This Peseat'ch was partialty supported by" the Anrty Research Office" DA-ARO-D-31-124~G910 and the u.s. Air Force Office of Scientific ReiJearoch under Contract AFOSR-68-1406 • Durham" under Grant No. ., o 7 8 ' 1 352 ~ 6 6 1 7 • '·2 4 350 5 0 2 78' 3 ~ 6 1'3 7. 065 .. ,.7"123 7 1 0 6 5 , • 2 3 ~ 812 1 069 3 .. 5 '8732 " 10"56 1 ~;8 7 .. 3.2 5 ' 0 3 Z 9 8 7 5 .. 601 5 ~" 3 9 ~ ~ 6·1 8 9 5 0 2 '613", 7 0 2 .. 6 1 3 5 COMBINATORIAL MATHEMATICS VEAR 7 UlU 0 1 9 " 7 8. 2' 9 7 - 7 , 0 1 2 Z 3 .. 560 1 789 .. 5 , 0 I" 2 3 8 , 1 ,."."." 1'" - .r..... 1'10 6 0 1 23" 5 , 7 8 STEINER TRIEDERS AN)) STRONGLY REGULAR GP.APHS by Elisabeth Carriere Department: of Statistics and FaauZte deB ScienaeB University oj" North Carolina Universite de Paris " University of North Carolilla at Chapel Hill Institute of Statistics rIimeo Series No. 600.26 }Iay 1970 STEINER TRIEDERS AND STRONGLY REGULAR GRAPHS by .. ELISABETH CARRIERE Depaz-tment of Statistics University of North Cazoolina at Chapel, Hil,l and Faaulte des Sciences Universite de Parois 1. INTRJIlJCTIQ\J A finite, undirected linear graph regular of valence exactly 1 Pu n , l G is strongly regular if it is each adjacent pair of vertices is adjacent to other vertices, and each non-adjacent pair of vertices is adjacent to exactly P~l other vertices. We shall consider the Steiner configuration of 45 triangles formed by 27 straight lines contained in a general cubic surface. The graph assOo-· . dated with this configuration will be proved to be strongly regular. The Steiner configuration has an interesting property about its triangles, and we shall see under which conditions graphs satisfying this property are strongly regular. 2. THE STEINER CDiFIGUPATlm The Steiner configuration, determined by the 27 straight Unes of any cubic surface has the following properties (see [2] and [4]): This l'eseaPch lJQB parrtial'Ly supported by the Army Reseazoch Office~ lAJ,phan.. unde1' Grant No. DA-AROD-31-124- G9IO and the u.S. Ail' F01'ce Office of Scientific Research uruier Contract AFOSR-68-1406. 2 P.2.l. Each straight line A meets ten others. P.2.2. The ten lines which meet any line A cut in pairs to form five triangles with A. P.2.3. AlBlC l , A2B2C2 with no side in common, there exists a unique triangle ~B3C3' such that Al A2A3 , Given two triangles Bl B2B3 , Cl C2C are three more triangles, and 3 ~B3C3 has no side in common with AlBlC l and A2B2C2 • These nine lines forming six triangles are called the Steiner trieder. Let us consider the graph G associated with the Steiner configuration and defined as follows: 1. The vertices of the graph G are the lines of the configuration. 2. Two vertices of the graph G are adjacent if their corresponding lines intersect in the configuration. Thus each triangle in the configuration determines a triangle in the graph (the sides of a triangle become its vertices). Let us rewrite the properties P.2.l, P.2.2, P.2.3 P.l: Each vertex is adjacent to ten others. P.2: The ten vertices adjacent to any vertex x for the graph G: of the graph are associated in adjacent pairs to form five triangles with x. P.3: Given two triangles xlylzl and x2YZzZ of G with no vertex in common, there exists a unique triangle x3Y3z3 such that x l x 2x 3 , YlY2Y3' zlz2z3 arc three nore triangles and x3Y3zj. has no vertex i~ common with xlylzl and x2Y2z2' These nine vertices will also be said to form a Steiner trieder. The graph G has 27 vertices and is regular of valance 10 by P.l. 3 PImEITla~ 1. The graph G associated with the Steiner configuration is strongly regular with the parameters: 1 v · 27, n • 10, l 2 Pll • 1, Pll· 5. PIUf: First, let us notice that the property P. 3 implies obviously the following property: P.2.3 