HW6: Answer key ***Note that there are several problems included below that weren’t assigned. *** Chapter 6 52a. 3.36x10-2 g H2O2 Chapter 7 52. 58. C3H8 + 5 O2 3 CO2 + 4 H2O 60. 2 NH3 + CO2 CO(NH2)2 + H2O Chapter 8: In 24a, below, the starting quantity should be 0.044 mol, and the answer is 0.088 mol. A. " 0.001 g %" 1 mole CO 2 %" 6.022x10 23 molecules CO 2 %" 2 atoms O % 21 180 mg CO 2 $ '$ '$ ' = 4.926x10 atoms O '$ 1 mole CO 2 # 1 mg &# 44.01 g CO 2 &#  molecule CO 2 & B. ! ! %"147.94 g Na 3PO 4 % "1 formula unit Na 3PO 4 %" 1 mole Na 3PO 4 2 9.8x10 24 Na + cations$ '$ '$ ' = 8.0x10 gNa 3PO 4 + 23 # &# 6.022x10 formula units Na 3PO 4 &# 1 mole Na 3PO 4 & 3 Na cations
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