Stable Commutator Length in Amalgamated Free Products Tim Susse CUNY Graduate Center GST Seminar University of Nebraska – Lincoln April 15, 2014 Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 1 / 32 Definitions Let G be a group, and g ∈ [G, G]. cl(g) is the minimal number of commutators whose product is g. In other words, cl(g) is the word length of g in [G, G] = h[a, b] : a, b ∈ Gi. Let G = F2 = ha, bi, then cl([a, b]) = 1, cl([a, b]2 ) = 2, but cl([a, b]3 ) = 2 Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 2 / 32 Definitions Let G be a group, and g ∈ [G, G]. cl(g) is the minimal number of commutators whose product is g. In other words, cl(g) is the word length of g in [G, G] = h[a, b] : a, b ∈ Gi. Let G = F2 = ha, bi, then cl([a, b]) = 1, cl([a, b]2 ) = 2, but cl([a, b]3 ) = 2 (Culler, 1981) [a, b]3 = [aba−1 , b−1 aba−2 ][b−1 ab, b2 ]. So, cl is not homogeneous with respect to taking powers. Definition. cl(g n ) . Since n 7→ cl(g n ) is subadditive, this limit always n→∞ n scl(g) = lim exists. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 2 / 32 Basic Facts 1 If cl(g) is uniformly bounded on G, then scl is identically zero. 2 If φ : G → H is a homomorphism then sclH (φ(g)) ≤ sclG (g). 3 If r : G → H is a retraction homomorphism, then r preserves scl (is an isometry). 4 sclG×H ((g, h)) = max{sclG (g), sclH (h)}. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 3 / 32 Reformulation Definition. Let π1 (X ) = G. A map f : S → X of a surface S is called admissible for h ∈ [G, G] if for some representative γ : S 1 → X of h, we have: i ∂S −−−−→ y∂f S yf γ S 1 −−−−→ X such that (∂f )∗ [∂S] = n(S)[S 1 ] and the diagram commutes up to homotopy. If S has one boundary component and genus g, this implies that hn(S) is a product of g commutators. This was first used by Culler in 1981 to study solutions to quadratic equations over free groups. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 4 / 32 Reformulation If S has one boundary component and genus g, this implies that hn(S) is a product of g commutators. This was first used by Culler in 1981 to study solutions to quadratic equations over free groups. Theorem. Let X be a topological space with π1 (X ) = G. Then for any g ∈ G −χ− (S) scl(g) = inf , 2n(S) where the infimum is taken over all admissible surfaces for g with one boundary component and χ− (S) the sum of the Euler characteristics of all components of S with non-positive Euler characteristic. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 4 / 32 Homology and One-Boundaries The bar complex of a group is a chain complex used to compute the homology of a group. Here, Cn (G, R) = R[Gn ], of some ring R with unit (usually R, Q or Z) and: ∂ ∂ ∂ ∂ ∂ ··· − → Cn (G, R) − → Cn−1 (G, R) − → ··· − → C2 (G, R) − → C1 (G, R) → 1 with ∂(g1 , g2 , . . . , gn+1 ) = + (g2 , g3 , . . . , gn+1 ) n X (−1)i (g1 , . . . , gi−2 , gi−1 gi , gi+1 , . . . , gn+1 ) i=1 (−1)n+1 (g1 , g2 , . . . , gn ). + Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 5 / 32 Homology and One-Boundaries The bar complex of a group is a chain complex used to compute the homology of a group. Here, Cn (G, R) = R[Gn ], of some ring R with unit (usually R, Q or Z) and: ∂(g1 , g2 , . . . , gn+1 ) = + (g2 , g3 , . . . , gn+1 ) n X (−1)i (g1 , . . . , gi−2 , gi−1 gi , gi+1 , . . . , gn+1 ) i=1 (−1)n+1 (g1 , g2 , . . . , gn ). + For example: ∂ : C2 (G) → C1 (G) is given by ∂(g, h) = h − gh + g = g + h − gh. . G Further H1 (G, Z) = , the abelianization. [G, G] Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 5 / 32 Reformulation Part II Theorem. Let X be a topological space with π1 (X ) = G. Then for any g ∈ G −χ− (S) , scl(g) = inf 2n(S) where the infimum is taken over all admissible surfaces for g. This reformulation of stable commutator length allows S to have multiple boundary components, and extends the scl to 1-boundaries of G. We consider B1 (G; R) the set of all real one-boundaries of G. Proposition. . scl is a pseudonorm on B1H (G; R) = B1 (G; R) g n − ng, hgh−1 − g . Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 6 / 32 Bavard Duality Theorem There is also an alternate way to compute stable commutator length from quasimoriphisms. Definition. A quasimorphism is a function φ : G → R so that there is a least non-negative number D(φ), called the defect, so that for every g, h ∈ G: |φ(gh) − φ(g) − φ(h)| ≤ D(φ). Further, a quasimorphism is called homogenous is φ(g n ) = nφ(g) for every integer n. For example, any homomorphism or bounded function to R is naturally a quasimorphism. