SP_Fall2013_HW7_Q2_answer.pdf

Answer of question 2 of HW6:
𝑃(𝑆2 = π‘Ÿ |𝑆1 = 𝑠, 𝑂2 = 𝑒) =
=
=
=
𝑃(𝑆2 = π‘Ÿ, 𝑆1 = 𝑠, 𝑂2 = 𝑒)
𝑃(𝑆1 = 𝑠, 𝑂2 = 𝑒)
𝑃(𝑆2 = π‘Ÿ, 𝑆1 = 𝑠, 𝑂2 = 𝑒)
βˆ‘π‘Žβˆˆ{π‘Ÿ,𝑠} 𝑃(𝑆2 = π‘Ž, 𝑆1 = 𝑠, 𝑂2 = 𝑒)
𝑃(𝑂2 = 𝑒 | 𝑆2 = π‘Ÿ, 𝑆1 = 𝑠)𝑃(𝑆2 = π‘Ÿ, 𝑆1 = 𝑠)
βˆ‘π‘Žβˆˆ{π‘Ÿ,𝑠,𝑓} 𝑃(𝑂2 = 𝑒 | 𝑆2 = π‘Ž, 𝑆1 = 𝑠)𝑃(𝑆2 = π‘Ž, 𝑆1 = 𝑠)
𝑃(𝑂2 = 𝑒 | 𝑆2 = π‘Ÿ, 𝑆1 = 𝑠)𝑃(𝑆2 = π‘Ÿ|𝑆1 = 𝑠)𝑃(𝑆1 = 𝑠)
βˆ‘π‘Žβˆˆ{π‘Ÿ,𝑠,𝑓} 𝑃(𝑂2 = 𝑒 | 𝑆2 = π‘Ž, 𝑆1 = 𝑠)𝑃(𝑆2 = π‘Ž|𝑆1 = 𝑠)𝑃(𝑆1 = 𝑠)
=
𝑃(𝑂2 = 𝑒 | 𝑆2 = π‘Ÿ)𝑃(𝑆2 = π‘Ÿ | 𝑆1 = 𝑠)𝑃(𝑆1 = 𝑠)
βˆ‘π‘Žβˆˆ{π‘Ÿ,𝑠,𝑓} 𝑃(𝑂2 = 𝑒 | 𝑆2 = π‘Ž)𝑃(𝑆2 = π‘Ž | 𝑆1 = 𝑠)𝑃(𝑆1 = 𝑠)
=
=
𝑃(𝑂2 = 𝑒 | 𝑆2 = π‘Ÿ)𝑃(𝑆2 = π‘Ÿ | 𝑆1 = 𝑠)
βˆ‘π‘Žβˆˆ{π‘Ÿ,𝑠,𝑓} 𝑃(𝑂2 = 𝑒 | 𝑆2 = π‘Ž)𝑃(𝑆2 = π‘Ž | 𝑆1 = 𝑠)
0.8 × 0.05
8
=
β‰… 0.2424
0.8 × 0.05 + 0.1 × 0.8 + 0.3 × 0.15 33
Note: Mentioning the 𝑃(𝑂1 = 𝑒) is irrelevant.