F15 Final Exam Problem 1 Linear Algebra, Dave Bayer [Reserved for Score] 9 test1a4p1 8 4 3 Test 1 Name Uni [1] Solve the following system of equations. w 1 1 1 0 1 1 1 1 0 x = 1 y 1 1 1 0 1 z w x = y z w 1 1 0 x 0 −1 1 = + y 0 0 −1 z 0 0 0 0 r 0 s 0 t 1 F15 Final Exam Problem 2 Linear Algebra, Dave Bayer [Reserved for Score] 3 test1a4p2 9 6 6 Test 1 [2] Find the 3 × 3 matrix A such that 1 0 A 1 = 0 , 1 0 1 0 A −2 = 0 , 0 0 0 0 A 1 = 1 −2 −2 A= 1 0 0 0 0 1 1 1 −3 A = 1 2 1 −3 = 2 7 7 −2 −4 −2 6 F15 Final Exam Problem 3 Linear Algebra, Dave Bayer [Reserved for Score] 6 test1a4p3 1 0 1 Test 1 [3] Let f(n) be the determinant of the n × n matrix in the sequence 1 1 1 −1 1 1 1 0 −1 1 1 0 −1 1 1 1 0 −1 1 1 0 −1 1 0 0 −1 0 0 1 1 1 1 0 0 −1 1 1 0 0 −1 1 1 0 0 −1 1 0 0 0 −1 Find f(8) . f(8) = f(8) = 34 0 0 0 1 1 F15 Final Exam Problem 4 Linear Algebra, Dave Bayer [Reserved for Score] 9 test1a4p4 8 3 4 Test 1 [4] Find eAt where A is the matrix A = 1 −3 −2 0 eAt = λ = −2, 3 e At e−2t = 5 2 3 2 3 + e 3t + 5 3 −3 −2 2 F15 Final Exam Problem 5 Linear Algebra, Dave Bayer [Reserved for Score] 1 test1a4p5 9 2 9 Test 1 [5] Find An where A is the matrix 2 1 0 A = 1 2 0 1 2 2 An = λ = 1, 2, 3 + + An 1 −1 0 1 1 0 0 0 0 n 1n 3 1 1 0 −1 1 0 + 2n 0 0 0 + = 2 2 −2 −1 1 1 −1 0 3 3 0 F15 Final Exam Problem 6 Linear Algebra, Dave Bayer [Reserved for Score] 6 test1a4p6 6 3 0 Test 1 [6] Solve the differential equation y 0 = Ay where 1 1 1 A = 1 1 1 , 2 0 1 y = eAt 0 y(0) = 1 1 + + 4 2 3 5 −2 −3 −1 1 0 e 1 t 4 2 3 + −4 7 −3 + −1 1 0 = 9 9 3 4 2 3 −4 −2 6 2 −2 0 3t λ = 3, 0, 0 5 −5 1 e3t 1 t 5 + 4 + 1 y = 9 9 3 5 4 −2 F15 Final Exam Problem 7 Linear Algebra, Dave Bayer [Reserved for Score] 4 test1a4p7 8 1 5 Test 1 [7] Express the quadratic form 2x2 + 2y2 − 2xz + 2yz + 3z2 as a sum of squares of othogonal linear forms. 2 + 2 + 2 1 −1 1 1 −1 −2 2 0 −1 1 1 0 1 2 1 −1 + 1 1 0 + −1 1 2 1 = −1 A = 0 2 3 3 1 −1 1 −2 2 4 −1 1 3 0 0 0 λ = 1, 2, 4 2 1 (x − y + z)2 + (x + y)2 + (x − y − 2z)2 3 3 F15 Final Exam Problem 8 [Reserved for Score] Linear Algebra, Dave Bayer test93a4p8 Te s t 9 3 [8] Solve for z in the system of differential equations y" = 2y'+y + z z = —2y -[- 2y T z where A f^n 4' 1 1 1 1 O 0 -zz \ y(0) = q'(0) = 0, z(0) = 1 h'l 1 z v^-vSA^t= 2--V0+I =3 rsvvt+st = \-lll= 'H 4+o ^3 A -i=ri-ioi bz'zoi rst—ilVU=» ^ v,s;t <1,"^ (^-\f=G f'l uuil (a C*)ecR ^At -gltgCA-r>F vf , ,3 . o l -
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