Introduction
Operations Scheduling
1. Setting up the Scheduling Problem
2. Single Machine Problems
3. Solving Scheduling Problems
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Operations Scheduling
Program
Week
1
2
3
4
5
6
7
Subject
Introduction, Single Machine Scheduling
Resource Constrainted Project Scheduling
Job Shop Scheduling
Flow Shop Scheduling
Economic Lot Scheduling
Interval Scheduling, Timetabling, Reservation
Workforce Scheduling
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Chapter
1, 2, 3
4
5
6
7
9
12
Operations Scheduling
2
Acknowledgement
We are very grateful for the slides
prepared by colleagues from other
universities, in particular the slides of
Siggi Olafsson has been used in our
course extensively.
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Topic 1
Setting up the Scheduling Problem
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Operations Scheduling
Scheduling
Scheduling concerns optimal allocation or assignment of
resources, over time, to a set of tasks or activities.
–
Machines Mi,
i=1,...,m
(ith machine)
–
Jobs Jj,
j=1,...,n
(jth job)
Schedule may be represented by Gantt charts.
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Notation
Static data:
–
Processing time (pij)
–
Release date
(rj)
–
Due date
(dj)
–
Weight
(wj)
on machine i
Dynamic data:
–
Completion time (Cij)
–
Flow Time
on machine i
(Fj = Cj – rj)
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Modeling
Three components for any machine scheduling model:
–
Machine configuration
–
Constraints and processing characteristics
–
Objective and performance measures
Notation: | |
Characteristics for obviously present because of , are NOT
mentioned.
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: Machine Configuration
Standard machine configurations:
–
(1)
Single-Machine models
–
(Pm)
Parallel-Machine models
–
(Jm)
Job Shop models
jobs have different routes
–
(Fm)
Flow Shop models:
jobs have same order and same machines
–
(Om)
Open Shop:
routing also to be determined
Real world always more complicated:
–
(FJc)
Flexible Job Shop:
with parallel machines at each workstation
–
(FFc)
Flexible Flow Shop:
with parallel machines at each stage
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: Constraints
(rj)
Release dates
(prec)
Precedence constraints
(sjk)
Sequence dependent setup times
(prmp)
Preemptions (resume or repeat)
(block)
Storage / waiting constraints
(Mj)
Machine eligibility
(circ)
Recirculation
Tooling / resource constraints
Personnel scheduling constraints
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: Objectives and Performance Measures
1. Throughput (TP) and makespan (Cmax)
2. Due date related objectives
3. Work-in-process (WIP), lead time (response time), finished
inventory
4. (Setup Times)
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1. Throughput and Makespan
Throughput
–
Defined by bottleneck machines
Cmax max C1 , C2 ,..., Cn
Makespan
Minimizing makespan tends to maximize throughput and balance
load
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2. Due Date Related Objectives
Lateness
Lj C j d j
Lmax
Minimize maximum lateness
Tardiness T j max{0, C j d j }
j
w jT j
Minimize the weighted tardiness
Tardy job
U j 1 if C j d j
U
j
j
Minimize the number of tardy jobs
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Due Date Penalties
Tardiness
Lateness
Lj
Tj
Cj
Cj
dj
dj
Late or Not
In practice
Uj
1
Cj
dj
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Cj
dj
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3. WIP and Lead Time
Work-in-Process (WIP) inventory cost
Minimizing WIP also minimizes average lead time (throughput
time)
Minimizing lead time tends to minimize the average number of
jobs in system
Equivalently, we can minimize sum of the completion times:
j
Cj
or
j
w jC j
WIP TP C j
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Topic 2
Single-Machine Scheduling Problems
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Classic Scheduling Theory
Look at a specific machine environment with a specific objective
Analyze to prove an optimal policy or to show that no simple
optimal policy exists
Thousands of problems have been studied in detail with
mathematical proofs!
