DECLARATION AND CERTIFICATION Except where mentioned, we verify that the experimental work, results, analysis and conclusions are set out in this project is entirely our own efforts. MFO 04/2012 –large deflections of beams. Laboratory validation of proposed project. ACHOLA KEVIN : F18/1887/2007 ………………………………………………… ONUNGA ERICK: F18/1857/2007 ……………………………………………….. KIRUGUMI DANIEL: F18/20991/2007 ………………………………………………… The above named students have submitted this report to the department of Mechanical and manufacturing Engineering, University of Nairobi with my approval as the supervisor (s) Professor Oduori F.M ………………………… Engineer Munyasi D.M ……………………………. DEDICATION We dedicate this project to human prosperity and enlightenment. ii | Page Abstract The deflection of a large cantilever beam made of linear elastic aluminum under the action of a vertical concentrated load applied at mid span was analyzed .this was done experimentally and numerically using Professor Oduori’s1 theory of large beam deflections. The experiment was done using aluminum beam of dimension length 47cm by 5cm and thickness of 1.7cm From first principles, we derived the equation for the determination of large deflection of beams. We set up tests in the laboratory in order to validate the theory; we then compared theoretical and experimental results. They were in good agreement. 1 Professor department of mechanical and manufacturing engineering university of Nairobi iii | Page Acknowledgements We take this opportunity to express our thanks to Professor Oduori and Engineer Munyasi for their inspiration, support and the appreciation for their work under taken in this project .we also express sincere gratitude to the staff at the mechanical engineering workshop. We also appreciate the moral and general support accorded to us by our friends. iv | Page Nomenclature b -Breath of the specimen d –Thickness of the specimen (depth) E –Young’s modulus F –Force causing deflection of the beam I –Second moment of area elasticity of aluminum L, M –Coordinates perpendicular to, and parallel to the force causing deflection of aluminum M –Bending moment P – Axial force q – Uniformly distributed load R –Radius of curvature S – Length along the deflected cantilever beam w, y -deflection X, Y –Cartesian coordinates in the plane respectively ɸ - Angular deformation of the deflected cantilever beam σb – Bending stress v| Page Table of contents Declaration and certification ………………………………………………………….......i Dedication ……………………………………………………………………………………ii Abstract ………………………………………………………………………………………iii Acknowledgements ………………………………………………………………………....iv Nomenclature ………………………………………………………………………………..v Chapter One 1.0 Introduction …………………………………………………………………………….1 1.1Assumptions………………………..…………………………………………………...3 1.2Objective ………………………………………………………………………………..4 Chapter Two 2.0 Literature review………………………………………………………………………5 2.1Theoretical Analysis ………………………………………………………………6 2.2 Formulation of the model ………………………………………………………..21 2.3 Model Validation and adaptation for laboratory experimentation ……….28 Chapter Three 3.0 Description of apparatus used ………………………………………………………32 3.1 Hand tools …………………………………..……………………………………...32 3.1.1 Tape measure ……………………………………………………………………32 3.1.2 Steel rule …………………………………………………………………………32 3.1.3 Vernier calipers …………………………………………………………………32 3.1.4 Vernier Height gauge ……………………………………………….………….32 3.1.5 Try-square ………………………………………………………………………..33 3.1.6 Dial gauge ………………………………………………………………………..33 3.1.7 Rough and smooth file …………………………………………………………33 3.1.8 Spirit level ………………………………………………………………………..34 vi | Page 3.1.9 Scriber …………………………………………………………………………….34 3.2 Machines ……………………………………………………………………………….35 3.2.1 Power hacksaw ………………………………………………....................35 3.2.2 Lathe machines ……………………………………………………………36 3.2.3 Milling machine ……………………………………………………………37 3.2.4 Planar machine …………………………………………………………….38 3.2.5 TIC machine ………………………………………………………………..38 Chapter four 4.0 laboratory data acquisition …………………………………………………………..40 4.1 specimen preparation …………………………………………………………….40 4.1.1 Procedure of preparation ……………………………………………………40 4.2 Test Rig preparation ………………………………………………………………42 4.2.1 Preparation of the support roller bearings..………………………………43 4.3 Test of specimen ……………………………………………………………………45 Chapter five 5.0 Analysis of experimental results……………………………………………………..51 5.1 Results ………………………………………………...…………………………….52 5.2 Data analysis ……………………………………………………………………….56 5.2.1 Sample calculation…………………………………………………………….56 Chapter Six 6.0 Discussion, conclusion and recommendations …………………………….………………66 6.1 Discussions …………………………………………………………………………………66 6.2 Conclusion …………………………………………….....................................................67 6.3 Recommendations for further work …………………………………………………….68 7.0 References …………………………………………………….…………………………….69 vii | Page Table of figures Figure page Fig 1 crop stem deflected by the reel……………………………………………………………………………………………………2 Fig 2 diagrammatic representation of deflected beam ……………………………………………………………………….6 Fig 3 bending of Euler-Bernoulli beam …………………………………………………………………………………………………8 Fig 4 elastic curve derivation ……………………………………………………………………………………………………………….11 Fig 5 triangle CDQ ……………………………………………………………………………………………………………………………….11 Fig 6 first area principle (semi-graphic form) .........................................................................................15 Fig 7 large deflections of buckled bars (the elastica) …….……………………………………………………………………..16 Fig 8 model of deflection ……………………………………………..……………………………………………………………………..21 Fig 9 transformed model of deflected stem ……………..