Lesson 20: Every Line Is a Graph of a Linear Equation

NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 20
8β€’4
Lesson 20: Every Line Is a Graph of a Linear Equation
Classwork
Opening Exercise
Show students Figure 1 below and challenge them to write the equation for the line. Provide students time to work
independently, then in pairs. Lead a discussion where students share their strategies for developing the equation of the
line. Ask students how they knew their equations were correct, i.e., did they verify that the points with integer
coordinates were solutions to the equation they wrote? Ask students what kind of equation they wrote: linear or
nonlinear. Ask students if they were given another line, could they write an equation for it using their strategy. Show
them Figure 2 and, again, ask them to write the equation of the line. Verify that they wrote the correct equation, and
conclude the discussion by stating that every line is the graph of a linear equation.
Opening Exercise
Figure 1
𝟐
πŸ‘
The equation for the line in Figure 1 is π’š = 𝒙 βˆ’ πŸ‘.
Lesson 20:
Date:
Every Line Is a Graph of a Linear Equation
1/4/15
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Lesson 20
NYS COMMON CORE MATHEMATICS CURRICULUM
8β€’4
Figure 2
𝟏
πŸ’
The equation for the line in Figure 2 is π’š = βˆ’ 𝒙 + 𝟐.
Example 1
ο‚§
Given a line, we want to be able to write the equation that represents it.
ο‚§
Which form of a linear equation do you think will be most valuable for this task, the standard form
π‘Žπ‘₯ + 𝑏𝑦 = 𝑐, or slope-intercept form 𝑦 = π‘šπ‘₯ + 𝑏?
οƒΊ
ο‚§
The slope-intercept form because we can easily identify the slope and 𝑦-intercept from both the
equation and the graph.
Write the equation that represents the line shown below.
Lesson 20:
Date:
Every Line Is a Graph of a Linear Equation
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ο‚§
8β€’4
First, identify the 𝑦-intercept.
οƒΊ
ο‚§
Lesson 20
The line intersects the 𝑦-axis at (0, 4).
Now, we must use what we know about slope to determine the slope of the line. Recall the following:
|𝑄𝑅|
π‘š=
.
|𝑃𝑄|
The point 𝑃 represents our 𝑦-intercept. Let’s locate a point 𝑅 on the line with integer coordinates.
οƒΊ
ο‚§
ο‚§
We can use the point (5, 2) or (βˆ’5, 6).
We can use either point. For this example, let’s use (5, 2).
Now we can locate point 𝑄. It must be to the right of point 𝑃 and be on a line parallel to the 𝑦-axis that goes
through point 𝑅. What is the location of 𝑄?
οƒΊ
Point 𝑄 must be (5, 4).
Lesson 20:
Date:
Every Line Is a Graph of a Linear Equation
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ο‚§
8β€’4
What fraction represents the slope of this line?
οƒΊ
ο‚§
Lesson 20
2
The slope π‘š = βˆ’ .
5
2
The slope of the line is π‘š = βˆ’ , and the 𝑦-intercept is (0, 4). What must the equation of the line be?
5
οƒΊ
2
The line is the graph of 𝑦 = βˆ’ π‘₯ + 4.
5
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Every Line Is a Graph of a Linear Equation
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Lesson 20
8β€’4
Example 2
ο‚§
What is the 𝑦-intercept of the line?
οƒΊ
ο‚§
The 𝑦-intercept is (0, βˆ’2).
Select another point, 𝑅, on the line with integer coordinates.
οƒΊ
Let 𝑅 be the point located at (1, 2).
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Every Line Is a Graph of a Linear Equation
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ο‚§
8β€’4
Now place point 𝑄, and find the slope of the line.
Q
οƒΊ
ο‚§
The slope of the line is π‘š = 4.
Write the equation for the line.
οƒΊ
The line is the graph of 𝑦 = 4π‘₯ βˆ’ 2.
Lesson 20:
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Every Line Is a Graph of a Linear Equation
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Lesson 20
8β€’4
Example 3
ο‚§
What is the 𝑦-intercept of the line? Notice the units on the coordinate plane have increased.
οƒΊ
ο‚§
The 𝑦-intercept is (0, βˆ’40).
Select another point, 𝑅, on the line with integer coordinates.
οƒΊ
Let 𝑅 = (50, 0).
