Particle on a Circular Path Classical Motion of a particle in 1-D described by linear momentum ⃑ ⃑⃑ Motion of particle on a circular path described by angular momentum ⃑⃑ ⃑ ⃑ If ⃑ and are ⃑⃑ ⊥ so Dynamic properties Linear motion Linear displacement (x) Mass (m) Speed (v) Momentum (p) Rotational motion Angular displacement, (θ, radians) Moment of inertia (I) ) for particle on a ring ( Angular speed (, rad.s-1) Angular momentum (L) Relations for particle on a ring ( Quantization of Rotation Classically, kinetic energy of particle constrained to a ring: De Broglie relation, wave behavior of particle, ) Wave function must be single valued Require constructive interference Require integral number of wavelengths in full circle From standing wave in a ring solution In terms of angular momentum: Wave behavior of particle & cyclic boundary condition → quantization ( ) Quantized energy states ( ) Quantum Solution for Particle on a Ring Particle free to move on the ring so, V ( x,y) = 0 on the ring Schrödinger Equation for ring system (in spherical coordinates) ( ) This Equation have the following Solutions √ , √ ( ( √ √ ) ) ( (| | ) (| | ) ) means states with given |ml | are 2-fold DEGENERATE (except for ml= 0) Energy Level Diagram & Standing Wave in a Ring 4h 2 E2 = 8m 2 r 2 h2 E1 = 8m 2 r 2 E0 = 0 C S The particle on a ring model can be applied to electrons moving freely (π electrons) in a molecule Consider the benzene molecule as an example of the free particle move on a ring, in which the six electrons, only, are free to move, while the electrons are frozen in bonds with atoms Benzene Benzene has an absorption band at 200 nm for the 1st π→ π* transition. As a simple approximation, consider benzene as being a particle on a ring of radius 1.4 A. and consider the 6 π electrons to occupy the levels calculated using the particle on ring model No. of e’s = 6 r = 1.4 Å E=ELUMO – EHOMO ( E2 2 E1 1 E0 0 LUMO HOMO ) Comment on the results Calculate for naphthalene and anthracene considering the radius = no. of rings * 1.4 A Rigid Rotor Diatomic molecule approximated as “Rigid Rotor” = Two masses (atoms) rotating around the center of mass separated by a fixed distance (= bond length, r) To describe rotation around center of mass →reduced mass Reduced mass Moment of inertia Schrödinger equation of rotating diatomic Solutions = spherical harmonics ( ) Rotational energy levels given by: ( ( ) Energy levels given by: ( ) ( ) ) Degeneracy = Selection Rules = Requirements for transitions to occur Require molecule has permanent electric dipole moment need fluctuating charge to interact with light Allowed transitions: ( Spectrum = series of lines separated by 2B... Units of B B has units of energy (J) ) It can has units of frequency (Hz) and it can be take unit of wave number cm-1 We can determine the bond length from the line spacing in the spectrum and moment of inertia (r= bond length of diatomic) Examples: The microwave spectrum of 1H35Cl consists of a series of equally spaced lines separated by 6.26×1011Hz. Calculate the bond length of H-Cl. If the wave number of the rotational transition l =0 1 of 1H81Br is 16.93 cm-1. a- Calculate the rotational constant B (Hz) b- Calculate the bond length of HBr (Å) c- Calculate the energy of l =5 6 transition (J) d- If we deuterate HBr without affecting the bond length, what will happen to the position of the absorption peak?
© Copyright 2026 Paperzz