………………………………………………………………………..23 Fig 10 triangle ABC ……………………………………………………………………………………………………………………………..26 Fig 11 the model adopted for laboratory validation …………………………………………………………………………..28 Fig 12 transformed model adopted for laboratory validation …………………………………………………………….29 Fig 13 force diagram ………………………………………………………………………………………………………………………….30 Fig 14 loading arrangement ………………………………………………………………………………………………………………50 Fig 15 deflections in progress ……………………………………………………………………………………………………………50 Fig 16 triangle adapted for data analysis …………………………………………………………………………………………..56 Fig 17 beam cross section …………………………………………………………………………………………………………………57 viii | Page Table of pictures Unless otherwise stated all pictures were taken at the department of mechanical and manufacturing Engineering workshop at the university of Nairobi. Picture page Picture 1 vernier height gauge ……………………………………………………………………………………………………….33 Picture 2 power hacksaw ……………………………………………………………………………………………………………….35 Picture 3 and 4 lathe machines ………………………………………………………………………………………………………36 Picture 4 milling machine ……………………………………………………………………………………………………………….37 Picture 5 planar machine ……………………………………………………………………………………………………………….38 Picture 6 TIC machine …………………………………………………………………………………………………………………….39 Picture 7 the unprepared aluminium beam ……………………………………………………………………………………40 Picture 8 aluminium bar on the planar workstation ……………………………………………………………………….41 Picture 9 aluminium beam after preparation …………………………………………………………………………………42 Picture 10 cast iron block with roller bearing supports ………………………………………………………………….43 Picture 11 roller bearings ………………………………………………………………………………………………………………44 Picture 12 knife-edge …………………………………………………………………………………………………………………….45 Picture 13 loading tip (knife-edge) 2 ……………………………………………………………………………………………..46 Picture 14 roller bearings on each groove …………………………………………………………………………………….47 Picture 15 loading arrangement ……………………………………………………………………………………………………48 Picture 16 the general arrangement on a TIC machine ………………………………………………………………..49 ix | Page Table of tables Table page Table 1: experimental raw data …………………………………………………………………………………………………52 Table 2: load and respective deflection (Experimental) …………………………………………………………….53 Table 3: table of analyzed values …...............................................................................................58 Table 4: load and calculated deflection ……………………………………………………………………………………..61 Table 5: comparisons between experimental and calculated values of deflections …………………..62 Table 6: load and percentage deviations ……………………………………………………………………………………65 x| Page Table of graphs Graph page Graph 1: of load against deflection ……………………………………………………………………………………………………54 Graph 2: for load against deflection for the elastic region………………………………………………………………..55 Graph 3: of ………………………………………………………………………………………..59 Graph 4: of calculated deflection against experimental deflection …..................................................63 xi | Page Chapter one 1.0 Introduction Beams are common elements of many architectural, civil and mechanical engineering structures and the study of the bending of straight beams forms an important and essential part of the study of the broad field of mechanics of materials and structural mechanics. All undergraduate courses on these topics include the analysis of the bending of beam but only small deflections of the beam are usually considered. In such a case, the differential equation that governs the behavior of the beam is linear and can easily be solved. Here we consider large deflections in cantilever beams. By definition beams are structural members capable of sustaining loads normal to their axis, a cantilever beam is a beam that is fixed at one end, while the other end is unsupported but suspended. A beam in application may be strong enough to resist safely the bending moments due to applied load yet not be suitable because its deflection is too great. Excessive deflection may impair the strength and stability of the structure giving rise to minor troubles such as cracking as well as affecting the functional needs and aesthetic requirements. Thus, there is always a need to consider deflection when designing beams. In much of the study and practice of mechanical and structural engineering, the equations used for determination of beam deflections, are derived with assumption of small deflections .This is appropriate because, in most mechanical and structural engineering applications, small deflections are a functional requirement. However, there arise cases in agricultural machinery engineering for instance, where beam deflections can no longer be assumed small. Then, it becomes necessary to develop and use equations other than those commonly found in mechanical and structural 1 engineering documents, which are largely based on small deflections. Timoshenko and Gere derived solutions to large deflection problems, which led to an elliptical integral. Elliptical integral problems can only be evaluated numerically, which is tedious and long. Hence, there is sufficient reason therefore to seek analytical solutions to problems of large deflections .such an equation is developed and evaluated in this presentation. An example of an application that would involve large crop stem (beam) deflections, in the design and operation of the combine harvester reel as illustrated in fig 1.10 1| Page Combine harvester reel Reel tine Deflected crop stem Ground Fig 1 crop stem deflected under the effect of a reel 2| Page 1.1 Assumptions The assumptions made in formulating a model of the deflected crop stems include A bunch of deflected crop stems deflected by the reel shall be considered by the reel shall be considered to behave like a single, initially vertical cantilever that is fixed at the base. At its point of action, the deflecting force shall be considered directed normal to the curvature of the cantilever beam. The stress-strain relationship for the deflected stems shall be tentatively assumed linearly elastic. We do not make the assumption of small deflections commonly made in mechanical and structural engineering applications. 