Lesson 20:
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Every Line Is a Graph of a Linear Equation
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ο‚§
8β€’4
Now place point 𝑄 and find the slope of the line.
οƒΊ
ο‚§
Lesson 20
The slope of the line is π‘š =
40
50
4
= .
5
Write the equation for the line.
οƒΊ
4
The line is the graph of 𝑦 = π‘₯ βˆ’ 40.
5
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Every Line Is a Graph of a Linear Equation
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Lesson 20
NYS COMMON CORE MATHEMATICS CURRICULUM
ο‚§
8β€’4
The last thing we will do to this linear equation is rewrite it in standard form π‘Žπ‘₯ + 𝑏𝑦 = 𝑐, where π‘Ž, 𝑏,
and 𝑐 are integers, and π‘Ž is not negative. That means we must multiply the entire equation by a number that
4
will turn into an integer. What number should we multiply by?
5
οƒΊ
ο‚§
4
5
(5) = 4
We multiply the entire equation by 5.
4
π‘₯ βˆ’ 40) 5
5
5𝑦 = 4π‘₯ βˆ’ 200
(𝑦 =
βˆ’4π‘₯ + 5𝑦 = 4π‘₯ βˆ’ 4π‘₯ βˆ’ 200
βˆ’4π‘₯ + 5𝑦 = βˆ’200
βˆ’1(βˆ’4π‘₯ + 5𝑦 = βˆ’200)
4π‘₯ βˆ’ 5𝑦 = 200
The standard form of the linear equation is 4π‘₯ βˆ’ 5𝑦 = 200.
Exercises 1–6
Students complete Exercises 1–6 independently.
Exercises
1.
Write the equation that represents the line shown.
π’š = πŸ‘π’™ + 𝟐
Use the properties of equality to change the
equation from slope-intercept form,
π’š = π’Žπ’™ + 𝒃, to standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄,
where 𝒂, 𝒃, and 𝒄 are integers, and 𝒂 is not
negative.
π’š = πŸ‘π’™ + 𝟐
βˆ’πŸ‘π’™ + π’š = πŸ‘π’™ βˆ’ πŸ‘π’™ + 𝟐
βˆ’πŸ‘π’™ + π’š = 𝟐
βˆ’πŸ(βˆ’πŸ‘π’™ + π’š = 𝟐)
πŸ‘π’™ βˆ’ π’š = βˆ’πŸ
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Every Line Is a Graph of a Linear Equation
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2.
Lesson 20
8β€’4
Write the equation that represents the line shown.
𝟐
π’š=βˆ’ π’™βˆ’πŸ
πŸ‘
Use the properties of equality to change the
equation from slope-intercept form,
π’š = π’Žπ’™ + 𝒃, to standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄,
where 𝒂, 𝒃, and 𝒄 are integers, and 𝒂 is not
negative.
𝟐
π’š=βˆ’ π’™βˆ’πŸ
πŸ‘
𝟐
(π’š = βˆ’ 𝒙 βˆ’ 𝟏) πŸ‘
πŸ‘
πŸ‘π’š = βˆ’πŸπ’™ βˆ’ πŸ‘
πŸπ’™ + πŸ‘π’š = βˆ’πŸπ’™ + πŸπ’™ βˆ’ πŸ‘
πŸπ’™ + πŸ‘π’š = βˆ’πŸ‘
3.
Write the equation that represents the line shown.
𝟏
π’š= βˆ’ π’™βˆ’πŸ’
πŸ“
Use the properties of equality to change the
equation from slope-intercept form,
π’š = π’Žπ’™ + 𝒃, to standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄,
where 𝒂, 𝒃, and 𝒄 are integers, and 𝒂 is not
negative.
𝟏
π’š=βˆ’ π’™βˆ’πŸ’
πŸ“
𝟏
(π’š = βˆ’ 𝒙 βˆ’ πŸ’) πŸ“
πŸ“
πŸ“π’š = βˆ’π’™ βˆ’ 𝟐𝟎
𝒙 + πŸ“π’š = βˆ’π’™ + 𝒙 βˆ’ 𝟐𝟎
𝒙 + πŸ“π’š = βˆ’πŸπŸŽ
𝒙 + πŸ“π’š = βˆ’πŸπŸŽ
Lesson 20:
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Every Line Is a Graph of a Linear Equation
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4.
Lesson 20
8β€’4
Write the equation that represents the line shown.