Given two triangles xlylzl and x2Y2z2 of the graph G, with no vertex in canmon, each vertex of one triangle is adjacent at least to one vertex of the other tr1aDgle. Given any pair a vertex to x,y Z and x,y of adjacent vertices of such that z. xyz is a triangle. adjacent neither to x G. vertex of the triangle nor to uvw y, xyz. nor to u u which is and a triangle z z, the 27 uvw which P.2.3, each is adjacent neither to xyz, x nor z. x,y is the unique vertex which is adj acent to Thus we have x and has to be adjacent to one vertex of Then, the 24 vertices adjacent to form with x,y But, by the property which contradicts our hypothesis that nor to There are 24 vertices adjacent If not, there exists a vertex has no vertex in common with y there exists, by P.2, If they -are distinct, we have, with vertices of the graph to G, 1 Pll. 1. x and z and are distinct and z y. The ten vertices adjacent to any vertex five triangles, two of them having only x x as a common vertex. Any pair triangles. x, y of nonadjacent vertices of G dcu.eminetO- distinct 4 Let xxIx and 2 yy lY2 be two of these triangles. two vertices in common, since say Xl· Y1' P~l· 1. If they have one vertex in common, and if the third vertex have a triangle l 2 is nonadjacent to y x 2 is adjacent to 1 Pu· 1. which is impossible since yx x and Y2 is nonadjacent to x If they have no vertex in common, the property that is that at least one of is adjacent to of Y1'Y x. x l ,x2 But if both of are adjacent to 2 x, They cannot have is adjacent to x ,x then l 2 yx x l 2 we will Hence, x 2 for the same reason. P. 2.3 y XYlY2 must hold, and one of are adjacent to or y, y, Yl' Y2 or if both will be a triangle which contradicts that P~l. 1. Thus each of the five triangles deter- mined by the vertex has one and only one vertex which is adj acent to x That is there are exactly five vertices adjacent to have x and y and we 2 Pll. S•. 3. GPJfHS SATISfYING 1lE PRH:RtY P.3. Consider a graph with at least two triangles with no vertex in G, cammon and satisfying P.3. Xi' Yi' zi' i D 1 to 3 G has at least nine distinct vertices which form a Steiner tr1eder TO' that is, which satisfy the following: P.3.3 Given two triangles which are two rows of Xl Y1 zl ~ Y2 z2 x 3 Y3 z3 the third row is the unique triangle such that each column is a triangle then we have the following property: P.3.4 for i . j, i, j • 1 to 3. y. 5 Yi and Y j and Zj are nonadjacent z1 and x are nonadj acent Xi j are nonadjacent PfmF: Suppose xl adjacent to Y2 , then xl x2Y2 and x l Yl Y2 will be two triangles with no vertex in common with be adjacent to xl' If have Xl x2 x3 z3 zlz2z3. Then z3 has to or to Y , or to x and Y • 2 2 l is adjacent to xl' then z l xl z 3 is a triangle and we Yl zl Y2 xl Y3 z3 where each row and each column 1s a triangle which contradicts If have 1s adjacent to P.3.3 is a tr1angle and we Y2' Xl Yl Y2 x 2 Y2 z2 x3 Y3 z3 where each row and each column is a triangle which contradicts P.3.3 If is adjacent to Yl are two triangles and we have and x2 ' xl Yl zl where each row and each column is a triangle which contradicts P. 3.3 6 Thus xl is not adjacent to Y2 other pair and 1'.3.4 holds. This implies three more properties: Any triangle xyz 1'.3.5 and we can reason similarly for any of G which is not contained in the trieder TO has at most one vertex in CODlllon with it. triangle xyz p.3~6 .Any 1'.3.7 For any pair xy one vertex If xyz of adjacent vertices of G, z adj acent to x is a triangle of vertices xy of G is contained in a Steiner trieder. G and y. not contained in TO' in common with TO' say x· xl' distinct from Y since they are not adjacent to then z;e zl and xyz· xlYlz that is which has two then Y2z2Y3z3 Xi Suppose are