Honors Geometry Summer Math Packet Answers 1. 2. 10π₯ ! β 3π₯ β 18 or its equivalent 3. 4. -5 and 3 2 5 5 5. n = β§ο£±β¨ο£² ,β β«ο£Όβ¬ο£½ β©ο£³ 3 3 βο£Ύ 6. -4.2 to -4 7. a) c = 5 b) b = 12 c) a = 6 d) c = 98 or approximately 9.9 Honors Geometry Summer Math Packet Answers 8. 9 9. d = 20 or approximately 4.47 10. d = 234 or approximately 15.3 11. d = 78.25 or approximately 8.85 12. d = ( J β P) 2 + ( K β Q) 2 13. a) 17 + 2π€ 13 + 2π€ = 396 or its equivalent b) w = 5 or equivalent values 2 14. D 15. 2π‘ + 3π‘ = 24 or an equivalent equation 16. Sample Response: I would buy the ticket from Airline P. Both airlines are likely to have an ontime arrival since they both have median values at 0. However, Airline Q has a much greater range in arrival times. Airline Q could arrive anywhere from 35 minutes early to 60 minutes late. For Airline P, the flights arrived within 10 minutes on either side of the scheduled arrival time about 2/3 of the time, and for Airline Q, that number was only about 1/2. For these reasons, I think Airline P is the better choice. Honors Geometry Summer Math Packet Answers 17. Sample response: Tina is incorrect because some orders of basic transformations do not produce the same results. Suppose we move triangle A 2 units to the right first. The point (4, 3) is then (6, 3). Then, we take the reflection across the x-axis, which makes that point (6, -3). A reflection of (6, -3) across the yaxis gives us (-6, -3), which is not one of the vertices of triangle Aβ. Therefore, the basic transformations done in any order do not produce the same result. 18. B 19. 20. (π₯ + 3)(π₯ + 1) 21. 5(π₯ ! + 5) 22. (2π₯ + 5)(π₯ β 2) 23. (3π₯ β 4)(π₯ + 2) 24. (π₯ β 6)(π₯ + 2) Honors Geometry Summer Math Packet Answers 25. -2(2π₯ + 5)(2π₯ β 5) 26. β4π₯(3π₯ β 1) 27. (π₯ + 5)(π₯ β 6) 28. (π₯ + 9)(π₯ β 2) 29. π₯ β 9 π₯ β 1 = 0 π₯ = 1 ππ π₯ = 9 30. 3π₯ 2π₯ β 5 = 0 π₯ = 0 ππ π₯ = ! ! 31. π₯ β 5 π₯ + 7 = 0 π₯ = β7 ππ π₯ = 5 32. π₯ β 6 π₯ β 6 = 0 π₯=6 33. π₯ β 2 π₯ + 8 = 0 π₯ = β8 ππ π₯ = 2 34. 2π₯ + 7 π₯ + 1 = 0 ! π₯ = β ππ π₯ = β1 !
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