W10BES3DS
1. Rayleigh distance corresponding to "resolution" is determined for two round
apertures at distance d between them.
2. 3D graph of pattern of two round apertures at distance d.
Radius of apertures is a, coordinate on the observation screen R, wavelength λ and
distance from aperture to screen is X.
1. Determination of Rayleigh distance.
a ≡ .05
X ≡ 4000
 J1 2⋅ π ⋅ a⋅ R  
 
X⋅ λ  
g1( R) := 

  2 ⋅ π ⋅ a⋅ R  
X⋅ λ  
 
R := 0 , .1 .. 50
2
 J1 2 ⋅ π ⋅ a⋅ R − d  
 
X⋅ λ  
gg1( R ) := 

  2⋅ π ⋅ a⋅ R − d  
X⋅ λ  
 
2
0.25
0.2
0.15
g1( R)
gg1( R )
0.1
0.05
0
0
10
20
30
R
40
50
2. 3D Graph
Distance d
i := 0 .. N
j := 0 .. N
xi := ( −40) + 2.0001⋅ i
2
RR( x , y) := ( x) + ( y)
y j := −40 + 2.0001⋅ j
2
 J1 2 ⋅ π ⋅ a⋅ RR( x , y)  
 
X⋅ λ  
g2( x , y) := 

  2 ⋅ π ⋅ a⋅ RR( x, y)  
X⋅ λ  
 
2
M i , j := g2( xi , y j) + gg2( xi , y j)
M
N ≡ 60
λ ≡ .0005
X := 4000
 J1 2 ⋅ π ⋅ a⋅ RR( x, y − d )  
 
X⋅ λ

gg2( x , y) := 

  2 ⋅ π ⋅ a⋅ RR( x , y − d )  
X⋅ λ
 
 
d ≡ 24.5
2