Always, Sometimes, or Never True Solve for x Limits Derivatives 10 10 10 10 20 20 20 20 30 30 30 30 40 40 40 40 50 50 50 50 Click here for game DIRECTIONS Hardtke Jeopardy Template 2011 10 Always, Sometimes, or Never lim π(π₯) π(π₯) π₯βπ lim = π₯βπ π(π₯) lim π(π₯) π₯βπ Click to check answer SOMETIMES Hint: Not true if lim π π₯ = 0 . π₯βπ Click to return to game board 20 Always, Sometimes, or Never A rational function f has an infinite discontinuity. Click to check answer SOMETIMES Hint: it might have only a removable discontinuity. Click to return to game board 30 Always, Sometimes, or Never x e For f(x) = as x ο β , f(x) ο 0. Click to check answer NEVER Hint: As x ο β, f(x) ο β As x ο - β, f(x) ο 0 Click to return to game board 40 Always, Sometimes, or Never lim π(π₯) = π(π). π₯βπ Click to check answer SOMETIMES Hint: true when f is continuous at a. Click to return to game board 50 Always, Sometimes, or Never If f(0) = -3 and f(5) = 2, then f(c) = 0 for at least one value of c in (-3, 2). Click to check answer SOMETIMES Hint: IVT will prove this true only if is continuous over that interval. Click to return to game board 10 Solve for n f(x) = 2 π₯ βπ₯β6 has an infinite π₯ 2 β4 discontinuity at n. Click to check answer 2 (π₯β3)(π₯+2) Hint: f(x) = has a (π₯β2)(π₯+2) removable discontinuity at -2 and an infinite discontinuity at 2. Click to return to game board 20 Solve for n f is continuous for this value of n. ππ₯ + π π₯ < 4 π π₯ = 3π₯ + π π₯ β₯ 4 Click to check answer 3 Hint: 4n + n = 12 + n when n = 3 Click to return to game board 30 Solve for n 2 25π₯ β3 For f(x) = π₯ + 34 as x ο β β , f(x)ο n Click to check answer β5 As x ο β β , f(x) β | 5π₯ | π₯ ο β5 Click to return to game board 40 lim Solve for n 3 π₯ β64 2 β5π₯+4 π₯ π₯ β4 =n Click to check answer 16 (π₯β4)(π₯ 2 + 4π₯ +16) lim (π₯β4)(π₯β1) π₯ β4 = 48 3 =16 Click to return to game board 50 Solve for n Given polynomial function f, where f(8) = -2 and f(-2) = 3, then there exists at least one value of c β (-2, n) such that f(c) = 0. Click to check answer π Hint: By IVT there must be an x-coordinate between -2 and 8 that produces a y-coordinate between -2 and3. Click to return to game board 10 Limits 2π₯β1 3π₯ 3 Given π π₯ = Find lim π π₯ . π₯ β0 Click to check answer d.n.e. As x β 0 -, f(x) β β. As x β 0 +, f(x) β - β Click to return to game board 20 Limits π₯β3 π₯β3 Given π π₯ = πΉπππ lim π π₯ . π₯ β3β Click to check answer -1 lim π π₯ = β1 πππ lim π π₯ = 1 . π₯ β3β π₯ β3+ Click to return to game board 30 lim π₯ β0 Limits π₯ + 25 β 5 =? π₯ Click to check answer π ππ π₯ + 25 β 5 π₯ + 25 + 5 lim β π₯ β0 π₯ π₯ + 25 + 5 Click to return to game board 40 Limits sin 7π₯ lim π₯ β0 3π₯ Click to check answer π π 7 sin 7π₯ lim 3 π₯ β0 7π₯ = 7 (1) 3 Click to return to game board 50 Limits π₯ π +2 lim π₯ π₯ ββ β 3π β 4 Click to check answer π π =β βπ π Click to return to game board 10 Derivatives π π π₯ =? ππ₯ Click to check answer n-1 nx Hint: This is the Power Rule Click to return to game board 20 Derivatives πβ² π₯ > 0 only on intervals where f(x) is ____. Click to check answer ππππππππππ Hint: rising or going up or has a positive slope are acceptable but not as nice Click to return to game board 30 Derivatives 3 3 2+β β2 lim ββ0 β Click to check answer 12 Hint: for f(x) = x3, you must recognize this as f β (2) where f β(x) = 3x2 and thus f β(2x) = 3(4) = 12 Click to return to game board 40 Derivatives 3 β4 π 6π₯ + 2π₯ ππ₯ 2π₯ β 8π₯ Click to check answer βπ ππ β ππ Hint: divide first then use Power Rule on each π term ο (3π₯ 2 + π₯ β5 β 4) ππ₯ Click to return to game board 50 Derivatives π ππ₯ 5 3 π₯ π₯ =? Click to check answer π βπ π ππ ππ Hint: Subtract exponents first. π ππ₯ 3 π₯5 1 π₯2 Click to return to game board = 1 π π₯ 10 ππ₯ =? Jeopardy Directions β’ Any group member may select the first question and students rotate choosing the next question in clockwise order regardless of points scored. β’ As a question is exposed, EACH student in the group MUST write his solution on paper. (No verbal responses accepted.) β’ The first student to finish sets down his pencil and announces β15 secondsβ for all others to finish working. β’ After the 15 seconds has elapsed, click to check the answer. β IF the first student to finish has the correct answer, he alone earns the point value of the question (and no other students earn points). β IF that student has the wrong answer, he subtracts the point value from his score and EACH of the other students with the correct answer earns/steals the point value of the question. (Those students do NOT lose points if incorrect, only the first student to βring inβ can lose points in this version of the game.) β’ Each student should keep a running total of his own score. β’ Good sportsmanship and friendly assistance in explaining solutions is expected! Reviewing your math concepts is more important than winning. Return to main game board
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