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 7 / 32 Bavard Duality Theorem Definition. A quasimorphism is a function φ : G → R so that there is a least non-negative number D(φ), called the defect, so that for every g, h ∈ G: |φ(gh) − φ(g) − φ(h)| ≤ D(φ). Further, a quasimorphism is called homogenous is φ(g n ) = nφ(g) for every integer n. For example, any homomorphism or bounded function to R is naturally a quasimorphism. The space of homogenous quasimorphisms of a group is denoted . HQH(G) is the kernel of the HQH(G). The vector space H 1 (G; R) comparison map Hb2 (G; R) → H 2 (G; R) between second real bounded cohomology and ordinary second real cohomology. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 7 / 32 Examples Example (Brooks) If G = Fr is the free group, and w ∈ Fr is some reduce word let cw (g) be the maximal number of disjoint copies of w appears as a subword of g. Let hw (g) = cw (g) − cw −1 (g). This is a quasimorphism with defect at most 2, called a Brooks Counting quasimorphism. Brooks originally did not have the disjoint condition. Removing it leads to a defect of at most 3(|w| − 1). Rotation Let G y S 1 . Lift this action to an action on R. Then g n (0) rot(g) = lim . This is the (lifted) rotation number. This a n→∞ n quasimorphism on the induced central extension of G. Its defect is 1 (this is due to Poincare). Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 8 / 32 Theorem. (Bavard Duality Theorem) Given a chain η ∈ B1H (G), the following holds: scl(η) = sup φ∈HQH/H 1 Tim Susse CUNY Graduate Center SCL in AFP φ(η) . 2D(φ) April 11, 2014 9 / 32 Theorem. (Bavard Duality Theorem) Given a chain η ∈ B1H (G), the following holds: scl(η) = sup φ∈HQH/H 1 φ(η) . 2D(φ) Why? Let φ ∈ HQH. Then firstly, φ(g) = φ(hgh−1 ) for all h ∈ G. So, given a commutator [a, b], we have: |φ([a, b])| = |φ(abAB)| ≤ D(φ) + |φ(a) + φ(bAB)| = D(φ) + |φ(a) + φ(A)| = D(φ) Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 9 / 32 Theorem. (Bavard Duality Theorem) Given a chain η ∈ B1H (G), the following holds: scl(η) = sup φ∈HQH/H 1 φ(η) . 2D(φ) Why? Let φ ∈ HQH. Then firstly, φ(g) = φ(hgh−1 ) for all h ∈ G. So, given a commutator [a, b], we have: |φ([a, b])| = |φ(abAB)| ≤ D(φ) + |φ(a) + φ(bAB)| = D(φ) + |φ(a) + φ(A)| = D(φ) So, if cl(w) = k, then |φ(w)| ≤ (2k − 1)D(φ). Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 9 / 32 Computing SCL In general, scl is very hard to compute. It is known to be identically zero in some cases: Abelian groups Amenable groups Lattices in higher rank Lie groups Subgroups of PLHomeo+ (I), where I ⊂ R is an interval (e.g., Thompson’s Group F ). Precise computations are only known in the following classes of finitely generated groups: 1 Free Groups [Calegari, 2009 & Walker, 2013 with an efficient algorithm] 2 Free products of Abelian groups [Calegari, 2011] 3 Stein-Thompson Groups [Zhuang, ’08] (only known irrational examples) 4 Some elements of Baumslag-Solitar groups [Clay-Forester-Louwsma, ’13] Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 10 / 32 PQL Groups In all but the fourth example above, the scl is rational on the group and is a piecewise rational linear (semi-)norm on B1H (G). Such a group is called PQL. Conjecture. (Calegari) Let M be a 3-manifold. Then π1 (M) is PQL. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 11 / 32 PQL Groups In all but the fourth example above, the scl is rational on the group and is a piecewise rational linear (semi-)norm on B1H (G). Such a group is called PQL. Conjecture. (Calegari) Let M be a 3-manifold. Then π1 (M) is PQL. Why the Conjecture? Let M be a (closed) 3-manifold. Consider the Thurston norm on H2 (M; R) (or relative to the boundary). For some class α ∈ H2 (M; R) : kαkT = inf −χ− (S), taken over all S representing α. S So, scl is a natural relativization of the Thurston norm! Since the Thurston norm is PQL, perhaps the scl norm on B1H (π1 (M)) is as well. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 11 / 32 Results Theorem. (Susse) Let A and B be two free Abelian groups of rank at least k , then A ∗Zk B is PQL. Further, there is an algorithm to compute scl on rational chains. Theorem. (Susse) Let {Ai } be a collection for free Abelian groups of rank at least k . Then ∗Zk Ai , their free product amalgamated over a single shared subgroup, is PQL. Further, there is an algorithm to compute scl on rational chains. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 12 / 32 Results Theorem. (Susse) Let A and B be two free Abelian groups of rank at least k , then A ∗Zk B is PQL. Further, there is an algorithm to compute scl on rational chains. Theorem. (Susse) Let {Ai } be a collection for free Abelian groups of rank at least k . Then ∗Zk Ai , their free product amalgamated over a single shared subgroup, is PQL. Further, there is an algorithm to compute scl on rational chains. Note that, up to isomorphism, G = a1 , . . . an , b1 , . . . , bn | [ai , aj ] = [bi , bj ] = 1, a1r1 = b1s1 , . . . , akrk = bksk . If A = B = Z, then A ∗Z B = a, b : ap = bq . If (p, q) = 1, then G = π1 (S 3 \ K ), where K is a torus knot. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 12 / 32 The Set-up Let G = A ∗Zk B and let TA and TB be tori whose fundamental groups are identified with A and B respectively. Let X be the space formed by taking a cylinder T k × [0, 1] and gluing T k × {0} to TA and T k × {1} to TB so that π1 (X ) = G. Let f : S → X be a map of a surface with (possible empty) boundary, and let C = T k × { 12 }. WLOG we can assume f −1 (C) is a disjoint collection of arcs with end points on ∂S and simple closed curves. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 13 / 32 Parameterizing Surfaces WLOG, components of S \ f −1 (C) are planar surfaces with boundary, whose boundaries are made of arcs alternating between: Arcs from ∂S (τ -edges); Arcs from f −1 (C) (σ-edges) Some boundary components may be loops from f −1 (C) (σ-loops) Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 14 / 32 Parameterizing Surfaces WLOG, components of S \ f −1 (C) are planar surfaces with boundary, whose boundaries are made of arcs alternating between: Arcs from ∂S (τ -edges); Arcs from f −1 (C) (σ-edges) Some boundary components may be loops from f −1 (C) (σ-loops) Using the σ- and τ -edges we can parameterize all of the surfaces S → X. Problem: We need to control contributions from σ-loops. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 14 / 32 Outline of the proof Let η ∈ B1H (G; Z) 1 Control σ-loops by investigating gluing equations and winding numbers. 2 Given a vector which can parameterize a surface (in one of the two tori), estimate the Euler characteristic in a piecewise rational linear way. 3 Given vectors parameterizing surfaces which are compatible, ensure that there is a way to glue them, after considering winding numbers – do this by adding loops. 4 Show that the Euler characteristic estimate from the second step is still good. 5 Maximize the Euler characteristic over a rational polyhedron parameterizing all surfaces with boundary (a multiple of) η using linear programming. Since we are looking at a piecewise rational linear function over a rational polyhedron, the maximum is rational. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 15 / 32 Step 1: Winding Numbers and Gluing Equations Take a component of S \ f −1 (C). Attached to each σ-edge is a k-tuple of integers, giving the class of the edge in H1 (C) ∼ = Zk . 4 a −1 −1 a4 a4 0 Figure: A disc in the (6, n) torus knot complement For every component, the sum of the τ -edges and labels of the σ-edges must be 0 in homology. Here, the τ -edges contribute 12a and each −1 on the σ-edges contributes −6a. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 16 / 32 Winding Numbers and Gluing Equations For each component the sum of the winding numbers σ-edges and σ-loops must make up the “homology deficit” of the τ -edges in the component. For each torus we get a system of gluing equations where each σ-edge or loop appears with a coefficient ±1 in exactly one equation. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 17 / 32 Winding Numbers and Gluing Equations For each component the sum of the winding numbers σ-edges and σ-loops must make up the “homology deficit” of the τ -edges in the component. For each torus we get a system of gluing equations where each σ-edge or loop appears with a coefficient ±1 in exactly one equation. Analyzing these gluing equations we get the following: Proposition. Let f : S → X be a continuous map of a surface. Then, up to replacing S with a surface of higher Euler characteristic, we can assume that all loop components of f −1 (C) are separating. The key ingredient in the proof is the following Lemma. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 17 / 32 Winding Numbers and Gluing Equations Lemma. Consider a linear system of equations as follows N1 MA v = , MB N2 such that all entries of MA and MB are either 0 or 1; each column in MA and each column in MB has a 1 in exactly one place; N1 and N2 are integral vectors and the system is consistent. Letting Aj be a row from MA and Bi a row from MB , it is possible to row reduce the matrix so that each fully reduced row is of the form X X i Bi − δj Aj , where i , δj ∈ {0, 1}. Consequently, the system has an integral solution. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 18 / 32 Proof of the Proposition Look for the equation lC = n in the reduced system, where lC is the variable corresponding to a given σ-loop. If not it’s not there, it is possible to set lC = 0, compress the loop, and still get a solution to the system. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 19 / 32 Proof of the Proposition Look for the equation lC = n in the reduced system, where lC is the variable corresponding to a given σ-loop. If not it’s not there, it is possible to set lC = 0, compress the loop, and still get a solution to the system. Rows represent a components of S \ f −1 (C). From the Lemma, reduction corresponds to taking a union of components and gluing along their common σ-edges. The reduced row then describes the remaining free σ-edges. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 19 / 32 Proof of the Proposition l4 l1 l3 l2 l2 −l1 l4 −l3 (a) Unglued (b) Glued Together Components Figure: The rows in (a): (1, 1, 1, 1) and (−1, 0, −1, 0) are glued together in (b). The rows are added and result is (0, 1, 0, 1). Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 20 / 32 Proof of the Proposition Thus, the equation lC = n occurs only if there is some union of components mapping to TB and TA that results in a surface whose only remaining σ-edge is our loop. Thus, the loop is separating. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 21 / 32 Parameterizing Let T (A) be a set of all τ -edges from TA . C(A) be the span of T (A). Let T2 (A) be the set of all σ-edges connecting elements of T (A). T2 (A) is the set of ordered pairs of elements of T (A) — they are the initial and terminal τ -edges. C2 (A) = span{T2 (A), a1r1 , . . . , akrk }. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 22 / 32 Parameterizing Let T (A) be a set of all τ -edges from TA . C(A) be the span of T (A). Let T2 (A) be the set of all σ-edges connecting elements of T (A). T2 (A) is the set of ordered pairs of elements of T (A) — they are the initial and terminal τ -edges. C2 (A) = span{T2 (A), a1r1 , . . . , akrk }. Given a surface S, we get a vector v (S) ∈ C2 (A), which is the formal sum of all σ-edges in S and the sum of their winding numbers. There is a system of (rational) linear equations that determines what combinations of σ-edges gives rises to a surface mapping to TA . The equations come in two types: closing equations and homology equations. The set of solutions with all non-negative T2 (A) components is called VA . Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 22 / 32 Computing χ The map that takes surfaces to vectors in VA is many-to-one — so we try to find the one with largest Euler characteristic Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 23 / 32 Computing χ The map that takes surfaces to vectors in VA is many-to-one — so we try to find the one with largest Euler characteristic To compute χ, we need to count the (maximal) number of disc components in a surface parameterized by v . Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 23 / 32 The Klein Function The set of disc vectors DA is the set of all integral vectors in v ∈ VA so that the surface parameterized by v has one boundary component. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 24 / 32 The Klein Function The set of disc vectors DA is the set of all integral vectors in v ∈ VA so that the surface parameterized by v has one boundary component. Definition. Let κ(v ), called the Klein function be the function which counts discs. In particular: nX o X 0 0 κ(v ) = max ti : v = ti vi + v , ti > 0, vi ∈ DA , v ∈ VA χo (v ) = κ(v ) − Tim Susse CUNY Graduate Center |v | , where |v | is the l1 -norm of the vector v . 