3| Page 1.2 Objective The purpose of this work is to validate a new theory for the determination of large beam deflections of a class of cantilever beams under the action of a concentrated force or load. This is done both experimentally and theoretically then the results compared to ascertain the validity of the theory and hence formula presented for use in deriving solutions analytically to large beam deflections. 4| Page Chapter two 2.0 Literature review In the literature, large deflections behavior of beams continues to be the subject of intensive research. Numerous researchers have studied the problem under different conditions and using different conditions and methods of solutions Jong-Dar Yau developed closed-form solutions of large deflections for a guyed cantilever column pulled by an inclined cable. He used elliptical integral method in deriving analytical solution for tip displacement of the guyed column. His theory can be useful in cable-stayed bridges, radio masts and cable supported roofs all of which involve large deflections. N. Tolou and J.L. Herder developed a semi analytical approach to large deflections in compliant beams under point load. In their work, they successfully investigated the feasibility of ADM (Adomian decomposition method) in analyzing compliant mechanisms. A.Kimiaeifar, G. Domairry, S.R. Mohebpour, A.R. Sohouli and A.G Davodi4 developed analytical solutions for large deflection of a cantilever beam under a nonconservative load based on homotopy analysis method (HAM) Stephen P. Timoshenko and James M. Gere1 analyzed large deflections by considering the case of buckled bars (the elastica) 5| Page 2.1 Theoretical analysis Beams are essentially one-dimensional systems. Figure 2.0 shows a cantilever beam of length L with a concentrated force P applied at the mid –span. In the evaluation of the various parameters that come into play when the beam deflects with the application of load, the assumption made in formulating the model of the deflected crop stems in chapter one are made here as well, that is: The stress-strain relationship for the deflected beam is to be linearly elastic. The material of the beam is homogeneous and its stress-strain curve is linear, i.e. the stress is proportional to strain by Hooke’s law. It will also be assumed that the cross section of the beam remains constant across the length of the beam, meaning that the effect of poisons ratio, or the ratio of axial elongation to lateral contraction can be neglected. It is assumed that the Bernoulli –Eurler theorem is valid, which states that the curvature of the beam is proportional to the bending moment. The beam has the same modulus of elasticity in compression as in tension The deflection due to the weight of the beam is neglected R y load ɸ Neutral axis X A X Fig 2 diagrammatic representation of deflected beam 6| Page B Several beam theories are in use to calculate and analyze deflections of beams under the action of different kinds of loading .The most common ones are Eurler-Bernoulli beam theory and Timoshenko beam theory. Euler-Bernoulli beam theory which is also known as engineers beam theory or classical beam theory is a simplification of the linear theory of elasticity which provides a means of calculating the load –carrying and deflection characteristics of beams .It covers the case for small deflections of the beam which is subjected to lateral loads only. Timoshenko beam theory covers beams under both lateral and axial loading. 7| Page Static beam equation of Euler-Bernoulli beam Fig 3 bending of an Euler –Bernoulli beam 8| Page The Euler-Bernoulli equation describes the relationship between the beam’s deflection and the applied load. Each cross-section of the beam is at 90 degree to the neutral axis The curve describes the deflection of the beam at some position –considering the beam model is a one-dimensional object. q is a distributed load. It is force per unit length analogous to pressure, that is force per unit area. It may be a function of or other variables. Note that E is the elastic modulus and that I is second moment of area I must be calculated with respect to the centroidal axis perpendicular to the applied loading. For a Eurler-Bernoulli beam not under any axial loading, this axis is axial loading. Often, and EI is a constant so that This equation describing the deflection of a uniform, static beam is used widely in engineering practice. For more situations that are complicated, the deflection can be determined by solving the Eurler-Bernoulli equation using techniques such as slope, moment distribution method, moment area method, conjugate beam method, the principle of virtual work, direct integration, Castigliano’s method, Macaulay’s method or the direct stiffness method and elastic curve method, the most commonly used methods include. 