Friday, September 25

MATH 817 Notes
JD Nir
[email protected]
www.math.unl.edu/∼jnir2/817.html
September 25, 2015
I’ll post the final version of problem set #4 today (due Wednesday)
Recall:
• G simple if G 6= {e} and {e} and G are the only normal subgroups of G.
• A composition series of G is a chain
e = N0 E N1 E . . . E N` = G
such that ` ≥ 0 and
is simple ∀i = 1, . . . , `
Ni/Ni−1
Note Ni need not be normal in G
Prop. If #G < ∞ then it has a composition series.
Pf:
• If G = {e}, ` = 0 works: {e} = N0 = G.
• #G > 1. S = {N | N E G, N 6= G}
S is non-empty since {e} ∈ S. So, let N ∈ S be maximal (S is a nonempty, finite poset).
Then #N < #G and by induction on order, N has a composition series:
{e} = N0 E N1 E . . . E Nj = N.
N
k
I claim {e} = N0 E N1 E . . . E Nj E Nj+1 = G is a composition series of G. It suffices to show
G/N is simple.
G/N
6= {e} , N 6= 0.
4
G
H
If L4
6= /N is a proper normal subgroup, then L = /N for some H ≤ G, N ≤ H and H 6= G,by the
Lattice Theorem (4th Isomorphism Theorem). So H ∈ L and N ≤ H ⇒ H = N ⇒ L = eG/N .
∴ G/N is simple.
Ex 1
=
”
4
“
6=
Z/2
5
hr i
Z/5
{e}
∼
=
∼
=
∼
=
Z/2
Z/5
Z/2
4
Z/2
hri
4
4
=
“ E and 6= ”
hri
4
”
4
“
D20
hr2 i
4
4
D20
{e}
` = 3 = k σ = (1 2)
1
JD Nir
[email protected]
MATH 817
Theorem [Jordan-Holder] If {e} = N0 E N1 E . . . E N` = G and {e} = M0 E M1 E . . . E Mk = G
are two composition series of the same group G, then ` = k and ∃σ ∈ S` such that
Ni/Ni−1
∼
= Mσ(i)/Mσ(i)−1 ∀i = 1, 2, . . . , `.
Z/2

S4

E
Ex 2
E
Z/2
∼Z
Z
V = {e, (1 2)(3 4), (1 3)(2 4), (1 4)(2 3)} = /2 × /2
h(1 2)(3 4)i
Z/2
E
Z/3
E
A4
{e}
Def: If G has a composition series,
{e} = N0 E . . . E N` = G,
the multi-set {N1/N0 , N2/N1 , . . . , N`/N`−1 } is the multi-set of composition functions of G. It’s well
defined by Jordan-Holder.
A group is solvable if it has a composition series and its composition factors are all abelian groups
(and thus are all Z/p, for various primes p.)
Note: If G us simple and abelian, then G ∼
= Z/p for some prime p.
Pf: Pick x ∈ G, x 6= e, then e 6= hxi E G and so G = hxi. It follows #G must be prime.
Ex D20 , S4 are solvable.
If G is solvable, then #G = pe11 pe22 · · · penn and the composition factos of G are
e
e
e
n
z
}|1
{ z
}|2
{
z
}|
{
Z/p1 , · · · , Z/p1 , Z/p2 , · · · , Z/p2 , . . . , Z/pn , · · · , Z/pn
Why? If {e} = N0 E N1 E . . . E N` = G and #G, then
#G = #N1/N0 · #N2/N1 · · · #N`/N`−1
Ex Sn , n ≥ 5
composition functions of Sn : An , Z/2
Since An is simple, An E Sn ,
Sn/An
∼
= Z/2 {e} E An E Sn
Def A normal series of a group G is any chain {e} = N0 E N1 E N2 E . . . E N` = G. (Ni need not
be normal in G, Ni/Ni−1 need not be simple, Ni = Ni−1 is allowed)
A refinement of a given normal series of G is any pther normal series of G obtained by “inserting
more steps”
2
MATH 817
JD Nir
[email protected]
Two normal series e = N0 E N1 E . . . E Nk = G and e = M0 E M1 v . . . E M` = G are equivalent
if k = ` and ∃σ ∈ S` such that
Mi/Mi−1
∼
= Nσ(i)/Nσ(i)−1 , i = 1, . . . , `
Prop Any two normal series for the same group admit equivalent refinements.
3