2 SCL in AFP April 11, 2014 24 / 32 The Klein Function Definition. Let κ(v ), called the Klein function be the function which counts discs. In particular: nX o X κ(v ) = max ti : v = ti vi + v 0 , ti > 0, vi ∈ DA , v 0 ∈ VA χo (v ) = κ(v ) − |v | , where |v | is the l1 -norm of the vector v . 2 Lemma. Given a vector v ∈ VA and > 0 there exists and integer n and a surface S parameterized by nv so that nχo (v ) > χo (S) and χo (v ) − χo (S) < . n Further, χo (S) is a piecewise rational linear function on VA . Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 24 / 32 Computing SCL Theorem. Let A and B be two free Abelian groups of rank at least k , then A ∗Zk B is PQL. Further, there is an algorithm to compute scl on rational chains. Proof. From the previous Lemma χo (vA ) + χo (vB ) is a sum of two piecewise rational linear functions which estimate the Euler characteristic of a surface (we skipped some steps here). Thus, using linear programming, we can minimize it over the rational polyhedron Y ⊆ VA × VB of compatible vectors with n(S) = 1, where vA and vB produce surfaces to give us the boundary η that we desire. (Note that if the vector is not an integer vector, we clear the denominators to obtain an integer vector admissable for η). Since we are minimizing a piecewise rational linear function over a rational polyhedron, the result is rational. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 25 / 32 Examples a b −1 1 0 a A −1 1 B B 0 0 A 0 b A mirror in the trefoil knot complement Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 26 / 32 Examples a2 b3 A2 B3 A2 b3 B3 b 3 a2 a2 B3 A2 An extremal surface for [a2 , b3 ] in the (7, 9) torus knot complement. cl7,9 ([a2 , b3 ]3 ) = 1. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 27 / 32 A Formula for SCL Proposition. In the group G = ha, b | ap = bq i: m 1 n 1 m n sclG ([a , b ]) = max min − , − ,0 2 lcm(m, p) 2 lcm(n, q) . Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 28 / 32 A Formula for SCL Proposition. In the group G = ha, b | ap = bq i: m 1 n 1 m n sclG ([a , b ]) = max min − , − ,0 2 lcm(m, p) 2 lcm(n, q) . For fixed p and q this depends only on the modulus of m (mod p) and n (mod q). For fixed m and n this formula is the quotient of two linear quasipolynomials (polynomials of degree 1 whose coefficients depend only on the modulus of p and q with respect to some modulus π – here, lcm(m, n). Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 28 / 32 Graphs of SCL On the left, a graph of sclp,q ([a2 , b3 ]). On the right, a graph of sclp,q (aba−4 b2 a2 b−1 a2 b−3 a−1 b). Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 29 / 32 Quasirationality The phenomenon seen in the previous slides is not a coincidence. Theorem. Let w ∈ F2 = ha, bi and let wp,q be the projection to the group G(p, q) = ha, b | ap = bq i. Let sclp,q (w) = sclG(p,q) (wp,q ). Then sclp,q (w) varies as the quotient of two quasipolynomials for p and q sufficiently large. To prove this Theorem, we need to investigate the way that the polyhedron VA (p) and the function κp (v ) depend on p. Thus, we need to investigate the geometry of conv(DA ). A Theorem of Calegari-Walker implies that the vertices of this polyhedron are quasilinear functions in p. Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 30 / 32 Open Questions and Conjectures Conjecture. Given a finite tree Γ, is the right-angled Artin group with generating graph Γ PQL? Such a group is a graph of groups whose underlying graph is a tree with cyclic edge groups and vertex groups Z2 . The methods above should extend to cover these groups, but it is not clear how to count discs. These groups are also precisely the right-angled Artin groups that are 3-manifold groups. Conjecture. sclp,q (w) is actually quasilinear in p1 and q1 [Walker]. Further, quasilinearity (or more weakly: quasirationality) occurs for p ≥ lcm(set combinations of a-exponents) and q ≥ lcm(set combinations of b-exponents). Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 31 / 32 Thank You! Tim Susse CUNY Graduate Center SCL in AFP April 11, 2014 32 / 32
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