3 Examples: single machine
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1. Completion Time Models
Lets say we have
–
Single machine (1), where
–
the total weighted completion time should be minimized (SwjCj)
We denote this problem as
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1|| wj C j
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Optimal Solution
Theorem: Weighted Shortest Processing Time first - called the
WSPT rule - is optimal for
1|| wj C j
Note: The SPT rule starts with the job that has the shortest
processing time, moves on the job with the second shortest
processing time, etc.
wj
WSPT starts with job with largest
pj
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Proof (by contradiction)
Suppose it is not true and schedule S is optimal
–
Then there are two adjacent jobs, say job j followed by job k such that
wj
wk
p j pk
that is
pk w j p j wk
Do a pairwise interchange to get schedule S’
j
k
t p j pk
t
k
t
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j
t p j pk
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Proof (continued)
The weighted completion time of the two jobs under S is
C ( S ) Const (t p j ) w j (t p j pk ) wk
The weighted completion time of the two jobs under S’ is
C ( S ') Const (t pk ) wk (t p j pk ) w j
Now:
C ( S ) C ( S ')
(t p j ) w j (t p j pk ) wk (t pk ) wk (t pk p j ) w j
p j w j p j wk pk wk pk wk pk w j p j w j
p j wk pk w j 0
Contradicting that S is optimal.
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More Completion Time Models
1|| C j
SPT rule
1 || w j C j
WSPT rule
1| rj | C j
NP-hard
1| rj , prmp | C j
preemptive SPT rule
1| rj , prmp | wj C j
NP-hard
1| prec | wj C j
NP-hard
1| chain | w j C j
polynomial algorithm
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2. Lateness Models
Lets say we have
–
Single machine (1), where
–
the maximum cost for late jobs should be minimized (hmax)
–
subject to precedence constraints
We denote this problem as
1| prec | hmax
hj(Cj) denotes the cost for completing job j at time Cj
e.g. hj(Cj) = Cj-dj
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(than hmax = Lmax and EDD optimal)
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Optimal Solution
Theorem: Lawler’s algorithm is optimal for
Lawler’s Backwards recursive algorithm (Minimizing Maximum Cost):
1| prec | hmax
Cmax j p j
1.
Determine makespan
2.
Determine job j* with smallest
3.
Schedule job j* as last job in the sequence
4.
Repeat same procedure with one job less (j*)
h j (Cmax )
Proof by contradiction
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More Lateness Models
1| prec | hmax
Lawler’s algorithm
1|| Lmax
EDD rule
1| rj | Lmax
B&B algorithm (App B2)
1| rj , prec | Lmax
same B&B procedure
1| rj , prmp | Lmax
preemptive EDD rule
Job j is interrupted when job k arrives
with dk < dj
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3. Tardiness Models
Lets say we have
–
Single machine (1), where
–
the number of late jobs should be minimized (SUj)
We denote this problem as 1|| U j
1
with U j
0
if C j d j
otherwise
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Optimal Solution
Theorem: Moore’s algorithm is optimal for 1|| U j
EDD rule with modification:
1. Three sets: J = empty; (complement of J) JC = {1..n}; (tardy jobs) JD
2. Determine job j* with smallest dj
3. If
jJ
p j d j*
then
and
add to J and delete from JC
remove job k from J with largest pj
and add k to JD
4. Repeat step 2 and 3 until JC is empty
Proof by induction
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More Tardiness Models
1|| U j
Moore’s algorithm
1|| w jU j
NP-hard
1|| T j
NP-hard
1|| w jT j
NP-hard
special cases: dj = 0
dj loose
WSPT
MS
otherwise: apparent tardiness heuristic
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Topic 3
Solving Scheduling Problems
(Appendix C)
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General Purpose Scheduling Procedures
Some scheduling problems are easy
–
Simple priority rules
–
Complexity: polynomial time
However, most scheduling problems are hard
–
Complexity: NP-hard, strongly NP-hard
–
Finding an optimal solution is infeasible in practice heuristic methods
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Different Methods
Basic Dispatching Rules
Composite Dispatching Rules
Branch and Bound
Beam Search
Simulated Annealing
Tabu Search
Genetic Algorithms
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Construction
Methods
Improvement
Methods
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Dispatching Rules
Other names: list scheduling, priority rules
Prioritize all waiting jobs
–
job attributes
–
machine attributes
–
current time
Whenever a machine becomes free: select the job with the
highest priority
Static or dynamic
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Release/Due Date Related
