’π§(ππ° + ππ°) = π¬π’π§(ππ°) = π, but π¬π’π§(ππ°) + π¬π’π§(ππ°) = 2. π βπ + , so the statement that π¬π’π§(ππ° + ππ°) = π¬π’π§(ππ°) + π¬π’π§(ππ°) is false. π π Is π(π) = π¬π’π§(π) a linear transformation? Why or why not? No. π¬π’π§(π + π) β π¬π’π§(π) + π¬π’π§(π) and π¬π’π§(ππ) β π π¬π’π§(π) Problem Set Sample Solutions Assign students some or all of the functions to investigate. Problems 1β4 are all trigonometric functions, Problem 5 is a rational function, and Problems 6 and 7 are logarithmic functions. These can be divided up. Problem 8 sets up Lesson 3 but is quite challenging. Examine the equations given in Problems 1β4, and show that the functions π(π) = ππ¨π¬(π) and π(π) = πππ§(π) are not linear transformations by demonstrating that they do not satisfy the conditions indicated for all real numbers. Then, find values of π and/or π for which the statement holds true. 1. ππ¨π¬(π + π) = ππ¨π¬(π) + ππ¨π¬(π) Answers that prove the statement false will vary but could include π = π and π = π. This statement is true when π = π. ππππ, or πππ. ππ°, and π = π. ππππ, or πππ. ππ°. This will be difficult for students to find without technology. 2. ππ¨π¬(ππ) = πβππ¨π¬(π) π π Answers that prove the statement false will vary but could include π = π or π = . This statement is true when π = π. ππππ, or πππ. ππ°. This will be difficult for students to find without technology. 3. πππ§(π + π) = πππ§(π) + πππ§(π) Answers that prove the statement false will vary but could include π = π π and π = . π π This statement is true when π = π and π = π. 4. πππ§(ππ) = πβπππ§(π) Answers that prove the statement false will vary but could include π = π π and π = . π π This statement is true when π = π and π = π. Lesson 2: Wishful ThinkingβDoes Linearity Hold? This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.31 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 2 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS 5. Let π(π) = π . Are there any real numbers π and π so that π(π + π) = π(π) + π(π)? Explain. ππ Neither π nor π can equal zero since they are in the denominator of the fractions. If π(π + π) = π(π) + π(π), then π (π+π)π = π ππ + π ππ . Multiplying each term by ππ ππ (π + π)π, we get ππ ππ (π + π)π π π π = ππ ππ (π + π)π π + ππ ππ (π + π)π π (π + π)π π π ππ ππ = ππ (π + π)π + ππ (π + π)π ππ ππ = (ππ + ππ )(π + π)π ππ ππ = ππ + πππ π + πππ ππ + ππππ + ππ ππ ππ = ππ + πππ(ππ + ππ ) + πππ ππ + ππ π = ππ + πππ(ππ + ππ ) + ππ ππ + ππ The terms ππ , ππ ππ, and ππ are positive because they are even-numbered powers of nonzero numbers. We established in the lesson that ππ = (π + π)π and, therefore, is also positive. The product πππ(ππ + ππ ) must then also be positive. The sum of four positive numbers will never equal zero, so there are no real solutions for π and π. 6. Let π(π) = π₯π¨π (π). Find values of π such that π(ππ) = ππ(π). π₯π¨π (ππ) = ππ₯π¨π (π) π₯π¨π (ππ) = π₯π¨π (π)π ππ = ππ π = ππ π = βπ This is true for the value of π when ππ = ππ that is in the domain, which is π = βπ. 7. Let π(π) = π₯π¨π (π). Find values of π such that π(ππ) = ππ(π). This is true for the values of π when ππ = ππ that are in the domain of the function. 8. Based on your results from the previous two problems, form a conjecture about whether π(π) = π₯π¨π (π) represents a linear transformation. The function is not an example of a linear transformation. The condition π(ππ) = ππ(π) does not hold for all values of π, for example, nonzero values of π and π = π. Lesson 2: Wishful ThinkingβDoes Linearity Hold? This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.32 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 2 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS 9. Let π(π) = πππ + ππ + π. a. Describe the set of all values for π, π, and π that make π(π + π) = π(π) + π(π) valid for all real numbers π and π. This is challenging for students, but the goal is for them to realize that π = π, π = π, and any real number π. They may understand that π = π, but π = π could be more challenging. The point is that it is unusual for functions to satisfy this condition for all real values of π and π. This is discussed in detail in Lesson 3. π(π + π) = π(π + π)π + π(π + π) + π = πππ + ππππ + πππ + ππ + ππ + π π(π) + π(π) = πππ + ππ + π + πππ + ππ + π π(π + π) = π(π) + π(π) πππ + ππππ + πππ + ππ + ππ + π = πππ + ππ + π + πππ + ππ + π ππππ + π = π + π ππππ = π Therefore, the set of values that satisfies this equation for all real numbers π and π is π = π, any real number π, and π = π. b. What does your result indicate about the linearity of quadratic functions? Answers will vary but should address that quadratic functions are not linear transformations, since they only meet the condition π(π + π) = π(π) + π(π) when π = π. Trigonometry Table Angle Measure (π Degrees) Angle Measure (π Radians) π¬π’π§(π) ππ¨π¬(π) π π π π ππ π π π π βπ π ππ π π βπ π βπ π ππ π π βπ π π π ππ π π π π Lesson 2: Wishful ThinkingβDoes Linearity Hold? This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.33 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
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