1. Area moment method 2. The elastic curve method The elastic method requires the use of calculus since it is based on the solution of the differential equation for the elastic curve by double integration. In its analysis, we get the equation of the elastic curve. From fig.2, it is evident that the magnitude of the bending stresses varies directly with the distance from the neutral axis, that is; Where R is the radius of curvature of the elastic curve. Taking the general flexure expression; 9| Page Then Now consider unloaded beam AB as shown in fig 4, the beam is deflects to A1B1 under a load q. 10 | Page Y O dθ θ B1 R D C dy Q θ A1 dx A B Fig. 4 elastic curve derivation From the figure above, the following can be deduced from the triangle CDQ. D ds C Fig. 5 Triangle CDQ 11 | Page dx dy Q CD= For small angle of θ The curved line A1B1 in fig.3 represents the neutral surface of a beam after bending .It is the elastic surface of a deflected beam of indefinite length. C and D are points on this elastic surface and are separated by a small distance When two lines are constructed perpendicular to the elastic curve at points C and D, their extensions will intersect at the centre of curvature O, a distance R from the curvature and will form a small angle, The curvature is actually very slight; therefore, CQ can replace the horizontal length Then from geometry However, since triangle CDQ is small And Therefore, 12 | Page But Substituting and evaluating, we get the differential equation of elastic curve as shown below From the general flexural equation Hence, Where EI-is the flexural stiffness - is the curvature of the neutral axis In the above derivation of the elementary theory, the assumption of small deflections has been made. Hence, this equation cannot be used in analyzing large beam deflections problems. The elementary theory also neglects the square of the first derivative in the curvature formula and provides no correction for the shortening of the moment arm as the loaded end of the beam deflects. From the area moment principle, the neutral surface of a homogeneous beam is considered to be on a continuous plane, which passes through the centre of gravity of 13 | Page each right section. When the beam deflects, the neutral surface becomes a continuous curved surface. Deflections are measured from the original position of the neutral surface to the elastic surface. The derivation of the area moment equations is shown in the semi-graphic form in fig 6 14 | Page O x dθ D C A E B1 dθ y A1 θ M EI dx X Fig 6 first area principle (semi-graphic form) 15 | Page From fig.6, the angle between the two tangents AA1 and BB1 is equal to summation of all elemental areas of the . And the diagram between the two tangent points (the cross hatched area shown) is presented in equation form as . This is the first area moment. it considers the assumptions of small deflections and thus cannot be used to determine large deflections . Timoshenko and Gere analyzed large deflections by considering the case of buckled bars (the elastic) as shown below. O s α L P m xa n θ ya Fig 7 large deflections of buckled bars (the elastica) 16 | Page At the critical loading, the bar can have any value of deflection, provided the deflection remains small, the differential equations used to calculate the critical loads are based on the approximate expression for the curvature of the buckled bar. If the exact expression for the curvature is used, there will be no indefiniteness in the value of deflection. The shape of the elastic curve, when found from the exact differential equation is called the elastica. Consider the slender rod shown in fig.7, which is fixed at the base and free at the upper end. If the load P is taken somewhat larger than the critical value, a large deflection of the bar is produced. Taking the axis as shown in the figure and measuring the distance s along the axis of the bar from the origin O, we find that the exact expression for the radius of the curvature of the bar is Since the bending moment in the bar is equal to the product of flexural rigidity the curvature, the exact differential equation of deflection is; The change in length of the column due to compression is neglected. Differentiating equation (i) with respect to s and using the relation We obtain, Multiplying through by Where Hence 17 | Page and integrating gives Therefore Boundary conditions At the upper end of the bar; And also, Substituting the boundary conditions and solving for constant c, we get , Therefore, we have, Or Solving for ds and noting that is negative we have, In addition, for the total length of the bar, after the limits of integration are interchanged we have 18 | Page Introducing ɸ and letting such that, Differentiating equation Substituting equation (iii) and noting that We obtain As the value of decrease, the integral K and the load P increase In calculating the deflection of the bar, we note that The total deflection of the top of the top of the bar in the horizontal direction becomes From equation (iv) we have; And therefore, ɸ By using the relation, 19 | Page We find that; Substituting expression (v)(vi) and (ix) into equation (viii) and changing the limits accordingly, we obtain; 20 | Page 2.2 Formulation of the model However, the integral appearing in equation (vii) is known as a complete elliptical integral of the first kind and is designated by K (p). Elliptical integrals can only be evaluated numerically which is both tedious and does not give very accurate results. In contrast, the introduction of L as the variable of integration instead of s greatly simplifies the problem. Hence, analytical solutions are sought to problems of large deflections. In this case, a cantilever beam is considered fixed horizontally and a point load applied near the free end such that the beam deflects upwards. Ym Fcos ɸm dy Beam Y dx ds r + dr dɸ r ɸ Fig 8 model of deflection 21 | Page X Xm The assumptions of small deflections commonly made in mechanical and structural engineering are not made here. Referring to fig.8 according to the elementary theory of elastic bending at an arbitrary point denoted (X, Y) along the length of the deflected cantilever, we may write; Where r is the radius of curvature of the elastic curve Taking the general flexure expression We have Therefore Then From fig 2.15, the bending is The following figure 9 illustrates the deflection model transformed in a manner similar to the transformation of rectangular Cartesian coordinates, common in the study of kinematics 22 | Page Ym Nm ɸm ɸm Y dy dL N Lm Ground Fig 9 transformed model of deflected stem 23 | Page dx X L Xm Accordingly, Since L and N are both zero when X and Y are both zero, then The transformation matrix of equations (3a) and (3b) is symmetric and therefore equal to its own transpose i.e. It is also orthogonal and therefore its transpose is equal to its inverse, considering the context of the plane transformation geometry, this matrix has the form of reflection matrix, which implies that; Lm = X m and Nm = Y m ………………………….