π’š=𝒙
Use the properties of equality to change the
equation from slope-intercept form,
π’š = π’Žπ’™ + 𝒃, to standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄,
where 𝒂, 𝒃, and 𝒄 are integers, and 𝒂 is not
negative.
π’š=𝒙
βˆ’π’™ + π’š = 𝒙 βˆ’ 𝒙
βˆ’π’™ + π’š = 𝟎
βˆ’πŸ(βˆ’π’™ + π’š = 𝟎)
π’™βˆ’π’š= 𝟎
5.
Write the equation that represents the line shown.
π’š=
𝟏
𝒙+πŸ“
πŸ’
Use the properties of equality to change the
equation from slope-intercept form,
π’š = π’Žπ’™ + 𝒃, to standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄,
where 𝒂, 𝒃, and 𝒄 are integers, and 𝒂 is not
negative.
𝟏
𝒙+πŸ“
πŸ’
𝟏
(π’š = 𝒙 + πŸ“) πŸ’
πŸ’
π’š=
πŸ’π’š = 𝒙 + 𝟐𝟎
βˆ’π’™ + πŸ’π’š = 𝒙 βˆ’ 𝒙 + 𝟐𝟎
βˆ’π’™ + πŸ’π’š = 𝟐𝟎
βˆ’πŸ(βˆ’π’™ + πŸ’π’š = 𝟐𝟎)
𝒙 βˆ’ πŸ’π’š = βˆ’πŸπŸŽ
Lesson 20:
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Every Line Is a Graph of a Linear Equation
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6.
Lesson 20
8β€’4
Write the equation that represents the line shown.
πŸ–
π’š=βˆ’ π’™βˆ’πŸ•
πŸ“
Use the properties of equality to change the
equation from slope-intercept form,
π’š = π’Žπ’™ + 𝒃, to standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄,
where 𝒂, 𝒃, and 𝒄 are integers, and 𝒂 is not
negative.
πŸ–
π’š =βˆ’ π’™βˆ’πŸ•
πŸ“
πŸ–
(π’š = βˆ’ 𝒙 βˆ’ πŸ•) πŸ“
πŸ“
πŸ“π’š = βˆ’πŸ–π’™ βˆ’ πŸ‘πŸ“
πŸ–π’™ + πŸ“π’š = βˆ’πŸ–π’™ + πŸ–π’™ βˆ’ πŸ‘πŸ“
πŸ–π’™ + πŸ“π’š = βˆ’πŸ‘πŸ“
Closing
The main points from the lesson:
ο‚§
We know that every line is a graph of a linear equation.
ο‚§
We know how to use the 𝑦-intercept and the slope of a line to write the equation of a line.
Lesson Summary
Write the equation of a line by determining the π’š-intercept, (𝟎, 𝒃) and the slope, π’Ž, and replacing the numbers 𝒃
and π’Ž into the equation π’š = π’Žπ’™ + 𝒃.
Example:
Lesson 20:
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Every Line Is a Graph of a Linear Equation
1/4/15
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Lesson 20
8β€’4
The π’š-intercept of this graph is (𝟎, βˆ’πŸ).
The slope of this graph is π’Ž =
πŸ’
= πŸ’.
𝟏
The equation that represents the graph of this line is π’š = πŸ’π’™ βˆ’ 𝟐.
Use the properties of equality to change the equation from slope-intercept form, π’š = π’Žπ’™ + 𝒃, to standard form,
𝒂𝒙 + π’ƒπ’š = 𝒄, where 𝒂, 𝒃, and 𝒄 are integers, and 𝒂 is not negative.
Problem Set Sample Solutions
Students practice writing equations for lines.
1.
Write the equation that represents the line shown.
𝟐
π’š=βˆ’ π’™βˆ’πŸ’
πŸ‘
Use the properties of equality to change the
equation from slope-intercept form,
π’š = π’Žπ’™ + 𝒃, to standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄,
where 𝒂, 𝒃, and 𝒄 are integers, and 𝒂 is not
negative.
𝟐
π’š=βˆ’ π’™βˆ’πŸ’
πŸ‘
𝟐
(π’š = βˆ’ 𝒙 βˆ’ πŸ’) πŸ‘
πŸ‘
πŸ‘π’š = βˆ’πŸπ’™ βˆ’ 𝟏𝟐
πŸπ’™ + πŸ‘π’š = βˆ’πŸπ’™ + πŸπ’™ βˆ’ 𝟏𝟐
πŸπ’™ + πŸ‘π’š = βˆ’πŸπŸ
Lesson 20:
Date:
Every Line Is a Graph of a Linear Equation
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2.
