M 1310 4.2 Dividing Polynomials 1 Terms you should know: Quotient Divisor Dividend Example using long division: 25 21 540 42 120 105 15 The remainder is 15, the quotient is 25 2x 3 − 2x 2 − 4 x − 6 x−4 Example of long division of polynomials: 2x 2 + 6x + 20 + x−4 74 x−4 2x 3 − 2x 2 − 4x − 6 − ( 2 x 3 − 8x 2 ) 6x 2 − 4x − (6x 2 − 24x ) 20x − 6 − ( 20x − 80) 74 This is your remainder. Recall: Dividend = Quotient ∗ Divisor + Reminder M 1310 Example 1: a. 4.2 Dividing Polynomials Use long division to find the quotient and remainder if any. 2x 4 − 8x 2 + 3x − 5 x−5 b. Use Synthetic Division on the same problem. 2x 4 − 8x 2 + 3x − 5 x−5 2 M 1310 4.2 Dividing Polynomials Example 2: Divide the following: 6x 3 + 9x 2 + 22x + 2 3x 2 − 2 Example 3: Divide the following: x 3 + 3x 2 − 18x − 40 x−4 3 M 1310 Example 4: 4.2 Dividing Polynomials 4 Divide the following: 3x 3 + 4x 2 − 13 2x − 4 Here are two theorems that can be helpful in working with polynomials. The Remainder Theorem: If P(x) is divided by x-c, then the remainder is P(c). The Factor Theorem: c is a zero of a P(x) if and only if x-c is a factor of P(x), that is if the remainder when dividing by x-c is zero. You can use synthetic division and the remainder theorem to evaluate a function at a given value. Example 5: Use synthetic division and the remainder theorem to find P(3) for P( x ) = 2 x 3 − x 2 + 4x + 3 M 1310 Example 6: 4.2 Dividing Polynomials Use synthetic division and the remainder theorem to find P(-1) for 5 P( x ) = 5x 4 − 8x − 5 Example 7: Determine if x + 2 is a factor of P( x ) = x 3 + 6x 2 + 3x − 10 . Example 8: Show that x = -1 is a zero of P( x ) = 3x 3 − 15x 2 − 3x + 15 . Find the remaining zeros of the function. M 1310 4.2 Dividing Polynomials 6 Example 9: Show that x =2 and x = -3 are zeros of P( x ) = x + 6x + 3x − 26x − 24 . Find the remaining zeros of the function. 4 3 2 Example 10: Find a 3rd degree polynomial with integer coefficients given that 0, 2 and - 3 are zeros.
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