Earliest release date first (ERD) rule
–
Earliest due date first (EDD) rule
–
variance in throughput times (flow times)
maximum lateness
Minimum slack first (MS) rule
–
maximum lateness
Current
Time
max d j p j t , 0
Deadline
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Processing
Time
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Processing Time Related
Longest Processing Time first (LPT) rule
–
balance load on parallel machines
–
makespan
Shortest Processing Time first (SPT) rule
–
sum of completion times
–
WIP
Weighted Shortest Processing Time first (WSPT) rule
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Processing Time Related
Critical Path (CP) rule
–
precedence constraints
–
makespan
Largest Number of Successors (LNS) rule
–
precedence constraints
–
makespan
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Other Dispatching Rules
Service in Random Order (SIRO) rule
Shortest Setup Time first (SST) rule
–
Least Flexible Job first (LFJ) rule
–
makespan and throughput
makespan and throughput
Shortest Queue at the Next Operation (SQNO) rule
–
machine idleness
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Discussion
Very simple to implement
Optimal for special cases
Only focus on one objective
Limited use in practice
Combine several dispatching rules:
Composite Dispatching Rules
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Example of
Composite Dispatching Rule
Single Machine with Weighted Total Tardiness
1|| w jT j
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Setup
1|| w jT j
Problem:
No efficient algorithm (NP-Hard)
Branch and bound can only solve very small problems (<30 jobs)
Are there any special cases we can solve?
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Case 1: Tight Deadlines
Assume dj=0
Then
T j max 0, C j d j
max 0, C j C j
w jT j w j C j
We know that WSPT is optimal for this problem!
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Case 2: “Easy” Deadlines
Theorem: If the deadlines are sufficiently spread out then the MS
rule
jselect arg min max d j p j t , 0
is optimal (proof a bit harder)
Conclusion: The MS rule should be a good heuristic whenever
deadlines are widely spread out
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Composite Rule
Two good heuristics
–
Weighted Shorted Processing Time (WSPT )
–
Minimum Slack (MS)
–
Optimal with due dates zero
Optimal when due dates are “spread out”
Any real problem is somewhere in between
Combine the characteristics of these rules into one composite
dispatching rule
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Apparent Tardiness Cost (ATC)
New ranking index
I j (t )
wj
pj
max d j p j t , 0
exp
K p (t )
Scaling constant
When machine becomes free:
–
Compute index for all remaining jobs
–
Select job with highest value
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Special Cases (Check)
If K is very large:
–
If K is very small and no overdue jobs:
–
ATC reduces to WSPT
ATC reduces to MS
If K is very small and overdue jobs:
–
ATC reduces to WSPT applied to overdue jobs
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Choosing K
Value of K determined empirically
Related to the due date tightness factor
1 1
d
Cmax
and the due date range factor
2
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d max dmin
Cmax
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Beam Search
Is B&B with restricted branching
1.
Quick evaluation of all candidates
2.
Choose the F best options (filter width)
3.
Evaluate F options more thoroughly
4.
Choose the B best options (beam width) for branching
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Local Search
N(S) = Neighborhood of a solution S =
set containing all solutions that can be obtained by a simple
modification of S
Step 1: Choose a starting solution S1 with value c(S1); k = 1;
Step 2: Evaluate all solutions S in N(Sk)
Step 3: Choose as Sk+1 the best solution only if c(Sk+1) < c(Sk) and
k = k+1; go to step 2
Otherwise stop (local optimum found)
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Tabu Search
TS = LS with worse solutions allowed
Step 3:
- Choose as Sk+1 the best solution within N(Sk) unless
the associated modification is on the Tabu List.
- Add the modification Sk -> Sk+1 on the Tabu List.
- Remove oldest entry of the Tabu List.
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Graphically
If c(Sk+2) > c(Sk+1) then
Sk+1 is a strong candidate
for Sk+3
Sk
Sk+1
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Sk+2
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Exercises
From chapter 3:
3.2, 3.4
From appendix C:
C.1, C.4, C.6 (1 step), C.9
Single Machine Problems (see Blackboard)
Proof algorithm of Moore optimal for 1|| U j
Proof EDD optimal for 1|| Lmax
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