(3c) From equation (3b) From equation (3c), it follows that And, The relations in (3c) above imply that; Dividing equation (8) by (9) gives, 24 | Page But Lm = X m and Nm = Ym Therefore From trigonometry Thus Therefore The maximum deflection Ym can be developed from equation (10), that is Equation (11) and (12) are based entirely on the geometry of deflection .they do not involve material properties of the deflected cantilever. 25 | Page From equation 3a, it follows that the bending moment at L is; And, dL A B ds C Fig 10 triangle ABC 26 | Page Combining equations (1)(13)and (14), it follows that, But Hence Rearranging gives, Cos ( The introduction of L as the variable of integration instead of s, greatly simplifies the problem. Equation (15) can be integrated if the relationship between EI and L is known. The following assumptions may be made as a matter of investigations. The product EI does not vary with L since ɸ=0 when L=0. By integrating equation (15) we get; 27 | Page 2.3 Model validation Adaptation of the model for laboratory validation With the equipment available at the university of Nairobi mechanical engineering workshop it was easier and more convenient to use an initially horizontal, simply supported beam of uniform cross-section rather than an initially vertical cantilever. The maximum load at the mid span of the beam is p. for easy analysis; each half of such a beam is equivalent to an initially horizontal cantilever, with a span that is half of that of a simply supported beam as illustrated in fig 10 P Rh Rh Rv Xm Rv Fsin ɸm Ym 0.5 Xm F cos ɸm Fig 11 the model adapted for laboratory validation 28 | Page From the figure Rh is the horizontal component of the reaction and Rv is the vertical component of the reaction From statics Therefore Where p is the load at mid-span L- axis Lm Nm c ɸm ɸm O A ɸm N-axis Fig 12 the transformed model adopted for laboratory validation 29 | Page F B From fig 12 we can draw triangle ABC as shown below C ɸm F A Fig 13 force diagram The force diagram can be analyzed as; From equation (14) of chapter two Substituting for F in equation (17) From trigonometry; 30 | Page B Substituting this into the equation (19), we get Now, in accordance with equation (3c) of chapter two, it follows from fig 10 and 11 that And Substituting equation (21), for Lm into equation (20), we get; The experimental results were also in agreement with the predictions of the theory from equation (12) below Therefore, it follows from equation (22) Dividing through by 4 gives Substituting the value of from equation (23) into equation (12) gives The above equation was used to validate the model. 31 | Page CHAPTER THREE 3.0 A DESCRIPTION OF APPARATUS USED. 3.1 HAND TOOLS 3.1.1 TAPE MEASURE A tape measure was used to measure the dimensions of the aluminium specimen. 3.1.2 STEEL RULE The steel rule was used in measuring the dimensions of the aluminium bar, aiding in drawing straight lines on the bar and as a straight guide for marking with the scriber. 3.1.3 VERNIER CALIPERS The vernier calipers was used to measure the thickness of the beam specimen, the diameter of the rollers and the measurement of the length x. 3.1.4 VERNIER HEIGHT GAUGE This is tool is used in marking out lines with particular interest in accuracy. With the underside as a datum, using the sharpened pointer (carbide tip) as a scriber, markings were made all round the bar where the machining would take place 32 | Page Picture 1 vernier height gauge 3.1.5 TRY-SQUARE The try square was for marking and measuring the aluminium work piece. It was also used to check the straightness to the adjoining surface. 3.1.6 DIAL GAUGE The dial gauge was used to measure the deflection of the aluminium specimen when a load was applied. The mounting of the dial gauge was done in such a way that the dial gauge sensor was perpendicular to the specimen axis. 3.1.7 ROUGH AND SMOOTH FILE The hand files were to make smooth the edge of the aluminium specimen after machining. 3.1.8 SPIRIT LEVEL The spirit level was used on the specimen to check whether it was level. 33 | Page 3.1.9 SCRIBER A scriber was used in conjunction with the rule and the try square to obtain thin semipermanent lines where they were required for machining of the specimen. 3.2 MACHINES 3.2.1 POWER HACKSAW The power hacksaw shown in figure below was for cutting the aluminium specimen. Picture 2 power hacksaw 34 | Page 3.2.2 LATHE MACHINE It consists of the tailstock that supports the work piece, the headstock and the tool post. It was for facing and turning of the roller bar for fitting into the roller bearing. Picture 3 and 4 lathe machines 35 | Page 3.2.3 MILLING MACHINE A milling machine is a tool used to machine/cut metal solid bars. The spindle is stationary spindle with the table moving perpendicular and parallel to the spindle axis to accomplish cutting. The aluminium bar was clamped on the bed. Picture 4 milling machine 36 | Page 3.2.4 PLANAR MACHINE The milling machine was also used in planing of the machined aluminium bar. Picture 5 planar machine 3.2.5 T.I.C MACHINE The T.I.C machine is for subjecting a specimen to tension by applying a load by means of a hydraulic lever operated manually. Reading off a gauge on the machine gives the load. The loaded specimen undergoes a deflection. The pre set dial gauge gives the value of deflection. 