Always, Sometimes, or Never True Solve for x Limits Derivatives

Always,
Sometimes,
or Never True
Solve for x
Limits
Derivatives
10
10
10
10
20
20
20
20
30
30
30
30
40
40
40
40
50
50
50
50
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Hardtke Jeopardy Template 2011
10
Always, Sometimes, or Never
lim 𝑓(π‘₯)
𝑓(π‘₯)
π‘₯β†’π‘Ž
lim
=
π‘₯β†’π‘Ž 𝑔(π‘₯)
lim 𝑔(π‘₯)
π‘₯β†’π‘Ž
Click to check answer
SOMETIMES
Hint: Not true if lim 𝑔 π‘₯ = 0 .
π‘₯β†’π‘Ž
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20
Always, Sometimes, or Never
A rational function f has
an infinite discontinuity.
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SOMETIMES
Hint: it might have only a removable discontinuity.
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30
Always, Sometimes, or Never
x
e
For f(x) =
as x οƒ βˆž , f(x) οƒ  0.
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NEVER
Hint: As x οƒ  ∞, f(x) οƒ  ∞
As x οƒ  - ∞, f(x) οƒ  0
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40
Always, Sometimes, or Never
lim 𝑓(π‘₯) = 𝑓(π‘Ž).
π‘₯β†’π‘Ž
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SOMETIMES
Hint: true when f is continuous at a.
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50
Always, Sometimes, or Never
If f(0) = -3 and f(5) = 2, then
f(c) = 0 for at least one
value of c in (-3, 2).
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SOMETIMES
Hint: IVT will prove this true only if is continuous over
that interval.
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10 Solve for n
f(x) =
2
π‘₯ βˆ’π‘₯βˆ’6
has
an
infinite
π‘₯ 2 βˆ’4
discontinuity at n.
Click to check answer
2
(π‘₯βˆ’3)(π‘₯+2)
Hint: f(x) =
has a
(π‘₯βˆ’2)(π‘₯+2)
removable discontinuity at -2 and an infinite discontinuity at 2.
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20
Solve for n
f is continuous for this value of n.
𝑛π‘₯ + 𝑛 π‘₯ < 4
𝑓 π‘₯ =
3π‘₯ + 𝑛 π‘₯ β‰₯ 4
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3
Hint: 4n + n = 12 + n when n = 3
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30
Solve for n
2
25π‘₯ βˆ’3
For f(x) =
π‘₯ + 34
as x οƒ  – ∞ , f(x)οƒ  n
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–5
As x οƒ  – ∞ , f(x) β‰ˆ
| 5π‘₯ |
π‘₯
–5
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40
lim
Solve for n
3
π‘₯ βˆ’64
2 βˆ’5π‘₯+4
π‘₯
π‘₯ β†’4
=n
Click to check answer
16
(π‘₯βˆ’4)(π‘₯ 2 + 4π‘₯ +16)
lim
(π‘₯βˆ’4)(π‘₯βˆ’1)
π‘₯ β†’4
=
48
3
=16
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50
Solve for n
Given polynomial function f, where
f(8) = -2 and f(-2) = 3, then there
exists at least one value of c ∈ (-2, n)
such that f(c) = 0.
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πŸ–
Hint: By IVT there must be an x-coordinate between -2 and
8 that produces a y-coordinate between -2 and3.
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10
Limits
2π‘₯βˆ’1
3π‘₯ 3
Given 𝑓 π‘₯ =
Find lim 𝑓 π‘₯ .
π‘₯ β†’0
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d.n.e.
As x β†’ 0 -, f(x) β†’ ∞. As x β†’ 0 +, f(x) β†’ - ∞
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20
Limits
π‘₯βˆ’3
π‘₯βˆ’3
Given 𝑓 π‘₯ =
𝐹𝑖𝑛𝑑 lim 𝑓 π‘₯ .
π‘₯ β†’3βˆ’
Click to check answer
-1
lim 𝑓 π‘₯ = βˆ’1 π‘Žπ‘›π‘‘ lim 𝑓 π‘₯ = 1 .
π‘₯ β†’3βˆ’
π‘₯ β†’3+
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30
lim
π‘₯ β†’0
Limits
π‘₯ + 25 βˆ’ 5
=?
π‘₯
Click to check answer
𝟏
𝟏𝟎
π‘₯ + 25 βˆ’ 5 π‘₯ + 25 + 5
lim
βˆ™
π‘₯ β†’0
π‘₯
π‘₯ + 25 + 5
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40
Limits
sin 7π‘₯
lim
π‘₯ β†’0 3π‘₯
Click to check answer
πŸ•
πŸ‘
7
sin 7π‘₯
lim
3 π‘₯ β†’0 7π‘₯
=
7
(1)
3
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50
Limits
π‘₯
𝑒 +2
lim
π‘₯
π‘₯ β†’βˆ’ ∞ 3𝑒 βˆ’ 4
Click to check answer
𝟐
𝟏
=βˆ’
βˆ’πŸ’
𝟐
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10
Derivatives
𝑑 𝑛
π‘₯ =?
𝑑π‘₯
Click to check answer
n-1
nx
Hint: This is the Power Rule
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20
Derivatives
𝑓′ π‘₯ > 0 only on intervals
where f(x) is ____.
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π’Šπ’π’„π’“π’†π’‚π’”π’Šπ’π’ˆ
Hint: rising or going up or has a positive slope are acceptable
but not as nice
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30
Derivatives
3
3
2+β„Ž βˆ’2
lim
β„Žβ†’0
β„Ž
Click to check answer
12
Hint: for f(x) = x3, you must recognize this as f β€˜ (2)
where f β€˜(x) = 3x2 and thus f β€˜(2x) = 3(4) = 12
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40
Derivatives
3
βˆ’4
𝑑 6π‘₯ + 2π‘₯
𝑑π‘₯
2π‘₯
βˆ’ 8π‘₯
Click to check answer
βˆ’πŸ”
πŸ”π’™ βˆ’ πŸ“π’™
Hint: divide first then use Power Rule on each
𝑑
term οƒ 
(3π‘₯ 2 + π‘₯ βˆ’5 βˆ’ 4)
𝑑π‘₯
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50
Derivatives
𝑑
𝑑π‘₯
5
3
π‘₯
π‘₯
=?
Click to check answer
𝟏 βˆ’πŸ—
𝒙 𝟏𝟎
𝟏𝟎
Hint: Subtract exponents first.
𝑑
𝑑π‘₯
3
π‘₯5
1
π‘₯2
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=
1
𝑑
π‘₯ 10
𝑑π‘₯
=?
Jeopardy Directions
β€’ Any group member may select the first question and students rotate choosing the
next question in clockwise order regardless of points scored.
β€’ As a question is exposed, EACH student in the group MUST write his solution on
paper. (No verbal responses accepted.)
β€’ The first student to finish sets down his pencil and announces β€œ15 seconds” for all
others to finish working.
β€’ After the 15 seconds has elapsed, click to check the answer.
– IF the first student to finish has the correct answer, he alone earns the point value of the
question (and no other students earn points).
– IF that student has the wrong answer, he subtracts the point value from his score and
EACH of the other students with the correct answer earns/steals the point value of the
question. (Those students do NOT lose points if incorrect, only the first student to β€œring
in” can lose points in this version of the game.)
β€’ Each student should keep a running total of his own score.
β€’ Good sportsmanship and friendly assistance in explaining solutions is expected!
Reviewing your math concepts is more important than winning.
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