y. Y1' has no vertex in common with x2Y2z2 x3y3 z3 and 1'.2.3 implies that are adjacent to z, there is at most z2 zZ2z3 and z3 and nonadjacent to Xl is a triangle. and Yl We have Xl Yl z x2 Y2 z2 x 3 Y3 z3 Where each row and each column is a triangle which contradicts 1'.3.3 since z;e zl. Thus 1'.3.5 is satisfied. It follows that any pair of adjacent vertices in TO unique triangle. determine a It also follows that for any triangle xyz of G there is a triangle of TO which has no vertex in common with it and by 1'.3 they must form with a third triangle a Steiner trieder. Thus P.3.6 and 1'.3.7 are satisfied. Let us introduce now one more property: 1'.3.8 Each vertex of the graph G is contained in at least one triangle. 7 A graph G with at least two triangles with no vertex in common, satisfying P.3.8 and P.3 also satisfies: P.3.9 Each vertex of G is contained in a Steiner trieder. THEOIm 1. A finite. undirected linear graph G, containing at least two triangles with no vertex in common satisfies P.3.9· iff it is strongly regular. v lID 3(2r-l), n l Its parameters are: lID 1 2r, r Pll ... 1, ~ 2 PfmF: Let xy be a pair of adjacent vertices of P.3.8 imply that there is a unique vertex z then P. 3. 7 and G, and which is adjacent to x 1 The valence n of each vertex x of G is even and x nx x is contained in 2 triangles. Let xy be a pair of nonadjacent y. Then Pll'" 1. vertices in G, and xxl x 2 ' "lY2 be two triangles. If they have one vertex in common, Xl III y1' and if x 2 is adjacent to y, or Y2 adjacent to x, diets that then yx x2 or XYIY2 will be a triangle which contral 1 PIl'" 1. If they have no vertex in common they must form with a third triangle a Steiner trieder and P.3.4 implies, since x is not adjacent to Y that one and only one of x ,x2 is adjacent to y, l and one and only one of Yl'Y2 is adjacent to x. of triangles containing respectively x and n n in x triangles and Y in .J.. triangles. 2 2 n -!X there are vertices of G adjacent to 2 Now let x be a vertex of valence n == l > 2. y. And this for any pair But x is contained That implies nx ... ny c: xy. 2r in G, r must be n xy and 8 xyz For any vertex y is a triangle. Then, for every adj acent to x nor to adjacent or not to is regular. x adjacent to y and then x. there is a vertex zi n n D y has the same valence 1:1 zi G is 3(2r-l). A strongly regular graph G, 3(2r-l), n 1 1:1 2r, l = 2r. is not Thus any vertex .. 2r, and the graph G 2 nl Pl1""2" .. r. Then the The converse is obvious. with at least two triangles with no vertex in common satisfies a n z, such that ~ It also is strongly regular with number of vertices in V adjacent to z P.3 iff its parameters are 1 Pl1 .. 1, 2 Pu 1:1 r, r > 2. Strongly regular graphs with such parameters have been proved by Seidel in [3] to exist only for r 1:1 1, 2, 3, andS. I would like to express my thanks to suggested to me the study of the property I. M. Chakravarti P.3. see [1]. who REFERENCES [1] Chakravarti, I. M., Some properties and applications of Hermitian varieties in a finite p~ojective space PG(N,q2) in the construction of strongly regular graphs (two-class association schemes) and block designs. Institute of Statistics Mimeo Series No. 600.23. March 1970, U.N.C., Chapel Hill. [2] J"ordan, -C., Trait~ des SUbstitutions et des Equaticns Gauthiers-Vi11ars, Paris (1870). [3] Seidel, J. J., Strongly regular graphs with (-1, 1, 0) adjacency matrix having eigenvalue 3. Linear AZgebraa and Its AppUaations, 1 (1968), 281-298• [4] Steiner, J., Uber e1ne besondere curve dritter Klasse (und vierten. Grao1.es),. J"ou.:ma'L fUra die Reine una. Angewandte Mathematik~ Berlin, 1857, Vol. 53, pp. 231-237. .. A19~brique8.
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