37 | Page Picture 6 TIC machine 38 | Page CHAPTER FOUR 4.0 LABORATORY DATA ACQUISITION 4.1 PREPARATION OF SPECIMEN 4.1.1 PROCEDURE OF PREPARATION 1. An aluminium beam of 50mm by 50mm was obtained from the workshop store. 2. Using a tape measure the length of the beam was measured and was found to be 470mm. The beam was as shown below. Picture 7 aluminium beam 39 | Page The bar was then marked using a vernier height gauge to produce a cross-section of 17mm thickness by 50mm width. A 2mm allowance was put into consideration for the cutting disc and for the planning. 3. The bar was then carefully set and clamped on the bed of the milling machine. A vernier caliper was used to measure accurately the length from the edge of the bed to ensure the bar lied parallel to its axis. 4. The milling machine was used to split the bar lengthwise to produce a bar of the cross-section 17mm by 50mm. Paraffin coolant was used to keep the work piece at a stable low temperature and reduce tip welding of the cutter. 5. The bar was then carefully mounted on the bed of the planar with the flat side facing downwards. The machine was turned on and the work was given a reciprocating movement while the tool was fed crosswise. A thickness of 17mm was achieved. Picture 8 aluminium bar on the planar workstation 40 | Page 6. We filled the machined surface to smoothen the edge. A spirit level was used to check for the flatness of the bar indicated that it was level. 7. The edges were verified to be perpendicular by means of a try-square. The prepped beam is as shown below. Picture 9 aluminium beam after preparation 4.2 TEST RIG PREPARATION. Requirements: 41 | Page A block of cast iron with two grooves for holding the support roller bearings as shown in picture 10 Four roller bearings each of inside diameter 25mm and outside diameter of 50mm are required. Two pieces of smoothened mild steel bar of length 96mm and diameter of 25.4 are required. The cast iron block of length 520mm, and cross section 98mm by 70mm with two grooves on upper surface, which had a diameter of 30mm and depth of 10mm each was made available. The grooves that were 300mm apart were thoroughly smoothened. Picture 10 cast iron block with roller bearing supports 4.2.0 PROCEDURE FOR THE PREPARATION OF THE SUPPORT ROLLER BEARINGS a. A length of 98mm was measured along the smoothened mild steel of length 570mm and diameter 25.4mm and that point marked by use of a scriber. b. The bar was properly fixed and tightened onto the work piece holder on the power hacksaw and cut along the mark. c. The procedure as illustrated in (a) and (b) were repeated to get the second identical piece. d. The two pieces were then mounted on a lathe, each at a time and their ends faced to a final length of 96mm while at the same time turning to a diameter of 25mm from the edge to a length of 16mm on either side of 42 | Page the roller bar. Sand paper was used on the surface to obtain a smooth finish. e. The pressing machine was then used to press fit the roller bearing onto each either side of the mild steel roller bar. f. The above step (e) was repeated for the other mild steel roller bar and the resulting support roller bearing were as shown in picture 11 Picture 11 roller bearings 43 | Page 4.2.1Test of specimen i. The test rig was placed at the base of the T. I. C such that the centre of the cast iron block coincided with the centre of the lower tip of the loading point of the machine. ( Knife edge ) Picture 12 knife-edge 44 | Page Picture 13 loading tip (knife-edge) 2 45 | Page I. The two roller bearings were placed on each groove. Picture 14 roller bearings on each groove ii. iii. iv. 46 | Page The beam to be tested was then placed on the two roller bearing such that its centre at 235mm coincided with the centre of the test rigs well as the centre of the loading point. In this way, the beam specimen would be a simply supported member. This ensured that a span of 30mm of the beam was between the two roller bearings. The dial gauge was mounted onto the setup as shown in the figure below. The load was lowered such that the loading point is just touching the specimen. The reading of the T. I. C machine and the dial gauge was adjusted such that the readings of the load applied and deflection respectively, were zero. The picture next illustrates the loading arrangement. Picture 15 loading arrangement v. vi. vii. viii. ix. 47 | Page The length of the overhanging span on one side of the beam was noted and denoted by the letter x. the heights of the beam before loading were also noted from the base of the test rig and noted by h1 and h2 as shown in figure X below The two measurements of height h1 coincided with that at the roller while h2 coincided with the end of the beam span (test specimen). A load of 454.8N (0.4×1.137KN) was then applied slowly and carefully. The dial gauge was let to stabilize before that reading corresponding to the load was taken. The values of x, h1, and h2 were taken and recorded as well. With an increment of 0.4×1.137KN steps (viii) and (ix) were repeated each time noting the readings while also making sure the loading was still within the elastic limit Picture 16 the general arrangement on TIC machine 48 | Page Fig 14 loading arrangement Fig 15 deflections in progress 49 | Page Chapter five Analysis of experimental results The test was carried out using T.I.C machine found in the strength of materials laboratory of the University of Nairobi, department of mechanical and manufacturing engineering workshop. After a series of preliminary tests on the specimens, finally stable results were recorded in the tables that follow. We recorded the exact values of load and deflections as shown in table 2. 