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// Program : sum_n .C
// Compute the sum of the first n natural numbers .
# include < iostream >
int main ()
{
// input
std :: cout < < " Compute the sum 1+...+ n for n =? " ;
unsigned int n;
std :: cin > > n;
// computation of sum_ {i =1}^ n i
unsigned int s = 0;
for ( unsigned int i = 1; i <= n ; ++ i ) s += i ;
// output
std :: cout < < " 1+...+ " < < n < < " = " < < s < < " .\ n ";
return 0;
}
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// Program : prime .C
// Test if a given natural number is prime .
# include < iostream >
int main ()
{
// Input
unsigned int n;
std :: cout < < " Test if n >1 is prime for n =? ";
std :: cin > > n;
// Computation : test possible divisors d
unsigned int d;
for ( d = 2; n % d != 0; ++ d );
// Output
if ( d < n)
// d is a divisor of n in {2 ,... ,n -1}
std :: cout < < n < < " = " < < d < < " * " < < n / d < < " .\ n";
else
// no proper divisor found
std :: cout < < n < < " is prime .\ n ";
return 0;
}
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// outputs 0 , 1 , 2 , 3 , 4
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// do something with k
}
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int i = 5;
for ( int j = 0; j < 5; ++ j ) {
std :: cout < < ++ i ; // outputs 6 , 7 , 8 , 9 , 10
int k = 2;
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}
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n ¯ ¬
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n0 , n1 , n2 , . . .
n0 = n
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// Program : collatz . C
// Compute the Collatz sequence of a number n.
# include < iostream >
1
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int main ()
{
// Input
std :: cout < < " Compute the Collatz sequence for n =? ";
unsigned int n;
std :: cin > > n;
// Iteration
while ( n > 1) {
if ( n % 2 == 0)
n = n / 2;
else
n = 3 * n + 1;
std :: cout < < n < < " ";
}
std :: cout < < "\ n";
return 0;
}
Program 9:
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2.4.7 Equivalence of iteration statements
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int main ()
{
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{
int i = 0;
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int s = 3;
i += s;
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return 0;
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int main ()
{
unsigned int x;
std :: cin > > x ;
int s = 0;
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return 0;
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Exercise 35
Õ
# include < iostream >
int main ()
{
int x ;
std :: cin > > x ;
int s = 0;
int i = -10;
do
for ( int j = 1;;)
if ( j ++ < i ) s += j - 1; else break ;
while (++ i <= x );
std :: cout < < s < < "\ n";
return 0;
}
Exercise 36
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Exercise 37
dec2bin.C
n
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JSE%'!'l!'%rL~!<d%/5!'%®= k<d%Y!6?# X 07D!'FV[~<d%
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Exercise 38
cross_sum.C
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Exercise 39
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0V%'<'02!/%³5&JCl®JMLh<d%rL3Fo,H*+#-n,GJM L/F n = k , s.t. k<n ∧ k|n k
28 = 1 + 2 + 4 + 7 + 14
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Exercise 40
n==11
2.4.12 Challenges
1011
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Exercise 41
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