Lesson 20
8β€’4
Write the equation that represents the line shown.
π’š = πŸ–π’™ + 𝟏
Use the properties of equality to change the equation from
slope-intercept form, π’š = π’Žπ’™ + 𝒃, to standard form,
𝒂𝒙 + π’ƒπ’š = 𝒄, where 𝒂, 𝒃, and 𝒄 are integers, and 𝒂 is not
negative.
π’š = πŸ–π’™ + 𝟏
βˆ’πŸ–π’™ + π’š = πŸ–π’™ βˆ’ πŸ–π’™ + 𝟏
βˆ’πŸ–π’™ + π’š = 𝟏
βˆ’πŸ(βˆ’πŸ–π’™ + π’š = 𝟏)
πŸ–π’™ βˆ’ π’š = βˆ’πŸ
3.
Write the equation that represents the line shown.
π’š=
𝟏
π’™βˆ’πŸ’
𝟐
Use the properties of equality to change the
equation from slope-intercept form, π’š = π’Žπ’™ + 𝒃, to
standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄, where 𝒂, 𝒃, and 𝒄 are
integers, and 𝒂 is not negative.
𝟏
π’™βˆ’πŸ’
𝟐
𝟏
(π’š = 𝒙 βˆ’ πŸ’) 𝟐
𝟐
πŸπ’š = 𝒙 βˆ’ πŸ–
π’š=
βˆ’π’™ + πŸπ’š = 𝒙 βˆ’ 𝒙 βˆ’ πŸ–
βˆ’π’™ + πŸπ’š = βˆ’πŸ–
βˆ’πŸ(βˆ’π’™ + πŸπ’š = βˆ’πŸ–)
𝒙 βˆ’ πŸπ’š = πŸ–
4.
Write the equation that represents the line shown.
π’š = βˆ’πŸ—π’™ βˆ’ πŸ–
Use the properties of equality to change the equation
from slope-intercept form, π’š = π’Žπ’™ + 𝒃, to standard
form, 𝒂𝒙 + π’ƒπ’š = 𝒄, where 𝒂, 𝒃, and 𝒄 are integers,
and 𝒂 is not negative.
π’š = βˆ’πŸ—π’™ βˆ’ πŸ–
πŸ—π’™ + π’š = βˆ’πŸ—π’™ + πŸ—π’™ βˆ’ πŸ–
πŸ—π’™ + π’š = βˆ’πŸ–
Lesson 20:
Date:
Every Line Is a Graph of a Linear Equation
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5.
Lesson 20
8β€’4
Write the equation that represents the line shown.
π’š = πŸπ’™ βˆ’ πŸπŸ’
Use the properties of equality to change the
equation from slope-intercept form, π’š = π’Žπ’™ + 𝒃,
to standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄, where 𝒂, 𝒃, and 𝒄
are integers, and 𝒂 is not negative.
π’š = πŸπ’™ βˆ’ πŸπŸ’
βˆ’πŸπ’™ + π’š = πŸπ’™ βˆ’ πŸπ’™ βˆ’ πŸπŸ’
βˆ’πŸπ’™ + π’š = βˆ’πŸπŸ’
βˆ’πŸ(βˆ’πŸπ’™ + π’š = βˆ’πŸπŸ’)
πŸπ’™ βˆ’ π’š = πŸπŸ’
6.
Write the equation that represents the line shown.
π’š = βˆ’πŸ“π’™ + πŸ’πŸ“
Use the properties of equality to change the
equation from slope-intercept form, π’š = π’Žπ’™ +
𝒃, to standard form, 𝒂𝒙 + π’ƒπ’š = 𝒄, where 𝒂, 𝒃,
and 𝒄 are integers, and 𝒂 is not negative.
π’š = βˆ’πŸ“π’™ + πŸ’πŸ“
πŸ“π’™ + π’š = βˆ’πŸ“π’™ + πŸ“π’™ + πŸ’πŸ“
πŸ“π’™ + π’š = πŸ’πŸ“
Lesson 20:
Date:
Every Line Is a Graph of a Linear Equation
1/4/15
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