50 | Page Table 1: Experimental raw data Reading of load (*1.137KN) Deflection (y) (mm) h1 (mm) h2 (mm) X (mm) 0.0 0.4 0.8 1.2 1.6 2.0 2.4 2.8 3.2 3.6 4.0 4.4 4.8 5.2 5.6 6.0 6.4 6.8 7.2 7.6 8.0 8.4 8.8 0 0.28 0.52 0.79 1.04 1.27 1.52 1.75 1.99 2.22 2.46 2.72 2.97 3.2 3.46 3.69 4.01 4.24 4.49 4.86 5.16 5.62 6.06 6.52 7.08 7.76 37.50 37.57 37.65 37.75 37.85 37.93 37.99 38.07 38.16 38.24 38.31 38.36 38.45 38.56 38.62 38.70 38.79 38.85 39.10 39.24 39.41 39.60 39.82 37.50 37.68 37.86 38.05 38.25 38.42 38.58 38.75 38.94 39.11 39.27 39.42 39.60 39.80 39.95 40.13 40.31 40.46 40.82 41.97 42.13 42.34 42.60 54.00 53.90 53.81 53.74 53.67 53.56 53.44 53.38 53.26 53.17 53.11 53.00 52.90 52.83 52.74 52.66 52.55 52.49 52.37 52.27 52.13 51.97 51.78 40.08 40.43 40.85 41.34 42.91 43.30 43.75 44.43 51.55 52.35 51.12 50.88 41.86 42.38 42.74 45.22 46.13 47.04 50.65 50.41 50.12 9.2 9.6 10.0 10.4 10.8 11.2 11.6 51 | Page 8.78 9.92 10.88 12.2 Table 2: Load and respective deflection (Experimental) P (N) 0 454.8 909.6 1364.4 1819.2 2274 2728.2 3183.6 3638.4 4093.2 4548 5002.8 5457.6 5912.4 6367.2 6822 7276.8 7731.6 8186.4 8641.2 9096.0 9550.8 10005.6 10460.4 10915.2 11370.0 11824.8 12279.6 12734.4 13189.2 52 | Page Deflection (mm) 0 0.28 0.52 0.79 1.04 1.27 1.52 1.75 1.99 2.22 2.46 2.72 2.97 3.2 3.46 3.69 4.01 4.24 4.49 4.86 5.16 5.62 6.06 6.52 7.08 7.76 8.78 9.92 10.88 12.2 From table 2, we plotted a graph of load against deflection as shown below graph 1. The graph illustrates that the elastic limit of the beam is reached when a load of 8186.4 KN is applied all the values after this are insignificant to this project. load against deflection 14000 12000 10000 Load(N) 8000 6000 4000 2000 0 0 2 4 6 8 Deflection (mm) Graph 1 53 | Page 10 12 14 The graph for load against deflection for the elastic region lo Elastic region 9000 y = 1844.6x - 44.532 8000 7000 6000 Load(N) 5000 Elastic limit Graph 4000 Linear (Elastic limit Graph) 3000 2000 1000 0 0 -1000 Graph 2 54 | Page 1 2 3 Deflection(mm) 4 5 Data analysis Sample calculations From figure 15 h2-h1 x Fig 16 triangle used for data analysis We can say that from fig 16 For a load of 2.274 KN, deflection of 1.27, h1 of 37.93 mm, h2 of 38.42mm and x of 53.56 mm And Therefore 55 | Page Hence We calculated the value of the right hand term of equation (22) using the above values as; For P=2.274 KN E = 70 × 109 NM-2 Where E is young’s modulus of aluminium I is second moment for a rectangular section and is given by b = width of the beam -0.017m d = the beam thickness – 0.05m The cross section of the beam in this case was as shown below d b Fig 17 beam cross section 56 | Page Therefore; Then Thus for the load of 2.274 KN mentioned above; =0.017853 The other values of ɸm , sin 2ɸm and were calculated and the results recorded as shown in table3 We then plotted a graph of against Table 3: Analyzed values Load (N) h1 (mm) h2 (mm) X (mm) 0 454.8 909.6 1364.4 1819.2 2274 2728.2 3183.6 3638.4 4093.2 4548 5002.8 5457.6 5912.4 6367.2 6822 7276.8 7731.6 8186.4 37.50 37.68 37.86 38.05 38.25 38.42 38.58 38.75 38.94 39.11 39.27 39.42 39.60 39.80 39.95 40.13 40.31 40.46 40.82 37.5 37.57 37.65 37.75 37.85 37.93 37.99 38.07 38.16 38.24 38.31 38.36 38.45 38.56 38.62 38.70 38.79 38.85 39.10 54.00 53.90 53.81 53.74 53.67 53.56 53.44 53.38 53.26 53.17 53.11 53.00 52.90 52.83 52.74 52.66 52.55 52.49 52.37 57 | Page (degrees) 0 0.002041 0.003903 0.005582 0.007468 0.009169 0.011052 0.012767 0.014669 0.016381 0.018113 0.020038 0.021768 0.023511 0.025218 0.027345 0.029305 0.030673 0.032843 0 0.23388 0.44725 0.63964 0.85575 1.05066 1.26641 1.46291 1.68082 1.87695 2.07536 2.29587 2.49403 2.69366 2.88915 3.13272 3.35714 3.51376 3.76217 0 0.0040816 0.0078059 0.0111635 0.014935 0.018336 0.022101 0.025529 0.029331 0.032753 0.036213 0.040059 0.043515 0.046995 0.050403 0.054649 0.058559 0.061288 0.065615 0 0.003571 0.007141 0.010712 0.014282 0.017853 0.021424 0.024994 0.028565 0.032135 0.035707 0.039276 0.042847 0.046418 0.049988 0.053560 0.057129 0.060700 0.064271 A graph of 0.07 y = 1.0105x + 0.0003 0.06 0.05 sin 2ɸm 0.04 0.03 0.02 0.01 0 0 0.01 0.02 0.03 pX2m Graph 3 58 | Page 0.04 /8EI 0.05 0.06 0.07 More sample calculations Theoretical values of deflection Based on the deflection formula the following sample calculations were obtained. Sample 1 For a load of 2.274 KN =1.3391mm Sample 2 For a load of 4.0932 =2.4106mm Values of Ym for corresponding loads in the elastic region were calculated and tabulated as shown in table 4 below. 59 | Page Table 4: Load and calculated deflection Load P(N) 0 454.8 909.6 1364.4 1819.2 2274 2728.2 3183.6 3638.4 4093.2 4548 5002.8 5457.6 5912.4 6367.2 6822 7276.8 7731.6 8186.4 60 | Page Deflection y (mm) 0 0.2678 0.5355 0.8034 1.0712 1.3391 1.6069 1.8748 2.1427 2.4106 2.6787 2.9466 3.2146 3.4828 3.7509 4.0192 4.2873 4.5557 4.8240 Table 5: comparison between experimental and calculated values of deflections Load P (N) 0 454.8 909.6 1364.4 1819.2 2274.0 2728.2 3183.6 3638.4 4093.2 4548.0 5002.8 5457.6 5912.4 6367.2 6822.0 7276.8 7731.6 8186.4 61 | Page Experimental 0 0.28 0.52 0.79 1.04 1.27 1.52 1.75 1.99 2.22 2.46 2.72 2.97 3.20 3.46 3.69 4.01 4.24 4.49 Calculated 0 0.2678 0.5355 0.8034 1.0712 1.3391 1.6069 1.8748 2.1427 2.4106 2.6787 2.9466 3.2146 3.4828 3.7509 4.0192 4.2873 4.5557 4.8240 A graph of calculated deflection against experimental deflection theoretical vs experimental deflection 6 5 y = 1.0869x - 0.0269 4 theoritical 3 2 1 0 0 -1 Graph 4 62 | Page 0.5 1 1.5 2 2.5 experimental 3 3.5 4 4.5 5 Percentage deviations Sample calculations For a load of 5.9124 KN =8.8375 For a load of 6.3672 KN =8.4075 The percentage deviations representing relative errors for the corresponding loads were calculated and tabulated as below. 63 | Page Table 6: Load and percentage deviations Load P (N) 0 454.8 909.6 1364.4 1819.2 2274 2728.2 3183.6 3638.4 4093.2 4548 5002.8 5457.6 5912.4 6367.2 6822 7276.8 7731.6 8186.4 64 | Page percentage deviations (relative errors) 0 4.3750 2.9808 1.6962 3.0000 5.4409 5.7171 7.1314 7.6734 8.5853 8.8902 8.3309 8.2397 8.8375 8.4075 8.9214 6.9152 7.4458 7.4388 Chapter six Discussions, conclusions and recommendations Discussion The results as tabulated were extensively analyzed as shown previously in the previous chapter. The analysis was restricted to the elastic region before yielding as we had made a prior assumption of linear elasticity in the project formulation. To determine the accuracy and the validity of the method of solution proposed in this study an in depth analysis of experimental and theoretical values was done. We first obtained the results experimentally of the large deflection of a simply supported beam under the action of a concentrated load P. secondly; the numerical results are calculated using the proposed theory. Comparison of the two set of values was then established. The agreement between the values obtained using our numerical method and those obtained experimentally was good. The distributed load due to the weight of the beam was considered negligible and therefore was not used in the analysis. The numerically calculated deflections were obtained using the Oduori’s proposed method, which is given by the following equation: Where is the deflection, P is load, E is young’s modulus, I is the second moment of area and the mean distance between the roller supports. Using equation 22, derived, a graph of from which the final large deflections formula for is above was was plotted, from the equation, the plotted graph should be having an expected gradient of 1 in our case it was 1.0105. Table 1 shows the deflection as a function of the applied load P whereas the table 4 represents the numerically calculated values with the aid of the numerical equation. We also included the relative error (percentage) in the values of calculated numerically as compared with the values measured experimentally. To further the validation, a comparison was done between theoretical and the experimental deflection then a graph was plotted of calculated against theoretical deflection. The expected gradient in case of absolute agreement was 1 however the gradient obtained was 1.0869. 65 | Page The comparisons above show there are some errors that were incurred during the experiment that caused the deviations from theoretical values. These errors could include: Calculations did not include deflections due to shearing Possible residual stresses introduced in the aluminium beam during machining while preparing the specimen. These stresses have an effect of decreasing the buckling load and are caused by heat and incompatible internal strains Errors incurred when taking experimental data ( ), taking the beam dimensions There was some play encountered from the dial gauge that was used to obtain deflection The T.I.C machine could not handle heavy tensions and started leaking at high values of load Young’s modulus for Aluminium varies from 65 GPa to 75 GPa, for the purposes of evaluation 70 GPa was used as the average which may have been inaccurate. Conclusion The study was a success. The laboratory validation of the new theory (Oduori’s formulae) for determination of large deflections for a class of cantilever beams by laboratory experimentation was carried out to satisfaction and found to hold. The theoretical analysis resulted in the following deflection equation corresponding to the general case of large deflections. And as shown in chapter 2 this equation is directly derived from equation 22 as quoted below. From values of a linear graph through the origin with a gradient of 1.662 against the expected gradient of 1. The variation occurred because of the experimental errors It can be concluded that the theory as proposed by professor Oduori is valid for linear analysis of large deflections of cantilever beams 66 | Page Recommendations for further work We recommend further work to prove this theory based on better experimentation methods and equipment. There should be extra vigilance to avoid the errors mentioned before. The following should be taken into consideration Shear deflections should be incorporated. The measurement of should be done with extra caution. Using a vernier as we did introduces errors and it is extremely hard to obtain exact values. The beam should be prepared using standard preparation methods and its properties like young’s modulus should be gauged properly. Dimensional in accuracies should also be avoided. The experiment could be done using a more reliable loading system other than the TIC machines. 67 | Page Chapter 7 References B. Shvartsman, large deflections of a cantilever beam subjected to a follower force’, J. Sound and Vib.304, pp.969-973 (2007) . F.V. Rhode, ` Large deflections of cantilever beams with uniformly distributed load’, Q. Appl. Math. , 11, pp. 337-338 (1953) J. M Gere, S.P .Timoshenko, `Mechanics of materials, second edition’, books Engineering Division, California (1984) M.F Oduori, J. Sakai, E. Inoue, `A paper on Modeling of crop stem Deflection in the context of the combine harvester reel design and operation. J. Case, C. Lord, and Carl T.F.R., `Strength of materials and structures , fourth edition chapter 13, deflections of beams,’ S.W. Crawley, R.M. Dillon steel buildings analysis and design, second edition’, chapter 4, beam deflections Wikipedia: http://en.wikipedia.org/wiki/Timoshenko beam theory Wikipedia: http://en.wikipedia.org/wiki/Euler-Bernoulli beam theory Wikipedia: http://en.wikipedia.org/wiki/Moment area method beam theory 68 | Page
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